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[The following information applies to the questions displayed
below.]
A sample of 36 observations is selected from a normal
population. The sample mean is 12, and the population standard
deviation is 3. Conduct the following test of hypothesis using
the 0.01 significance level.
H0: μ ≤ 10
H1: μ > 10
1.
Value:
10.00 points
Required information
a.
Is this a one- or two-tailed test?
One-tailed test
Two-tailed test
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective:
10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
2.
Value:
10.00 points
Required information
b.
What is the decision rule?
Reject H0 when z ≤ 2.326
Reject H0 when z > 2.326
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective:
10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
3.
Value:
10.00 points
Required information
c.
What is the value of the test statistic?
Value of the test statistic
References
EBook & Resources
Worksheet Difficulty: 2 Intermediate Learning Objective: 10-05
Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
4.
Value:
10.00 points
Required information
d.
What is your decision regarding H0?
Fail to reject H0
Reject H0
References
EBook & Resources
Multiple Choice Difficulty: 2 Intermediate Learning Objective:
10-05 Conduct a test of a hypothesis about a population mean.
eBook: Conduct a test of a hypothesis about a population mean.
Check my work
5.
Value:
10.00 points
Required information
e.
What is the p-value?
p-value
References
Given the following hypotheses:
H0 : μ = 400
H1 : μ ≠ 400
A random sample of 12 observations is selected from a normal
population. The sample mean was 407 and the sample standard
deviation 6. Using the .01 significance level:
a.
State the decision rule. (Negative amount should be indicated
by a minus sign. Round your answers to 3 decimal places.)
Reject H0 when the test statistic is the interval (,).
b.
Compute the value of the test statistic. (Round your answer to 3
decimal places.)
Value of the test statistic
c.
What is your decision regarding the null hypothesis?
Do not reject
Reject
The management of White Industries is considering a new
method of assembling its golf cart. The present method requires
42.3 minutes, on the average, to assemble a cart. The mean
assembly time for a random sample of 24 carts, using the new
method, was 40.6 minutes, and the standard deviation of the
sample was 2.7 minutes. Using the .10 level of significance, can
we conclude that the assembly time using the new method is
faster?
a.
What is the decision rule? (Negative amount should be indicated
by a minus sign. Round your answer to 3 decimal places.)
Reject H0 : μ ≥ 42.3 when the test statistic is .
b.
Compute the value of the test statistic. (Negative amount should
be indicated by a minus sign. Round your answer to 3 decimal
places.)
Value of the test statistic
c.
What is your decision regarding H0?
Fail to reject
Reject
Given the following hypotheses:
H0 : μ = 100
H1 : μ ≠ 100
A random sample of six resulted in the following values: 118,
105, 112, 119, 105, and 111. Assume a normal population.
a.
Using the .05 significance level, determine the decision rule?
(Negative amounts should be indicated by a minus sign. Round
your answers to 3 decimal places.)
Reject H0 : μ = 100 when the test statistic is (, ).
b.
Compute the value of the test statistic. (Round your answer to 2
decimal places.)
Value of the test statistic
C-1.
What is your decision regarding the H0?
Reject
Do not reject
C-2.
Can we conclude the mean is different from 100?
No
Yes
d.
Estimate the p-value.
The p-value is
A sample of 65 observations is selected from one population
with a population standard deviation of 0.75. The sample mean
is 2.67. A sample of 50 observations is selected from a second
population with a population standard deviation of 0.66. The
sample mean is 2.59. Conduct the following test of hypothesis
using the .08 significance level.
H0 : μ1 ≤ μ2
H1 : μ1 > μ2
a.
This a -tailed test.
b.
State the decision rule. (Negative values should be indicated by
a minus sign. Round your answer to 2 decimal places.)
The decision rule is to reject H0 if z is .
c.
Compute the value of the test statistic. (Round your answer to 2
decimal places.)
Value of the test statistic
d.
What is your decision regarding H0?
H0.
e.
What is the p-value? (Round your answer to 4 decimal places.)
p-value
The null and alternate hypotheses are:
A random sample of 15 observations from the first population
revealed a sample mean of 350 and a sample standard deviation
of 12. A random sample of 17 observations from the second
population revealed a sample mean of 342 and a sample
standard deviation of 15.
At the .10 significance level, is there a difference in the
population means?
a.
This is a -tailed test.
b.
The decision rule is to reject if or . (Negative amounts should
be indicated by a minus sign. Round your answers to 3 decimal
places.)
c.
The test statistic is t =. (Round your answer to 3 decimal
places.)
d.
What is your decision regarding?
e.
The p-value is.
The null and alternate hypotheses are:
H0: μ1 ≤ μ2
H1: μ1 > μ2
A random sample of 20 items from the first population showed a
mean of 100 and a standard deviation of 15. A sample of 16
items for the second population showed a mean of 94 and a
standard deviation of 8. Use the .05 significant level.
a.
Find the degrees of freedom for unequal variance test. (Round
down your answer to the nearest whole number.)
Degrees of freedom
b.
State the decision rule for .05 significance level. (Round your
answer to 3 decimal places.)
Reject H0 if t>.
c.
Compute the value of the test statistic. (Round your answer to 3
decimal places.)
Value of the test statistic
d.
What is your decision regarding the null hypothesis? Use the
.05 significance level.
The null hypothesis is.
The following are six observations collected from treatment 1,
four observations collected from treatment 2, and five
observations collected from treatment 3. Test the hypothesis at
the 0.05 significance level that the treatment means are equal.
Treatment 1
Treatment 2
Treatment 3
9
13
10
7
20
9
11
14
15
9
13
14
12
15
10
a.
State the null and the alternate hypothesis.
Ho : μ1 μ2 μ3
H1 : Treatment means all the same.
b.
What is the decision rule? (Round your answer to 2 decimal
places.)
Reject Ho if F >
c.
Compute SST, SSE, and SS total. (Round your answers to 2
decimal places.)
SST =
SSE =
SS total =
d.
Complete the ANOVA table. (Round SS, MS and F values to 2
decimal places.)
Source
SS
df
MS
F
Treatments
Error
6.88
Total
152.93
e.
State your decision regarding the null hypothesis.
Decision: Ho
A stock analyst wants to determine whether there is a difference
in the mean rate of return for three types of stock: utility, retail,
and banking stocks. The following output is obtained:
a.
Using the .05 level of significance, is there a difference in the
mean rate of return among the three types of stock?
since the test statistic is the critical value .
b.
Can the analyst conclude there is a difference between the mean
rates of return for utility and retail stocks? For utility and
banking stocks? For banking and retail stocks? Explain.
Since 0 between and the mean rates of return from utility stocks
and retail stocks .
Since 0 between and , the mean rates of return from utility and
banking stocks .
Since 0 between and , the mean rates of return from retail and
banking stocks .
There are three hospitals in the Tulsa, Oklahoma, area. The
following data show the number of outpatient surgeries
performed on Monday, Tuesday, Wednesday, Thursday, and
Friday at each hospital last week. At the 0.05 significance level,
can we conclude there is a difference in the mean number of
surgeries performed by hospital or by day of the week?
Number of Surgeries Performed
Day
St. Luke's
St. Vincent
Mercy
Monday
14
18
24
Tuesday
20
24
14
Wednesday
16
22
14
Thursday
18
20
22
Friday
20
28
24
Click here for the Excel Data File
1.
Set up the null hypothesis and the alternative hypothesis.
For Treatment:
Null hypothesis
H0: µSt. Luke's = µSt. Vincent = µMercy
H0: µSt. Luke's ≠ µSt. Vincent ≠ µMercy
2.
Alternative hypothesis
H1: Not all means are equal.
H1: All means are equal.
3.
For blocks:
Null hypothesis
H0: µMon = µTue = µWed = µThu = µFri
H0: µMon ≠ µTue ≠ µWed ≠ µThu ≠ µFri
4.
Alternative hypothesis
H1: All means are equal.
H1: Not all means are equal.
5.
State the decision rule for .05 significance level. (Round your
answers to 2 decimal places.)
For Treatment:
Reject H0 if F>
For blocks:
Reject H0 if F>
6.
Complete the ANOVA table. (Round SS, MS and F to 2 decimal
places.)
Source
SS
df
MS
F
Treatments
Blocks
Error
Total
7.
What is your decision regarding the null hypothesis?
The decision for the F value (Treatment) at 0.05 significance is:
Reject H0
Do not Reject H0
8.
The decision for the F value (Block) at 0.05 significance is:
Reject H0
Do not Reject H0
9.
Can we conclude there is a difference in the mean number of
surgeries performed by hospital or by day of the week?
There is in the mean number of surgeries performed by hospital
or by day of the week.
Mr. James McWhinney, president of Daniel-James Financial
Services, believes there is a relationship between the number of
client contacts and the dollar amount of sales. To document this
assertion, Mr. McWhinney gathered the following sample
information. The X column indicates the number of client
contacts last month, and the Y column shows the value of sales
($ thousands) last month for each client sampled.
Number of
Contacts,
X
Sales
($ thousands),
Y
Number of
Contacts,
X
Sales
($ thousands),
Y
14
24
23
30
12
14
48
90
20
28
50
85
16
30
55
120
46
80
50
110
Click here for the Excel Data File
a.
Determine the regression equation. (Negative amounts should be
indicated by a minus sign. Do not round intermediate
calculations. Round final answers to 2 decimal places.)
X
Y
( ) 2
( )2
( )( )
14
376.36
1376.41
719.74
12
14
−21.4
−47.1
20
−13.4
179.56
443.54
16
30
−31.1
967.21
46
12.6
357.21
23
−10.4
967.21
48
90
28.9
213.16
421.94
50
85
23.9
275.56
396.74
55
466.56
3469.21
1,272.24
50
110.0
16.6
48.9
=
=
sx
=
sy
=
r
=
b =
a =
Y' = + X
b.
Determine the estimated sales if 40 contacts are made.(Do not
round intermediate calculations. Round final answers to 2
decimal places.)
We are studying mutual bond funds for the purpose of investing
in several funds. For this particular study, we want to focus on
the assets of a fund and its five-year performance. The question
is: Can the five-year rate of return be estimated based on the
assets of the fund? Nine mutual funds were selected at random,
and their assets and rates of return are shown below.
Assets
Return
Assets
Return
Fund
($ millions)
(%)
Fund
($ millions)
(%)
AARP High Quality Bond
$622.2
10.8
MFS Bond A
$494.5
11.6
Babson Bond L
160.4
11.3
Nichols Income
158.3
9.5
Compass Capital Fixed Income
275.7
11.4
T. Rowe Price Short-term
681.0
8.2
Galaxy Bond Retail
433.2
9.1
Thompson Income B
241.3
6.8
Keystone Custodian B-1
437.9
9.2
Click here for the Excel Data File
b-1.
Compute the coefficient of correlation. (Round your answer to 3
decimal places. Negative amount should be indicated by a minus
sign.)
r =
b-2.
Compute the coefficient of determination. (Round your answer
to 3 decimal places.)
r2 =
c.
Give a description of the degree of association between the
variables.
There is association between the variables.
d.
Determine the regression equation. Use assets as the
independent variable. (Round your answers to 4 decimal places.
Negative amounts should be indicated by a minus sign.)
b =
a =
e.
For a fund with $400.0 million in sales, determine the five-year
rate of return (in percent). (Round your answer to 4 decimal
places.)
= The equation should be used with caution. Assets do not
account for much of the variation in the rate of return.
On the first statistics exam, the coefficient of determination
between the hours studied and the grade earned was 80%. The
standard error of estimate was 10. There were 20 students in the
class. Develop an ANOVA table for the regression analysis of
hours studied as a predictor of the grade earned on the first
statistics exam.
Source
DF
SS
MS
Regression
Error
Total
-2-2
http://ezto.mhedu
(Click to select)
0
(Click to select)
(Click to select)
(Click to select)
(Click to select)

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[The following information applies to the questions displayed belo.docx

  • 1. [The following information applies to the questions displayed below.] A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.01 significance level. H0: μ ≤ 10 H1: μ > 10 1. Value: 10.00 points Required information a. Is this a one- or two-tailed test? One-tailed test Two-tailed test References EBook & Resources Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean. eBook: Conduct a test of a hypothesis about a population mean. Check my work 2. Value: 10.00 points Required information b. What is the decision rule?
  • 2. Reject H0 when z ≤ 2.326 Reject H0 when z > 2.326 References EBook & Resources Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean. eBook: Conduct a test of a hypothesis about a population mean. Check my work 3. Value: 10.00 points Required information c. What is the value of the test statistic? Value of the test statistic References EBook & Resources Worksheet Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean. eBook: Conduct a test of a hypothesis about a population mean. Check my work 4. Value: 10.00 points Required information
  • 3. d. What is your decision regarding H0? Fail to reject H0 Reject H0 References EBook & Resources Multiple Choice Difficulty: 2 Intermediate Learning Objective: 10-05 Conduct a test of a hypothesis about a population mean. eBook: Conduct a test of a hypothesis about a population mean. Check my work 5. Value: 10.00 points Required information e. What is the p-value? p-value References Given the following hypotheses: H0 : μ = 400 H1 : μ ≠ 400
  • 4. A random sample of 12 observations is selected from a normal population. The sample mean was 407 and the sample standard deviation 6. Using the .01 significance level: a. State the decision rule. (Negative amount should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject H0 when the test statistic is the interval (,). b. Compute the value of the test statistic. (Round your answer to 3 decimal places.) Value of the test statistic c. What is your decision regarding the null hypothesis? Do not reject Reject The management of White Industries is considering a new method of assembling its golf cart. The present method requires 42.3 minutes, on the average, to assemble a cart. The mean assembly time for a random sample of 24 carts, using the new method, was 40.6 minutes, and the standard deviation of the
  • 5. sample was 2.7 minutes. Using the .10 level of significance, can we conclude that the assembly time using the new method is faster? a. What is the decision rule? (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) Reject H0 : μ ≥ 42.3 when the test statistic is . b. Compute the value of the test statistic. (Negative amount should be indicated by a minus sign. Round your answer to 3 decimal places.) Value of the test statistic c. What is your decision regarding H0? Fail to reject Reject Given the following hypotheses:
  • 6. H0 : μ = 100 H1 : μ ≠ 100 A random sample of six resulted in the following values: 118, 105, 112, 119, 105, and 111. Assume a normal population. a. Using the .05 significance level, determine the decision rule? (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) Reject H0 : μ = 100 when the test statistic is (, ). b. Compute the value of the test statistic. (Round your answer to 2 decimal places.) Value of the test statistic C-1. What is your decision regarding the H0? Reject Do not reject C-2. Can we conclude the mean is different from 100?
  • 7. No Yes d. Estimate the p-value. The p-value is A sample of 65 observations is selected from one population with a population standard deviation of 0.75. The sample mean is 2.67. A sample of 50 observations is selected from a second population with a population standard deviation of 0.66. The sample mean is 2.59. Conduct the following test of hypothesis using the .08 significance level. H0 : μ1 ≤ μ2 H1 : μ1 > μ2 a. This a -tailed test. b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answer to 2 decimal places.) The decision rule is to reject H0 if z is . c.
  • 8. Compute the value of the test statistic. (Round your answer to 2 decimal places.) Value of the test statistic d. What is your decision regarding H0? H0. e. What is the p-value? (Round your answer to 4 decimal places.) p-value The null and alternate hypotheses are: A random sample of 15 observations from the first population revealed a sample mean of 350 and a sample standard deviation of 12. A random sample of 17 observations from the second population revealed a sample mean of 342 and a sample standard deviation of 15. At the .10 significance level, is there a difference in the population means? a.
  • 9. This is a -tailed test. b. The decision rule is to reject if or . (Negative amounts should be indicated by a minus sign. Round your answers to 3 decimal places.) c. The test statistic is t =. (Round your answer to 3 decimal places.) d. What is your decision regarding? e. The p-value is. The null and alternate hypotheses are: H0: μ1 ≤ μ2 H1: μ1 > μ2 A random sample of 20 items from the first population showed a mean of 100 and a standard deviation of 15. A sample of 16 items for the second population showed a mean of 94 and a standard deviation of 8. Use the .05 significant level. a. Find the degrees of freedom for unequal variance test. (Round down your answer to the nearest whole number.)
  • 10. Degrees of freedom b. State the decision rule for .05 significance level. (Round your answer to 3 decimal places.) Reject H0 if t>. c. Compute the value of the test statistic. (Round your answer to 3 decimal places.) Value of the test statistic d. What is your decision regarding the null hypothesis? Use the .05 significance level. The null hypothesis is. The following are six observations collected from treatment 1, four observations collected from treatment 2, and five observations collected from treatment 3. Test the hypothesis at the 0.05 significance level that the treatment means are equal. Treatment 1 Treatment 2 Treatment 3 9 13
  • 12. Ho : μ1 μ2 μ3 H1 : Treatment means all the same. b. What is the decision rule? (Round your answer to 2 decimal places.) Reject Ho if F > c. Compute SST, SSE, and SS total. (Round your answers to 2 decimal places.) SST = SSE = SS total = d. Complete the ANOVA table. (Round SS, MS and F values to 2 decimal places.) Source SS df MS F
  • 14. Decision: Ho A stock analyst wants to determine whether there is a difference in the mean rate of return for three types of stock: utility, retail, and banking stocks. The following output is obtained:
  • 15. a. Using the .05 level of significance, is there a difference in the mean rate of return among the three types of stock? since the test statistic is the critical value . b.
  • 16. Can the analyst conclude there is a difference between the mean rates of return for utility and retail stocks? For utility and banking stocks? For banking and retail stocks? Explain. Since 0 between and the mean rates of return from utility stocks and retail stocks . Since 0 between and , the mean rates of return from utility and banking stocks . Since 0 between and , the mean rates of return from retail and banking stocks . There are three hospitals in the Tulsa, Oklahoma, area. The
  • 17. following data show the number of outpatient surgeries performed on Monday, Tuesday, Wednesday, Thursday, and Friday at each hospital last week. At the 0.05 significance level, can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week? Number of Surgeries Performed Day St. Luke's St. Vincent Mercy Monday 14 18 24 Tuesday 20 24 14 Wednesday 16 22 14 Thursday 18 20 22
  • 18. Friday 20 28 24 Click here for the Excel Data File 1. Set up the null hypothesis and the alternative hypothesis. For Treatment: Null hypothesis H0: µSt. Luke's = µSt. Vincent = µMercy H0: µSt. Luke's ≠ µSt. Vincent ≠ µMercy 2. Alternative hypothesis H1: Not all means are equal.
  • 19. H1: All means are equal. 3. For blocks: Null hypothesis H0: µMon = µTue = µWed = µThu = µFri H0: µMon ≠ µTue ≠ µWed ≠ µThu ≠ µFri 4. Alternative hypothesis H1: All means are equal. H1: Not all means are equal. 5. State the decision rule for .05 significance level. (Round your answers to 2 decimal places.) For Treatment: Reject H0 if F>
  • 20. For blocks: Reject H0 if F> 6. Complete the ANOVA table. (Round SS, MS and F to 2 decimal places.) Source SS df MS F Treatments Blocks Error
  • 21. Total 7. What is your decision regarding the null hypothesis? The decision for the F value (Treatment) at 0.05 significance is: Reject H0 Do not Reject H0 8. The decision for the F value (Block) at 0.05 significance is:
  • 22. Reject H0 Do not Reject H0 9. Can we conclude there is a difference in the mean number of surgeries performed by hospital or by day of the week? There is in the mean number of surgeries performed by hospital or by day of the week.
  • 23. Mr. James McWhinney, president of Daniel-James Financial Services, believes there is a relationship between the number of client contacts and the dollar amount of sales. To document this assertion, Mr. McWhinney gathered the following sample information. The X column indicates the number of client contacts last month, and the Y column shows the value of sales ($ thousands) last month for each client sampled. Number of Contacts, X Sales ($ thousands), Y Number of Contacts, X Sales ($ thousands), Y 14 24 23 30 12
  • 25. Determine the regression equation. (Negative amounts should be indicated by a minus sign. Do not round intermediate calculations. Round final answers to 2 decimal places.) X Y ( ) 2 ( )2 ( )( ) 14 376.36 1376.41 719.74 12 14 −21.4 −47.1 20 −13.4 179.56 443.54 16 30 −31.1
  • 28. b = a = Y' = + X b. Determine the estimated sales if 40 contacts are made.(Do not round intermediate calculations. Round final answers to 2 decimal places.) We are studying mutual bond funds for the purpose of investing in several funds. For this particular study, we want to focus on the assets of a fund and its five-year performance. The question is: Can the five-year rate of return be estimated based on the
  • 29. assets of the fund? Nine mutual funds were selected at random, and their assets and rates of return are shown below. Assets Return Assets Return Fund ($ millions) (%) Fund ($ millions) (%) AARP High Quality Bond $622.2 10.8 MFS Bond A $494.5 11.6 Babson Bond L 160.4 11.3 Nichols Income 158.3 9.5 Compass Capital Fixed Income 275.7 11.4 T. Rowe Price Short-term 681.0 8.2 Galaxy Bond Retail 433.2 9.1
  • 30. Thompson Income B 241.3 6.8 Keystone Custodian B-1 437.9 9.2 Click here for the Excel Data File b-1. Compute the coefficient of correlation. (Round your answer to 3 decimal places. Negative amount should be indicated by a minus sign.) r = b-2. Compute the coefficient of determination. (Round your answer to 3 decimal places.) r2 = c. Give a description of the degree of association between the variables. There is association between the variables.
  • 31. d. Determine the regression equation. Use assets as the independent variable. (Round your answers to 4 decimal places. Negative amounts should be indicated by a minus sign.) b = a = e. For a fund with $400.0 million in sales, determine the five-year rate of return (in percent). (Round your answer to 4 decimal places.) = The equation should be used with caution. Assets do not account for much of the variation in the rate of return. On the first statistics exam, the coefficient of determination between the hours studied and the grade earned was 80%. The standard error of estimate was 10. There were 20 students in the class. Develop an ANOVA table for the regression analysis of hours studied as a predictor of the grade earned on the first statistics exam. Source DF SS MS
  • 32. Regression Error Total -2-2 http://ezto.mhedu (Click to select) 0 (Click to select) (Click to select) (Click to select) (Click to select)