Introduction
This experiment uses the computer program TracerDAQ to determine heat loss and record temperature over a period of time. Higher surface areas would result in a high cooling temperatures according to convective cooling. However, standard calculations don’t account for other factors such as gravity. One focus is to determine whether or not changing the surface area subject to gravity affects the cooling rate of the object. Another focus is comparing heat loss rates with different materials.
The program uses the same thermocouple to acquire results for the experiments. Information then goes through an amplifier and A / D board to constantly record the temperature.
Theory
The purpose of the experiment was to determine whether or not the orientation or position of an object in respect to gravity will affect the rate of cooling. In a Control Volume system, the formula for heat loss is:
Qdot = m * Cp * DT/dt
In relation, the formula for convective cooling is:
Qdot = -h * A * (T - Ta)
Where h is the heat transfer coefficient. If both equations were to equal together, the resulting equation will be:
dT / (T−T∞) = − dt / τ
Where τ = mCp / hA. The equation can then be integrated and rewritten as:
(T−T∞ ) / (Ti − T∞) = e ^ (-t / τ)
Where Ti is the initial temperature at t = 0.
Furthermore, we can declare that an object has a uniform heat distribution if Bi (Biot Number) is less than .1. The equation for the Bi is:
Bi = - hL∗ / k
Because our objects is spheres and cubes, L∗ = D / 6. Once h is determined, we can calculate the Biot number value and verify the uniform heat distribution throughout the objects.
Experimental Procedure
Header Size: 8
Version: 2
Sampling Interval: 4
Sampling Rate: 0.25
Sample Count: 675
Device Serial Number: 0
Culture Info: en-US
Sample Number
Date/Time
CHANNEL0
CHANNEL1
CHANNEL2
CHANNEL3
Events
1
09:31.3
96.78052
100.049
93.51766
92.7237
DAQ Start
LOG Start
2
09:35.3
94.6349
94.97813
90.32169
90.18092
3
09:39.3
93.60907
92.20478
88.24907
89.70265
4
09:43.3
92.83234
90.62181
86.27366
89.06199
5
09:47.3
92.18414
89.4566
84.56087
88.533
6
09:51.3
91.79549
88.86477
83.20285
87.94211
7
09:55.3
91.49573
88.31786
82.09596
87.68462
8
09:59.3
91.06771
87.97991
81.15548
87.6514
9
10:03.3
90.54916
87.70117
79.92236
87.63866
10
10:07.3
90.07372
87.452
79.10197
87.55497
11
10:11.3
89.66562
87.16432
78.33322
87.48182
12
10:15.3
89.33918
86.90532
77.6238
87.455
13
10:19.3
89.12218
86.7028
76.7456
87.35918
14
10:23.3
88.83614
86.4519
76.02013
87.23562
15
10:27.3
88.62991
86.23685
75.48945
87.07291
16
10:31.3
88.36901
86.02271
74.77069
86.8427
17
10:35.3
88.06332
85.81754
74.18481
86.66035
18
10:39.3
87.81767
85.59622
73.48264
86.46247
19
10:43.3
87.5909
85.35168
72.69301
86.26788
20
10:47.3
87.36056
85.22088
72.17264
86.09603
21
10:51.3
87.06657
85.14114
71.58565
85.7243
22
10:55.3
86.85239
85.19849
71.01501
85.60702
23
10:5.
IntroductionThis experiment uses the computer program Tracer.docx
1. Introduction
This experiment uses the computer program TracerDAQ to
determine heat loss and record temperature over a period of
time. Higher surface areas would result in a high cooling
temperatures according to convective cooling. However,
standard calculations don’t account for other factors such as
gravity. One focus is to determine whether or not changing the
surface area subject to gravity affects the cooling rate of the
object. Another focus is comparing heat loss rates with different
materials.
The program uses the same thermocouple to acquire results for
the experiments. Information then goes through an amplifier and
A / D board to constantly record the temperature.
Theory
The purpose of the experiment was to determine whether or not
the orientation or position of an object in respect to gravity will
affect the rate of cooling. In a Control Volume system, the
formula for heat loss is:
Qdot = m * Cp * DT/dt
In relation, the formula for convective cooling is:
Qdot = -h * A * (T - Ta)
Where h is the heat transfer coefficient. If both equations were
to equal together, the resulting equation will be:
dT / (T−T∞) = − dt / τ
2. Where τ = mCp / hA. The equation can then be integrated and
rewritten as:
(T−T∞ ) / (Ti − T∞) = e ^ (-t / τ)
Where Ti is the initial temperature at t = 0.
Furthermore, we can declare that an object has a uniform heat
distribution if Bi (Biot Number) is less than .1. The equation for
the Bi is:
Bi = - hL∗ / k
Because our objects is spheres and cubes, L∗ = D / 6. Once h is
determined, we can calculate the Biot number value and verify
the uniform heat distribution throughout the objects.
Experimental Procedure
Header Size: 8
Version: 2
Sampling Interval: 4
3. Sampling Rate: 0.25
Sample Count: 675
Device Serial Number: 0
Culture Info: en-US
Sample Number
Date/Time
CHANNEL0
CHANNEL1
CHANNEL2
154. 34.41415
DAQ Stop
LOG
Stop
Biot Numbers
Data Set
h (
Bi
Copper Sphere
291.121
0.00309
Stainless Steel Sphere
265.350
0.00282
Copper cube connected at the corner
783.299
0.00833
Copper cube connected at the center
275.168
0.00292
Copper Sphere
0.0596
155. 6.347E-6
Stainless Steel Sphere
0.0557
5.926E-6
Copper cube connected at the corner
0.247
2.632E-6
Copper cube connected at the center
0.6406
6.813E-6
Discussion
1)
2)
3)
4)
Uncertainty
The thermocouples used in this experiment are of Copper-
Constantan composition (Type T). According to Measurement
Computing USB -Temp and TC Series user’s manual, the Type
T thermocouple has a temperature range of -200 to 400 degrees
Celsius. At -200 degrees, the maximum error is 2.082 degrees,
while the average error is 0.744 degrees. At 0 degrees, the
maximum error is 0.870, while the average is 0.290 degrees. At
the maximum temperature of 400 degrees, the maximum is
0.568 degrees and the average is 0.208 degrees. The amount of
digital bits (maximum resolution) of the USB measuring device
is 24.
MCE 313 – LAB # 2
156. Combined Convective and Radiative Cooling of
Objects in the Environment
February 8, 2017
1 Purpose of Experiment
In this experiment is an introduction to heat transfer phenomena
and to the use of a data acquisition software
(TracerDAQ). The experiment consists of two major sections,
which are variations of a single theme and
result in the investigation of slightly different effects.
1.1 Geometric effects
In this section, the investigation focuses on the coupled natural
convective and radiative cooling of two
copper cubes suspended in air (see Fig. 1). The data obtained is
to be used to find the effective heat transfer
coefficients of the cubes and to determine whether orientation
with respect to the direction of gravity has a
significant influence on the heat transfer processes.
Figure 1: Copper cubes hung from corner (left) and from mid-
face (right).
1.2 Material effects
In this section, the investigation focuses on the cooling of two
spheres. One sphere is made of copper and
the other is made from 316 stainless steel (see Fig. 2). They will
be suspended in air and the cooling process
will be monitored. The effective heat transfer coefficients of the
two spheres will be determined and the data
157. will be used to quantify the effect of using different metals on
the cooling process.
All four objects have Type T (coper-constantan) thermocouples
embedded within them, and are posi-
tioned at the respective specimens’ geometric centers. These
thermocouples are connected to an amplifier
(Fig. 3), which, in turn, is attached to an A/D board. Using
TracerDAQ, the time history of the temperature
of the cubes and spheres can be measured as they cool.
1
Figure 2: Copper (left) and stainless steel (right) spheres.
Figure 3: USB-based 8-channel thermocouple input.
2 Theoretical Background
Consider an object surrounded by a control volume taken to
coincide with the object’s surface. Applying
the first law of thermodynamics to this control volume gives:
q = mCp
dT
dt
, (1)
where m is the mass of the specimen; Cp is the specific heat of
the material; q is the heat transfer rate; T
denotes temperature; and t represents time.
158. The right hand side of the equation represents the time rate of
change of the energy inside the control
volume and the left hand side, known as the rate of heat
transfer, is the total energy transferred into the
control volume, per unit time, across its surface. In writing this
equation, two assumptions are made. The
first is that the specific heat is a constant. The second is that the
entire object, consisting of its surface and
interior, can be taken to have a single temperature. The latter
assumption depends upon the object having a
very high internal ability to conduct energy from point to point
when compared to the rate at which energy
is transported across the surface. This condition can be
quantified and the validity of this assumption can
be verified after determining the effective heat transfer
coefficient.
Newton suggested that the rate of energy transported across the
surface could be related to the differ-
ence between the surface temperature, taken to be T because of
the above assumption, and the ambient
temperature of the surroundings T∞ = Ta. Thus,
q = −h̄ A(T − Ta), (2)
where h̄ is the assumed constant surface averaged film
coefficient or heat transfer coefficient; and
A is the surface area of the object. The equation also assumes
that the objects temperature is greater
than the surroundings so that energy will flow out of the control
volume. Equating 1 and 2 gives a simple
differential equation in terms of temperature:
2
159. mCp
dT
dt
= −h̄ A(T − T∞). (3)
Separating the variable, this equation can be rewritten as:
dT
T − T∞
= −
dt
τ
, (4)
where
τ =
mCp
h̄ A
. (5)
Note that in this form, the left side of the equation in non-
dimensional. Therefore, the right side must
also be unitless. Thus τ must have units of time.
To solve for temperature, note that Eq. 4 can be directly
integrated, the left side from To to T and the
right side, from 0 to t, yielding:
160. ln
T − T∞
Ti − T∞
= −
t
τ
, (6)
where Ti is the temperature at t = 0. The equation can also be
rewritten by taking the exponent of both
sides:
T − T∞
Ti − T∞
= exp
(
−
t
τ
)
. (7)
So, given the assumptions made, i.e. the object can be
characterized by a single temperature and the
average heat transfer coefficient is constant, the temperature of
the object decreases exponentially from its
initial value Ti to its final value T∞, which is reached only as
time tends toward infinity. The rate of the
exponential decay is controlled by the time constant τ.
161. Research has shown that the assumption of a uniform internal
temperature is justified if a certain non-
dimensional parameter called the Biot number is small. If the
Biot number is less than 0.1, then assuming
a constant internal temperature results in an error that is less
than 5%. The Biot number is the ratio of the
average surface heat transfer coefficient to the internal unit heat
conductance. This is expressed as:
Bi =
h̄ L∗
k
, (8)
where k is the coefficient of heat conduction ; L∗ is a
characteristic length corresponding to the ratio of
volume to surface area. For a cube, L∗ = S
6
. For a sphere, L∗ = D
6
. S is the length of one side of the cube,
and D is the diameter of the sphere.
Since both S and D are have a numerical value of 1 inch, L∗ =
0.1667in = 0.4233cm for both cube and
sphere.
In these experiments, once the heat conduction coefficient has
been determined, the value of the Biot
number can be calculated and the uniform temperature
assumption can be verified. The physical properties
of copper relevant to this experiment are given in Tbl 1.
162. 3 Procedure
1. Record the ambient temperature, T∞, in the lab. This can be
done by verifying the temperature of
any of the specimens, through TracerDAQ.
3
Table 1: Physical properties of copper and 316 stainless steel at
20oC
Material k (W/m oK) ρ (kg/m3) Cp (J/kg
oK)
Copper 398 8954 384
SS 13.8 8000 400
2. Turn on the hot plate, fill the container with water, and heat
it to boiling.
3. Open and setup TracerDAQ.
On the basic setup window
• Channel 0 is connected to the copper sphere.
• Channel 1 is connected to the stainless steel sphere.
• Channel 2 is connected to the corner of the copper cube.
• Channel 3 is connected to the center of the copper cube.
Set the frequency of acquisition.
163. Using a sample frequency of 10 Hz, for instance, means that 10
data values will be collected every 1 sec-
ond. This is a negligible time on the order of the total time to
cool these objects to room temperature.
Experience has shown that the total time to observe significant
cooling hovers in the vicinity of 30 to
45 minutes. Therefore, set the frequency such as to collect
approximately one (1) data point per minute.
The data output should be in terms of oC for each channel.
4. While in the process of setting up the TracerDAQ software,
place the four specimens into the boiling
water. Allow them to heat up until they attain constant, uniform
temperature. This should take
several minutes. When TracerDAQ is fully ready to begin
sampling, swiftly remove the objects and
suspend them from the horizontal rods held by the provided
stands. Place each object at one end of
the rod, making sure they hang vertically. Partitions screens
will be present and are meant to shield
the cooling objects from random disturbances (air streams)
coming from the surroundings. They also
prevent the radiation emanating from the objects from cross-
influencing each other. As soon as this is
done, activate the computer software to initiate data collection.
5. New data will appear on the computer screen every (1)
minute for the next forty-five minutes. The
computer software will desist its task of data collection at this
point. Save the data as a text (.txt)
file, which can then be read by a spreadsheet. Plan your time
efficiently during the waiting period,
monitoring the data collection, and discussing the meaning of
the various tasks required for the report.
164. This may seem trivial but in effect requires much thought.
A sample screen shot from TracerDAQ is show in Fig. 4
4
Figure 4: Screen shot of TracerDAQ software.
4 Data reduction
1. Plot the data for each object against time. Write a small code
to generate these initial plots, repre-
senting data values with symbols. View the results and decide
whether it is necessary to remove the
first few data points because they do not appear consistent with
the rest of the data set. The first
few points may have been subjected to unwanted transient
effects such as swinging back and forth
after being hung or the surface water film evaporating. If this is
not necessary just continue; or else
edit the unreliable data values from the data arrays. Remove
both the suspect temperatures and their
corresponding times. If this is done, be sure to readjust the time
values so that the first temperature
retained corresponds to time equal zero.
2. Next, perform a linear least squares fit with the remainder of
the data on semi-ln scales with a curve-
fitting program or software. The variables used are to be x = t
and y = ln T−T∞
Ti−T∞
, as in Eq. 6. Note
165. that when this is done, the first point is T = Ti. From the slope
of this fit, which will be the value of
(− 1
τ
), calculate the average heat transfer coefficient for each data
set and the associated Biot numbers.
3. Make eight (8) plots, two for each data set. One is a semi-ln
plot representing the fitting process with
the fit curve and the data (using a curve-fitting program or
software). The second plot for each data
set is to be the data compared to Eq. 7 on rectangular
coordinates showing the exponential behavior
(or lack of it) for each data set. Generate these plots by
modifying the code written for section 1 above.
5
5 Contents of the report
Each team is to produce a formal report, as described in the
syllabus.
The presentation of “results” that must contain at a minimum:
1. The eight plots indicated in the above section (50 points)
2. A presentation of the Biot numbers calculated for the
experiment (20 points)
3. Other considerations and text (30 points)
The “discussion” section should address each section of the
166. results listed above. Present your discussion
quantitatively rather than qualitatively. Specifically address the
following questions, among others
1. Does the data demonstrate that the assumption of a constant
heat transfer coefficient is reasonable,
i.e., are the semi-ln plots straight lines? Quantify this answer
using some uncertainties analysis.
2. Does the data demonstrate that the assumption of a constant
internal temperature for the objects in
the experiment is valid?
3. For Part 1 of the lab, is there an effect of orientation shown
in the results? Orientation relates to the
geometry of suspension, either being face centered or diagonal
down.
4. For Part 2 of the lab, is there any association between heat
transfer and material property?
For purposes of “uncertainty” at the minimum the following
should be considered:
1. The thermocouples are Type T (coper-constantan). (Please
refer to the user manuals associated with
this experiment to obtain the accuracies associated with the
equipment.) (25% of section mark).
2. The number of digital bits associated with the equipment.
(Again refer to use manual). (25% of section
mark).
In the “equipment” section, the following will be discussed,
amongst others:
167. 1. Discussion of voltages associated with the temperatures of
the thermocouples being used. (25% of
section mark).
2. Discussion of the fact that Type T thermocouples have a
sensitivity of about 43 µV/oC. (25% of section
mark).
6
PLEASE CHECK PAGE 32-37 IN DOCX FILE FOR DATA
NEEDED TO ANSWER QUESTIONS
The “discussion” section should address each section of the
results listed above. Present your discussion quantitatively
rather than qualitatively. Specifically address the following
questions, among others
1. Does the data demonstrate that the assumption of a constant
heat transfer coe cient is reasonable, i.e., are the semi-ln plots
straight lines? Quantify this answer using some uncertainties
analysis.
2. Does the data demonstrate that the assumption of a constant
internal temperature for the objects in the experiment is valid?
3. For Part 1 of the lab, is there an e?ect of orientation shown in
the results? Orientation relates to the geometry of suspension,
either being face centered or diagonal down.
4. For Part 2 of the lab, is there any association between heat
transfer and material property?