Given the information regarding mitosis and meiosis, clearly and convincingly explain in your own words how an error in MITOSIS could possibly lead to a gamete containing new genetic information and thereby giving rise to a new phenotype. Use detail be comprehensive. (7 points) Solution The process of mitosis is divided into two phases: Interphase and M-phase. Interphase is further divided into G1, S and G2 phase. In G1, protein synthesis occurs for S- phase, in S phase, DNA replicates and in G2 phase, protein synthesis occurs for M-phase to start properly. Now, during S phase, the ‘2n’ nucleus converts into 4n. So, the cell entering M-phase is already ‘4n’. M-phase is the actual mitotic phase, in which the cell divides into two. It contains four phases, prophase, metaphase, anaphase and telophase. Your question is related with these four phases. In prophase, the entire DNA converts into chromosomes; the process is known as condensation of DNA. In metaphase, these chromosomes align on the equator. Now, if alignment at equator is not correct, then anaphase cannot be started due to metaphase check point. In anaphase, the aligned chromosomes move towards the opposite poles. This phase is the main phase, related with formation of gametes. The cell is already ‘4n’. ‘2n’ chromosomes move towards one end, and the rest of ‘2n’ move towards the other end. Now, suppose an error occurs in mitosis, and ‘3n’ chromosomes move towards one end, and 1n goes towards the other cell; then two gametes, ‘3n’ and n will be formed. This ‘3n’ and ‘n’ gametes are gametes having different genetic information in comparison to their ‘2n’ counterparts. Interestingly, Meiosis II will result in gamete formation is mitotic division (equational division). Haploid cells with \'2c\' amount of DNA leave Meiosis I. Now, in anaphase, suppose one chromosome\' 2c DNA migrates to one end (due to error) and no DNA migrates to the other end; then two gametes will be formed; one having all normal chromosomes + one double chromosome with 2c DNA, and the other having no DNA. Please note: normally gametes are 1n (haploid) and 1c. Suppose this gamete with double DNA (2c) fertilizes with a gamete with half DNA (1c), then the resulting cell will have “all normal chromosomes + one chromosome with ‘3c’ amount of DNA”. This condition if occurring with chromosome 21 is known as Down\' syndrome. It is important to note that errors in Mitosis result in non-disjunction; which further results in many Mendelian disorders; as well as ploidy defects. ** Hope it helps..