Is -e^-x = -(e^x)^r = e^rx...r=-1...but what about the -1 in front of the e??does that come up with r..or since it is not like lne^r where r would come in front so it would just stay in front of the e??Thank You Solution -e^-x = -(e^x)^-r when r=-1 but -e^-x is not equal to e^rx when r=-1 because then e^rx will become e^-x.