A block of mass m = 0.215 Kg is attached to one end of a spring. The other end is fixed and the block slides on a horizontal, frictionless surface At some time t, the position, velocity, and acceleration of the block are X = 0.1 11 m, V = -3.14 m/s, a = -14.8 m/s^2. Find the spring constant of the spring in N/m. a = -14.8 m/s^2 Solution F=-kx ma= -kx (0.215 kg)(-14.8)= -k (0.111 m) k=28.6 N/m.