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Wei LI Int. Journal of Engineering Research and Applications www.ijera.com
ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32
www.ijera.com 29 | P a g e
Calculating the closure jacking-force of a large-span pre-stressed
concrete continuous rigid frame bridge
Wei LI*, Hui Liu**
*(School of civil engineering and architecture, Chongqing Jiaotong University, Chongqing-66)
** (School of civil engineering and architecture, Chongqing Jiaotong University, Chongqing)
ABSTRACT
Before closuring the mid-span of a large-span pre-stressed concrete continuous rigid frame bridge, imposing
jacking-force could commendably eliminate the down-warping of main beam, horizontal deviation of main pier
and the additional internal force caused by temperature differential and concrete shrink-creep. Two formulas
deduced in this article to calculate the jacking-force have been applied to an engineering example to analyze and
compare their applicability by combining with finite element simulation. The results showed that both formulas
were practicable and could be as a simple computational method extended to other bridges with the same type.
Keywords - bridge, closure, continuous rigid frame bridge, jacking-force
I. INTRODUCTION
The continuous rigid frame bridge is widely used
in modern bridge construction for the advantages of
strong crossing competencies, good entirety, driving
comfort and attractive outlook. Moreover, with the
mature construction technology, rational project cost,
it has a strong competitiveness among bridges with
the main span between 100 and 300 meters.
However, this bridge type is statically
indeterminate structure, the temperature changes and
concrete shrink-creep will cause additional internal
force in the structure. Moreover, during the stage of
constructing the closure segment, the actual
temperature may not match the design value. This
temperature differential will cause displacement of
beam. Similarly, the concrete shrink-creep will cause
the beam deflected vertically and shifted horizontally.
Due to the pier-beam fixed form of continuous rigid-
frame, the main pier would deviate to the mid-span
while the beam deflected. And the displacement will
result in generating secondary stress in the bridge
structure which is particularly greater in the pounding
bottom. These adverse states not only impact on the
driving comfort and aesthetic, but also work against
to the carrying capacity of pier.
In order to improve these situations, the
construction method of imposing jacking-force on the
cantilever end of closure section, which could give
the main pier a preliminary reverse displacement, can
be implemented. Two mathematical formulas to
express the relationship between the jacking-force
and the horizontal displacement have been deduced
on the base of structural mechanics. Combining the
formulas with a finite element model of engineering
example, how to confirm the jacking force of
continuous rigid frame bridge has been studied in this
article.
II. DERIVATION OF THE FORMULAS
Basing on a three-span continuous rigid frame,
two formulas for jacking dorce calculation have been
deduced.
1.1 Statically indeterminate structure
The simplified model of a continuous rigid frame
bridge with double thin-wall piers is illustrated in
Fig.1. It is in the phase of mid-span closure. P is the
closure jacking force and Pe (e is the vertical distance
from P to centroid of the cross section) is a eccentric
bending moment caused by P as its point of
application could not be in a straight line with the
centroid of box section during the construction.
Taking the left section of the bridge as a basic
structure which is three-fold statically indeterminate.
As shown in Fig.2.
figure1: the simplified model
RESEARCH ARTICLE OPEN ACCESS
Wei LI Int. Journal of Engineering Research and Applications www.ijera.com
ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32
www.ijera.com 30 | P a g e
figure2: the basic structure
Establishing the compatibility equation of force
method:
δ11X1 + δ12X2 + δ13X3 + ∆1p= 0
δ21X1 + δ22X2 + δ23X3 + ∆2p= 0
δ31X1 + δ32X2 + δ33X3 + ∆3p= 0
(1)
The bending moment diagrams of the basic
structure under the action of each force are shown in
Fig.3.
(1)M1 (2) M2
(3)M3 (4) Mp
figure3: the bending moment diagrams
Because X1 and X2 are symmetric forces, X3 is
anti-symmetric force, so the parameters. By using the
graphic multiplication method, each parameter is
worked out as follows:
δ11 = 2l1 EI1 + l2 EI2
δ22 = 2l1
3
3EI1
δ33 = l1l2
2
2EI1 + l2
3
12EI2
δ12 = δ21 = l1
2
EI1
∆1p= − (2el1 + l1
2
)P 2EI1
∆2p= − (3el1
2
+ 2l1
3
)P 6EI1
∆3p= − (2el1l2 + l1
2
l2)p 4EI1
The stiffness of zero block is much larger than
the thin-wall pier, therefore it can be assumed the
stiffness of zero block for infinity ( EI2 ∝ ∞ ).
Substituting these parameters in the formula (1), the
outcome is as follows:
X1 = Pe 2
X2 = P 2
X3 = (2e + l1)P 2l2
Basing on the principle of superposition, the
bending moment of the simplified model is
M=M1+M2+M3+Mp
According to the principle of virtual work force
and displacement are independent and unrelated[1], it
can be assumed that point A of the basic structure
bore a horizontal unit virtual force (FA=1) on the
premise that all the redundant unknown forces were
worked out. And because the displacement of rigid
frame is mainly dominated by the bending moment,
so the value can be obtained on the basis of
displacement calculation formula:
∆AX = MMAds EI1
= l1
2
Pe 4 + l1
3
P 6 − l1
3
+ 2el1 P 8 EI1
= l1
3
p 24EI1
Cosh x:
∆BX = MMBds EI3 = l3
3
p 24EI3
The relative displacement of two piers:
∆AB = ∆AX + ∆BX = l1
3
p 24EI1 + l3
3
p 24EI3
The calculation formula of the jacking force:
P = 24EI1I3∆AB (I3l1
3
+ I1l3
3
) (2)
1.2 Statically indeterminate structure
Due to the stiffness of zero block is much larger
than the thin-wall pier, the statically indeterminate
structure can be simplified to a statically
indeterminate structure with single thin-wall pier.
The practical jacking force to cause is 1/2p [2]. The
simplified model of the single thin-wall pier structure
is illustrated in Fig.4.
↓
figure4: the simplified model (2)
Wei LI Int. Journal of Engineering Research and Applications www.ijera.com
ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32
www.ijera.com 31 | P a g e
The bending moment diagrams are shown in
Fig.5.
(1)M1’ (2) Mp’
figure5: the bending moment diagrams (2)
Basing on the displacement calculation formula,
the calculation formula of offset value:
∆AX
′
= MMA ds EI1 = (3el1
2
+ 2l1
3
)p 12EI1
Cosh x:
∆BX
′
= (3el3
2
+ 2l3
3
)p 12EI3
The calculation formula of the jacking force:
p = 12EI1I3∆AB
′
I3 3l1
2
e + 2l1
3
+ I1 3l3
2
e + 2l3
3
(3)
III. ESTABLISHMENT OF FINITE ELEMENT
MODEL AND CALCULATION OF THE
HORIZONTAL DISPLACEMENT
The Huaihe River highway bridge is located near
the South Lake Avenue outside the main districts of
Fengtai County. The main bridge superstructure is
continuous rigid-frame of 370m (97m+176m+97m)
long, 15.95m wide. The beam section is single box
with double chamber. The change of beam depth is in
accordance with cubic parabola (side span 4m——
zero block 10m——mid-span 4m). Construction
method of this bridge is symmetrical cantilever
construction. Constructing in the sequence of firstly
pouring cantilevers symmetrically, then closuring the
mid-span, finally the side span.
The finite element model is established in order
of the construction sequence by bridge design and
calculation software MIDAS/CIVIL8.0. Its main
girder and main pier are divided into 128 and 56 units
respectively, the boundary conditions are pier-beam
consolidation and the bottom of the pier
consolidation. As illustrated in Fig.6. To add 10000
days for considering the impact of concrete shrink-
creep. Setting the temperature difference between
actual temperature and design value is 3℃. By using
the software calculation, the horizontal displacement
of both main piers can be given.
The displacement of pier 2: ∆AX= 3.79cm
The pier 3: ∆BX= −3.79cm (Taking the right as
the positive direction)
figure6: the finite element model
IV. CONFIRMATION OF JACKING FORCE
In the real construction process, it can
symmetrically apply the jacking force to the tapered
haunch as it cannot be loaded directly in the centroid
of box section. P·e is an additional eccentric bending
moment to the centroid. Using the computerization
software to calculate, the horizontal jacking force
aroused by the forced displacement ∆AX(= −3.79cm)
is 7431 (KN).
According to formula (2), the jacking force:
P =
12EI1∆AB l1
3
=12×3.25×107×5.32×0.0379×2/283=71
64 (KN)
According to formula (3), p=8411(KN)
V. ANALYSIS OF THE CALCULATING RESULTS
In the situation of different jacking force, to
compare the displacements of pier 1 calculated by
analytical formulas and finite-element analysis
(FEA). As shown in table 1.
Table 1: the displacements calculated in 3 methods
The
jacking
force/(KN
)
FEA/(c
m)
Statically in-
determinate
structure/(cm
)
Statically
determinate
structure/(c
m)
2000 1.02 1.06 0.9
4000 2.06 2.12 1.8
6000 3.05 3.17 2.7
From the table, it can be observed the
displacements calculated by both analytical formulas
and FEA are similar. Comparing the changes of
structure additional internal forces in case of
imposing the jacking force and not. As shown in
table 2.
Table 2: the stress of each control section (KN·m)
Major
control
sections
Without
jacking force
Imposing
jacking
force (2)
Imposing
jacking
force (3)
Bottom of
pier 1
1.94E+05 -7.56E+03 -4.8E+04
The middle
span
section
2.05E+04 1.76+03 1.2E+03
Wei LI Int. Journal of Engineering Research and Applications www.ijera.com
ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32
www.ijera.com 32 | P a g e
It is thus evident that the internal force of the
control sections has been substantially improved after
imposing the jacking force. The effect of optimizing
the stress performance has been obtained.
VI. CONCLUSION
1) From these two analytical formulas for calculating
the jacking force, the conclusion jacking force is
linear with displacement can be drawn. And the
calculated results prove that the theoretical
calculating values match well with the values from
finite element calculation. These two formulas can be
extended as a simple computational method to other
bridges with the same type.
2) However, in the process of deducing, only the
effects of bending moment on pier displacement were
considered, the effects of axial force and shearing
force had been ignored. Consequently, the formulas
exists certain errors. That the stiffness of zero block
was assumed to infinite also has some influence on
computational accuracy for it is impossible in
practical engineering.
3) According to the results from table 1 and table 2,
during the closure segment construction of large-span
pre-stressed concrete continuous rigid frame bridge,
imposing jacking-force properly to give the pier a
pre-displacement could effectively counteract the pier
offset and improve the stress performance of the
bridge.
REFERENCES
[1] Liankun Li, Structural Mechanics (Beijing:
Higher Education Press, 2010).
[2] Guowen Yao, S. Wenfeng, Z. Zhixiang,
Horizontal jacking force and closure order
optimization of rigid frame-continuous
girder bridge with multi-span, Highways &
Automotive 124(1), 2008, 91-93.
[3] Yisong Zou, D. Xiangrong, The
confirmation closure jacking force of
continuous rigid frame bridge, Journal of
Chongqing Jiaotong University 25(2), 2006,
12-15.
[4] Heqing Hu, D. Jiangming, Z. Shuixing and
D. Yangfang, The studies of closure
program of multi - span continuous rigid
frame bridge, Journal of China and Foreign
Highway, 29(3), 2009, 109-114.
[5] Kunpeng Luan, Z. Xuesong, G. Hongru,
Optimum calculation method of closure
jacking force of continuous rigid frame
bridge, Ludong University Journal, 27(1),
2011, 92-96.
[6] Ganggang Zhang, W. Chongnan, Discussion
on the design of closure jacking force of
continuous rigid frame bridge, Journal of
China and Foreign Highway,
31(5),2011,119-122.
[7] General Code for Design of Highway
Bridges and Culverts JTG D60-2004
(Beijing: China Communications Press,
2004).

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Calculating the closure jacking-force of a large-span pre-stressed concrete continuous rigid frame bridge

  • 1. Wei LI Int. Journal of Engineering Research and Applications www.ijera.com ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32 www.ijera.com 29 | P a g e Calculating the closure jacking-force of a large-span pre-stressed concrete continuous rigid frame bridge Wei LI*, Hui Liu** *(School of civil engineering and architecture, Chongqing Jiaotong University, Chongqing-66) ** (School of civil engineering and architecture, Chongqing Jiaotong University, Chongqing) ABSTRACT Before closuring the mid-span of a large-span pre-stressed concrete continuous rigid frame bridge, imposing jacking-force could commendably eliminate the down-warping of main beam, horizontal deviation of main pier and the additional internal force caused by temperature differential and concrete shrink-creep. Two formulas deduced in this article to calculate the jacking-force have been applied to an engineering example to analyze and compare their applicability by combining with finite element simulation. The results showed that both formulas were practicable and could be as a simple computational method extended to other bridges with the same type. Keywords - bridge, closure, continuous rigid frame bridge, jacking-force I. INTRODUCTION The continuous rigid frame bridge is widely used in modern bridge construction for the advantages of strong crossing competencies, good entirety, driving comfort and attractive outlook. Moreover, with the mature construction technology, rational project cost, it has a strong competitiveness among bridges with the main span between 100 and 300 meters. However, this bridge type is statically indeterminate structure, the temperature changes and concrete shrink-creep will cause additional internal force in the structure. Moreover, during the stage of constructing the closure segment, the actual temperature may not match the design value. This temperature differential will cause displacement of beam. Similarly, the concrete shrink-creep will cause the beam deflected vertically and shifted horizontally. Due to the pier-beam fixed form of continuous rigid- frame, the main pier would deviate to the mid-span while the beam deflected. And the displacement will result in generating secondary stress in the bridge structure which is particularly greater in the pounding bottom. These adverse states not only impact on the driving comfort and aesthetic, but also work against to the carrying capacity of pier. In order to improve these situations, the construction method of imposing jacking-force on the cantilever end of closure section, which could give the main pier a preliminary reverse displacement, can be implemented. Two mathematical formulas to express the relationship between the jacking-force and the horizontal displacement have been deduced on the base of structural mechanics. Combining the formulas with a finite element model of engineering example, how to confirm the jacking force of continuous rigid frame bridge has been studied in this article. II. DERIVATION OF THE FORMULAS Basing on a three-span continuous rigid frame, two formulas for jacking dorce calculation have been deduced. 1.1 Statically indeterminate structure The simplified model of a continuous rigid frame bridge with double thin-wall piers is illustrated in Fig.1. It is in the phase of mid-span closure. P is the closure jacking force and Pe (e is the vertical distance from P to centroid of the cross section) is a eccentric bending moment caused by P as its point of application could not be in a straight line with the centroid of box section during the construction. Taking the left section of the bridge as a basic structure which is three-fold statically indeterminate. As shown in Fig.2. figure1: the simplified model RESEARCH ARTICLE OPEN ACCESS
  • 2. Wei LI Int. Journal of Engineering Research and Applications www.ijera.com ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32 www.ijera.com 30 | P a g e figure2: the basic structure Establishing the compatibility equation of force method: δ11X1 + δ12X2 + δ13X3 + ∆1p= 0 δ21X1 + δ22X2 + δ23X3 + ∆2p= 0 δ31X1 + δ32X2 + δ33X3 + ∆3p= 0 (1) The bending moment diagrams of the basic structure under the action of each force are shown in Fig.3. (1)M1 (2) M2 (3)M3 (4) Mp figure3: the bending moment diagrams Because X1 and X2 are symmetric forces, X3 is anti-symmetric force, so the parameters. By using the graphic multiplication method, each parameter is worked out as follows: δ11 = 2l1 EI1 + l2 EI2 δ22 = 2l1 3 3EI1 δ33 = l1l2 2 2EI1 + l2 3 12EI2 δ12 = δ21 = l1 2 EI1 ∆1p= − (2el1 + l1 2 )P 2EI1 ∆2p= − (3el1 2 + 2l1 3 )P 6EI1 ∆3p= − (2el1l2 + l1 2 l2)p 4EI1 The stiffness of zero block is much larger than the thin-wall pier, therefore it can be assumed the stiffness of zero block for infinity ( EI2 ∝ ∞ ). Substituting these parameters in the formula (1), the outcome is as follows: X1 = Pe 2 X2 = P 2 X3 = (2e + l1)P 2l2 Basing on the principle of superposition, the bending moment of the simplified model is M=M1+M2+M3+Mp According to the principle of virtual work force and displacement are independent and unrelated[1], it can be assumed that point A of the basic structure bore a horizontal unit virtual force (FA=1) on the premise that all the redundant unknown forces were worked out. And because the displacement of rigid frame is mainly dominated by the bending moment, so the value can be obtained on the basis of displacement calculation formula: ∆AX = MMAds EI1 = l1 2 Pe 4 + l1 3 P 6 − l1 3 + 2el1 P 8 EI1 = l1 3 p 24EI1 Cosh x: ∆BX = MMBds EI3 = l3 3 p 24EI3 The relative displacement of two piers: ∆AB = ∆AX + ∆BX = l1 3 p 24EI1 + l3 3 p 24EI3 The calculation formula of the jacking force: P = 24EI1I3∆AB (I3l1 3 + I1l3 3 ) (2) 1.2 Statically indeterminate structure Due to the stiffness of zero block is much larger than the thin-wall pier, the statically indeterminate structure can be simplified to a statically indeterminate structure with single thin-wall pier. The practical jacking force to cause is 1/2p [2]. The simplified model of the single thin-wall pier structure is illustrated in Fig.4. ↓ figure4: the simplified model (2)
  • 3. Wei LI Int. Journal of Engineering Research and Applications www.ijera.com ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32 www.ijera.com 31 | P a g e The bending moment diagrams are shown in Fig.5. (1)M1’ (2) Mp’ figure5: the bending moment diagrams (2) Basing on the displacement calculation formula, the calculation formula of offset value: ∆AX ′ = MMA ds EI1 = (3el1 2 + 2l1 3 )p 12EI1 Cosh x: ∆BX ′ = (3el3 2 + 2l3 3 )p 12EI3 The calculation formula of the jacking force: p = 12EI1I3∆AB ′ I3 3l1 2 e + 2l1 3 + I1 3l3 2 e + 2l3 3 (3) III. ESTABLISHMENT OF FINITE ELEMENT MODEL AND CALCULATION OF THE HORIZONTAL DISPLACEMENT The Huaihe River highway bridge is located near the South Lake Avenue outside the main districts of Fengtai County. The main bridge superstructure is continuous rigid-frame of 370m (97m+176m+97m) long, 15.95m wide. The beam section is single box with double chamber. The change of beam depth is in accordance with cubic parabola (side span 4m—— zero block 10m——mid-span 4m). Construction method of this bridge is symmetrical cantilever construction. Constructing in the sequence of firstly pouring cantilevers symmetrically, then closuring the mid-span, finally the side span. The finite element model is established in order of the construction sequence by bridge design and calculation software MIDAS/CIVIL8.0. Its main girder and main pier are divided into 128 and 56 units respectively, the boundary conditions are pier-beam consolidation and the bottom of the pier consolidation. As illustrated in Fig.6. To add 10000 days for considering the impact of concrete shrink- creep. Setting the temperature difference between actual temperature and design value is 3℃. By using the software calculation, the horizontal displacement of both main piers can be given. The displacement of pier 2: ∆AX= 3.79cm The pier 3: ∆BX= −3.79cm (Taking the right as the positive direction) figure6: the finite element model IV. CONFIRMATION OF JACKING FORCE In the real construction process, it can symmetrically apply the jacking force to the tapered haunch as it cannot be loaded directly in the centroid of box section. P·e is an additional eccentric bending moment to the centroid. Using the computerization software to calculate, the horizontal jacking force aroused by the forced displacement ∆AX(= −3.79cm) is 7431 (KN). According to formula (2), the jacking force: P = 12EI1∆AB l1 3 =12×3.25×107×5.32×0.0379×2/283=71 64 (KN) According to formula (3), p=8411(KN) V. ANALYSIS OF THE CALCULATING RESULTS In the situation of different jacking force, to compare the displacements of pier 1 calculated by analytical formulas and finite-element analysis (FEA). As shown in table 1. Table 1: the displacements calculated in 3 methods The jacking force/(KN ) FEA/(c m) Statically in- determinate structure/(cm ) Statically determinate structure/(c m) 2000 1.02 1.06 0.9 4000 2.06 2.12 1.8 6000 3.05 3.17 2.7 From the table, it can be observed the displacements calculated by both analytical formulas and FEA are similar. Comparing the changes of structure additional internal forces in case of imposing the jacking force and not. As shown in table 2. Table 2: the stress of each control section (KN·m) Major control sections Without jacking force Imposing jacking force (2) Imposing jacking force (3) Bottom of pier 1 1.94E+05 -7.56E+03 -4.8E+04 The middle span section 2.05E+04 1.76+03 1.2E+03
  • 4. Wei LI Int. Journal of Engineering Research and Applications www.ijera.com ISSN : 2248-9622, Vol. 5, Issue 4, ( Part -1) April 2015, pp.29-32 www.ijera.com 32 | P a g e It is thus evident that the internal force of the control sections has been substantially improved after imposing the jacking force. The effect of optimizing the stress performance has been obtained. VI. CONCLUSION 1) From these two analytical formulas for calculating the jacking force, the conclusion jacking force is linear with displacement can be drawn. And the calculated results prove that the theoretical calculating values match well with the values from finite element calculation. These two formulas can be extended as a simple computational method to other bridges with the same type. 2) However, in the process of deducing, only the effects of bending moment on pier displacement were considered, the effects of axial force and shearing force had been ignored. Consequently, the formulas exists certain errors. That the stiffness of zero block was assumed to infinite also has some influence on computational accuracy for it is impossible in practical engineering. 3) According to the results from table 1 and table 2, during the closure segment construction of large-span pre-stressed concrete continuous rigid frame bridge, imposing jacking-force properly to give the pier a pre-displacement could effectively counteract the pier offset and improve the stress performance of the bridge. REFERENCES [1] Liankun Li, Structural Mechanics (Beijing: Higher Education Press, 2010). [2] Guowen Yao, S. Wenfeng, Z. Zhixiang, Horizontal jacking force and closure order optimization of rigid frame-continuous girder bridge with multi-span, Highways & Automotive 124(1), 2008, 91-93. [3] Yisong Zou, D. Xiangrong, The confirmation closure jacking force of continuous rigid frame bridge, Journal of Chongqing Jiaotong University 25(2), 2006, 12-15. [4] Heqing Hu, D. Jiangming, Z. Shuixing and D. Yangfang, The studies of closure program of multi - span continuous rigid frame bridge, Journal of China and Foreign Highway, 29(3), 2009, 109-114. [5] Kunpeng Luan, Z. Xuesong, G. Hongru, Optimum calculation method of closure jacking force of continuous rigid frame bridge, Ludong University Journal, 27(1), 2011, 92-96. [6] Ganggang Zhang, W. Chongnan, Discussion on the design of closure jacking force of continuous rigid frame bridge, Journal of China and Foreign Highway, 31(5),2011,119-122. [7] General Code for Design of Highway Bridges and Culverts JTG D60-2004 (Beijing: China Communications Press, 2004).