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January 05, 2012


The Parabola       The set of all points equidistant from
a fixed point (focus) and a fixed line (directrix)


  The vertex form of a parabola is given by:
  y = (x-h)2+k, where (h,k) is the vertex.


The standard form of a parabola is
1. (x-h)2=4p(y-k) where (h,k) is the
vertex
                OR
2. (y-k)2=4p(x-h) where (h,k) is the
vertex.

Equation 1, the parabola opens up or down
Equation 2, the parabola opens left or
right

                                    focus

                                            vertex

                                     directrix




 p is the distance from the vertex to the
 focus and the distance from the vertex to
 the directrix
January 05, 2012


 Example: Graph the following parabola and
 list the vertex, focus and directrix
     y2- 6y -8x + 49 = 0

1) This parabola opens left or right
                2
because of the y .

2) We need to get y's on one side and
x's on the other side
     2
   y - 6y = 8x - 49

3) Now complete the square on the y's
    2
   y - 6y + 9 = 8x - 49 + 9
        2
   (y-3) = 8x - 40

 4) The coefficient in front of the x and y
 must be a 1 (according to our formula).
           2
    (y - 3) = 8(x - 5)
           2
    (y - k) = 4p(x-h) original formula
                       so…4p = 8
                        or…p = 2


 Our parabola has a vertex at (5, 3) with a p
 value of 2. It opens right because the p is
 positive.


                                  Focus: (7, 3)


                                  Directrix: x = 3

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Parabolas

  • 1. January 05, 2012 The Parabola The set of all points equidistant from a fixed point (focus) and a fixed line (directrix) The vertex form of a parabola is given by: y = (x-h)2+k, where (h,k) is the vertex. The standard form of a parabola is 1. (x-h)2=4p(y-k) where (h,k) is the vertex OR 2. (y-k)2=4p(x-h) where (h,k) is the vertex. Equation 1, the parabola opens up or down Equation 2, the parabola opens left or right focus vertex directrix p is the distance from the vertex to the focus and the distance from the vertex to the directrix
  • 2. January 05, 2012 Example: Graph the following parabola and list the vertex, focus and directrix y2- 6y -8x + 49 = 0 1) This parabola opens left or right 2 because of the y . 2) We need to get y's on one side and x's on the other side 2 y - 6y = 8x - 49 3) Now complete the square on the y's 2 y - 6y + 9 = 8x - 49 + 9 2 (y-3) = 8x - 40 4) The coefficient in front of the x and y must be a 1 (according to our formula). 2 (y - 3) = 8(x - 5) 2 (y - k) = 4p(x-h) original formula so…4p = 8 or…p = 2 Our parabola has a vertex at (5, 3) with a p value of 2. It opens right because the p is positive. Focus: (7, 3) Directrix: x = 3