1. BUILDING STRUCTURE [ARC 2522]
PROJECT 2: EXTENSION OF A R.C. BUNGALOW
CHOOSEN BUILDING:
KAJANG BUNGALOW, JADE HILLS
LECTURER: MS. NORITA JOHAR
GROUP MEMBERS:
BENNY TAN SHIOWEE 0315447
LEE YAUE SHEN 0315381
NICOLAS WONG XIAO EN 0314377
PRESTON LIEW RU PING 0313822
TAN SHING YEOU 0314850
WOO WEN JIAN 0315123
YUAN KHAI SHIEN 0314818
2. TABLE OF CONTENT
1.0 Introduction to case study
2.0 Architectural Drawings
3.0 Structural Drawings
4.0 Load Distribution Table
5.0 Dead & Live Load Acting Table
6.0 Calculation
7.0 Conclusion
3. 1.0 Introduction to case study
The case study we chose is a two and half storey bungalow. It is located in Jade Hill,
Kajang. It is designed by Arkitek Juruperunding Suria Rahim Sdn. Bhd.
The built up area of a single unit of the bungalow is approximately 4400 sq. ft. Col-
umns and beams are assembled in moment resisting frames which is a common prac-
tice in residential design, in order to define the location of each columns in the build-
ing, we have studied and analyzed the spaces through plans.
19. BEDROOM B-C/7-8
= 4800 / 2712
= 1.77 < 2 (Two way slab)
TOILET C-D/8a-8
= 2700 / 1800
= 1.5 < 2 ( Two way slab)
CORRIDOR C-D/7-8a
= 2100 / 1800
= 1.17 < 2 ( Two way slab)
BEDROOM D-G/7-8
= 4800 / 4500
= 1.07 < 2 ( Two way slab)
STUDIO A-C/6-7
= 4200 / 3900
= 1.08 < 2 ( Two way slab)
CORRIDOR C-D/6-7
= 3900 / 1800
= 2.17 > 2 ( One way slab)
TOILET E1-G/6a-7
= 2700 / 1800
= 1.5 < 2 ( Two way slab)
FAMILY AREA D-G/6-6a
= 4500 / 2100
= 2.14 > 2 ( One way slab)
CORRIDOR B-D/5-6
= 4512 / 1800
= 2.51 > 2 ( One way slab)
CORRIDOR D-G/5-6
= 450 / 1800
= 2.5 > 2 ( One way slab)
CORRIDOR C-G/4-5
= 6300 / 3500
= 1.8 < 2 ( Two way slab)
20. 5.0 QUANTITY DEAD LOADS ACTING ON STRUCTURE
GROUND FLOOR PLAN
Slab Thickness = 150 mm
Slab self-weight = 0.15m x 24kN/m
= 3.6kN/m
3
2
FIRST FLOOR PLAN
Slab Thickness = 150 mm
Slab self-weight = 0.15m x 24kN/m
= 3.6kN/m
3
2
SECOND FLOOR PLAN
Slab Thickness = 150 mm
Slab self-weight = 0.15m x 24kN/m
= 3.6kN/m
3
2
ROOF PLAN
Slab Thickness = 150 mm
Slab self-weight = 0.15m x 24kN/m
= 3.6kN/m
3
2
3
3
3
BRICK WALL
= wall height x thickness x density
= 3.1m x 0.15m x 19kN/m
= 8.84kN/m
BEAM SELF WEIGHT
(Beam Size 125mm x 450mm)
= Beam size x Concrete density
= 0.125m x 0.45m x 24kN/m
= 1.35kN/m
COLUMN SELF WEIGHT
(Column Size 125mm x 300mm)
= Beam size x Height x Concrete density
= 0.125m x 0.3m x 3.1m x 24kN/m
= 2.79kN
3
(Column Size 450mm x 450mm)
= Beam size x Height x Concrete density
= 0.45m x 0.45m x 3.1m x 24kN/m
= 15.066kN
21. QUANTITY LIVE LOADS ACTING ON STRUCTURE
GROUND FLOOR PLAN
KITCHEN
BATHROOM
BEDROOM
CORRIDOR
DINING AREA
STORE
LIVING AREA
PRAYING AREA
CAR POACH
STAIRWELL
= 3.0 kN/m
= 2.0 kN/m
= 1.5 kN/m
= 2.0 kN/m
= 2.0 kN/m
= 3.0 kN/m
= 4.0 kN/m
= 2.0 kN/m
= 2.5 kN/m
= 2.0 kN/m
SECOND FLOOR PLAN
BATHROOM
BEDROOM
CORRIDOR
DRESSING AREA
STUDIO
FAMILY AREA
STUDY AREA
ROOF
STAIRWELL
= 2.0 kN/m
= 1.5 kN/m
= 2.0 kN/m
= 2.0 kN/m
= 2.0 kN/m
= 4.0 kN/m
= 2.0 kN/m
= 0.5 kN/m
= 2.0 kN/m
THIRD FLOOR PLAN
BATHROOM
CORRIDOR
STAIRWELL
ENTERTAINMENT AREA
LOUNGE
(According to 4 schedule of UBBL for live load according to the function of the space)
= 2.0 kN/m
= 2.0 kN/m
= 2.0 kN/m
= 4.0 kN/m
= 2.0 kN/m
th
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
2
22. 7.0 Conclusion
Throughout this project, we learnt about structural theory and basic structural pro-
posal. We learnt about the load path in slab ( one way and two way slabs). We are
now understand the concept of structural analysis which needed to identify the
structural components.
We learnt how load is sitting on beams on columns. By calculating load transferred
to beams and loads, we clearly understand the basic requirement such as thickness
needed for a column or beam while designing a building. This is helpful as it is
important for us in our future study.