What is wrong with this code Please fix.code#include stdio.h.pdf

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What is wrong with this code? Please fix. code: #include #include #define ROWS 3 #define COLS 3 void display(double[ROWS][COLS]); double main(){ double mat[ROWS][COLS] = { {1./2, 1, 0}, {0, 2./3, 0}, {-1./2, -1, 2./3} }; display(mat); return 0; } void display(double nums[ROWS][COLS]) { double rowNum, colNum; for (rowNum = 0.; rowNum < ROWS; rowNum++) { for (colNum = 0.; colNum < COLS; colNum++) printf(\"%1.1s\", nums[rowNum][colNum]); printf(\"\ \"); } } Solution #include #include #define ROWS 3 #define COLS 3 void display(double[ROWS][COLS]); int main(){ double mat[ROWS][COLS] = { {1./2, 1, 0}, {0, 2./3, 0}, {-1./2, -1, 2./3} }; display(mat); return 0; } void display(double nums[][COLS]) { //problem with declaring array subscripts with double, so changed to int int rowNum, colNum; for (rowNum = 0.; rowNum < ROWS; rowNum++) { for (colNum = 0.; colNum < COLS; colNum++) printf(\"%1.1f\\t\", nums[rowNum][colNum]); printf(\"\ \"); } }.

What is wrong with this code? Please fix.
code:
#include
#include
#define ROWS 3
#define COLS 3
void display(double[ROWS][COLS]);
double main(){
double mat[ROWS][COLS] = { {1./2, 1, 0},
{0, 2./3, 0},
{-1./2, -1, 2./3} };
display(mat);
return 0;
}
void display(double nums[ROWS][COLS]) {
double rowNum, colNum;
for (rowNum = 0.; rowNum < ROWS; rowNum++)
{
for (colNum = 0.; colNum < COLS; colNum++)
printf("%1.1s", nums[rowNum][colNum]);
printf(" ");
}
}
Solution
#include
#include
#define ROWS 3
#define COLS 3
void display(double[ROWS][COLS]);
int main(){
double mat[ROWS][COLS] = { {1./2, 1, 0},
{0, 2./3, 0},
{-1./2, -1, 2./3} };

display(mat);
return 0;
}
void display(double nums[][COLS]) {
//problem with declaring array subscripts with double, so changed to int
int rowNum, colNum;
for (rowNum = 0.; rowNum < ROWS; rowNum++)
{
for (colNum = 0.; colNum < COLS; colNum++)
printf("%1.1ft", nums[rowNum][colNum]);
printf(" ");
}
}

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Todo package hwk6; // This class contains the configuration of a type of apartment public class Apartment { int numOfUnits; // the number of apartments of this type Room[] rooms; // rooms in this type of apartment Apartment(int numOfUnits, Room[] rooms) { this.numOfUnits = numOfUnits; this.rooms = rooms; } // return an array of window orders for one unit of this type of apartment WindowOrder[] orderForOneUnit() { // TODO } // return an array of window orders for all units of this type of apartment WindowOrder[] totalOrder() { // TODO } // return text like: // // 15 apartments with (Living room: 5 (6 X 8 window)) (Master bedroom: 3 (4 X 6 window)) (Guest room: 2 (5 X 6 window)) public String toString() { // TODO } } class OneBedroom extends Apartment { OneBedroom(int numOfUnits) { super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom() }); } } class TwoBedroom extends Apartment { TwoBedroom(int numOfUnits) { super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom(), new GuestRoom() }); } } class ThreeBedroom extends Apartment { ThreeBedroom(int numOfUnits) { super(numOfUnits, new Room[] { new LivingRoom(), new MasterBedroom(), new GuestRoom(), new GuestRoom() }); } // return an array of window orders for all units of this type of apartment // // Notice we have two guest rooms and they have the same size of windows. // override the inherited method to merge the order for the two guest rooms since their windows have the same size @Override WindowOrder[] orderForOneUnit() { // TODO } } package hwk6; public class Building { Apartment[] apartments; public Building(Apartment[] apartments) { this.apartments= apartments; } // Return an array of window orders for all apartments in the building // Ensure that the orders for windows of the same sizes are merged. WindowOrder[] order() { // TODO } // return a string to represent all types of apartments in the building such as: // 20 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window)) // 15 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window))(Guest room: 2 (5 X 6 window)) // 10 apartments with (Living room: 5 (6 X 8 window))(Master bedroom: 3 (4 X 6 window))(Guest room: 2 (5 X 6 window))(Guest room: 2 (5 X 6 window)) // public String toString() { // TODO } } package hwk6; public class Hwk6 { public static void main(String[] args) { Apartment[] apartments = { new OneBedroom(20), new TwoBedroom(15), new ThreeBedroom(10) }; Building building = new Building(apartments); WindowOrder[] orders = building.order(); System.out.println(building); System.out.println(\"Window orders are: \"); for(WindowOrder order: orders) { System.out.println(order); } } } package hwk6; public class Room { Window window; int numOfWindows; Room(Window window, int numOfWindows) { this.window = window; this.numOfWindows = numOfWindows; } WindowOrder order() { return new WindowOrder(window, numOfWindows); } // Print text like: 5 (6 X 8 window) @Override publ.

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This question refers to the ABO blood type locus. Remember that the A and B alleles are codominant to each other and both are dominant to the O allele. Assume no epistatic interactions with the H locus. A man has blood type A. Mark all genotypes below that are possible for this man. Select one or more: AA AB AO BB BO OO Solution Hence both A and B are codominant and dominant over O, the possible genotype of man having blood group A are AA and AO. Explanation: As both A and B are codominant if both are present iegenotype AB results in AB blood group BB and BO results in B blood group (as there is no A in genotype and B is dominant over O) OO results in O bllod group(Absence of both A and B in genotype).

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