This document provides instructions on how to solve projectile motion problems using the formula s(t) = -16t^2 + VoT + So, where s(t) is the position of the projectile at time t, Vo is the initial velocity, and So is the initial height. It gives an example of finding the maximum height and time for a ball thrown upward with an initial velocity of 96 feet/second from a height of 200 feet. It then provides two example problems to solve using the same approach.

1. By:Sam and Andrew

2. What you need to know First you need to know how to solve quadratic equations. Then you should know how to find the vertex parabola. Then know how to write out the problem. Last you need to know the formula: s(t)= -16t 2 +V o T + S o .

4. S(t) represents the projectiles exact height ant any time t V o . Represents initial velocity. S o . The height where the projectile starts before movement T represents time in seconds after it moves In this formula –16 2 stands the earths gravitational force since the acceleration is being measured in feet/sec. 2 we must also measure s(t), V o , and S o .