A certain ROM has 32 words x 16 bit structure. The input lines to the ROM are A, B, C, D, and
E. If E is the LSB, what binary input sequence would we enter to select the 10th word stored
inside the ROM?
Solution
32 words x 16 bit
it says the no of word(32) in size of bit(16) can store in the ROM.
the address for the store value will form By ABCDE vector value start from 0(00000)
to31(11111).
to access the 10th word(the binaryvalue for 10 is 01010) we need to enter
A=0,B=1,C=0,D=1,E=0
inside the ROM.
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A certain ROM has 32 words x 16 bit structure. The input lines to th.pdf
1. A certain ROM has 32 words x 16 bit structure. The input lines to the ROM are A, B, C, D, and
E. If E is the LSB, what binary input sequence would we enter to select the 10th word stored
inside the ROM?
Solution
32 words x 16 bit
it says the no of word(32) in size of bit(16) can store in the ROM.
the address for the store value will form By ABCDE vector value start from 0(00000)
to31(11111).
to access the 10th word(the binaryvalue for 10 is 01010) we need to enter
A=0,B=1,C=0,D=1,E=0
inside the ROM
