Question 1. Dscribe the change you observed when you added 1 mL of 0.1 M KSCN to the 2 mL portion of the diluted solution. Copy the equation from the procedure and explain your observations in terms of LeChatelier’s Principle. Choose the best answer. The additional thiocyantate ion shifted the equilibrium toward the products, producing morehexathiocyanatoferrate(III) lightening the color. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). The additional thiocyantate ion shifted the equilibrium toward the reactants, producing lesshexathiocyanatoferrate(III) and deepening the color. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). The additional thiocyantate ion shifted the equilibrium toward the reactants, producing morehexathiocyanatoferrate(III) lightening the color. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). The additional thiocyantate ion shifted the equilibrium toward the products, producing morehexathiocyanatoferrate(III) and deepening the color. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). Question 2. Show your calculations to determine the final volume of the 0.001 M FeCl3 solution. Choose the best answer. M1V1 = M2V2. (0.001 M)V1=(0.1 M)(0.05 L) V1=0.050 L = 50 mL M1V1 = M2V2. (0.001 M)V1=(0.1 M)(0.005 L) V1=0.500 L = 500 mL M1V1 = M2V2. (0.1 M)(0.005 L)=(0.001 M)V2 V2=0.500 L = 500 mL M1V1 = M2V2. (0.1 M)(0.0005 L)=(0.001 M)V2 V2=0.050 L = 50 mL Question 3. Describe the change you observed when you added 1 mL of 0.1 M FeCl3 to the diluted mixture of 0.001 M FeCl3(aq) and 0.1 M KSCN(aq). Refer to the equation in step 1 and explain your observations in terms of LeChatelier’s Principle. Choose the best answer. Additional iron(III) ion shifted the equilibrium toward the products to form the red-colored hexathiocyanatoferrate(III) complex and the intensity of color increased.color. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). Additional iron(III) ion shifted the equilibrium toward the products to form the red-colored hexathiocyanatoferrate(III) chloride precipitate. Fe3+(aq) + 6SCN-(aq) Fe(SCN)6Cl3(s). Additional iron(III) ion caused the equilibrium to shift to the reactants to compensate for the additional added iron(III), which increased the intensity of the red color. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). Additional iron(III) ion increased the concentration of the red-colored iron(III) ion. Fe3+(aq) + 6SCN-(aq) Fe(SCN)63-(aq). Question 4. Predict and then describe what happened when you added HCl(aq) to the copper nitrate solution. Write down the equation for the reaction. Choose the best answer. The added hydrogen ion shifted the equilibrium toward the products so that more CuCl42-(aq) was createdand the solution changed from blue to green. Cu(H2O)42+(aq) + 4Cl-(aq) CuCl42-(aq) + 4H2O(l). The added chloride ion shifted the equilibrium toward the products so that more CuCl42-(aq) was created and the solution changed from blue to green. Cu(H2O)42+(aq) + 4Cl-(aq) CuCl42-(aq) + 4H2O(l). The added chloride ion caused the precipitation of CuCl42-(s), which shifted the equilibrium toward t.

1. Question 11 of 24 In E. coli, three structural Deand enzymes A. D, and E, respectively. Gene ois
an operator. The genes are in the order O-A-D-E on the chromosome and might form an operon.
These the the osynthesis of valine. Mutations were isolated at the A, D, E, and o genes to
production of cellular A. Adel be enzymes by partial-diploid E. coli with various combinations
of mutations are shown in the following table. The wild type is indicated with a and the mutant is
indicated with a What type of regulator protein is binding to the operator in this possible operon?
Amount of enzyme produced Genotype E D A O an activator O 240 3.50 O a coactivator 2.00 E*
D* A* O l O a repressor E* 35.80 38.60 46.80 o an inducer D* A* O O an attenuator 1.00 47.00
D+ A- O D* A Orl Et 35.30 38.00 1.70 E D At 2.38 38.00 47.70 Are genes A, D, and E all under
control of the operator o? o Yes, because when the operator is functional the genes E. D. and A
expression levels are high. Previous Check Answer 0 Next d Exit
Solution
Please find the answers below:
Part 1: Choice 4 (the present operon is an inducer type becuase presence of the genetic sequence
upstream the operator up-regulates gene expression of the cistron by modultion of transcription
of operator gene. This suggests that positive regulation of operator and cistron take place when
the up-stream regulator is switched "on", hence it is an inducer type operon)
Part 2: Choice 1 (The genes A,D and E are indeed under the transcriptional control of gene O.
This is because when levels of gene O are high enough even under heterozygous condition, the
expression levels of all these three up-stream regulators are also very high. It must be carefully
observed from the dataset that absence of any of the gene A, D or E leads to down-regulation of
their expression even when O is dominant/heterozygous. This clearly deciphers the
transcriptional co-regulation of this cistron.)