We know that from Nernst Equation , E o cell = E o – ( 0.059 / n ) log ( [ products ] / [reactants ]) Given Eo cell = 0.17 V Eo = 0.24 V [products ] = [Cd 2+ ] = ? [reactants ] = [ Ni 2+ ] = 1.0 M N = no . of electrons transferred = 2 Solution We know that from Nernst Equation , E o cell = E o – ( 0.059 / n ) log ( [ products ] / [reactants ]) Given Eo cell = 0.17 V Eo = 0.24 V [products ] = [Cd 2+ ] = ? [reactants ] = [ Ni 2+ ] = 1.0 M N = no . of electrons transferred = 2.