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Projectile Motion Formulas
f(x) = a𝒙 𝟐
+ bx + c
When objects are thrown.
feet:
𝒉 𝒕 = βˆ’πŸπŸ”π’• 𝟐
+ 𝒗 𝟎 𝒕 + 𝒉 𝟎
When objects are dropped.
feet:
𝒉 𝒕 = βˆ’πŸπŸ”π’• 𝟐 + 𝒉 𝟎
meters:
𝒉 𝒕 = βˆ’πŸ’. πŸ—π’• 𝟐
+ 𝒗 𝟎 𝒕 + 𝒉 𝟎
meters:
𝒉 𝒕 = βˆ’πŸ’. πŸ—π’• 𝟐
+ 𝒉 𝟎
Projectile Motion Critical Feature Formulas
roots
𝒙 =
βˆ’π’ƒ Β± 𝒃 𝟐 βˆ’ πŸ’π’‚π’„
πŸπ’‚
y-intercept
(0, y)
vertex
βˆ’π’ƒ
πŸπ’‚
, 𝒇
βˆ’π’ƒ
πŸπ’‚
,
Initial height of object.
x: time it takes to reach max height
y: max height
Time the object is on the ground.
Only + values.height time
12
9
6
3
1 2 3 4
height(feet)
time (seconds)
The y-intercept is the height in which the
object begins. It is when x, seconds, is zero.
In this example the y-intercept
is (0, 6) The basketball begins
at 6 feet. This is the β€œc” value
of the quadratic equation.
𝒉 𝒕 = 𝒂𝒕 𝟐
+ 𝒃𝒕 + 𝒄
𝒉 𝒕 = 𝒂𝒕 𝟐
+ 𝒃𝒕 + πŸ”
12
9
6
3
1 2 3 4
height(feet)
time (seconds)
The vertex gives the amount of time, x in
seconds, the object reaches its maximum height,
y in feet or meters.
In this example the vertex is
(2, 12). In 2 seconds the basket-
ball reaches its maximum height
of 12 feet.
Use the vertex formula to find
the maximum height and time.
𝒉 𝒕 = 𝒂𝒕 𝟐
+ 𝒃𝒕 + 𝒄 β†’
βˆ’π’ƒ
πŸπ’‚
, 𝒇
βˆ’π’ƒ
πŸπ’‚
,
12
9
6
3
1 2 3 4
height(feet)
time (seconds)
The positive root gives the amount of time, x in
seconds, it takes the object to hit the ground,
when y is zero feet or meters.
In this example the positive root
is (4, 0). In 4 seconds the basket-
ball reaches the ground of zero
feet.
Use the quadratic formula or
factor the quadratic to find
how long it takes the object
to reach the ground.
𝒉 𝒕 = 𝒂𝒕 𝟐
+ 𝒃𝒕 + 𝒄 β†’ 𝒙 =
βˆ’π’ƒΒ± 𝒃 πŸβˆ’πŸ’π’‚π’„
πŸπ’‚

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Projectile motion overview

  • 1. Projectile Motion Formulas f(x) = a𝒙 𝟐 + bx + c When objects are thrown. feet: 𝒉 𝒕 = βˆ’πŸπŸ”π’• 𝟐 + 𝒗 𝟎 𝒕 + 𝒉 𝟎 When objects are dropped. feet: 𝒉 𝒕 = βˆ’πŸπŸ”π’• 𝟐 + 𝒉 𝟎 meters: 𝒉 𝒕 = βˆ’πŸ’. πŸ—π’• 𝟐 + 𝒗 𝟎 𝒕 + 𝒉 𝟎 meters: 𝒉 𝒕 = βˆ’πŸ’. πŸ—π’• 𝟐 + 𝒉 𝟎
  • 2. Projectile Motion Critical Feature Formulas roots 𝒙 = βˆ’π’ƒ Β± 𝒃 𝟐 βˆ’ πŸ’π’‚π’„ πŸπ’‚ y-intercept (0, y) vertex βˆ’π’ƒ πŸπ’‚ , 𝒇 βˆ’π’ƒ πŸπ’‚ , Initial height of object. x: time it takes to reach max height y: max height Time the object is on the ground. Only + values.height time
  • 3. 12 9 6 3 1 2 3 4 height(feet) time (seconds) The y-intercept is the height in which the object begins. It is when x, seconds, is zero. In this example the y-intercept is (0, 6) The basketball begins at 6 feet. This is the β€œc” value of the quadratic equation. 𝒉 𝒕 = 𝒂𝒕 𝟐 + 𝒃𝒕 + 𝒄 𝒉 𝒕 = 𝒂𝒕 𝟐 + 𝒃𝒕 + πŸ”
  • 4. 12 9 6 3 1 2 3 4 height(feet) time (seconds) The vertex gives the amount of time, x in seconds, the object reaches its maximum height, y in feet or meters. In this example the vertex is (2, 12). In 2 seconds the basket- ball reaches its maximum height of 12 feet. Use the vertex formula to find the maximum height and time. 𝒉 𝒕 = 𝒂𝒕 𝟐 + 𝒃𝒕 + 𝒄 β†’ βˆ’π’ƒ πŸπ’‚ , 𝒇 βˆ’π’ƒ πŸπ’‚ ,
  • 5. 12 9 6 3 1 2 3 4 height(feet) time (seconds) The positive root gives the amount of time, x in seconds, it takes the object to hit the ground, when y is zero feet or meters. In this example the positive root is (4, 0). In 4 seconds the basket- ball reaches the ground of zero feet. Use the quadratic formula or factor the quadratic to find how long it takes the object to reach the ground. 𝒉 𝒕 = 𝒂𝒕 𝟐 + 𝒃𝒕 + 𝒄 β†’ 𝒙 = βˆ’π’ƒΒ± 𝒃 πŸβˆ’πŸ’π’‚π’„ πŸπ’‚