E° = 0.07 - (0.14) = 0.21 V 2UO22+(aq) + Sn(s) 2UO2+(aq) + Sn2+(aq) [UO22+] = [UO2+] =[Sn2+] = 1.1mM = 0.0011 M Q =[UO2+]2[Sn2+]/[UO22+]2 = 0.0011 E = E° - 0.0592/n logQ = 0.21 - 0.0592/2 log 0.0011 = 0.2976 V Solution E° = 0.07 - (0.14) = 0.21 V 2UO22+(aq) + Sn(s) 2UO2+(aq) + Sn2+(aq) [UO22+] = [UO2+] =[Sn2+] = 1.1mM = 0.0011 M Q =[UO2+]2[Sn2+]/[UO22+]2 = 0.0011 E = E° - 0.0592/n logQ = 0.21 - 0.0592/2 log 0.0011 = 0.2976 V.