1. LESSON PLAN
Name of the teacher : Aswathy. A
Subject : Mathematics
Unit : Equations
Subunit : Different
problems.
Name of the school : MTHSS
Standard : VIII
Strength : 40/43
Date : 10/08/2015
Time : 30 minutes
CURRICULAR STATEMENT
To understand about different problems in equations and its importance in
mathematics through discussion, observation, organization of chart and by
analyzing prepared notes of the pupil.
CONTENT ANALYSIS
NEW TERMS : equations, algebraic form.
FACTS : algebraic method of solving problems.
CONCEPTS : concept of algebraic method in equations.
PROCESS : process of finding solution to different problems using algebraic
equations.
LEARNING OUTCOMES
The pupil will be able to,
1. Recall the term algebra.
2. Recognize algebraic form of different equations.
3. Explain the term algebra and equations.
4. Observe all aspects of equations keenly.
2. 5. Discuss the different problems through algebraic equations.
6. Read chart quickly and accurately.
7. Ask questions to know more about algebraic equations.
8. Give illustration of algebraic equations.
9. Plan to do problems on algebraic equations.
PRE-REQUISITES: The students have knowledge on algebraic method, its
addition, subtraction, multiplication, division.
TEACHING LEARNING RESOURCES: Usual classroom aids, activity cards.
LEARNING STRATEGIES: Individual work, group discussion, observation and
explanation by teacher.
CLASSROOM INTERACTION
PROCEDURE
EXPECTED PUPIL RESPONSE
INTRODUCTION
ACTIVITY - 1
i. Yesterday we study to make
algebraic form of different
equations.
ii. Today we are going to make and
solve different equation.
iii. Will you interest?
PRESENTATION
ACTIVITY – 2
Then teacher presents a problem
“Ticket rate for the science exhibition is
10 rupees for a child and 26 rupees for
an adult, 740 rupees were got from 50
‘Yes’ all students replied.
3. persons. How many children among
them? ”
Teacher writes answer on blackboard
after give an explanation.
Let x be the number of children.
Number of adults =50-x.
Ticket rate for a child = 10.
Ticket rate for x children’s = 10x.
Ticket rate for an adult = 26.
Ticket rate for (50-x) adults = 26(50-x).
Total price = 740.
10x + 26(50-x) = 740.
10x + 1300 – 26x = 740
10x – 26x = 740 -
1300
16x = 560.
X = 560/16
= 35.
Number of children = 35.
Number of adult = 50-35
= 15.
ACTIVITY – 3
Teacher gives another problem.
“A class has the same number of boys
and girls. Only 8 boys were present on a
particular day and then the number of
girls was double the number of boys.
What is the number of boys and girls?”
Teacher gave opportunity to students to
explain the question. Then teacher
explain the answer and writes on
blackboard.
Students listen to teacher.
Students write answer on their
notebook.
Students carefully listen to teacher and
writes question on notebook.
4. Let the number of boys and girls be x.
If 8boys were absent,
then the number of boys = x-8.
Number of girls =
2(number of boys).
x = 2(x-8).
x = 2x-16.
2x-x = 16.
x = 16.
Number of boys = 16.
Number of girls = 16.
ACTIVITY-4
Teacher divides the class into 5 groups
and gives activity cards containing
questions.
”Ajayan is 10 years older than Vijayan.
Next year, Ajayan’s age would be double
that of Vijayan. What are their ages
now?”
“5 times a number is equal to 3 times
the sum of the number and 4. What is
the number? ”
CLOSURE
ACTIVITY – 5
Teacher concludes the class by telling
what have learned in the class. Teacher
clarifies all the doubts of students.
REVIEW
ACTIVITY – 6
Teacher ask questions to students and
ask to form questions related to the
All students are participated in group
work. They actively find the answers.
5. topic
FOLLOW UP ACTIVITY
1. In a co-operative society the
number of men is thrice the
number of women .29 women
and 16 men more joined the
society and now the number of
men is double the number of
women. How many women were
there in the society at first?
2. 8 times a number is equal to 4
times the sum of the number and
4.what is the number?
Students do according to the instruction
of the teacher.
