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Sample Placement in
Spectroscopy
FTIR
 Fourier transform infrared spectroscopy shines a beam
containing many frequencies of light at once, and
measures how much of that beam is absorbed by the
sample
 Solves problems of IR
 difficult mechanics
 hard to transport
 limited resolution
 slow and inaccurate analysis
 stray light
 limited sensitivity
 lack of reproducibility
Sample Location
Sample Location
Reasons for Sample Locations
 The sample is located after the interferometer
 The moving mirrors reflect an array of frequencies
 As this mirror moves, each wavelength of light in the beam is
periodically blocked or transmitted by the
interferometer, acting similar to a monochromator, due to
wave interference
 Different wavelengths are modulated at different rates by the
moving mirror
 This set up for FTIR is used to see how the sample absorbs at
an array of wavelengths in a short period of time
The Moving mirror causes the array
of wavelengths within the FTIR
spectrometer.
A. True
B. False
C. Neither
D. Both
E. This is not the answer
Infrared Spectroscopy
 Pass a beam of infrared light through the sample.
 When the frequency of the IR is the same as the vibrational
frequency of a bond, absorption occurs.
 Examination of the transmitted light reveals how much
energy was absorbed at each frequency (or wavelength)
 This can lead to identification/study of different molecules
Sample location
 The sample is placed in line with a reference for comparison
 Sample placed before the chopper/splitter
 The chopper/splitter alternates which beam (sample or reference) enters
the monochromator and detector
 This is done to prevent fluctuations in the output of the source affecting
the data and allows the effects of the solvent of the sample to be
cancelled out
 The sample is placed before the monochromator so that it can adjust which
wavelength range is detected by the IR detector
UV/Visible Spectroscopy
 Utilizes light in the
UV/Visible region to
measure the absorption
 Measures transition of
non-binding electrons
from ground state to
excited state as opposed
to fluorescence, which
measures excited to
ground state
UV/Visible Spectroscopy
 A beam of light from a visible
and/or UV light source is
separated into its component
wavelengths by a prism or
diffraction grating.
 Each wavelength is split into
two equal intensity beams by a
half-mirrored device.
 One beam passes through the
sample and the other through
the reference or blank.
 The intensities of these light
beams are then measured by
electronic detectors and
compared.
 Sample is placed behind the
dispersive element
Why the sample is located behind
the dispersive element
 UV/visible spectroscopy is used in quantitative
determinations of solutions especially transition metal
ions, conjugated organic compounds, and biological
macromolecules
 These samples used in UV/visible spectroscopy only
absorb at specific wavelengths in the UV/visible range
of 200-800 nm
 A single wavelength is needed to identify the compound
within the sample, so the sample must be behind the
monochromator
For Example:
 NADH absorbs at 340 nm
 NADH is broken down into NAD+ to allow many reactions to
occur
 Utilizing Beer’s Law the rate of reaction (decrease in NADH
concentration) can be determined by the decrease in absorbance
as the reaction
 One can determine whether an enzyme, such as MDH
above, used in this kinetic assay was successful or not depending
on the rate of reaction
Where is the sample in UV/Visible
Spectroscopy located?
A. After the monochromator
B. Before the monochromator
C. Right in front of the deuterium lamp
D. You don’t need a sample in UV/Visible
spectroscopy
E. This one is wrong
Fluorescence Spectroscopy
 Emission at lower energy than absorption
 Greater selectivity but fluorescent yields vary for
different molecules
 Detection at right angles to excitation
 S/N is improved so sensitivity is better
 Fluorescent tags
In fluorescence spectroscopy…
A) We can select for wavelength by having the excitation
source pass through a filter or monochromator
B) We want the detection at ~180° to the excitation for
an improved signal/noise ratio
C) Emission occurs at an equal energy to absorption
D) All of the above
Fluorescence within
Chromatography
 The use of an excitation
monochromator can be
avoided using a laser
because it emits light at a
very narrow wavelength
interval
 Disadvantage: Cannot
drastically change the
wavelength
Resources
 http://www2.chemistry.msu.edu/faculty/reusch/virttxtjml/s
pectrpy/uv-vis/spectrum.htm
 http://en.wikipedia.org/wiki/Ultraviolet–
visible_spectroscopy
 http://en.wikipedia.org/wiki/Fourier_transform_infrared_spe
ctroscopy
 http://david-
bender.co.uk/metonline/CHO/shuttles/shuttles9.htm
 https://www.princeton.edu/~achaney/tmve/wiki100k/docs/
Ultraviolet-visible_spectroscopy.html
 http://en.wikipedia.org/wiki/Infrared_spectroscopy

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Wavelength dispersion seen in spectroscopy

  • 2. FTIR  Fourier transform infrared spectroscopy shines a beam containing many frequencies of light at once, and measures how much of that beam is absorbed by the sample  Solves problems of IR  difficult mechanics  hard to transport  limited resolution  slow and inaccurate analysis  stray light  limited sensitivity  lack of reproducibility
  • 5. Reasons for Sample Locations  The sample is located after the interferometer  The moving mirrors reflect an array of frequencies  As this mirror moves, each wavelength of light in the beam is periodically blocked or transmitted by the interferometer, acting similar to a monochromator, due to wave interference  Different wavelengths are modulated at different rates by the moving mirror  This set up for FTIR is used to see how the sample absorbs at an array of wavelengths in a short period of time
  • 6. The Moving mirror causes the array of wavelengths within the FTIR spectrometer. A. True B. False C. Neither D. Both E. This is not the answer
  • 7. Infrared Spectroscopy  Pass a beam of infrared light through the sample.  When the frequency of the IR is the same as the vibrational frequency of a bond, absorption occurs.  Examination of the transmitted light reveals how much energy was absorbed at each frequency (or wavelength)  This can lead to identification/study of different molecules
  • 8. Sample location  The sample is placed in line with a reference for comparison  Sample placed before the chopper/splitter  The chopper/splitter alternates which beam (sample or reference) enters the monochromator and detector  This is done to prevent fluctuations in the output of the source affecting the data and allows the effects of the solvent of the sample to be cancelled out  The sample is placed before the monochromator so that it can adjust which wavelength range is detected by the IR detector
  • 9. UV/Visible Spectroscopy  Utilizes light in the UV/Visible region to measure the absorption  Measures transition of non-binding electrons from ground state to excited state as opposed to fluorescence, which measures excited to ground state
  • 10. UV/Visible Spectroscopy  A beam of light from a visible and/or UV light source is separated into its component wavelengths by a prism or diffraction grating.  Each wavelength is split into two equal intensity beams by a half-mirrored device.  One beam passes through the sample and the other through the reference or blank.  The intensities of these light beams are then measured by electronic detectors and compared.  Sample is placed behind the dispersive element
  • 11. Why the sample is located behind the dispersive element  UV/visible spectroscopy is used in quantitative determinations of solutions especially transition metal ions, conjugated organic compounds, and biological macromolecules  These samples used in UV/visible spectroscopy only absorb at specific wavelengths in the UV/visible range of 200-800 nm  A single wavelength is needed to identify the compound within the sample, so the sample must be behind the monochromator
  • 12. For Example:  NADH absorbs at 340 nm  NADH is broken down into NAD+ to allow many reactions to occur  Utilizing Beer’s Law the rate of reaction (decrease in NADH concentration) can be determined by the decrease in absorbance as the reaction  One can determine whether an enzyme, such as MDH above, used in this kinetic assay was successful or not depending on the rate of reaction
  • 13. Where is the sample in UV/Visible Spectroscopy located? A. After the monochromator B. Before the monochromator C. Right in front of the deuterium lamp D. You don’t need a sample in UV/Visible spectroscopy E. This one is wrong
  • 14. Fluorescence Spectroscopy  Emission at lower energy than absorption  Greater selectivity but fluorescent yields vary for different molecules  Detection at right angles to excitation  S/N is improved so sensitivity is better  Fluorescent tags
  • 15.
  • 16.
  • 17. In fluorescence spectroscopy… A) We can select for wavelength by having the excitation source pass through a filter or monochromator B) We want the detection at ~180° to the excitation for an improved signal/noise ratio C) Emission occurs at an equal energy to absorption D) All of the above
  • 18. Fluorescence within Chromatography  The use of an excitation monochromator can be avoided using a laser because it emits light at a very narrow wavelength interval  Disadvantage: Cannot drastically change the wavelength
  • 19. Resources  http://www2.chemistry.msu.edu/faculty/reusch/virttxtjml/s pectrpy/uv-vis/spectrum.htm  http://en.wikipedia.org/wiki/Ultraviolet– visible_spectroscopy  http://en.wikipedia.org/wiki/Fourier_transform_infrared_spe ctroscopy  http://david- bender.co.uk/metonline/CHO/shuttles/shuttles9.htm  https://www.princeton.edu/~achaney/tmve/wiki100k/docs/ Ultraviolet-visible_spectroscopy.html  http://en.wikipedia.org/wiki/Infrared_spectroscopy

Editor's Notes

  1. Dispersion of light occurs in the monochromator
  2. This is a general picture of a spectrophotomotor with a monochromator (includes the entrance, dispersion, and exit) we will be specifically talking about the Dispersion devices within
  3. The answer is D
  4. The answer is B
  5. The answer is A
  6. Lasers – A laser makes it possible to have narrow wavelength intervals that offer very high energy irradiation. This is useful when a large amount of energy is needed to produce the fluorescence in the sample.Photodiodes – Photodiodes are specialized diodes that can be configured in a manner that allows electrons to flow towards the sample so that the excess energy excites the fluorescent particles.Lamps – Specialized lamps that provide the necessary amount of excess energy to excite the fluorescent particles in the sample.Xenon Arcs – Arcs of Xenon can produce the right amount of radiation for fluorescent materials to fluoresce for observation with the equipment.Mercury Vapor – Since mercury vapor can create ultraviolet radiation when electrical current is passed through it, it is good for use with materials that fluoresce under the ultraviolet radiation.
  7. Answer is AWe want ~90°Emission occurs at a LOWER energy to absorption