Show your work for the following questions- 11- Consider the following.docx

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Show your work for the following questions. 11. Consider the following two reactions and enthalpies: 1) 2c(s) + 0:(g)--2Co() 2) C(s) +(gCO2) AH220 kJ/mol AH393 kJ/mol From these two reactions, calculate the heat effeet (enthalpy ehange AH) for the reaction: 3) CO2(g)-CO(g)+HO(g) 12. When 1.00 g glucose (CH 0 180 g/mo is combusted in an open calorimeter with calorimeter constant 8000 J/K, the temperature rises from 19.20 Â°C to 21.14 C^Calculate: a) The enthalpy of combustion of AHseabuionsglucose) in kJ/g b) The molar enthalpy of combustion of glucose 13. (Chang 6.37) A 0.1375 g sample of Mg(s) is burned (reacted with O2) in a calorimeter. The heat capacity C of the calorimeter + content is 3024 JrCThe temperature increases by 1.126 *C. Calculate the Molar enthalpy of combustion, AH of Mg (kJ/moD. This problem is worded slightly different from the version in Chang, because in a \"bomb calorimeter we would measure ??, not ??!) Hint: We are looking for Akl in kliua, i.e., the enthalpy change for the combustion of 1 malofMg. 14. 25.0 mL.0.500 M .HCI(ag) is added to 75.0 mL 0.500 M NaO in an open adiabatic styrofoam \"coffee cup calorimeter\". The temperature rises by1.68 JC.Calculate the molar enthalpy of neutralization on HCl The heat capacity of the Styrofoam cup can be neglected. The heat capacity of 1 mL solution can be assumed to be equal to the heat capacity of 1 mL (1 g) water. Solution 11) from the given data CO2(g) ----> c(s) + o2(g)Â Â Â DH1 = +393 kj/mol (2C(s) + O2(g) ---> 2CO(g)Â Â Â DH2 = -220 kj/mol)*1/2 --------------------------------------------------- CO2(g) ----> CO(g) + 1/2O2(g) DH = DH1+DH2*1/2 ---------------------------------------------------- DHrxn = 393-220*1/2 = 283 kj 12) energy released (q) = C*DT = 8000*(21.14-19.2) = 15520 j = 15.52 kj a) DHcombustion = -q/w = -15.52/1 = -15.52 kj/g b) No of mol of glucose = w/Mwt = 1/180 = 0.00555 mol molar enthalpy of combustion = -q/n = -15.52/0.00555 = -2796.4 kj/mol .

Education

= 15520 j
= 15.52 kj
a) DHcombustion = -q/w
= -15.52/1
= -15.52 kj/g
b) No of mol of glucose = w/Mwt = 1/180 = 0.00555 mol
molar enthalpy of combustion = -q/n
= -15.52/0.00555
= -2796.4 kj/mol

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