En este ejercicio veremos como analizar una estructura compuesta por una viga y una estructura articulada. Para ello basta con aislarlas

1.
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The system shown in the figure is made
1.
DSI Isolated truss
up of a beam connected on its right end to
3
a truss.
3.2. 2
Data:
1
3. 3
4
1
6
0
2
0
Young modulus = 210 GPA
Alternatively
Determine:
a)
0
6
0,04 (diameter)
1 ;
3
2
3
3
2.6
0
DSI of the truss and its possible
implications.
Thus, structure is entirely linked and the
b)
Reaction forces in supports A and E.
reactions exerted by the supports can be
c)
Reaction forces in supports F and G.
determined using equilibrium conditions.
2.
d) Using the method of the joints, the
axial forces in all members of the
structure indicating if they are tensile
or compressive.
e)
f)
8 kN
A
1m
C
D
2m
1m
B
0→5
1m
4.8
2.2.2
D
C
F
G
0→
2.2
12
8
Solution:
0→
In order to solve the exercise, we will
separate both structures and add the
3.
Reaction forces in the truss
corresponding internal forces as it is
shown in the drawings.
E
1m
2 kN/m
E
1m
B
VE
Normal stress in member EF.
A
2 kN/m
HE
Using the method of the sections, the
axial forces in bars FE and FG.
8 kN
Reaction forces beam
Isolating the system:
0

2.
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√
VE
HE
5.
E
Internal forces (using the method of
sections)
VE
HE
G
F
E
0→4
2.4
NEG
F
0→
4
0→
4.
0
2→
NFG
tan 60°
Internal forces (using the method of
2
→
√
Node F
NFE
0 kN
2√3
0 → 2.
the nodes)
. 2√3
√
6.
2 kN
. cos 30
. sin 60
Calculation of the normal stress in EF.
√
√
.
0
∆
0→
. cos 60
0
0
0→2
0
0→
NFG
.
∆
→∆
4
.4
3 √3 10
210. 10
. . 0,02
,