SlideShare a Scribd company logo
1 of 29
Download to read offline
Launch: 12/2
  Grab your binder and immediately take a seat!
  Place homework (practice questions), binder paper, and
  a pen/pencil on your desk.



Today’s Objective: I can convert between grams and
  atoms using both molecular mass and
  Avogadro’s number as a conversion factors
Tonight’s HW: Finish the back of the practice
  question worksheet
Launch 12/2
4.  How many molecules of C3OH are in .5 moles?
  a.    3.01 X 1023 molecules
  b.    6.02 X 1023 molecules
  c.    9.03 X 1023 molecules
  d.    1.204 X 1024 atoms
Launch 12/2
5.  If there are 1.204 X 1024 particles of gold (Au), how
   many moles are there?
  a.  .5 moles
  b.  1 mole
  c.  2 moles
  d.  4 moles
Announcements
  Quiz on Friday
    The mole
    Conversions

  Unit exam in 2 weeks
How many atoms? – Part II
          Mr. Heffner
           12/1/09
How many atoms?
     Conversion factors…                 ..or particles, or molecules

       are used to convert one unit to another unit
sum of
atomic     Molar Mass                    Avogadro’s #
masses
          ? grams/mole              6.02 X 1023 atoms/mole
            ? grams                   6.02 X 1023 atoms
             1 mole                         1 mole
             1 mole                         1 mole
            ? grams                   6.02 X 1023 atoms
         Grams  Moles               Atoms  Moles
How many atoms?
  What if we want to convert grams  atoms?
    Need to use both conversion factors!
How many atoms?
  There is a 3-step process for conversions:
  1.  Write down the starting unit and look at the ending unit.
  2.  Write the conversion factor with the starting units on the
      bottom.
      If grams, start with molar mass
      If atoms (or particles, or molecules), start with Avogadro’s #
  3.  Cancel like terms and multiply across the top and bottom.
Example #1
   How many atoms are there in 12.01 grams of carbon (C)?

  Step #1: Write down the starting unit and look at the
  ending unit.



  12.01 grams
Example #1
    How many atoms are there in 12.01 grams of carbon (C)?

  Step #2: Write the conversion factor with the starting units
   on the bottom.
                    1 mol        6.02 X 1023 atoms
  12.01 g X                    X                   =
                   12.01 g             1 mol


      Start with               Then use
      molecular              Avogadro’s #
        mass
Example #1
   How many atoms are there in 12.01 grams of carbon (C)?

  Step #3: Cancel like terms and multiply across the top
   and bottom
                  1 mol         6.02 X 1023 atoms
  12.01 g X                   X                   =
                 12.01 g              1 mol
                                                   Ignore

                            1 X 6.02 X 1023 atoms
                                                  =
                                      1

                                 6.02 X 1023 atoms =
Example #3
 How many grams of CH4 are there in 12.04 X 1023 molecules?

Step #1: Write down the starting unit and look at the ending
                             unit.


  12.04 X 1023 molecules
Example #3
  How many grams of CH4 are there in 12.04 X 1023 molecules?

  Step #2: Write the conversion factor with the starting units
   on the bottom.

                                     1 mol              16.05 g
12.04 X   1023   molecules X                        X
                                                         1 mol
                                                                  =
                             6.02 X 10 23 molecules




                                                  Then use
                     Start with                   molecular
                    Avogadro’s #                   mass
Example #3
  How many grams of CH4 are there in 12.04 X 1023 molecules?

  Step #3: Cancel like terms and multiply across the top
   and bottom

                                     1 mol              16.05 g
12.04 X   1023   molecules X                        X
                                                         1 mol
                                                                  =
                             6.02 X 10 23 molecules



                                       12.04 X 1 X 16.05 g
                                                                  =
                                            6.02 X 1

                                        32.10 g = 2 X 16.05 g =
Example #2
       How many atoms are there in 16.00 grams of O2?

  Step #1: Write down the starting unit and look at the
  ending unit.



  16.00 grams
Example #2
       How many atoms are there in 16.00 grams of O2?

  Step #2: Write the conversion factor with the starting units
   on the bottom.
                    1 mol        6.02 X 1023 atoms
  16.00 g X                    X                   =
                   32.00 g             1 mol


      Start with               Then use
      molecular              Avogadro’s #
        mass
Example #2
       How many atoms are there in 16.00 grams of O2?

  Step #3: Cancel like terms and multiply across the top
   and bottom
                  1 mol         6.02 X 1023 atoms
  16.00g X                    X                   =
                 32.00 g              1 mol
                                                   Ignore

                        16.00 X 6.02 X 1023 atoms
                                                  =
                                32.00 X 1

     3.01 X 1023 atoms = .5 X 6.02 X 1023 atoms =
Whiteboards
  Work in pairs
    Trade-off marker every question
  You have 60 seconds to solve the question
    Show all of your work!
    Don’t forget units!

  Lift board only when prompted
How many atoms are there in
8.00 grams of helium (He) ?
How many molecules are
there in 4.04 grams of H2?
What is the mass (in grams)
 of 6.02 X 10  23 particles

        of gold (Au)?
How many grams does
3.01 X 1023 molecules

    of HCl weight?
Practice Questions
  Practice question worksheet
Exit Slip
1.  Which conversion factor would need to be used to
   convert between gramsmoles?
  a.  Avogadro’s number
  b.  6.02 X 1023 atoms/mole
  c.  Molecular mass
  d.  Atomic weight
Exit Slip
2.  Which conversion factor would need to be used to
   convert grams into atoms?
  a.  Avogadro’s number
  b.  Atomic weight
  c.  Molecular mass
  d.  both a & c
Exit Slip
3.  Which of the following correctly shows how to convert
   64.00g of O2 to atoms?
               6.02 X 1023 atoms
  a.  32.00g X
                    32.00g
                  1 mole
  b.  64.00g X    32.00 g
                  1 mole      6.02 X 1023 atoms
  c.  64.00g X    32.00 g X        1 mole
                     1 mole            1 atoms
  d.  64.00 g X                  X
                  6.02 X 10 23 g
                                     32.00 moles
Exit Slip
4.  How many atoms of nitrogen (N) are there in 14.01g?
  a.    3.01 X 1023 atoms
  b.    6.02 X 1023 atoms
  c.    9.03 X 1023 atoms
  d.    1.204 X 1024 atoms
Exit Slip
5.  How many grams does 12.04 X 1023 molecules of
   H2O weigh?
  a.  9.01g
  b.  18.02g
  c.  27.03g
  d.  36.04g
Homework
  Finish practice questions
  Study for Friday’s Quiz!

More Related Content

What's hot

Moles molar mass_avonumb pt2
Moles molar mass_avonumb pt2Moles molar mass_avonumb pt2
Moles molar mass_avonumb pt2Lumen Learning
 
2016 topic 01 part 1
2016 topic 01   part 12016 topic 01   part 1
2016 topic 01 part 1David Young
 
12 7 What Are Mole Ratios
12 7 What Are Mole Ratios12 7 What Are Mole Ratios
12 7 What Are Mole Ratiosmrheffner
 
IB Chemistry on Mole Concept
IB Chemistry on Mole ConceptIB Chemistry on Mole Concept
IB Chemistry on Mole ConceptLawrence kok
 
Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02
Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02
Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02Cleophas Rwemera
 
11 25 How Many Moles1
11 25 How Many Moles111 25 How Many Moles1
11 25 How Many Moles1mrheffner
 
Electron claustrophobia and stability of atoms
Electron claustrophobia and stability of atomsElectron claustrophobia and stability of atoms
Electron claustrophobia and stability of atomsMaurice Maeck
 
First term review answers
First term review answersFirst term review answers
First term review answersFer Pelaez
 
First term review answers
First term review answersFirst term review answers
First term review answersFer Pelaez
 
Chapter 10 notes
Chapter 10 notesChapter 10 notes
Chapter 10 notesTia Hohler
 
Moles, Calculations, Dimensional Analysis!!!
Moles, Calculations, Dimensional Analysis!!!Moles, Calculations, Dimensional Analysis!!!
Moles, Calculations, Dimensional Analysis!!!guest806c70
 

What's hot (19)

Moles molar mass_avonumb pt2
Moles molar mass_avonumb pt2Moles molar mass_avonumb pt2
Moles molar mass_avonumb pt2
 
2016 topic 01 part 1
2016 topic 01   part 12016 topic 01   part 1
2016 topic 01 part 1
 
Chapter6
Chapter6Chapter6
Chapter6
 
Mole Concept
Mole ConceptMole Concept
Mole Concept
 
What’s in a mole
What’s in a mole What’s in a mole
What’s in a mole
 
How Big Is A Mole
How Big Is A MoleHow Big Is A Mole
How Big Is A Mole
 
12 7 What Are Mole Ratios
12 7 What Are Mole Ratios12 7 What Are Mole Ratios
12 7 What Are Mole Ratios
 
IB Chemistry on Mole Concept
IB Chemistry on Mole ConceptIB Chemistry on Mole Concept
IB Chemistry on Mole Concept
 
Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02
Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02
Chapter9molesequationsandstoichiometry 150202130904-conversion-gate02
 
Mole concept
Mole conceptMole concept
Mole concept
 
Chapter 3.powerpoint
Chapter 3.powerpointChapter 3.powerpoint
Chapter 3.powerpoint
 
11 25 How Many Moles1
11 25 How Many Moles111 25 How Many Moles1
11 25 How Many Moles1
 
Electron claustrophobia and stability of atoms
Electron claustrophobia and stability of atomsElectron claustrophobia and stability of atoms
Electron claustrophobia and stability of atoms
 
First term review answers
First term review answersFirst term review answers
First term review answers
 
First term review answers
First term review answersFirst term review answers
First term review answers
 
Mole
MoleMole
Mole
 
The Atomic Theory
The Atomic TheoryThe Atomic Theory
The Atomic Theory
 
Chapter 10 notes
Chapter 10 notesChapter 10 notes
Chapter 10 notes
 
Moles, Calculations, Dimensional Analysis!!!
Moles, Calculations, Dimensional Analysis!!!Moles, Calculations, Dimensional Analysis!!!
Moles, Calculations, Dimensional Analysis!!!
 

Similar to 12 2 How Many Atoms Part Ii

12 10 How Many Grams Part Ii
12 10 How Many Grams   Part Ii12 10 How Many Grams   Part Ii
12 10 How Many Grams Part Iimrheffner
 
Chapter_3_Mass_Relationships.ppt
Chapter_3_Mass_Relationships.pptChapter_3_Mass_Relationships.ppt
Chapter_3_Mass_Relationships.pptIvyJoyceBuan2
 
Avogadro constant
Avogadro constantAvogadro constant
Avogadro constantfhairuze
 
Mole Concept.pptx (Grade 9, second quarter)
Mole Concept.pptx (Grade 9, second quarter)Mole Concept.pptx (Grade 9, second quarter)
Mole Concept.pptx (Grade 9, second quarter)AprilJoyMangurali1
 
Chapter 9 moles, equations, and stoichiometry
Chapter 9 moles, equations, and stoichiometryChapter 9 moles, equations, and stoichiometry
Chapter 9 moles, equations, and stoichiometrytanzmanj
 
NWTC General Chemistry Ch 07
NWTC General Chemistry Ch 07NWTC General Chemistry Ch 07
NWTC General Chemistry Ch 07Steve Sinclair
 
Chemistry - Chp 10 - Chemical Quantities - PowerPoint
Chemistry - Chp 10 - Chemical Quantities - PowerPointChemistry - Chp 10 - Chemical Quantities - PowerPoint
Chemistry - Chp 10 - Chemical Quantities - PowerPointMel Anthony Pepito
 
Chapter 3 notes
Chapter 3 notes Chapter 3 notes
Chapter 3 notes Wong Hsiung
 
Student Ch 9 The Mole
Student Ch 9 The MoleStudent Ch 9 The Mole
Student Ch 9 The Molejeanine
 
CHEMISTRY CHAPTER 1.2 Mole Concepts.pptx
CHEMISTRY CHAPTER 1.2 Mole Concepts.pptxCHEMISTRY CHAPTER 1.2 Mole Concepts.pptx
CHEMISTRY CHAPTER 1.2 Mole Concepts.pptxLokiIkol2
 
This activity is designed to introduce a convenient unit used by.docx
This activity is designed to introduce a convenient unit used by.docxThis activity is designed to introduce a convenient unit used by.docx
This activity is designed to introduce a convenient unit used by.docxhowardh5
 
Chapter 7.3 : Using Chemical Formulas
Chapter 7.3 : Using Chemical FormulasChapter 7.3 : Using Chemical Formulas
Chapter 7.3 : Using Chemical FormulasChris Foltz
 

Similar to 12 2 How Many Atoms Part Ii (20)

12 10 How Many Grams Part Ii
12 10 How Many Grams   Part Ii12 10 How Many Grams   Part Ii
12 10 How Many Grams Part Ii
 
7648568.ppt
7648568.ppt7648568.ppt
7648568.ppt
 
Chapter_3_Mass_Relationships.ppt
Chapter_3_Mass_Relationships.pptChapter_3_Mass_Relationships.ppt
Chapter_3_Mass_Relationships.ppt
 
Avogadro constant
Avogadro constantAvogadro constant
Avogadro constant
 
Mole Concept.pptx (Grade 9, second quarter)
Mole Concept.pptx (Grade 9, second quarter)Mole Concept.pptx (Grade 9, second quarter)
Mole Concept.pptx (Grade 9, second quarter)
 
Moles
MolesMoles
Moles
 
The mole
The moleThe mole
The mole
 
Chapter 9 moles, equations, and stoichiometry
Chapter 9 moles, equations, and stoichiometryChapter 9 moles, equations, and stoichiometry
Chapter 9 moles, equations, and stoichiometry
 
mole.ppt
mole.pptmole.ppt
mole.ppt
 
NWTC General Chemistry Ch 07
NWTC General Chemistry Ch 07NWTC General Chemistry Ch 07
NWTC General Chemistry Ch 07
 
Moles
MolesMoles
Moles
 
Ch 11 notes complete
Ch 11 notes completeCh 11 notes complete
Ch 11 notes complete
 
Mole Concept
Mole ConceptMole Concept
Mole Concept
 
Chemistry - Chp 10 - Chemical Quantities - PowerPoint
Chemistry - Chp 10 - Chemical Quantities - PowerPointChemistry - Chp 10 - Chemical Quantities - PowerPoint
Chemistry - Chp 10 - Chemical Quantities - PowerPoint
 
Chapter 3 notes
Chapter 3 notes Chapter 3 notes
Chapter 3 notes
 
Student Ch 9 The Mole
Student Ch 9 The MoleStudent Ch 9 The Mole
Student Ch 9 The Mole
 
CHEMISTRY CHAPTER 1.2 Mole Concepts.pptx
CHEMISTRY CHAPTER 1.2 Mole Concepts.pptxCHEMISTRY CHAPTER 1.2 Mole Concepts.pptx
CHEMISTRY CHAPTER 1.2 Mole Concepts.pptx
 
This activity is designed to introduce a convenient unit used by.docx
This activity is designed to introduce a convenient unit used by.docxThis activity is designed to introduce a convenient unit used by.docx
This activity is designed to introduce a convenient unit used by.docx
 
Chapter 7.3 : Using Chemical Formulas
Chapter 7.3 : Using Chemical FormulasChapter 7.3 : Using Chemical Formulas
Chapter 7.3 : Using Chemical Formulas
 
Mole calculations
Mole calculationsMole calculations
Mole calculations
 

More from mrheffner

3 2 What Is Heat
3 2 What Is Heat3 2 What Is Heat
3 2 What Is Heatmrheffner
 
2 24 Unit #7 Jeopardy
2 24 Unit #7 Jeopardy2 24 Unit #7 Jeopardy
2 24 Unit #7 Jeopardymrheffner
 
2 23 Gases Review
2 23 Gases Review2 23 Gases Review
2 23 Gases Reviewmrheffner
 
2 22 What Is The Combined Gas Law
2 22 What Is The Combined Gas Law2 22 What Is The Combined Gas Law
2 22 What Is The Combined Gas Lawmrheffner
 
2 10 How Are P And T Related
2 10 How Are P And T Related2 10 How Are P And T Related
2 10 How Are P And T Relatedmrheffner
 
2 9 Chemical Bonding Benchmark Review Part Ii
2 9 Chemical Bonding Benchmark Review   Part Ii2 9 Chemical Bonding Benchmark Review   Part Ii
2 9 Chemical Bonding Benchmark Review Part Iimrheffner
 
2 4 What Is Pressure
2 4 What Is Pressure2 4 What Is Pressure
2 4 What Is Pressuremrheffner
 
2 3 What Is Temperature
2 3 What Is Temperature2 3 What Is Temperature
2 3 What Is Temperaturemrheffner
 
1 27 Unit #6 Jeopardy
1 27  Unit #6  Jeopardy1 27  Unit #6  Jeopardy
1 27 Unit #6 Jeopardymrheffner
 
1 27 Unit #6 Jeopardy
1 27 Unit #6 Jeopardy1 27 Unit #6 Jeopardy
1 27 Unit #6 Jeopardymrheffner
 
1 26 Unit #6 Exam Review
1 26 Unit #6 Exam Review1 26 Unit #6 Exam Review
1 26 Unit #6 Exam Reviewmrheffner
 
1 22 What Are Strong Acids And Bases
1 22 What Are Strong Acids And Bases1 22 What Are Strong Acids And Bases
1 22 What Are Strong Acids And Basesmrheffner
 
1 25 What Is P H
1 25 What Is P H1 25 What Is P H
1 25 What Is P Hmrheffner
 
1 14 What Is Concentration Part Iii
1 14 What Is Concentration   Part Iii1 14 What Is Concentration   Part Iii
1 14 What Is Concentration Part Iiimrheffner
 
1 12 What Is Concentration Part Ii
1 12 What Is Concentration   Part Ii1 12 What Is Concentration   Part Ii
1 12 What Is Concentration Part Iimrheffner
 
1 11 What Is Concentration
1 11 What Is Concentration1 11 What Is Concentration
1 11 What Is Concentrationmrheffner
 
1 7 What Is Solubility
1 7 What Is Solubility1 7 What Is Solubility
1 7 What Is Solubilitymrheffner
 
1 6 How Are Solutes Dissolved
1 6 How Are Solutes Dissolved1 6 How Are Solutes Dissolved
1 6 How Are Solutes Dissolvedmrheffner
 
1 5 What Are Solutions
1 5 What Are Solutions1 5 What Are Solutions
1 5 What Are Solutionsmrheffner
 
1 5 What Are Solutions
1 5 What Are Solutions1 5 What Are Solutions
1 5 What Are Solutionsmrheffner
 

More from mrheffner (20)

3 2 What Is Heat
3 2 What Is Heat3 2 What Is Heat
3 2 What Is Heat
 
2 24 Unit #7 Jeopardy
2 24 Unit #7 Jeopardy2 24 Unit #7 Jeopardy
2 24 Unit #7 Jeopardy
 
2 23 Gases Review
2 23 Gases Review2 23 Gases Review
2 23 Gases Review
 
2 22 What Is The Combined Gas Law
2 22 What Is The Combined Gas Law2 22 What Is The Combined Gas Law
2 22 What Is The Combined Gas Law
 
2 10 How Are P And T Related
2 10 How Are P And T Related2 10 How Are P And T Related
2 10 How Are P And T Related
 
2 9 Chemical Bonding Benchmark Review Part Ii
2 9 Chemical Bonding Benchmark Review   Part Ii2 9 Chemical Bonding Benchmark Review   Part Ii
2 9 Chemical Bonding Benchmark Review Part Ii
 
2 4 What Is Pressure
2 4 What Is Pressure2 4 What Is Pressure
2 4 What Is Pressure
 
2 3 What Is Temperature
2 3 What Is Temperature2 3 What Is Temperature
2 3 What Is Temperature
 
1 27 Unit #6 Jeopardy
1 27  Unit #6  Jeopardy1 27  Unit #6  Jeopardy
1 27 Unit #6 Jeopardy
 
1 27 Unit #6 Jeopardy
1 27 Unit #6 Jeopardy1 27 Unit #6 Jeopardy
1 27 Unit #6 Jeopardy
 
1 26 Unit #6 Exam Review
1 26 Unit #6 Exam Review1 26 Unit #6 Exam Review
1 26 Unit #6 Exam Review
 
1 22 What Are Strong Acids And Bases
1 22 What Are Strong Acids And Bases1 22 What Are Strong Acids And Bases
1 22 What Are Strong Acids And Bases
 
1 25 What Is P H
1 25 What Is P H1 25 What Is P H
1 25 What Is P H
 
1 14 What Is Concentration Part Iii
1 14 What Is Concentration   Part Iii1 14 What Is Concentration   Part Iii
1 14 What Is Concentration Part Iii
 
1 12 What Is Concentration Part Ii
1 12 What Is Concentration   Part Ii1 12 What Is Concentration   Part Ii
1 12 What Is Concentration Part Ii
 
1 11 What Is Concentration
1 11 What Is Concentration1 11 What Is Concentration
1 11 What Is Concentration
 
1 7 What Is Solubility
1 7 What Is Solubility1 7 What Is Solubility
1 7 What Is Solubility
 
1 6 How Are Solutes Dissolved
1 6 How Are Solutes Dissolved1 6 How Are Solutes Dissolved
1 6 How Are Solutes Dissolved
 
1 5 What Are Solutions
1 5 What Are Solutions1 5 What Are Solutions
1 5 What Are Solutions
 
1 5 What Are Solutions
1 5 What Are Solutions1 5 What Are Solutions
1 5 What Are Solutions
 

Recently uploaded

Beyond Boundaries: Leveraging No-Code Solutions for Industry Innovation
Beyond Boundaries: Leveraging No-Code Solutions for Industry InnovationBeyond Boundaries: Leveraging No-Code Solutions for Industry Innovation
Beyond Boundaries: Leveraging No-Code Solutions for Industry InnovationSafe Software
 
Enhancing Worker Digital Experience: A Hands-on Workshop for Partners
Enhancing Worker Digital Experience: A Hands-on Workshop for PartnersEnhancing Worker Digital Experience: A Hands-on Workshop for Partners
Enhancing Worker Digital Experience: A Hands-on Workshop for PartnersThousandEyes
 
Are Multi-Cloud and Serverless Good or Bad?
Are Multi-Cloud and Serverless Good or Bad?Are Multi-Cloud and Serverless Good or Bad?
Are Multi-Cloud and Serverless Good or Bad?Mattias Andersson
 
Science&tech:THE INFORMATION AGE STS.pdf
Science&tech:THE INFORMATION AGE STS.pdfScience&tech:THE INFORMATION AGE STS.pdf
Science&tech:THE INFORMATION AGE STS.pdfjimielynbastida
 
Kotlin Multiplatform & Compose Multiplatform - Starter kit for pragmatics
Kotlin Multiplatform & Compose Multiplatform - Starter kit for pragmaticsKotlin Multiplatform & Compose Multiplatform - Starter kit for pragmatics
Kotlin Multiplatform & Compose Multiplatform - Starter kit for pragmaticsAndrey Dotsenko
 
Artificial intelligence in the post-deep learning era
Artificial intelligence in the post-deep learning eraArtificial intelligence in the post-deep learning era
Artificial intelligence in the post-deep learning eraDeakin University
 
Pigging Solutions in Pet Food Manufacturing
Pigging Solutions in Pet Food ManufacturingPigging Solutions in Pet Food Manufacturing
Pigging Solutions in Pet Food ManufacturingPigging Solutions
 
Benefits Of Flutter Compared To Other Frameworks
Benefits Of Flutter Compared To Other FrameworksBenefits Of Flutter Compared To Other Frameworks
Benefits Of Flutter Compared To Other FrameworksSoftradix Technologies
 
Connect Wave/ connectwave Pitch Deck Presentation
Connect Wave/ connectwave Pitch Deck PresentationConnect Wave/ connectwave Pitch Deck Presentation
Connect Wave/ connectwave Pitch Deck PresentationSlibray Presentation
 
SIEMENS: RAPUNZEL – A Tale About Knowledge Graph
SIEMENS: RAPUNZEL – A Tale About Knowledge GraphSIEMENS: RAPUNZEL – A Tale About Knowledge Graph
SIEMENS: RAPUNZEL – A Tale About Knowledge GraphNeo4j
 
My Hashitalk Indonesia April 2024 Presentation
My Hashitalk Indonesia April 2024 PresentationMy Hashitalk Indonesia April 2024 Presentation
My Hashitalk Indonesia April 2024 PresentationRidwan Fadjar
 
Build your next Gen AI Breakthrough - April 2024
Build your next Gen AI Breakthrough - April 2024Build your next Gen AI Breakthrough - April 2024
Build your next Gen AI Breakthrough - April 2024Neo4j
 
Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024
Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024
Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024BookNet Canada
 
Pigging Solutions Piggable Sweeping Elbows
Pigging Solutions Piggable Sweeping ElbowsPigging Solutions Piggable Sweeping Elbows
Pigging Solutions Piggable Sweeping ElbowsPigging Solutions
 
AI as an Interface for Commercial Buildings
AI as an Interface for Commercial BuildingsAI as an Interface for Commercial Buildings
AI as an Interface for Commercial BuildingsMemoori
 
CloudStudio User manual (basic edition):
CloudStudio User manual (basic edition):CloudStudio User manual (basic edition):
CloudStudio User manual (basic edition):comworks
 

Recently uploaded (20)

Vulnerability_Management_GRC_by Sohang Sengupta.pptx
Vulnerability_Management_GRC_by Sohang Sengupta.pptxVulnerability_Management_GRC_by Sohang Sengupta.pptx
Vulnerability_Management_GRC_by Sohang Sengupta.pptx
 
Beyond Boundaries: Leveraging No-Code Solutions for Industry Innovation
Beyond Boundaries: Leveraging No-Code Solutions for Industry InnovationBeyond Boundaries: Leveraging No-Code Solutions for Industry Innovation
Beyond Boundaries: Leveraging No-Code Solutions for Industry Innovation
 
Enhancing Worker Digital Experience: A Hands-on Workshop for Partners
Enhancing Worker Digital Experience: A Hands-on Workshop for PartnersEnhancing Worker Digital Experience: A Hands-on Workshop for Partners
Enhancing Worker Digital Experience: A Hands-on Workshop for Partners
 
Are Multi-Cloud and Serverless Good or Bad?
Are Multi-Cloud and Serverless Good or Bad?Are Multi-Cloud and Serverless Good or Bad?
Are Multi-Cloud and Serverless Good or Bad?
 
Science&tech:THE INFORMATION AGE STS.pdf
Science&tech:THE INFORMATION AGE STS.pdfScience&tech:THE INFORMATION AGE STS.pdf
Science&tech:THE INFORMATION AGE STS.pdf
 
Kotlin Multiplatform & Compose Multiplatform - Starter kit for pragmatics
Kotlin Multiplatform & Compose Multiplatform - Starter kit for pragmaticsKotlin Multiplatform & Compose Multiplatform - Starter kit for pragmatics
Kotlin Multiplatform & Compose Multiplatform - Starter kit for pragmatics
 
Artificial intelligence in the post-deep learning era
Artificial intelligence in the post-deep learning eraArtificial intelligence in the post-deep learning era
Artificial intelligence in the post-deep learning era
 
Pigging Solutions in Pet Food Manufacturing
Pigging Solutions in Pet Food ManufacturingPigging Solutions in Pet Food Manufacturing
Pigging Solutions in Pet Food Manufacturing
 
Benefits Of Flutter Compared To Other Frameworks
Benefits Of Flutter Compared To Other FrameworksBenefits Of Flutter Compared To Other Frameworks
Benefits Of Flutter Compared To Other Frameworks
 
E-Vehicle_Hacking_by_Parul Sharma_null_owasp.pptx
E-Vehicle_Hacking_by_Parul Sharma_null_owasp.pptxE-Vehicle_Hacking_by_Parul Sharma_null_owasp.pptx
E-Vehicle_Hacking_by_Parul Sharma_null_owasp.pptx
 
Hot Sexy call girls in Panjabi Bagh 🔝 9953056974 🔝 Delhi escort Service
Hot Sexy call girls in Panjabi Bagh 🔝 9953056974 🔝 Delhi escort ServiceHot Sexy call girls in Panjabi Bagh 🔝 9953056974 🔝 Delhi escort Service
Hot Sexy call girls in Panjabi Bagh 🔝 9953056974 🔝 Delhi escort Service
 
Connect Wave/ connectwave Pitch Deck Presentation
Connect Wave/ connectwave Pitch Deck PresentationConnect Wave/ connectwave Pitch Deck Presentation
Connect Wave/ connectwave Pitch Deck Presentation
 
SIEMENS: RAPUNZEL – A Tale About Knowledge Graph
SIEMENS: RAPUNZEL – A Tale About Knowledge GraphSIEMENS: RAPUNZEL – A Tale About Knowledge Graph
SIEMENS: RAPUNZEL – A Tale About Knowledge Graph
 
The transition to renewables in India.pdf
The transition to renewables in India.pdfThe transition to renewables in India.pdf
The transition to renewables in India.pdf
 
My Hashitalk Indonesia April 2024 Presentation
My Hashitalk Indonesia April 2024 PresentationMy Hashitalk Indonesia April 2024 Presentation
My Hashitalk Indonesia April 2024 Presentation
 
Build your next Gen AI Breakthrough - April 2024
Build your next Gen AI Breakthrough - April 2024Build your next Gen AI Breakthrough - April 2024
Build your next Gen AI Breakthrough - April 2024
 
Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024
Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024
Transcript: New from BookNet Canada for 2024: BNC BiblioShare - Tech Forum 2024
 
Pigging Solutions Piggable Sweeping Elbows
Pigging Solutions Piggable Sweeping ElbowsPigging Solutions Piggable Sweeping Elbows
Pigging Solutions Piggable Sweeping Elbows
 
AI as an Interface for Commercial Buildings
AI as an Interface for Commercial BuildingsAI as an Interface for Commercial Buildings
AI as an Interface for Commercial Buildings
 
CloudStudio User manual (basic edition):
CloudStudio User manual (basic edition):CloudStudio User manual (basic edition):
CloudStudio User manual (basic edition):
 

12 2 How Many Atoms Part Ii

  • 1. Launch: 12/2   Grab your binder and immediately take a seat!   Place homework (practice questions), binder paper, and a pen/pencil on your desk. Today’s Objective: I can convert between grams and atoms using both molecular mass and Avogadro’s number as a conversion factors Tonight’s HW: Finish the back of the practice question worksheet
  • 2. Launch 12/2 4.  How many molecules of C3OH are in .5 moles? a.  3.01 X 1023 molecules b.  6.02 X 1023 molecules c.  9.03 X 1023 molecules d.  1.204 X 1024 atoms
  • 3. Launch 12/2 5.  If there are 1.204 X 1024 particles of gold (Au), how many moles are there? a.  .5 moles b.  1 mole c.  2 moles d.  4 moles
  • 4. Announcements   Quiz on Friday   The mole   Conversions   Unit exam in 2 weeks
  • 5. How many atoms? – Part II Mr. Heffner 12/1/09
  • 6. How many atoms?   Conversion factors… ..or particles, or molecules   are used to convert one unit to another unit sum of atomic Molar Mass Avogadro’s # masses ? grams/mole 6.02 X 1023 atoms/mole ? grams 6.02 X 1023 atoms 1 mole 1 mole 1 mole 1 mole ? grams 6.02 X 1023 atoms Grams  Moles Atoms  Moles
  • 7. How many atoms?   What if we want to convert grams  atoms?   Need to use both conversion factors!
  • 8. How many atoms?   There is a 3-step process for conversions: 1.  Write down the starting unit and look at the ending unit. 2.  Write the conversion factor with the starting units on the bottom.   If grams, start with molar mass   If atoms (or particles, or molecules), start with Avogadro’s # 3.  Cancel like terms and multiply across the top and bottom.
  • 9. Example #1 How many atoms are there in 12.01 grams of carbon (C)?   Step #1: Write down the starting unit and look at the ending unit. 12.01 grams
  • 10. Example #1 How many atoms are there in 12.01 grams of carbon (C)?   Step #2: Write the conversion factor with the starting units on the bottom. 1 mol 6.02 X 1023 atoms 12.01 g X X = 12.01 g 1 mol Start with Then use molecular Avogadro’s # mass
  • 11. Example #1 How many atoms are there in 12.01 grams of carbon (C)?   Step #3: Cancel like terms and multiply across the top and bottom 1 mol 6.02 X 1023 atoms 12.01 g X X = 12.01 g 1 mol Ignore 1 X 6.02 X 1023 atoms = 1 6.02 X 1023 atoms =
  • 12. Example #3 How many grams of CH4 are there in 12.04 X 1023 molecules? Step #1: Write down the starting unit and look at the ending unit. 12.04 X 1023 molecules
  • 13. Example #3 How many grams of CH4 are there in 12.04 X 1023 molecules?   Step #2: Write the conversion factor with the starting units on the bottom. 1 mol 16.05 g 12.04 X 1023 molecules X X 1 mol = 6.02 X 10 23 molecules Then use Start with molecular Avogadro’s # mass
  • 14. Example #3 How many grams of CH4 are there in 12.04 X 1023 molecules?   Step #3: Cancel like terms and multiply across the top and bottom 1 mol 16.05 g 12.04 X 1023 molecules X X 1 mol = 6.02 X 10 23 molecules 12.04 X 1 X 16.05 g = 6.02 X 1 32.10 g = 2 X 16.05 g =
  • 15. Example #2 How many atoms are there in 16.00 grams of O2?   Step #1: Write down the starting unit and look at the ending unit. 16.00 grams
  • 16. Example #2 How many atoms are there in 16.00 grams of O2?   Step #2: Write the conversion factor with the starting units on the bottom. 1 mol 6.02 X 1023 atoms 16.00 g X X = 32.00 g 1 mol Start with Then use molecular Avogadro’s # mass
  • 17. Example #2 How many atoms are there in 16.00 grams of O2?   Step #3: Cancel like terms and multiply across the top and bottom 1 mol 6.02 X 1023 atoms 16.00g X X = 32.00 g 1 mol Ignore 16.00 X 6.02 X 1023 atoms = 32.00 X 1 3.01 X 1023 atoms = .5 X 6.02 X 1023 atoms =
  • 18. Whiteboards   Work in pairs   Trade-off marker every question   You have 60 seconds to solve the question   Show all of your work!   Don’t forget units!   Lift board only when prompted
  • 19. How many atoms are there in 8.00 grams of helium (He) ?
  • 20. How many molecules are there in 4.04 grams of H2?
  • 21. What is the mass (in grams) of 6.02 X 10 23 particles of gold (Au)?
  • 22. How many grams does 3.01 X 1023 molecules of HCl weight?
  • 24. Exit Slip 1.  Which conversion factor would need to be used to convert between gramsmoles? a.  Avogadro’s number b.  6.02 X 1023 atoms/mole c.  Molecular mass d.  Atomic weight
  • 25. Exit Slip 2.  Which conversion factor would need to be used to convert grams into atoms? a.  Avogadro’s number b.  Atomic weight c.  Molecular mass d.  both a & c
  • 26. Exit Slip 3.  Which of the following correctly shows how to convert 64.00g of O2 to atoms? 6.02 X 1023 atoms a.  32.00g X 32.00g 1 mole b.  64.00g X 32.00 g 1 mole 6.02 X 1023 atoms c.  64.00g X 32.00 g X 1 mole 1 mole 1 atoms d.  64.00 g X X 6.02 X 10 23 g 32.00 moles
  • 27. Exit Slip 4.  How many atoms of nitrogen (N) are there in 14.01g? a.  3.01 X 1023 atoms b.  6.02 X 1023 atoms c.  9.03 X 1023 atoms d.  1.204 X 1024 atoms
  • 28. Exit Slip 5.  How many grams does 12.04 X 1023 molecules of H2O weigh? a.  9.01g b.  18.02g c.  27.03g d.  36.04g
  • 29. Homework   Finish practice questions   Study for Friday’s Quiz!