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Fórmulas de Cálculo Diferencial e Integral (Página 1 de 3)                                                                                                                                                                                                        http://www.geocities.com/calculusjrm/                                               Jesús Rubí M.

Fórmulas de                                                                ( a + b ) ⋅ ( a 2 − ab + b 2 ) = a 3 + b3                                                        θ      sin  cos   tg   ctg  sec csc                                  Gráfica 4. Las funciones trigonométricas inversas
                                                                                                                                                                                                                                                 arcctg x , arcsec x , arccsc x :                      sin α + sin β = 2sin
                                                                                                                                                                                                                                                                                                                            1               1
                                                                                                                                                                                                                                                                                                                              (α + β ) ⋅ cos (α − β )
                                                                                                                                                                                                    ∞        ∞
                                                                           ( a + b ) ⋅ ( a3 − a 2 b + ab 2 − b3 ) = a 4 − b 4
                                                                                                                                                                           0        0    1    0          1                                                                                                                  2               2
Cálculo Diferencial                                                                                                                                                        30      12    3 2 1 3     3 2 3 2                                             4                                                                  1               1
                                                                                                                                                                                                                                                                                                       sin α − sin β = 2 sin (α − β ) ⋅ cos (α + β )
                                                                           ( a + b ) ⋅ ( a 4 − a 3b + a 2 b 2 − ab3 + b 4 ) = a 5 + b5
e Integral VER.6.8                                                                                                                                                         45     1 2 1 2      1    1     2   2                                          3
                                                                                                                                                                                                                                                                                                                            2               2
                                                                           ( a + b ) ⋅ ( a5 − a 4 b + a 3b 2 − a 2 b3 + ab 4 − b5 ) = a 6 − b 6
                                                                                                                                                                                                                                                                                                                             1               1
                                                                                                                                                                           60       3 2 12      3 1 3    2 2 3                                                                                         cos α + cos β = 2 cos (α + β ) ⋅ cos (α − β )
Jesús Rubí Miranda (jesusrubim@yahoo.com)                                                                                                                                  90       1    0    ∞     0    ∞   1
                                                                                                                                                                                                                                                         2                                                                   2               2
http://www.geocities.com/calculusjrm/                                                  ⎛ n                     ⎞                                                                                                                                                                                                              1               1
                                                                                                                                                                                                                                                                                                       cos α − cos β = −2 sin (α + β ) ⋅ sin (α − β )
                                                                           ( a + b ) ⋅ ⎜ ∑ ( −1) a n− k b k −1 ⎟ = a n + b n ∀ n ∈
                                                                                                k +1
                                                                                                                                                                                                 ⎡ π π⎤                                                  1
                                                                                                                                                              impar    y = ∠ sin x y ∈ ⎢− , ⎥                                                                                                                                 2               2
                                                                                       ⎝ k =1                  ⎠                                                                       ⎣ 2 2⎦
                             VALOR ABSOLUTO
                                                                                                                                                                                                                                                                                                                                sin (α ± β )
                                                                                                                                                                                                                                                         0

                                                                                           ⎛                         ⎞                                                 y = ∠ cos x y ∈ [ 0, π ]
                                                                                               n
    ⎧a si a ≥ 0                                                            ( a + b ) ⋅ ⎜ ∑ ( −1)
                                                                                                              k +1
                                                                                                      a n − k b k −1 ⎟ = a n − b n ∀ n ∈                      par                                                                                                                                      tg α ± tg β =
 a =⎨                                                                                      ⎝ k =1                    ⎠
                                                                                                                                                                                                                                                         -1
                                                                                                                                                                                                                                                                                       arc ctg x                            cos α ⋅ cos β
    ⎩− a si a < 0                                                                                                                                                                                          π π                                                                         arc sec x

                                                                                                                                                                       y = ∠ tg x           y∈ −            ,                                                                          arc csc x
                                                                                                                                                                                                                                                                                                                      1
                                                                                                  SUMAS Y PRODUCTOS                                                                                                                                                                                    sin α ⋅ cos β =   ⎡sin (α − β ) + sin (α + β ) ⎤
                                                                                                                                                                                                                                                         -2

 a = −a                                                                                                                                                                                                    2 2
                                                                                                                                                                                                                                                                                                                      2⎣                              ⎦
                                                                                                                                                                                                                                                           -5                 0                    5

                                                                                                                    n

a ≤ a y −a ≤ a                                                             a1 + a2 +               + an = ∑ ak                                                         y = ∠ ctg x = ∠ tg
                                                                                                                                                                                          1
                                                                                                                                                                                                            y ∈ 0, π                                      IDENTIDADES TRIGONOMÉTRICAS                                 1
                                                                                                                k =1                                                                      x                                                                                                            sin α ⋅ sin β = ⎡cos (α − β ) − cos (α + β ) ⎤
                                                                                                                                                                                                                                                 sin θ + cos 2 θ = 1                                                  2⎣                              ⎦
                                                                                                                                                                                                                                                     2

 a ≥0 y a =0 ⇔ a=0                                                          n

                                                                           ∑ c = nc
                                                                                                                                                                                           1
                                                                                                                                                                       y = ∠ sec x = ∠ cos   y ∈ [ 0, π ]                                        1 + ctg 2 θ = csc 2 θ                                                 1
                              n                    n
                                                                                                                                                                                           x                                                                                                           cos α ⋅ cos β = ⎡cos (α − β ) + cos (α + β ) ⎤
                             ∏a          = ∏ ak                                                                                                                                                                                                                                                                        2⎣                               ⎦
                                                                           k =1
 ab = a b ó                                                                                                                                                                                                                                      tg 2 θ + 1 = sec 2 θ
                                    k                                       n                   n
                                                                                                                                                                                           1       ⎡ π π⎤
                             k =1              k =1
                                                                           ∑ ca           = c ∑ ak                                                                     y = ∠ csc x = ∠ sen    y ∈ ⎢− , ⎥                                                                                                               tg α + tg β
                                                                                                                                                                                                   ⎣ 2 2⎦                                        sin ( −θ ) = − sin θ
                                                                                  k
                                     n                      n              k =1                k =1                                                                                        x                                                                                                           tg α ⋅ tg β =
 a+b ≤ a + b ó                      ∑a                 ≤ ∑ ak               n                           n                n                                                                                                                                                                                            ctg α + ctg β
                                                                                                                                                                                                                                                 cos ( −θ ) = cos θ
                                               k
                                    k =1                k =1
                                                                           ∑ ( ak + bk ) = ∑ ak + ∑ bk                                                                Gráfica 1. Las funciones trigonométricas: sin x ,
                                                                                                                                                                                                                                                                                                                    FUNCIONES HIPERBÓLICAS
                                                                                                                                                                      cos x , tg x :
                                                                                                                                                                                                                                                 tg ( −θ ) = − tg θ
                                                                           k =1                        k =1             k =1
                                    EXPONENTES
                                                                                                                                                                                                                                                                                                                ex − e− x
                                                                                                                                                                                                                                                                                                       sinh x =
                                                                            n
a p ⋅ a q = a p+q                                                          ∑(a
                                                                           k =1
                                                                                  k       − ak −1 ) = an − a0                                                               2
                                                                                                                                                                                                                                                 sin (θ + 2π ) = sin θ                                               2
ap                                                                                                                                                                                                                                                                                                              e x + e− x
   = a p−q
                                                                                                                                                                          1.5
                                                                            n
                                                                                                  n                                                                                                                                              cos (θ + 2π ) = cos θ                                 cosh x =
aq
                                                                           ∑ ⎡ a + ( k − 1) d ⎤ = 2 ⎡ 2a + ( n − 1) d ⎤
                                                                                ⎣              ⎦    ⎣                 ⎦
                                                                                                                                                                            1

                                                                                                                                                                                                                                                 tg (θ + 2π ) = tg θ
                                                                                                                                                                                                                                                                                                                     2
(a )
   p q
            =a          pq                                                 k =1                                                                                           0.5

                                                                                                                                                                                                                                                                                                       tgh x =
                                                                                                                                                                                                                                                                                                               sinh x e x − e − x
                                                                                                                                                                                                                                                                                                                       =
                                                                                                 n
                                                                                                = (a + l )                                                                                                                                       sin (θ + π ) = − sin θ                                        cosh x e x + e− x
(a ⋅b)
                                                                                                                                                                            0
                = a ⋅b
            p            p    p
                                                                                                 2                                                                       -0.5
                                                                                                                                                                                                                                                 cos (θ + π ) = − cos θ                                            1       e x + e− x
        p                                                                   n
                                                                                          1 − r n a − rl                                                                                                                                                                                               ctgh x =        =
⎛a⎞  ap
⎜ ⎟ = p                                                                    ∑ ar = a 1 − r = 1 − r
                                                                                  k −1                                                                                     -1
                                                                                                                                                                                                                                                 tg (θ + π ) = tg θ                                             tgh x e x − e − x
⎝b⎠  b                                                                     k =1
                                                                                                                                                                         -1.5                                                        sen x
                                                                                                                                                                                                                                                                                                                    1            2
                                                                                                                                                                                                                                                 sin (θ + nπ ) = ( −1) sin θ                           sech x =          =
                                                                                                                                                                                                                                     cos x                                n

                                                                           ∑ k = 2 ( n2 + n )
                                                                            n
                                                                                     1                                                                                                                                               tg x
a p/q = a p                                                                                                                                                                                                                                                                                                     cosh x e x + e − x
                q
                                                                                                                                                                           -2
                                                                                                                                                                             -8   -6        -4        -2     0   2       4       6           8

                                                                                                                                                                                                                                                 cos (θ + nπ ) = ( −1) cos θ
                                                                                                                                                                                                                                                                          n
                                                                           k =1
                  LOGARITMOS                                                                                                                                                                                                                                                                                       1            2
                                                                                                                                                                                                                                                                                                       csch x =         =
                                                                           ∑ k 2 = 6 ( 2n3 + 3n2 + n )
                                                                            n
                                                                                       1                                                                              Gráfica 2. Las funciones trigonométricas csc x ,
log a N = x ⇒ a x = N                                                                                                                                                                                                                            tg (θ + nπ ) = tg θ                                            sinh x e x − e − x
                                                                                                                                                                      sec x , ctg x :
log a MN = log a M + log a N                                               k =1
                                                                                                                                                                                                                                                                                                       sinh :     →
                                                                                                                                                                                                                                                 sin ( nπ ) = 0
                                                                           ∑ k 3 = 4 ( n 4 + 2n3 + n 2 )
                                                                            n
                                                                                       1
      M                                                                                                                                                                   2.5
                                                                                                                                                                                                                                                                                                       cosh :     → [1, ∞
log a     = log a M − log a N                                              k =1                                                                                             2                                                                    cos ( nπ ) = ( −1)
                                                                                                                                                                                                                                                                      n
      N                                                                                                                                                                                                                                                                                                tgh :    → −1,1
                                                                           ∑ k 4 = 30 ( 6n5 + 15n4 + 10n3 − n )                                                                                                                                  tg ( nπ ) = 0
                                                                            n
                                                                                        1                                                                                 1.5

log a N r = r log a N                                                                                                                                                       1                                                                                                                          ctgh :     − {0} → −∞ , −1 ∪ 1, ∞
                                                                           k =1
                                                                                                                                                                                                                                                     ⎛ 2n + 1 ⎞
                                                                                                                                                                                                                                                              π ⎟ = ( −1)
          log b N ln N
                                                                                                                                                                                                                                                                                                                  → 0 ,1]
                                                                                                                                                                                                                                                                          n
                                                                                                      + ( 2n − 1) = n
                                                                                                                                                                          0.5
log a N =         =                                                        1+ 3 + 5 +                                            2                                                                                                               sin ⎜                                                 sech :
           log b a ln a                                                                                                                                                     0
                                                                                                                                                                                                                                                     ⎝ 2        ⎠
                                                                                      n                                                                                                                                                                                                                csch :     − {0} →             − {0}
                                                                           n! = ∏ k                                                                                                                                                                   ⎛ 2n + 1 ⎞
                                                                                                                                                                         -0.5
log10 N = log N y log e N = ln N                                                                                                                                           -1                                                                    cos ⎜        π⎟=0
                ALGUNOS PRODUCTOS                                                 k =1
                                                                                                                                                                         -1.5                                                                         ⎝ 2        ⎠                                     Gráfica 5. Las funciones hiperbólicas sinh x ,
a ⋅ ( c + d ) = ac + ad                                                    ⎛n⎞         n!                                                                                                                                            csc x
                                                                                                                                                                                                                                                    ⎛ 2n + 1 ⎞
                                                                           ⎜ ⎟=                 , k≤n                                                                                                                                                                                                  cosh x , tgh x :
                                                                                                                                                                           -2
                                                                                                                                                                                                                                                             π⎟=∞
                                                                                                                                                                                                                                     sec x


                                                                           ⎝ k ⎠ ( n − k )!k !
                                                                                                                                                                                                                                     ctg x       tg ⎜
( a + b) ⋅ ( a − b) = a − b         2              2
                                                                                                                                                                         -2.5
                                                                                                                                                                             -8   -6        -4        -2     0   2       4       6           8      ⎝ 2        ⎠                                                    5


                                                                                         n
                                                                                            ⎛n⎞                                                                                                                                                                   π⎞
                                                                                                                                                                                                                                                                                                                    4


( a + b ) ⋅ ( a + b ) = ( a + b ) = a 2 + 2ab + b 2                        ( x + y ) = ∑ ⎜ ⎟ xn−k y k                                                                                                                                                        ⎛
                                                                                    n
                                 2                                                                                                                                    Gráfica 3. Las funciones trigonométricas inversas
                                                                                                                                                                                                                                                 sin θ = cos ⎜ θ − ⎟                                                3

                                                                                       k =0 ⎝ k ⎠                                                                     arcsin x , arccos x , arctg x :                                                        ⎝    2⎠
( a − b ) ⋅ ( a − b ) = ( a − b ) = a 2 − 2ab + b 2
                                                                                                                                                                                                                                                                                                                    2
                                 2

                                                                                                                                      n!                                                                                                                     ⎛    π⎞
                                                                           ( x1 + x2 +                + xk ) = ∑
                                                                                                                                                                                                                                                                                                                    1

                                                                                                                                              x1n1 ⋅ x2 2                                                                                        cos θ = sin ⎜ θ + ⎟
                                                                                                                n
( x + b ) ⋅ ( x + d ) = x 2 + ( b + d ) x + bd
                                                                                                                                                      n
                                                                                                                                                            xknk            4

                                                                                                                                                                                                                                                             ⎝    2⎠                                                0
                                                                                                                               n1 ! n2 ! nk !
( ax + b ) ⋅ ( cx + d ) = acx 2 + ( ad + bc ) x + bd
                                                                                                                                                                                                                                                                                                                    -1

                                                                                                                                                                                                                                                 sin (α ± β ) = sin α cos β ± cos α sin β
                                                                                                                                                                            3
                                                                                           CONSTANTES                                                                                                                                                                                                               -2


( a + b ) ⋅ ( c + d ) = ac + ad + bc + bd                                  π = 3.14159265359…                                                                               2
                                                                                                                                                                                                                                                 cos (α ± β ) = cos α cos β ∓ sin α sin β                           -3
                                                                                                                                                                                                                                                                                                                                                      senh x
                                                                                                                                                                                                                                                                                                                                                      cosh x
                                                                                                                                                                                                                                                                                                                                                      tgh x


( a + b ) = a3 + 3a 2b + 3ab 2 + b3
         3                                                                 e = 2.71828182846…                                                                               1
                                                                                                                                                                                                                                                                tg α ± tg β
                                                                                                                                                                                                                                                                                                                    -4
                                                                                                                                                                                                                                                                                                                      -5                          0            5


                                                                                         TRIGONOMETRÍA                                                                                                                                           tg (α ± β ) =                                                  FUNCIONES HIPERBÓLICAS INV
( a − b ) = a 3 − 3a 2b + 3ab 2 − b3
         3                                                                                                                                                                                                                                                     1 ∓ tg α tg β
                                                                                                                                                                                                                                                                                                                           (                  )
                                                                                                                                                                            0


                                                                           sen θ =
                                                                                    CO
                                                                                               cscθ =
                                                                                                        1
                                                                                                                                                                                                                                                 sin 2θ = 2sin θ cos θ                                 sinh −1 x = ln x + x 2 + 1 , ∀x ∈
( a + b + c ) = a 2 + b 2 + c 2 + 2ab + 2ac + 2bc
               2
                                                                                   HIP                sen θ
                                                                                                                                                                                                                                                                                                                            (                 )
                                                                                                                                                                           -1

                                                                                                                                                                                                                                                 cos 2θ = cos 2 θ − sin 2 θ
                                                                                                                                                                                                                             arc sen x

                                                                                                                                                                                                                                                                                                       cosh −1 x = ln x ± x 2 − 1 , x ≥ 1
                                                                                                                                                                                                                             arc cos x


( a − b ) ⋅ ( a + ab + b ) = a − b
                                                                                    CA                  1                                                                                                                    arc tg x
                         2               2              3       3
                                                                           cosθ =              secθ =                                                                      -2
                                                                                                                                                                                                                                                            2 tg θ
                                                                                                      cosθ
                                                                                                                                                                             -3        -2        -1          0       1       2               3
                                                                                   HIP                                                                                                                                                           tg 2θ =                                                             1 ⎛1+ x ⎞
( a − b ) ⋅ ( a 3 + a 2 b + ab 2 + b3 ) = a 4 − b 4                               sen θ CO             1                                                                                                                                                  1 − tg 2 θ                                   tgh −1 x =     ln ⎜   ⎟,            x <1
                                                                           tgθ =       =       ctgθ =                                                                                                                                                                                                                2 ⎝1− x ⎠
( a − b ) ⋅ ( a 4 + a 3b + a 2 b 2 + ab3 + b 4 ) = a 5 − b5                       cosθ CA             tgθ                                                                                                                                                  1
                                                                                                                                                                                                                                                 sin 2 θ = (1 − cos 2θ )                                          1 ⎛ x +1⎞
                                                                                                                                                                                                                                                           2                                           ctgh −1 x = ln ⎜   ⎟,                   x >1
                    ⎛   n
                                           ⎞                               π radianes=180                                                                                                                                                                                                                         2 ⎝ x −1⎠
( a − b ) ⋅ ⎜ ∑ a n − k b k −1 ⎟ = a n − b n                        ∀n ∈                                                                                                                                                                                    1
                                                                                                                                                                                                                                                 cos 2 θ = (1 + cos 2θ )
                    ⎝ k =1                 ⎠                                                                                                                                                                                                                2                                                         ⎛ 1 ± 1 − x2 ⎞
                                                                                                                                                                                                                                                          1 − cos 2θ                                   sech −1 x = ln ⎜             ⎟, 0 < x ≤ 1
                                                                                                                                                                                                                                                 tg 2 θ =                                                             ⎜     x       ⎟
                                                                                                                                                                                                                                                                                                                      ⎝             ⎠
                                                                                                                     HIP
                                                                                                                                                   CO                                                                                                     1 + cos 2θ
                                                                                                                                                                                                                                                                                                                      ⎛1      x2 + 1 ⎞
                                                                                                                                                                                                                                                                                                       csch −1 x = ln ⎜ +             ⎟, x ≠ 0
                                                                                                            θ                                                                                                                                                                                                         ⎜x       x ⎟
                                                                                                                                                                                                                                                                                                                      ⎝               ⎠
                                                                                                                        CA
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Calculo

  • 1. Fórmulas de Cálculo Diferencial e Integral (Página 1 de 3) http://www.geocities.com/calculusjrm/ Jesús Rubí M. Fórmulas de ( a + b ) ⋅ ( a 2 − ab + b 2 ) = a 3 + b3 θ sin cos tg ctg sec csc Gráfica 4. Las funciones trigonométricas inversas arcctg x , arcsec x , arccsc x : sin α + sin β = 2sin 1 1 (α + β ) ⋅ cos (α − β ) ∞ ∞ ( a + b ) ⋅ ( a3 − a 2 b + ab 2 − b3 ) = a 4 − b 4 0 0 1 0 1 2 2 Cálculo Diferencial 30 12 3 2 1 3 3 2 3 2 4 1 1 sin α − sin β = 2 sin (α − β ) ⋅ cos (α + β ) ( a + b ) ⋅ ( a 4 − a 3b + a 2 b 2 − ab3 + b 4 ) = a 5 + b5 e Integral VER.6.8 45 1 2 1 2 1 1 2 2 3 2 2 ( a + b ) ⋅ ( a5 − a 4 b + a 3b 2 − a 2 b3 + ab 4 − b5 ) = a 6 − b 6 1 1 60 3 2 12 3 1 3 2 2 3 cos α + cos β = 2 cos (α + β ) ⋅ cos (α − β ) Jesús Rubí Miranda (jesusrubim@yahoo.com) 90 1 0 ∞ 0 ∞ 1 2 2 2 http://www.geocities.com/calculusjrm/ ⎛ n ⎞ 1 1 cos α − cos β = −2 sin (α + β ) ⋅ sin (α − β ) ( a + b ) ⋅ ⎜ ∑ ( −1) a n− k b k −1 ⎟ = a n + b n ∀ n ∈ k +1 ⎡ π π⎤ 1 impar y = ∠ sin x y ∈ ⎢− , ⎥ 2 2 ⎝ k =1 ⎠ ⎣ 2 2⎦ VALOR ABSOLUTO sin (α ± β ) 0 ⎛ ⎞ y = ∠ cos x y ∈ [ 0, π ] n ⎧a si a ≥ 0 ( a + b ) ⋅ ⎜ ∑ ( −1) k +1 a n − k b k −1 ⎟ = a n − b n ∀ n ∈ par tg α ± tg β = a =⎨ ⎝ k =1 ⎠ -1 arc ctg x cos α ⋅ cos β ⎩− a si a < 0 π π arc sec x y = ∠ tg x y∈ − , arc csc x 1 SUMAS Y PRODUCTOS sin α ⋅ cos β = ⎡sin (α − β ) + sin (α + β ) ⎤ -2 a = −a 2 2 2⎣ ⎦ -5 0 5 n a ≤ a y −a ≤ a a1 + a2 + + an = ∑ ak y = ∠ ctg x = ∠ tg 1 y ∈ 0, π IDENTIDADES TRIGONOMÉTRICAS 1 k =1 x sin α ⋅ sin β = ⎡cos (α − β ) − cos (α + β ) ⎤ sin θ + cos 2 θ = 1 2⎣ ⎦ 2 a ≥0 y a =0 ⇔ a=0 n ∑ c = nc 1 y = ∠ sec x = ∠ cos y ∈ [ 0, π ] 1 + ctg 2 θ = csc 2 θ 1 n n x cos α ⋅ cos β = ⎡cos (α − β ) + cos (α + β ) ⎤ ∏a = ∏ ak 2⎣ ⎦ k =1 ab = a b ó tg 2 θ + 1 = sec 2 θ k n n 1 ⎡ π π⎤ k =1 k =1 ∑ ca = c ∑ ak y = ∠ csc x = ∠ sen y ∈ ⎢− , ⎥ tg α + tg β ⎣ 2 2⎦ sin ( −θ ) = − sin θ k n n k =1 k =1 x tg α ⋅ tg β = a+b ≤ a + b ó ∑a ≤ ∑ ak n n n ctg α + ctg β cos ( −θ ) = cos θ k k =1 k =1 ∑ ( ak + bk ) = ∑ ak + ∑ bk Gráfica 1. Las funciones trigonométricas: sin x , FUNCIONES HIPERBÓLICAS cos x , tg x : tg ( −θ ) = − tg θ k =1 k =1 k =1 EXPONENTES ex − e− x sinh x = n a p ⋅ a q = a p+q ∑(a k =1 k − ak −1 ) = an − a0 2 sin (θ + 2π ) = sin θ 2 ap e x + e− x = a p−q 1.5 n n cos (θ + 2π ) = cos θ cosh x = aq ∑ ⎡ a + ( k − 1) d ⎤ = 2 ⎡ 2a + ( n − 1) d ⎤ ⎣ ⎦ ⎣ ⎦ 1 tg (θ + 2π ) = tg θ 2 (a ) p q =a pq k =1 0.5 tgh x = sinh x e x − e − x = n = (a + l ) sin (θ + π ) = − sin θ cosh x e x + e− x (a ⋅b) 0 = a ⋅b p p p 2 -0.5 cos (θ + π ) = − cos θ 1 e x + e− x p n 1 − r n a − rl ctgh x = = ⎛a⎞ ap ⎜ ⎟ = p ∑ ar = a 1 − r = 1 − r k −1 -1 tg (θ + π ) = tg θ tgh x e x − e − x ⎝b⎠ b k =1 -1.5 sen x 1 2 sin (θ + nπ ) = ( −1) sin θ sech x = = cos x n ∑ k = 2 ( n2 + n ) n 1 tg x a p/q = a p cosh x e x + e − x q -2 -8 -6 -4 -2 0 2 4 6 8 cos (θ + nπ ) = ( −1) cos θ n k =1 LOGARITMOS 1 2 csch x = = ∑ k 2 = 6 ( 2n3 + 3n2 + n ) n 1 Gráfica 2. Las funciones trigonométricas csc x , log a N = x ⇒ a x = N tg (θ + nπ ) = tg θ sinh x e x − e − x sec x , ctg x : log a MN = log a M + log a N k =1 sinh : → sin ( nπ ) = 0 ∑ k 3 = 4 ( n 4 + 2n3 + n 2 ) n 1 M 2.5 cosh : → [1, ∞ log a = log a M − log a N k =1 2 cos ( nπ ) = ( −1) n N tgh : → −1,1 ∑ k 4 = 30 ( 6n5 + 15n4 + 10n3 − n ) tg ( nπ ) = 0 n 1 1.5 log a N r = r log a N 1 ctgh : − {0} → −∞ , −1 ∪ 1, ∞ k =1 ⎛ 2n + 1 ⎞ π ⎟ = ( −1) log b N ln N → 0 ,1] n + ( 2n − 1) = n 0.5 log a N = = 1+ 3 + 5 + 2 sin ⎜ sech : log b a ln a 0 ⎝ 2 ⎠ n csch : − {0} → − {0} n! = ∏ k ⎛ 2n + 1 ⎞ -0.5 log10 N = log N y log e N = ln N -1 cos ⎜ π⎟=0 ALGUNOS PRODUCTOS k =1 -1.5 ⎝ 2 ⎠ Gráfica 5. Las funciones hiperbólicas sinh x , a ⋅ ( c + d ) = ac + ad ⎛n⎞ n! csc x ⎛ 2n + 1 ⎞ ⎜ ⎟= , k≤n cosh x , tgh x : -2 π⎟=∞ sec x ⎝ k ⎠ ( n − k )!k ! ctg x tg ⎜ ( a + b) ⋅ ( a − b) = a − b 2 2 -2.5 -8 -6 -4 -2 0 2 4 6 8 ⎝ 2 ⎠ 5 n ⎛n⎞ π⎞ 4 ( a + b ) ⋅ ( a + b ) = ( a + b ) = a 2 + 2ab + b 2 ( x + y ) = ∑ ⎜ ⎟ xn−k y k ⎛ n 2 Gráfica 3. Las funciones trigonométricas inversas sin θ = cos ⎜ θ − ⎟ 3 k =0 ⎝ k ⎠ arcsin x , arccos x , arctg x : ⎝ 2⎠ ( a − b ) ⋅ ( a − b ) = ( a − b ) = a 2 − 2ab + b 2 2 2 n! ⎛ π⎞ ( x1 + x2 + + xk ) = ∑ 1 x1n1 ⋅ x2 2 cos θ = sin ⎜ θ + ⎟ n ( x + b ) ⋅ ( x + d ) = x 2 + ( b + d ) x + bd n xknk 4 ⎝ 2⎠ 0 n1 ! n2 ! nk ! ( ax + b ) ⋅ ( cx + d ) = acx 2 + ( ad + bc ) x + bd -1 sin (α ± β ) = sin α cos β ± cos α sin β 3 CONSTANTES -2 ( a + b ) ⋅ ( c + d ) = ac + ad + bc + bd π = 3.14159265359… 2 cos (α ± β ) = cos α cos β ∓ sin α sin β -3 senh x cosh x tgh x ( a + b ) = a3 + 3a 2b + 3ab 2 + b3 3 e = 2.71828182846… 1 tg α ± tg β -4 -5 0 5 TRIGONOMETRÍA tg (α ± β ) = FUNCIONES HIPERBÓLICAS INV ( a − b ) = a 3 − 3a 2b + 3ab 2 − b3 3 1 ∓ tg α tg β ( ) 0 sen θ = CO cscθ = 1 sin 2θ = 2sin θ cos θ sinh −1 x = ln x + x 2 + 1 , ∀x ∈ ( a + b + c ) = a 2 + b 2 + c 2 + 2ab + 2ac + 2bc 2 HIP sen θ ( ) -1 cos 2θ = cos 2 θ − sin 2 θ arc sen x cosh −1 x = ln x ± x 2 − 1 , x ≥ 1 arc cos x ( a − b ) ⋅ ( a + ab + b ) = a − b CA 1 arc tg x 2 2 3 3 cosθ = secθ = -2 2 tg θ cosθ -3 -2 -1 0 1 2 3 HIP tg 2θ = 1 ⎛1+ x ⎞ ( a − b ) ⋅ ( a 3 + a 2 b + ab 2 + b3 ) = a 4 − b 4 sen θ CO 1 1 − tg 2 θ tgh −1 x = ln ⎜ ⎟, x <1 tgθ = = ctgθ = 2 ⎝1− x ⎠ ( a − b ) ⋅ ( a 4 + a 3b + a 2 b 2 + ab3 + b 4 ) = a 5 − b5 cosθ CA tgθ 1 sin 2 θ = (1 − cos 2θ ) 1 ⎛ x +1⎞ 2 ctgh −1 x = ln ⎜ ⎟, x >1 ⎛ n ⎞ π radianes=180 2 ⎝ x −1⎠ ( a − b ) ⋅ ⎜ ∑ a n − k b k −1 ⎟ = a n − b n ∀n ∈ 1 cos 2 θ = (1 + cos 2θ ) ⎝ k =1 ⎠ 2 ⎛ 1 ± 1 − x2 ⎞ 1 − cos 2θ sech −1 x = ln ⎜ ⎟, 0 < x ≤ 1 tg 2 θ = ⎜ x ⎟ ⎝ ⎠ HIP CO 1 + cos 2θ ⎛1 x2 + 1 ⎞ csch −1 x = ln ⎜ + ⎟, x ≠ 0 θ ⎜x x ⎟ ⎝ ⎠ CA