What networking challenges does for the Open Ethernet address and ho.pdf

•

0 likes•7 views

What networking challenges does for the Open Ethernet address and how does it improve them? What would be some of the future business demands on data networks that Open Ethernet would satisfy? Solution 1)Answer: challenges: If a networked Layer 2 device such as a bridge or LAN switch could contain a list of all known MAC addresses, then the network node could function in much the same way as a router, forwarding frames instead of packets hop-by-hop through the network from source LAN to destination LAN. However, the MAC address is much larger than the IPv4 address currently used on the Internet backbone (48 bits compared to the 32 bits of IPv4). This poses problems. Also, because the MAC address has no “network organization” like the IPv4 or IPv6 address, an Layer 2 network node must potentially store every conceivable MAC address in memory for next-hop table lookups. Instead of tables of about 125,000 entries, every Layer 2 network node would have to store millions of entries. Improvement: Wireless access points often use MAC addresses for access control. They only allow access for known devices (MAC address is unique and identifies devices) with the correct passphrase. DHCP servers use the MAC address to identify devices and give some devices fixed IP addresses. uses: Hotels, restaurants and bars are increasingly being pushed to offer ubiquitous and free WiFi – in hotel rooms and also in all common areas. Travelers and patrons, now used to having access anywhere, at any time for their multiple smart devices, demand connectivity and choose where to patronize accordingly. Ethernet-based Dedicated Internet Access can provide this feature both costeffectively and reliably. Moreover, multi-site hotel and restaurant chains operating in today’s fastpaced online business environment can upgrade and consolidate services onto a single network that supports voice, data and video traffic alike..

Education

Similar to What networking challenges does for the Open Ethernet address and ho.pdf

Computer Networks.pptx

DeepthiB29

Common network devices

Raza Muhammad Jamali

Summarize the purpose of a WAN and define what makes up a WAN connection. Detail the types of devices used to establish and maintain a WAN connection and list some of the more common WAN connection methods. Discuss the differences between WAN and LAN connections, and who is responsible for providing WAN connections. Discuss how a modem handles digital information over analog signals. Describe how to configure and setup remote access protocols. What factors need careful consideration? Solution Remote Access Protocols Remote access protocols square measure accustomed management the institution of connections and therefore the transmission of information over WAN links. 3 varieties of remote access protocols square measure supported by Windows Server 2003 remote access: Point-to-Point Protocol (PPP): AN industry-standard set of protocols providing the most effective security, multi-protocol support and ability. Serial Line net Protocol (SLIP): employed by older remote access servers. A Windows Server 2003 RAS server doesn\'t support SLIP dial-up connections. Microsoft remote access protocol: additionally called Asynchronous NetBEUI (AsyBEUI) and is employed by inheritance remote access purchasers, like Windows NT three.1, Windows for Workgroups, DOS and computer network Manager purchasers. LAN may be a electronic network that connects computers in tiny areas. WAN may be a network that covers a broad space victimization personal or public network transports. The terms {lan|local square measurea network|LAN|computer network} and WAN are usually confusing for those that aren’t that school savvy. These square measure each connections that permit users to attach their laptop to a network, as well as the web. computer network is brief for native space Network, whereas WAN is brief for Wide space Network. These 2 disagree from one another in distinct ways that. computer network may be a electronic network that connects computers in tiny areas like home, office, school, corporation, etc. employing a network media. it\'s helpful for sharing resources like printers, files, games, etc. A computer network network includes a few of laptop systems connected to every alternative, with one system connected to a router, electronic equipment or AN outlet for net access. The computer network network is made victimization cheap technologies like local area network cables, network adapters and hubs. However, alternative wireless technologies are obtainable to attach the pc through a wireless access. so as to put together a computer network network, an individual might also need specialised software system software system. the foremost widespread software system includes the Microsoft Windows’ net affiliation Sharing (ICS), that permits users to make computer network. distinction between computer network and WAN Key Difference: computer network may be a electronic network that connects computers in tiny areas. WAN may be a network that covers a broad space victimizat.

Summarize the purpose of a WAN and define what makes up a WAN connec.pdf

FOREVERPRODUCTCHD

Introduction to Computer Networks and Network Security.pptx

ShehanMarasinghe1

1. What is Data Communication? 2. What is a network? 3. What is Node? 4. What is a network interface card (NIC)? 5. Types of Computer Networks 6. What is a MAC Address? 7. What Types of Addressing? 8. What is a port? 9. What are the different port numbers? 10.What is Hub? 11.What is Router? 12.What is a Bridge? 13.What is Gateway? 14.What is Brouter? 15.What is OSI Model? 16.What is the OSI model (Open Systems Interconnection)? 17.7 layers of the OSI model? 18.What Is the TCP/IP Model? 19.What Is the TCP/IP Model? 20.Classification of IP address Addressing?

Data communication class note 1

Prosanta Mazumder

Network

nvuong

lis508p02a-10.ppt

webhostingguy

Nwk assignment body copy

Tonny Michael

Introduction to Computer Networks Lecture slides ppt

Osama Yousaf

There are many kinds of network devices.pdf

EIHEducation

MPLS ppt

Jagtar Dhaliwal

Data communication assignment id1925102518

MdZakirHossain66

Introduction to networking

Mohsen Sarakbi

Class-note-data communications-01

Md. Abdur Rahim Khan

Ccna

AdityaKumar1548

W 10 introduction to network

Institute of Management Studies UOP

Many types of networking devices 2.pdf

EIHEducation

Fundamentals of Computer Networking - Shift Education of Technology

Raphaff

PRE-FINAL.pdf

NoralieNicol

Dasar komputer chapter8

teknik komputer ui

Similar to What networking challenges does for the Open Ethernet address and ho.pdf (20)

Computer Networks.pptx

Common network devices

Summarize the purpose of a WAN and define what makes up a WAN connec.pdf

Introduction to Computer Networks and Network Security.pptx

Data communication class note 1

Network

lis508p02a-10.ppt

Nwk assignment body copy

Introduction to Computer Networks Lecture slides ppt

There are many kinds of network devices.pdf

MPLS ppt

Data communication assignment id1925102518

Introduction to networking

Class-note-data communications-01

Ccna

W 10 introduction to network

Many types of networking devices 2.pdf

Fundamentals of Computer Networking - Shift Education of Technology

PRE-FINAL.pdf

Dasar komputer chapter8

More from malavshah9013

gen diffuses Oxygen enters a from the blood to red blood cell. the body\'s tissues oxygen is di through blood from the alveoli vessels to a into sumounding capillaries. capillary. a molecule of hemoglobin reset help Solution Steps wise - 1.Oxygen is carried through blood vessels to a capillary. 2.Oxygen diffuses from the alveoli into surrounding capillaries. 3.Oxygen enters a red blood cell. 4.Oxygen binds to a molecule of hemoglobin. 5.Oxygen diffuses form the blood to the body\'s tissues..

gen diffuses Oxygen enters a from the blood to red blood cell. the bo.pdf

malavshah9013

Fill in parameters Public New Hash table (int initial Capacity, float load Factor) Constructs a new, empty hash table with the specified initial capacity and the specified load factor. Parameters: initial Capacity - the initial capacity of the hash table. load Factor - the load factor of the hash table. Throws: if the initial capacity is less than zero, or if the load factor is nonpositive. public New hostable (int initial 1Capac.ity) Constructs a new, empty hash table with the specified initial capacity and default load factor (0.75). Parameters: initia1Capacity - the initial capacity of the hash table. Throws: IllegalArqumentException - if the initial capacity is less than zero. public NewHashtable() Constructs a new, empty hash table with a default initial capacity (11) and load factor (0.75). Solution //NewHashTable.java import java.util.LinkedList; @SuppressWarnings({ \"unchecked\", \"unused\", \"rawtypes\", \"hiding\" }) public class NewHashTable { //private class to hold a key and its value private class HashEntry{ private K key; private V value; public HashEntry(K key, V value){ this.key = key; this.value = value; } public String toString(){ return key+\"=\"+value; } @Override public boolean equals(Object obj) { if(!(obj instanceof HashEntry)) return false; HashEntry other = (HashEntry) obj; return (key.equals(other.key)); } } private int capacity; private float loadFactor; private LinkedList[] table; private int size; //Default Constructor public NewHashTable(){ capacity = 11; loadFactor = .75f; table =new LinkedList[capacity]; for(LinkedList bucket : table) bucket = null; size = 0; } //One argument Constructor //@param initialCapacity initial capacity of table public NewHashTable(int initialCapacity){ if(initialCapacity<0) throw new IllegalArgumentException(\"\"+initialCapacity); capacity = initialCapacity; loadFactor = .75f; table = new LinkedList[capacity]; for(LinkedList bucket : table) bucket = null; size = 0; } //Two argument Constructor //@param initialCapacity initial capacity of this NewHashTable //@param loadFactor customized loadFactor public NewHashTable(int initialCapacity, float loadFactor){ if(initialCapacity<0) throw new IllegalArgumentException(\"Capacity: \"+initialCapacity); if(loadFactor<0) throw new IllegalArgumentException(\"Load Factor: \"+loadFactor); capacity = initialCapacity; this.loadFactor = loadFactor; } //@return capacity the capacity of this NewHashTable public int getCapacity(){ return capacity; } //@return true if this NewHashTable is empty, false otherwise public boolean isEmpty(){ return size==0; } //@return size the number of keys in this NewHashTable public int size(){ return size; } //@param key key to be searched for in this NewHashTable //@return true if key is found within this NewHashTable public boolean containsKey(K key){ int hash = Math.abs(key.hashCode()%capacity); return table[hash]!=null &&table[hash].contains(new HashEntry(key,null)); } //Increases the capacity and reorganizes this Ne.

Fill in parameters Public New Hash table (int initial Capacity, floa.pdf

malavshah9013

For Phantom Limb Syndrome, please describe the symptoms and the part of the brain affected explicitly, and the cure. How do sea stars\' cat? Describe the Water Vascular System in Sea Stars (WVS). What is its structure? How does the water get into the WVS? How does it control the tube feet? Besides moving the tube feet, what does the WVS do? Solution 1) Phantom limb syndrome is a condition or a sensation in which the cut or missed limb is being still attached with the person\'s body. It can also be caused due to removal of the body parts due to the certain reasons.. It affects the brain nerve ending called Neuromas..!! The symptoms include limb pain in some cases, gesturing, feeling itchiness, and most important is the feeling of one hand small and long which can bring to severe pain..!! Some of the cure way of this is meditation, acupuncture, anti-depressants, spinal cord stimulation..!! Some chemicals like morphine could also be a used... 3) water vascular system is a hydraulic water system present in echinodermata like sea stars.. It help in food, water movement, locomotion, waste transportation and even respiration too.. They are composed of canals which connects to tube feet . it moves by contacting muscles present in them which forces the water inside it resulting in extending, pushing on to the ground and again retracing.. The structure of it is like it has a sieve like structure which is connected to central duct called amphula. This amphula is connected to another duct called stone canal. This canal runs as a ambulagrel grooves on each arm of the sea star underside..!! This gives its appearance like a tube foot. The contraction of the amphulle cause podia to stretch water inside which allows for the movement..!!.

For Phantom Limb Syndrome, please describe the symptoms and the part .pdf

malavshah9013

Explain why the organisms that were studied by Sergei Winogradsky could not be grown on Robert Koch’s plate media containing agar or gelatin. Solution The organisms studied by Sergei Winogradsky are lithotrophs. Lithotrophs are the organisms that need inorganic nutrients to synthesise the biomolecules necessary for the survival. Robert Koch’s plate media containing agar or gelatin provides only organic nutrients. So, the lithotrophs studied by Sergei Winogradsky could not be grown on Robert Koch’s plate media..

Explain why the organisms that were studied by Sergei Winogradsky co.pdf

malavshah9013

Electron transport powers the first steps of photosynthesis. The following diagram shows the passage of electrons through the photosynthetic electron transport chain (ETC). a. What is the source of the electrons (e) that enter Photosystem II (PSII)? What membrane are these complexes embedded in? What is the final e^- acceptor for e^- leaving Photosystem I (PSI)? (Please indicate both the unreduced and the reduced form of this acceptor) The light energy captured by the photosynthetic reaction centers is used to establish a pH gradient across this chloroplast membrane. (This means a gradient of H ions.) a. Indicate on the diagram above, where the concentration of H is low and where it is high. How is this pH gradient established? Specify at least 2 different ways. How is the H gradient (potential energy) used? What are the products that the proton gradient made? Where in the chloroplast are they made? Solution Question number 1 : A. In Higher plants, the ultimate source of the electrons passed to NADPH in plant (oxygenic) photosynthesis is water. Photosynthetic bacteria use a variety of electron donors for this purpose acetate, succinate, malate, or sulfide depending on what is available in a particular ecological niche. B. These photosystems are embedded in the thylokoid membranes. Higher plants contsins two types of photosynthetic units associated with two different pigment systems, whcih obsorbs light of different wavelengths. C. The final electron acceptor in photosynthesis is NADP+, which is reduced to NADPH by NADP reductase..

Electron transport powers the first steps of photosynthesis. The fo.pdf

malavshah9013

Describe 5 key traits the lung cancer cells within the primary tumor acquire and why they are significant. •As genetic stability is lost and genetic mutations accumulate some of these mutation result in advantageous changes to cellular function. As a result, lung cancer cells acquire traits effective for growth and development of tumors and invasion into surrounding tissue. Describe five of the traits lung cancer cells have that are advantageous and justify why you chose those traits. Solution Thanks for the question 1. self-sufficiency in growth signals- the cell can keep growing by itself 2. insensitivity to growth-inhibitory (antigrowth) signals - the cell looses the ability to restrict its unrestricted growth 3. evasion of programmed cell death (apoptosis),- the cell looses the ability of the body to evade death and discard. 4. limitless replicative potential - the cell can keep on multiplying as much as it can without any blocks or barriers 5. sustained angiogenesis- there is a constant and adequate emergence of blood supply for the new grown tissues and cells 6. tissue invasion and metastasis. - the cancer cells are able to spread themselves into other tissues physically and through blood Each of these physiologic changes cause the successful transformation of non cancer cells to cancer cells and make ineffective the anticancer defense mechanism present in the cells. These six capabilities are shared in common by most and perhaps all types of human tumors. Regards.

Describe 5 key traits the lung cancer cells within the primary tumor.pdf

malavshah9013

Complete the ANOVA table Source DF SS MS Between Groups 3 5 Within groups 12 337 total 472 How many groups were in the study How many total observations were there State the H0 and H1 and test at 5% level of significant Source DF SS MS Between Groups 3 5 Within groups 12 337 total 472 Solution How many groups were in the study k = df1 + 1 = 3 + 1 = 4 [ANSWER] ************* how many total observations were there N = df1 + df2 + 1 = 3 + 12 + 1 = 16 [ANSWER] ******************** State the H0 and H1 and test at 5% level of significant Ho: All the means in the 4 groups are equal. Ha: At least 2 means in the 4 groups are different. Here, F = (SSB/df1) / (SSW/df2) = ((472-337)/3)/(337/12) = 1.602373887 As at 5%, df1 = 3, df2= 12, Fcrit = 3.490294819 As F > Fcrit, we fail to reject Ho. Thus, there is no significant evidence that at least 2 means are not equal. [CONCLUSION].

Complete the ANOVA tableSourceDFSSMSBetween Groups35.pdf

malavshah9013

English Composition II - mutiple questions on researchQuestion 1 o.pdf

malavshah9013

Customers arrive at a bank teller\'s booth at a rate of 2 per minute. What is the probability (to four decimal places) that 4 customers will arrive at the bank teller\'s booth within the next minute (assume a Poisson distribution) Solution Possion Distribution PMF of P.D is = f ( k ) = e- x / x! Where = parameter of the distribution. x = is the number of independent trials P( X = 4 ) = e ^-2 * 2^4 / 4! = 0.0902.

Customers arrive at a bank tellers booth at a rate of 2 per minute.pdf

malavshah9013

Create a JAVA program that performs file IO and database interaction via SQL. The program needs to read data from the provided file: \"Project.csv\" and insert the data into a database. Then the program needs to create a report from the database sorted by price descending. The report should be in the format demonstrated below. id (primary key - generated by the database) cpuname performance price Project.csv contents:CPU NamePerformancePrice (USD)Intel Core i7-3770K @ 3.50GHz9,556$560.50Intel Core i7-3770 @ 3.40GHz9,327$335.55Intel Core i7-3820 @ 3.60GHz8,990$404.38AMD FX-8350 Eight-Core8,940$149.99Intel Core i7-2600K @ 3.40GHz8,501$379.97Intel Core i7-2600 @ 3.40GHz8,242$214.99Intel Core i7-4720HQ @ 2.60GHz8,046NAAMD FX-8320 Eight-Core8,008$145.99Intel Core i7-6700HQ @ 2.60GHz7,997$1509Intel Core i7-4710HQ @ 2.50GHz7,826NAIntel Core i5-6600K @ 3.50GHz7,762$239.99Intel Core i7-4700HQ @ 2.40GHz7,754$383.00Intel Core i7-4700MQ @ 2.40GHz7,736$467.40Intel Core i5-4690K @ 3.50GHz7,690$239.99AMD FX-8150 Eight- Core7,619$165.99Intel Core i7-3630QM @ 2.40GHz7,604$304.49Intel Core i5-4670K @ 3.40GHz7,598$249.99Intel Core i5-4690 @ 3.50GHz7,542$224.99Intel Core i7-3610QM @ 2.30GHz7,460$399.99Intel Core i5-4670 @ 3.40GHz7,342$226.99Intel Core i5-4590 @ 3.30GHz7,174$199.99Intel Core i7-4702MQ @ 2.20GHz7,146NAIntel Core i5-3570K @ 3.40GHz7,130$477.23 Solution import java.io.IOException; import java.nio.file.Files; import java.nio.file.Paths; import java.util.Arrays; public class Main { /** * This the main function that runs at the start * param args - input arguments from the command line */ static public void main(String[] args) { CPUList cpuList = new CPUList(); //The CPUList used to retrieve data from the fiile and store in the db CPUList cpuListRetrieved = new CPUList(); //The CPUList used to retrieve data from the database CpuDb cpuDb = new CpuDb(); //The database object used to move data to and from the CPU Lists try { //Read in the file and store each line into the CPU objects in a list Files.lines(Paths.get(\"Project04Data.csv\")) .map(line -> line.split(\"\ \ \")) // Stream .flatMap(Arrays::stream) // Stream .forEach(line -> cpuList.AddCpu(line)); //Clear the list table for the new listing cpuDb.Clear(); //Insert the Cpu List into the database cpuDb.SetCpuList(cpuList); //Retrieve the Cpu List into a different CPU List object from the database cpuDb.GetCpuList(cpuListRetrieved); //Show the report from the new list that was retrieved from the database cpuListRetrieved.ShowReport(); } catch (IOException e) { e.printStackTrace(); } } } CPUList.java import java.util.ArrayList; import java.util.Collections; import java.util.Iterator; public class CPUList { ArrayList theList = new ArrayList<>(); /** * Default constructor for the CPU */ public void CPUList() { } /** * param strInputLine Input line to be used in creating the CPU object */ public void AddCpu(String strInputLine) { theList.add(new CPU(strInputLine)); } /** * param tempCPU - A CPU object to.

Create a JAVA program that performs file IO and database interaction.pdf

malavshah9013

Wolves were hunted and poisoned to extinction in Sweden and Norway by the mid-20th century. Three wolves migrated from Russia and founded a new Scandinavian wolf population in the early 1980s. That population now consists of approximately 100 animals. How large do you think the Scandinavian wolf population should be to maintain genetic variation that may be important for the viability (continued persistence) and continued evolution of this population? There is some possibility of gene flow into this population from Russian wolves. Do you think that it is important that gene flow between the Scandinavian and the Russian populations be maintained in the future? Why? Solution There is no cut-off formula for calculating the length of population to maintain genetic diversity. It is important to note that even after bottleneck effect populations are able to survive and are able to maintain genetic diversity. Here, there are 100 animals; and these 100 animals are heterozygous, not pure lines; because they have already mixed up with the Scandinavian population. So, the population is large enough to maintain genetic variation. Yes, there is further possibility of mixing of this population with Russian wolves further also; but that possibility is very rare. This is so because wolves have already been extinct over there; as per the question. No, it is no more compulsion for gene flow between the two populations. This is so because the populations have already diverged. And a subsequent amount of genetic variability has been attained..

Wolves were hunted and poisoned to extinction in Sweden and Norway b.pdf

malavshah9013

Describe the differences between OpenPGP, PGP and GPG. Solution All the three mentioned are encryption method and stands for PGP - Pretty Good Privacy, GPG(GNU Privacy Guard) The difference between three could be below: Availability in market - PGP is a licensed product whereas OpenPGP and GPG are freewares. Functionality - PGP is a encyrption method that uses hashing,compression, cyrptography concepts, OpenPgP is an encryption method which uses processes that are interoperatable with PGP and GPG is a encryption method which provides a graphical inerface to encrypt files..

Describe the differences between OpenPGP, PGP and GPG.Solution.pdf

malavshah9013

Declaring a Pointer To define a pointer, use an asterisk, (*), in the declaration to specify the variable will be a pointer to the specified data type. Recall that the name of an array holds the memory address of the first element of the array. The second statement then would store the memory address of the first value in the variable valuePtr. The name of a pointer is an identifier and must follow the rules for defining an identifier. Some programmers place the letters ptr, a common abbreviation for pointer, at the end of the variable name, others prefix a pointer with p_ or ptr_, and there are those who do nothing to distinguish a pointer by its name. The naming of a pointer variable is a matter of programming style. Once a pointer has been declared and initialized, it can be used to access the data to which it points. In order to access this value, the dereference operator, *, must be used to prefix the name of the pointer. From the code above, valuePtr holds the address of the first element of the values array; therefore, *valuePtr will access the value 325. Add the following to main and execute the program. The output generated should look something like the following. Where 0xbfad43e8 is a memory address displayed in hexadecimal. Obtaining the Memory Address of a Variable The address operator, &, is used to determine the memory address of a variable that is not an array. Add code necessary to use fixed and setprecision, then add the following to main and run the program to confirm the use of the address operator. Using a Pointer to Alter Data Just as the dereference operator is used to retrieve data, so too is it used to store data. Add the following to function main and run the program. The pointer, ratePtr, is used to change the data stored in payRate. The output of payRate confirms the change. Using a Pointer in an Expression As previously shown, the value pointed to by a pointer variable can be retrieved by dereferencing the pointer. In the above code, the retrieved value was simply displayed to the screen; however, it can also be used in an expression. Add the following to main and execute the program. Pointer Arithmetic It is possible to add to or subtract from a memory address stored in a pointer. These actions can be accomplished using the addition operator,+, subtraction operator, - and the increment and decrement operators, ++ and --. This is helpful when accessing arrays via pointers. The increment operator has been used to add the value 1 to a variable. When used with a pointer, the increment operator adds the size of the data referenced to the memory address stored in the pointer, effectively moving the pointer to the next data value. Building on the code from above, add the following to main and execute the program. We initialized valuePtr to the memory address of the first element of the array values. Incrementing valuePtr instructs the computer to add four bytes, the size of an integer, to the memory addressed stored in .

Declaring a PointerTo define a pointer, use an asterisk, (), in t.pdf

malavshah9013

Who identified three key economic “advantages” that firms should hav.pdf

malavshah9013

Which of these is the largesta. The surface zoneb. The mixed la.pdf

malavshah9013

Which of the following concepts is exemplified by the story of Parus major and the island of Vlieland? Gene flow reduces the genetic differences between populations. Gene flow can affect how well populations are adapted to local environmental conditions. Genetic drift is significant in small populations. Genetic drift can lead to a loss of genetic variation within populations. Relative fitness is not the same as fitness when calculated on a 0-1 scale. Solution ANS: E. Relative fitness is not the same as fitness when calculated on a 0-1 scale. Explanation: Ex: the great tit (Parus major) on the Dutch island of Vlieland. In Parus major high immigrated central region birds have a lower fitness, when compare with the low immigration birds which are present in east. This phenomenon clearly explains low immigrated birds had higher fitness. Definitions of Other Terminology: Darwin\'s fitness: It is the ability of an individual to survive and reproduce in its environment. Fitness of an organism is measured by how many offspring it produces compared to other individuals of a species. Adaptation refers to the trait that increases organism fitness relative to individuals without the trait. Genetic drift: It is random and happens in every population due to chance. Because of this smaller population are more susceptible to the effect of genetic drift. Gene pool: Gene pool is a reservoir of all genes, which was present in a population. Gene pool corresponds with a number of unique alleles present in a population..

Which of the following concepts is exemplified by the story of Parus .pdf

malavshah9013

You will be implementing the following functions. You may modify the main to test the functions, but this programwill work as a starting point. //********** Function Prototypes ****************** //function isPrime //input parameter - positive integer greater than 1 //returns true if the number is prime, otherwise false // bool isPrime (int number); //function findPrimes //input parameter - positive integer //Uses the isPrime method to print a list of prime numbers between 1 and n. void findPrimes (int n); //function findFibo //input parameter - positive integer //returns the nth fibonacci number where //Fib(0) -> 0 //Fib(1) -> 1 //Fib(N) -> Fib(N-2) + Fib(N-1) //Note: You must use a loop in your solution. Also, if passed a 0, return 0. int findFibo (int n); //function findFactors //input parameter - positive integer //prints the prime factors of the given number to standard output (cout) //example output: 52=2*2*13 (or 52=1*2*2*13) or 13=prime //Hint: You will need nested loops for your solution. void findFactors (int number); Solution #include #include using namespace std; //********** Function Prototypes ****************** //function isPrime //input parameter - positive integer greater than 1 //returns true if the number is prime, otherwise false // bool isPrime (int number); //function findPrimes //input parameter - positive integer //Uses the isPrime method to print a list of prime numbers between 1 and n. void findPrimes (int n); //function findFibo //input parameter - positive integer //returns the nth fibonacci number where //Fib(0) -> 0 //Fib(1) -> 1 //Fib(N) -> Fib(N-2) + Fib(N-1) //Note: You must use a loop in your solution. Also, if passed a 0, return 0. int findFibo (int n); //function findFactors //input parameter - positive integer //prints the prime factors of the given number to standard output (cout) //example output: 52=2*2*13 (or 52=1*2*2*13) or 13=prime //Hint: You will need nested loops for your solution. void findFactors (int number); //****************** MAIN ***************************** int main () { int testNum; //test for the isPrime function cout << \"Enter a test number - \"; cin >> testNum; cout << endl; if (isPrime(testNum)) cout << testNum << \" is prime.\" << endl; else cout << testNum << \" is not prime.\" << endl; //test for how many primes cout << \"Enter n to print the prime numbers between 1 and n: \"; cin >> testNum; cout << endl; findPrimes(testNum); cout << endl; //test for Fibonacci number finder cout << \"Which Fibonacci number? \"; cin >> testNum; cout << endl; cout << \"The \" << testNum << \" Fibonacci number is : \" << findFibo(testNum) << endl; cout << endl; //test for prime factors cout << \"Factor what number: \"; cin >> testNum; cout << endl; findFactors(testNum); return 0; } //function isPrime //input parameter - positive integer greater than 1 //returns true if the number is prime, otherwise false // bool isPrime (int number) { int c, f = 0; if(number > 1) { for(c = 2; c < number; c++) { i.

You will be implementing the following functions. You may modify the.pdf

malavshah9013

When Elvis swims with the current, he swims 18km in 2 hours. Against.pdf

malavshah9013

What tarsal is lateral to the medial cuneiform? What tarsal is lateral to the medial cuneiform? Solution Answer: The tarsal bone lateral to the medial cuneiform is themiddle cuneiform (or the intermediate cuneiform) . There are seven tarsal bones and they are the calcaneus, talus, cuboid, navicular, and the medial, middle, and lateral cuneiforms. Among the three cuneiforms, the medial cuneiform (also known as first cuneiform) is the largest cuneiform bone. Lateral to the medial cuneiform is the middle cuneiform and its lateral surface is marked by an inverted L-shaped facet along the posterior and superior margins for the middle cuneiform bone..

What tarsal is lateral to the medial cuneiform What tarsal is .pdf

malavshah9013

What is the definition of memory access time? A. The difference between read and write times B, the time required to store data in the memory array C. The time required to get valid output after a valid address is applied D none of thee above Also is read and times the same on typical computers the same or is one faster? Solution opptin B Memory access time is how long it takes for a character in memory to be transferred to or from the CPU.

What is the definition of memory access timeA. The difference bet.pdf

malavshah9013

More from malavshah9013 (20)