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The Discriminant Activity
 Pg. 656
Discriminant
 In the quadratic formula, the expression b 2 - 4ac is
 called the discriminant of the associated equation
  ax + bx + c = 0
    2
Using the Discriminant of ax + bx + c = 0
                            2
Example 1       Use the discriminant

   Equation             Discriminant               Number of
                                                   solutions
a. 2x2 + 6x + 5 = 0     62 – 4(2 ) (5 ) = –4       No solution

b. x2 – 7 = 0           02 – 4(1 ) ( – 7 ) = 28    Two solutions

c. 4x2 – 12x + 9 = 0    ( –12 )2 – 4(4 ) (9) = 0   One solution
Example 2       Multiple Choice Practice

Which statement best explains why there is only one
real solution to the quadratic equation 9x2 + 6x + 1 = 0?

       The value of ( 6 )2 – 4 • 9 • 1 is positive.

       The value of ( 6 )2 – 4 • 9 • 1 is equal to 0.

       The value of ( 6 )2 – 4 • 9 • 1 is negative.

       The value of ( 6 )2 – 4 • 9 • 1 is not a perfect
       square.
Example 2        Multiple Choice Practice

SOLUTION
Find the value of the discriminant.

   b2 – 4 • a • c = ( 6 )2 – 4 • 9 • 1 = 36 – 36 = 0
The discriminant is zero, so the equation has one real
solution.

ANSWER        The correct answer is B.
Example 3       Find the number of x-intercepts

Find the number of x-intercepts of the graph of
y = x2 – 3x – 10.

SOLUTION
Find the number of solutions of the equation
0 = x2 – 3x – 10.
   b2 – 4ac = ( – 3)2 – 4(1 ) ( –10 )   Substitute 1 for a, – 3 for b,
                                        and –10 for c.

             = 49                       Simplify.

The discriminant is positive, so the equation has two
solutions. This means that the graph of y = x2 – 3x – 10
has two x-intercepts.
Example 3    Find the number of x-intercepts

CHECK You can use a graphing calculator to check
      the answer. Notice that the graph of
       y = x2 – 3x – 10 has two x-intercepts.




        You can also use factoring to check the answer.
        Because x2 – 3x – 10 = ( x – 5 ) ( x + 2 ), the
        graph of y = x2 – 3x – 10 crosses the x-axis at
        x – 5 = 0, or x = 5, and at x + 2 = 0, or x = – 2.
Example 4     Solve a multi-step problem

FOUNTAINS
The Centennial Fountain in Chicago shoots a water arc
that can be modeled by the graph of the equation
y = – 0.006x2 + 1.2x + 10 where x is the horizontal
distance (in feet) from the river’s north shore and y is
the height (in feet) above the river. Does the water arc
reach a height of 50 feet? If so, about how far from the
north shore is the water arc 50 feet above the water?
Example 4      Solve a multi-step problem

SOLUTION
STEP 1 Write a quadratic equation. You want to know
       whether the water arc reaches a height of 50
       feet, so let y = 50. Then write the quadratic
       equation in standard form.
         y = – 0.006x2    + 1.2x   + 10    Write given equation.

         50 = – 0.006x2   + 1.2x   + 10    Substitute 50 for y.

         0 = – 0.006x2    + 1.2x   – 40    Subtract 50 from each side.

STEP 2 Find the value of the discriminant of
         0 = – 0.006x2    + 1.2x   – 40.
Example 4       Solve a multi-step problem

  b2 – 4ac   = ( 1.2)2 – 4 ( – 0.006 ) ( – 40 ) a = – 0.006, b = 1.2,
                                              c = – 40

             = 0.48                           Simplify.

STEP 3 Interpret the discriminant. Because the
       discriminant is positive, the equation has two
       solutions. So, the water arc reaches a height of
       50 feet at two points on the water arc.

STEP 4 Solve the equation 0 = – 0.006x2 + 1.2x – 40 to
       find the distance from the north shore where
       the water arc is 50 feet above the water.
Example 4        Solve a multi-step problem

                –b +
                   –      b2 – 4ac
        x =                               Quadratic formula
                          2a

                – 1.2 +
                      –    0.48
            =                             Substitute values in
                  2 ( – 0.006 )           the quadratic formula.
        x ≈ 42 or 158                     Use a calculator.

ANSWER
The water arc is 50 feet above the water about 42 feet
from the north shore and about 158 feet from the north
shore.
10.8 Warm-Up
Tell whether the equation has 2 solutions, one solution,
or no solution.
1. x 2 + 4x + 3 = 0
2. 2x 2 - 5x + 6 = 0
3. -x 2 + 2x =1
Find the number of x-intercepts of the graph of the
function.
4. y = x 2 +10x + 25
5. y = x 2 - 9x

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10.8

  • 1.
  • 3. Discriminant  In the quadratic formula, the expression b 2 - 4ac is called the discriminant of the associated equation ax + bx + c = 0 2
  • 4. Using the Discriminant of ax + bx + c = 0 2
  • 5. Example 1 Use the discriminant Equation Discriminant Number of solutions a. 2x2 + 6x + 5 = 0 62 – 4(2 ) (5 ) = –4 No solution b. x2 – 7 = 0 02 – 4(1 ) ( – 7 ) = 28 Two solutions c. 4x2 – 12x + 9 = 0 ( –12 )2 – 4(4 ) (9) = 0 One solution
  • 6. Example 2 Multiple Choice Practice Which statement best explains why there is only one real solution to the quadratic equation 9x2 + 6x + 1 = 0? The value of ( 6 )2 – 4 • 9 • 1 is positive. The value of ( 6 )2 – 4 • 9 • 1 is equal to 0. The value of ( 6 )2 – 4 • 9 • 1 is negative. The value of ( 6 )2 – 4 • 9 • 1 is not a perfect square.
  • 7. Example 2 Multiple Choice Practice SOLUTION Find the value of the discriminant. b2 – 4 • a • c = ( 6 )2 – 4 • 9 • 1 = 36 – 36 = 0 The discriminant is zero, so the equation has one real solution. ANSWER The correct answer is B.
  • 8. Example 3 Find the number of x-intercepts Find the number of x-intercepts of the graph of y = x2 – 3x – 10. SOLUTION Find the number of solutions of the equation 0 = x2 – 3x – 10. b2 – 4ac = ( – 3)2 – 4(1 ) ( –10 ) Substitute 1 for a, – 3 for b, and –10 for c. = 49 Simplify. The discriminant is positive, so the equation has two solutions. This means that the graph of y = x2 – 3x – 10 has two x-intercepts.
  • 9. Example 3 Find the number of x-intercepts CHECK You can use a graphing calculator to check the answer. Notice that the graph of y = x2 – 3x – 10 has two x-intercepts. You can also use factoring to check the answer. Because x2 – 3x – 10 = ( x – 5 ) ( x + 2 ), the graph of y = x2 – 3x – 10 crosses the x-axis at x – 5 = 0, or x = 5, and at x + 2 = 0, or x = – 2.
  • 10. Example 4 Solve a multi-step problem FOUNTAINS The Centennial Fountain in Chicago shoots a water arc that can be modeled by the graph of the equation y = – 0.006x2 + 1.2x + 10 where x is the horizontal distance (in feet) from the river’s north shore and y is the height (in feet) above the river. Does the water arc reach a height of 50 feet? If so, about how far from the north shore is the water arc 50 feet above the water?
  • 11. Example 4 Solve a multi-step problem SOLUTION STEP 1 Write a quadratic equation. You want to know whether the water arc reaches a height of 50 feet, so let y = 50. Then write the quadratic equation in standard form. y = – 0.006x2 + 1.2x + 10 Write given equation. 50 = – 0.006x2 + 1.2x + 10 Substitute 50 for y. 0 = – 0.006x2 + 1.2x – 40 Subtract 50 from each side. STEP 2 Find the value of the discriminant of 0 = – 0.006x2 + 1.2x – 40.
  • 12. Example 4 Solve a multi-step problem b2 – 4ac = ( 1.2)2 – 4 ( – 0.006 ) ( – 40 ) a = – 0.006, b = 1.2, c = – 40 = 0.48 Simplify. STEP 3 Interpret the discriminant. Because the discriminant is positive, the equation has two solutions. So, the water arc reaches a height of 50 feet at two points on the water arc. STEP 4 Solve the equation 0 = – 0.006x2 + 1.2x – 40 to find the distance from the north shore where the water arc is 50 feet above the water.
  • 13. Example 4 Solve a multi-step problem –b + – b2 – 4ac x = Quadratic formula 2a – 1.2 + – 0.48 = Substitute values in 2 ( – 0.006 ) the quadratic formula. x ≈ 42 or 158 Use a calculator. ANSWER The water arc is 50 feet above the water about 42 feet from the north shore and about 158 feet from the north shore.
  • 14. 10.8 Warm-Up Tell whether the equation has 2 solutions, one solution, or no solution. 1. x 2 + 4x + 3 = 0 2. 2x 2 - 5x + 6 = 0 3. -x 2 + 2x =1 Find the number of x-intercepts of the graph of the function. 4. y = x 2 +10x + 25 5. y = x 2 - 9x

Editor's Notes

  1. 1. 2 2. no soln. 3. 1 4. 1 5. 2