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Alternative 1: Continuing present job PV = Pmt x (1 + i) x (1 - (1 + g) n x (1 + i)-n) / (i - g) Pmt = 60,000 Discount rate (i) = 12% Growth rate (g) = 14% No of years (n) = 10 = 60000 × (1+0.12) × (1- (1+0.14)10 × (1+0.12)-10/ (0.12-0.14) = 650583.51 (Or) Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51 Alternative2: Going for MBA Year Cash flow Present value@12% Discounted cash flow 1 -45000.00 1 -45000.00 2 -45000.00 0.8929 -40178.57 3 90000.00 0.7972 71747.45 4 99000.00 0.7118 70466.24 5 108900.00 0.6355 69207.92 6 119790.00 0.5674 67972.06 7 131769.00 0.5066 66758.28 8 144945.90 0.4523 65566.16 9 159440.49 0.4039 64395.34 10 175384.54 0.3606 63245.42 Net present value 454180.31 The NPV of most attractive choice of continuing current job is 650583.51 Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51 Solution Alternative 1: Continuing present job PV = Pmt x (1 + i) x (1 - (1 + g) n x (1 + i)-n) / (i - g) Pmt = 60,000 Discount rate (i) = 12% Growth rate (g) = 14% No of years (n) = 10 = 60000 × (1+0.12) × (1- (1+0.14)10 × (1+0.12)-10/ (0.12-0.14) = 650583.51 (Or) Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51 Alternative2: Going for MBA Year Cash flow Present value@12% Discounted cash flow 1 -45000.00 1 -45000.00 2 -45000.00 0.8929 -40178.57 3 90000.00 0.7972 71747.45 4 99000.00 0.7118 70466.24 5 108900.00 0.6355 69207.92 6 119790.00 0.5674 67972.06 7 131769.00 0.5066 66758.28 8 144945.90 0.4523 65566.16 9 159440.49 0.4039 64395.34 10 175384.54 0.3606 63245.42 Net present value 454180.31 The NPV of most attractive choice of continuing current job is 650583.51 Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51.
Alternative 1 Continuing present jobPV = Pmt x (1 + i) x (1 - (1 .pdf
Alternative 1 Continuing present jobPV = Pmt x (1 + i) x (1 - (1 .pdf
anupamele
#include #include using namespace std; void getData(ifstream &in, int highLowTemperatures[][2]){ for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][0]; } for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][1]; } } int indexHighTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][0] < temperatures[i][0]){ val = i; } } return val; } int indexLowTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][1] > temperatures[i][1]){ val = i; } } return val; } int main(){ ifstream in; string fName; cout << \"Enter file name: \"; cin >> fName; in.open(fName.c_str()); int highLowTemperatures[12][2]; if(in.is_open()){ getData(in, highLowTemperatures); cout << \"Highest temperature of the year is \" << highLowTemperatures[indexHighTemp(highLowTemperatures)][0] << endl; cout << \"Lowest temperature of the year is \" << highLowTemperatures[indexLowTemp(highLowTemperatures)][1] << endl; } else{ cout << \"Can not open the file\" << endl; } return 0; } Solution #include #include using namespace std; void getData(ifstream &in, int highLowTemperatures[][2]){ for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][0]; } for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][1]; } } int indexHighTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][0] < temperatures[i][0]){ val = i; } } return val; } int indexLowTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][1] > temperatures[i][1]){ val = i; } } return val; } int main(){ ifstream in; string fName; cout << \"Enter file name: \"; cin >> fName; in.open(fName.c_str()); int highLowTemperatures[12][2]; if(in.is_open()){ getData(in, highLowTemperatures); cout << \"Highest temperature of the year is \" << highLowTemperatures[indexHighTemp(highLowTemperatures)][0] << endl; cout << \"Lowest temperature of the year is \" << highLowTemperatures[indexLowTemp(highLowTemperatures)][1] << endl; } else{ cout << \"Can not open the file\" << endl; } return 0; }.
#include iostream #include fstreamusing namespace std;void.pdf
#include iostream #include fstreamusing namespace std;void.pdf
anupamele
Wilhelm Johannsen first proposed the distinction between genotype and phenotype in the study of heredity while working in Denmark in 1909. The distinction is between the hereditary dispositions of organisms (their genotypes) and the ways in which those dispositions manifest themselves in the physical characteristics of those organisms (their phenotypes). This distinction was an outgrowth of Johannsen Solution Wilhelm Johannsen first proposed the distinction between genotype and phenotype in the study of heredity while working in Denmark in 1909. The distinction is between the hereditary dispositions of organisms (their genotypes) and the ways in which those dispositions manifest themselves in the physical characteristics of those organisms (their phenotypes). This distinction was an outgrowth of Johannsen.
Wilhelm Johannsen first proposed the distinction between genotype a.pdf
Wilhelm Johannsen first proposed the distinction between genotype a.pdf
anupamele
True, they are identical Thats just the bottom view and top view of the molecule Man please rate. Solution True, they are identical Thats just the bottom view and top view of the molecule Man please rate..
True, they are identical Thats just the bottom vi.pdf
True, they are identical Thats just the bottom vi.pdf
anupamele
The NH2OH is in acidic solution as a reactant and copper is reduced to Cu+. The rest is confusing so here you go. 2Cu2+ + 2NH3OH+ -> 2Cu+ + 2H20 + N2 + 4H+......your welcome. Solution The NH2OH is in acidic solution as a reactant and copper is reduced to Cu+. The rest is confusing so here you go. 2Cu2+ + 2NH3OH+ -> 2Cu+ + 2H20 + N2 + 4H+......your welcome..
The NH2OH is in acidic solution as a reactant and.pdf
The NH2OH is in acidic solution as a reactant and.pdf
anupamele
The atom is a basic unit of matter consisting of central nucleus surrounded by a cloud of negatively charged electrons. The atomic nucleus contains a mix of positively charged protons and electrically neutral neutrons (except in the case of hydrogen-1, which is the only stable nuclide with no neutrons). The electrons of an atom are bound to the nucleus by the electromagnetic force. Likewise, a group of atoms can remain bound to each other, forming a molecule. An atom containing an equal number of protons and electrons is electrically neutral, otherwise it has a positive charge if there are fewer electrons (electron deficiency) or negative charge if there are more electrons (electron excess). A positively or negatively charged atom is known as an ion. An atom is classified according to the number of protons and neutrons in its nucleus: the number of protons determines the chemical element, and the number of neutrons determines the isotope of the element.[1] The name atom comes from the Greek ?t?µ?? (atomos, \"indivisible\") from ?- (a-, \"not\") and t?µ?? (temno, \"I cut\")[2], which means uncuttable, or indivisible, something that cannot be divided further.[3] The concept of an atom as an indivisible component of matter was first proposed by early Indian and Greek philosophers. In the 17th and 18th centuries, chemists provided a physical basis for this idea by showing that certain substances could not be further broken down by chemical methods. During the late 19th and early 20th centuries, physicists discovered subatomic components and structure inside the atom, thereby demonstrating that the \'atom\' was divisible. The principles of quantum mechanics were used to successfully model the atom.[4][5] Atoms are minuscule objects with proportionately tiny masses. Atoms can only be observed individually using special instruments such as the scanning tunneling microscope. Over 99.94% of an atom\'s mass is concentrated in the nucleus,[note 1] with protons and neutrons having roughly equal mass. Each element has at least one isotope with unstable nuclei that can undergo radioactive decay. This can result in a transmutation that changes the number of protons or neutrons in a nucleus.[6] Electrons that are bound to atoms possess a set of stable energy levels, or orbitals, and can undergo transitions between them by absorbing or emitting photons that match the energy differences between the levels. The electrons determine the chemical properties of an element, and strongly influence an atom\'s magnetic properties. Solution The atom is a basic unit of matter consisting of central nucleus surrounded by a cloud of negatively charged electrons. The atomic nucleus contains a mix of positively charged protons and electrically neutral neutrons (except in the case of hydrogen-1, which is the only stable nuclide with no neutrons). The electrons of an atom are bound to the nucleus by the electromagnetic force. Likewise, a group of atoms can remain bound to each .
The atom is a basic unit of matter consisting of .pdf
The atom is a basic unit of matter consisting of .pdf
anupamele
see the inner one is union of events from 1-inf. 2-inf. 3-inf and so on Solution see the inner one is union of events from 1-inf. 2-inf. 3-inf and so on.
see the inner one is union of events from 1-inf. .pdf
see the inner one is union of events from 1-inf. .pdf
anupamele
No you wouldn\'t include the intermediates in the rate law but you need to identify them Solution No you wouldn\'t include the intermediates in the rate law but you need to identify them.
No you wouldnt include the intermediates in the.pdf
No you wouldnt include the intermediates in the.pdf
anupamele
Recommended
Alternative 1: Continuing present job PV = Pmt x (1 + i) x (1 - (1 + g) n x (1 + i)-n) / (i - g) Pmt = 60,000 Discount rate (i) = 12% Growth rate (g) = 14% No of years (n) = 10 = 60000 × (1+0.12) × (1- (1+0.14)10 × (1+0.12)-10/ (0.12-0.14) = 650583.51 (Or) Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51 Alternative2: Going for MBA Year Cash flow Present value@12% Discounted cash flow 1 -45000.00 1 -45000.00 2 -45000.00 0.8929 -40178.57 3 90000.00 0.7972 71747.45 4 99000.00 0.7118 70466.24 5 108900.00 0.6355 69207.92 6 119790.00 0.5674 67972.06 7 131769.00 0.5066 66758.28 8 144945.90 0.4523 65566.16 9 159440.49 0.4039 64395.34 10 175384.54 0.3606 63245.42 Net present value 454180.31 The NPV of most attractive choice of continuing current job is 650583.51 Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51 Solution Alternative 1: Continuing present job PV = Pmt x (1 + i) x (1 - (1 + g) n x (1 + i)-n) / (i - g) Pmt = 60,000 Discount rate (i) = 12% Growth rate (g) = 14% No of years (n) = 10 = 60000 × (1+0.12) × (1- (1+0.14)10 × (1+0.12)-10/ (0.12-0.14) = 650583.51 (Or) Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51 Alternative2: Going for MBA Year Cash flow Present value@12% Discounted cash flow 1 -45000.00 1 -45000.00 2 -45000.00 0.8929 -40178.57 3 90000.00 0.7972 71747.45 4 99000.00 0.7118 70466.24 5 108900.00 0.6355 69207.92 6 119790.00 0.5674 67972.06 7 131769.00 0.5066 66758.28 8 144945.90 0.4523 65566.16 9 159440.49 0.4039 64395.34 10 175384.54 0.3606 63245.42 Net present value 454180.31 The NPV of most attractive choice of continuing current job is 650583.51 Year Cashflow Present value@12% Discounted cashflow 1 60000.00 1 60000.00 2 68400.00 0.8929 61071.43 3 77976.00 0.7972 62161.99 4 88892.64 0.7118 63272.03 5 101337.61 0.6355 64401.88 6 115524.87 0.5674 65551.92 7 131698.36 0.5066 66722.49 8 150136.13 0.4523 67913.96 9 171155.19 0.4039 69126.71 10 195116.91 0.3606 70361.11 Net Present value 650583.51.
Alternative 1 Continuing present jobPV = Pmt x (1 + i) x (1 - (1 .pdf
Alternative 1 Continuing present jobPV = Pmt x (1 + i) x (1 - (1 .pdf
anupamele
#include #include using namespace std; void getData(ifstream &in, int highLowTemperatures[][2]){ for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][0]; } for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][1]; } } int indexHighTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][0] < temperatures[i][0]){ val = i; } } return val; } int indexLowTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][1] > temperatures[i][1]){ val = i; } } return val; } int main(){ ifstream in; string fName; cout << \"Enter file name: \"; cin >> fName; in.open(fName.c_str()); int highLowTemperatures[12][2]; if(in.is_open()){ getData(in, highLowTemperatures); cout << \"Highest temperature of the year is \" << highLowTemperatures[indexHighTemp(highLowTemperatures)][0] << endl; cout << \"Lowest temperature of the year is \" << highLowTemperatures[indexLowTemp(highLowTemperatures)][1] << endl; } else{ cout << \"Can not open the file\" << endl; } return 0; } Solution #include #include using namespace std; void getData(ifstream &in, int highLowTemperatures[][2]){ for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][0]; } for(int i = 0; i < 12; ++i){ in >> highLowTemperatures[i][1]; } } int indexHighTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][0] < temperatures[i][0]){ val = i; } } return val; } int indexLowTemp(int temperatures[][2]){ int val = 0; for(int i = 1; i < 12; ++i){ if(temperatures[val][1] > temperatures[i][1]){ val = i; } } return val; } int main(){ ifstream in; string fName; cout << \"Enter file name: \"; cin >> fName; in.open(fName.c_str()); int highLowTemperatures[12][2]; if(in.is_open()){ getData(in, highLowTemperatures); cout << \"Highest temperature of the year is \" << highLowTemperatures[indexHighTemp(highLowTemperatures)][0] << endl; cout << \"Lowest temperature of the year is \" << highLowTemperatures[indexLowTemp(highLowTemperatures)][1] << endl; } else{ cout << \"Can not open the file\" << endl; } return 0; }.
#include iostream #include fstreamusing namespace std;void.pdf
#include iostream #include fstreamusing namespace std;void.pdf
anupamele
Wilhelm Johannsen first proposed the distinction between genotype and phenotype in the study of heredity while working in Denmark in 1909. The distinction is between the hereditary dispositions of organisms (their genotypes) and the ways in which those dispositions manifest themselves in the physical characteristics of those organisms (their phenotypes). This distinction was an outgrowth of Johannsen Solution Wilhelm Johannsen first proposed the distinction between genotype and phenotype in the study of heredity while working in Denmark in 1909. The distinction is between the hereditary dispositions of organisms (their genotypes) and the ways in which those dispositions manifest themselves in the physical characteristics of those organisms (their phenotypes). This distinction was an outgrowth of Johannsen.
Wilhelm Johannsen first proposed the distinction between genotype a.pdf
Wilhelm Johannsen first proposed the distinction between genotype a.pdf
anupamele
True, they are identical Thats just the bottom view and top view of the molecule Man please rate. Solution True, they are identical Thats just the bottom view and top view of the molecule Man please rate..
True, they are identical Thats just the bottom vi.pdf
True, they are identical Thats just the bottom vi.pdf
anupamele
The NH2OH is in acidic solution as a reactant and copper is reduced to Cu+. The rest is confusing so here you go. 2Cu2+ + 2NH3OH+ -> 2Cu+ + 2H20 + N2 + 4H+......your welcome. Solution The NH2OH is in acidic solution as a reactant and copper is reduced to Cu+. The rest is confusing so here you go. 2Cu2+ + 2NH3OH+ -> 2Cu+ + 2H20 + N2 + 4H+......your welcome..
The NH2OH is in acidic solution as a reactant and.pdf
The NH2OH is in acidic solution as a reactant and.pdf
anupamele
The atom is a basic unit of matter consisting of central nucleus surrounded by a cloud of negatively charged electrons. The atomic nucleus contains a mix of positively charged protons and electrically neutral neutrons (except in the case of hydrogen-1, which is the only stable nuclide with no neutrons). The electrons of an atom are bound to the nucleus by the electromagnetic force. Likewise, a group of atoms can remain bound to each other, forming a molecule. An atom containing an equal number of protons and electrons is electrically neutral, otherwise it has a positive charge if there are fewer electrons (electron deficiency) or negative charge if there are more electrons (electron excess). A positively or negatively charged atom is known as an ion. An atom is classified according to the number of protons and neutrons in its nucleus: the number of protons determines the chemical element, and the number of neutrons determines the isotope of the element.[1] The name atom comes from the Greek ?t?µ?? (atomos, \"indivisible\") from ?- (a-, \"not\") and t?µ?? (temno, \"I cut\")[2], which means uncuttable, or indivisible, something that cannot be divided further.[3] The concept of an atom as an indivisible component of matter was first proposed by early Indian and Greek philosophers. In the 17th and 18th centuries, chemists provided a physical basis for this idea by showing that certain substances could not be further broken down by chemical methods. During the late 19th and early 20th centuries, physicists discovered subatomic components and structure inside the atom, thereby demonstrating that the \'atom\' was divisible. The principles of quantum mechanics were used to successfully model the atom.[4][5] Atoms are minuscule objects with proportionately tiny masses. Atoms can only be observed individually using special instruments such as the scanning tunneling microscope. Over 99.94% of an atom\'s mass is concentrated in the nucleus,[note 1] with protons and neutrons having roughly equal mass. Each element has at least one isotope with unstable nuclei that can undergo radioactive decay. This can result in a transmutation that changes the number of protons or neutrons in a nucleus.[6] Electrons that are bound to atoms possess a set of stable energy levels, or orbitals, and can undergo transitions between them by absorbing or emitting photons that match the energy differences between the levels. The electrons determine the chemical properties of an element, and strongly influence an atom\'s magnetic properties. Solution The atom is a basic unit of matter consisting of central nucleus surrounded by a cloud of negatively charged electrons. The atomic nucleus contains a mix of positively charged protons and electrically neutral neutrons (except in the case of hydrogen-1, which is the only stable nuclide with no neutrons). The electrons of an atom are bound to the nucleus by the electromagnetic force. Likewise, a group of atoms can remain bound to each .
The atom is a basic unit of matter consisting of .pdf
The atom is a basic unit of matter consisting of .pdf
anupamele
see the inner one is union of events from 1-inf. 2-inf. 3-inf and so on Solution see the inner one is union of events from 1-inf. 2-inf. 3-inf and so on.
see the inner one is union of events from 1-inf. .pdf
see the inner one is union of events from 1-inf. .pdf
anupamele
No you wouldn\'t include the intermediates in the rate law but you need to identify them Solution No you wouldn\'t include the intermediates in the rate law but you need to identify them.
No you wouldnt include the intermediates in the.pdf
No you wouldnt include the intermediates in the.pdf
anupamele
mole of NaOH= 12/40 =0.3 so molarity = 0.3/1.8 = 0.167 so ans B) 0.167 Solution mole of NaOH= 12/40 =0.3 so molarity = 0.3/1.8 = 0.167 so ans B) 0.167.
mole of NaOH= 1240 =0.3 so molarity = 0.31.8 = .pdf
mole of NaOH= 1240 =0.3 so molarity = 0.31.8 = .pdf
anupamele
millimoles of HBr=50*0.04=2 millimoles of KOH=25*.107=2.675 millimoles of acid remaining=0 millimoles of base remaining=0.675 Kb=[OH-][K+]/[KOH] 1=[OH-]*2/0.675 [oh-]=0.675/2 =0.3375 pH=14+log(0.3375) =13.53 Solution millimoles of HBr=50*0.04=2 millimoles of KOH=25*.107=2.675 millimoles of acid remaining=0 millimoles of base remaining=0.675 Kb=[OH-][K+]/[KOH] 1=[OH-]*2/0.675 [oh-]=0.675/2 =0.3375 pH=14+log(0.3375) =13.53.
millimoles of HBr=500.04=2 millimoles of KOH=25.pdf
millimoles of HBr=500.04=2 millimoles of KOH=25.pdf
anupamele
initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L Solution initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L.
initially 2 moles of HCl per L of water suppose x.pdf
initially 2 moles of HCl per L of water suppose x.pdf
anupamele
i cant see the question.. please post the complete question so dat i can provide uthe best possible answer..... Solution i cant see the question.. please post the complete question so dat i can provide uthe best possible answer......
i cant see the question.. please post the complet.pdf
i cant see the question.. please post the complet.pdf
anupamele
hey pls give the reactions.... Solution hey pls give the reactions.....
hey pls give the reactions.... .pdf
hey pls give the reactions.... .pdf
anupamele
FT-Raman spectra of some calcium phosphates, calcium carbonate and calcium hydroxide are reported. Comparing with dispersive Raman spectra, it is shown that some strong bands in the FT-Raman spectra of these compounds which have been erroneously assigned to Ramanbands, are in fact fluorescence emission bands. The origin of these fluorescencebands have been discussed in terms of rare earth impurities in a particular structure. It is further concluded that in using FT-Raman spectroscopy of minerals, care should be taken in not confusing the fluorescencebands with Raman scattering bands. Among instrumental techniques, fluorescence spectroscopy is recognized as one of the more sensitive. In fluorescence, the intensity of the emission of the sample is measured. The reason for the high sensitivity of fluorescence techniques is that the emission signal is measured above a low background level. This is inherently more sensitive than comparing two relatively large signals as in absorption spectroscopy. The sensitivity of fluorescence techniques is as much as 1000 times more sensitive than absorption spectroscopy. A spectrofluorometer with high sensitivity is an asset for the researcher. It is obvious that an instrument with high sensitivity will be able to perform experiments with the fluorescing species at a low concentration. For analytical measurements, sensitivity determines the detection limit of a material. For research in life science, it may be important to work at concentration levels that are very low. This is almost always the case in biomedical research. A more subtle requirement is the need to measure changes in fluorescence during the course of an experiment. Even though the gross signal levels may be high, the changes in the signal may be quite small. The ability to reliably measure these small changes is directly dependent upon the sensitivity of the fluorometer. The measurement of sensitivity has been discussed in the literature [1]. Unfortunately, there is little consensus on a standard procedure for determining this important capability. This paper discusses the measurement of sensitivity and details two methods that are applicable to any instrument. The Spectrofluorometer The sensitivity of fluorescence is dependent on both the fluorophore and the instrument. The response of a fluorophore will depend on the molar absorptivity and the quantum yield. These factors are, in general, beyond the control of the analyst. The sensitivity of a spectrofluorometer depends on a number of factors. Instrumental contributions to sensitivity are described below. 1. Source intensity. In general, a brighter excitation source will result in brighter emission. The source for most fluorometers is a xenon arc, which has a high intensity between 200-900 nm, the spectral region where most fluorescence experiments are performed. While a high power arc lamp is good for highest intensity, a more important criteria is the brightness of the lamp. The brightness.
FT-Raman spectra of some calcium phosphates, calc.pdf
FT-Raman spectra of some calcium phosphates, calc.pdf
anupamele
H is oxidised here no O2 is not oxidised as it gains electrons yes Cu is reduced here Solution H is oxidised here no O2 is not oxidised as it gains electrons yes Cu is reduced here.
H is oxidised here no O2 is not oxidised as it g.pdf
H is oxidised here no O2 is not oxidised as it g.pdf
anupamele
Current Stock price = Expected dividend / (Required rate of return - Growth rate) = $2.54 / (11% - 3.50%) = $2.54 / 7.50% = $33.87 Current Stock price is $33.87. Solution Current Stock price = Expected dividend / (Required rate of return - Growth rate) = $2.54 / (11% - 3.50%) = $2.54 / 7.50% = $33.87 Current Stock price is $33.87..
Current Stock price = Expected dividend (Required rate of return -.pdf
Current Stock price = Expected dividend (Required rate of return -.pdf
anupamele
YES the news stories in the Illustrated American sympathetic or non-sympathetic to the cause of the strikers. The Homestead Strike - this was at the Homestead Steel Works, owned by Andrew Carnegie but run by Henry Clay Frick. Labor went on strike because of pay rates that were continually adjusted down as well as poor working conditions. Carnegie was in Scotland at this time and Frick was the man on the spot and in charge. A miscommunication between these two resulted in Frick using too much force to suppress the strikers. Labor was responsible for the strike, but Frick (and maybe Carnegie) were resposible for subsequent events and deaths. The Homestead strike was organized and purposeful, a harbinger of the type of strike which would mark the modern age of labor relations in the United States. The AA strike at the Homestead steel mill in 1892 was different from previous large-scale strikes in American history such as the Great railroad strike of 1877 or the Great Southwest Railroad Strike of 1886. Earlier strikes had been largely leaderless and disorganized mass uprisings of workers. The AFL refused to call for a boycott of Carnegie products in September 1892. Wholesale crossing of the picket line occurred, first among Eastern European immigrants and then among all workers. The strike had collapsed so much that the state militia pulled out on October 13, ending the 95-day occupation. The AA was nearly bankrupted by the job action. Weekly Union relief for a member averaged $6.25 but totalled a staggering $10,000 per week when including 1,600 strikers. With only 192 out of more than 3,800 strikers in attendance, the Homestead chapter of the AA voted, 101 to 91, to return to work on November 20, 1892. Solution YES the news stories in the Illustrated American sympathetic or non-sympathetic to the cause of the strikers. The Homestead Strike - this was at the Homestead Steel Works, owned by Andrew Carnegie but run by Henry Clay Frick. Labor went on strike because of pay rates that were continually adjusted down as well as poor working conditions. Carnegie was in Scotland at this time and Frick was the man on the spot and in charge. A miscommunication between these two resulted in Frick using too much force to suppress the strikers. Labor was responsible for the strike, but Frick (and maybe Carnegie) were resposible for subsequent events and deaths. The Homestead strike was organized and purposeful, a harbinger of the type of strike which would mark the modern age of labor relations in the United States. The AA strike at the Homestead steel mill in 1892 was different from previous large-scale strikes in American history such as the Great railroad strike of 1877 or the Great Southwest Railroad Strike of 1886. Earlier strikes had been largely leaderless and disorganized mass uprisings of workers. The AFL refused to call for a boycott of Carnegie products in September 1892. Wholesale crossing of the picket line occurred, first among Eastern European i.
YES the news stories in the Illustrated American sympathetic or non-.pdf
YES the news stories in the Illustrated American sympathetic or non-.pdf
anupamele
Well its quite an easy one. The given curve is a cardioid. The limits of theta, unless otherwise mentioned is always from 0 to . The secret to finding it is that, cos=(r-4)/3 . So for any value of r in polar coordinate, (r-4)/3 will give some value. But we know cos=cos(2-), so the same value wil be given by and 2- . So if we put =2-, we get = which is maximum range for non repeatation of r values. A simpler way to find the range is: You get the minimum value of r at cos=-1, so minimum r=1. So range of r must be from 1 to 4 + 3cos. r is minimm at = and maximum of r is when cos=1 that is =0. So your can range from 0 to . However, integrating from 0 to will only give you half the area ( upper part of curve). So multiply the answer with 2 to get the full area. Solution Well its quite an easy one. The given curve is a cardioid. The limits of theta, unless otherwise mentioned is always from 0 to . The secret to finding it is that, cos=(r-4)/3 . So for any value of r in polar coordinate, (r-4)/3 will give some value. But we know cos=cos(2-), so the same value wil be given by and 2- . So if we put =2-, we get = which is maximum range for non repeatation of r values. A simpler way to find the range is: You get the minimum value of r at cos=-1, so minimum r=1. So range of r must be from 1 to 4 + 3cos. r is minimm at = and maximum of r is when cos=1 that is =0. So your can range from 0 to . However, integrating from 0 to will only give you half the area ( upper part of curve). So multiply the answer with 2 to get the full area..
Well its quite an easy one. The given curve is a cardioid. The limit.pdf
Well its quite an easy one. The given curve is a cardioid. The limit.pdf
anupamele
Total ionic Equation is : 2Cu2+ +4 Cl - + 4H+ +SO42- ---> Cu2SiO4+ 4H+ + 4Cl- Spectator ions are : H+ & Cl - Spectator ions are : H+ & Cl - Net ionic Equation is : 2Cu2+ + SO42- --->Cu2SiO4 Solution Total ionic Equation is : 2Cu2+ +4 Cl - + 4H+ +SO42- ---> Cu2SiO4+ 4H+ + 4Cl- Spectator ions are : H+ & Cl - Spectator ions are : H+ & Cl - Net ionic Equation is : 2Cu2+ + SO42- --->Cu2SiO4.
Total ionic Equation is 2Cu2+ +4 Cl - + 4H+ +SO42- --- Cu2SiO4+ 4.pdf
Total ionic Equation is 2Cu2+ +4 Cl - + 4H+ +SO42- --- Cu2SiO4+ 4.pdf
anupamele
Answer: SOCS are the supressor of cytokine signaling proteins and are negative feedback regulators of JAK-STAT signaling pathway. It means the SOCS are inhibitors of activation of JAK-STAT pathway proteins. As JAK-STAT pathway plays essential roles in initiation and development of cancers, mutation in SOCS family proteins could be one of the mechanism of abnormal activation of STAT . The expression of SOCS are inversly related to the STAT-3 activation. Hence overexpression of SOCS may not be lead to cancer risk. Overexpression of SOCS may supress the cytokine signaling or inhibit cytokine signaling by (i) Blocking STAT recruitment to the cytokine receptor (ii) may target protein for degradation (iii) bind to JAK and inhibit their kinase (iv) target JAK for degradation via proteosome pathway Solution Answer: SOCS are the supressor of cytokine signaling proteins and are negative feedback regulators of JAK-STAT signaling pathway. It means the SOCS are inhibitors of activation of JAK-STAT pathway proteins. As JAK-STAT pathway plays essential roles in initiation and development of cancers, mutation in SOCS family proteins could be one of the mechanism of abnormal activation of STAT . The expression of SOCS are inversly related to the STAT-3 activation. Hence overexpression of SOCS may not be lead to cancer risk. Overexpression of SOCS may supress the cytokine signaling or inhibit cytokine signaling by (i) Blocking STAT recruitment to the cytokine receptor (ii) may target protein for degradation (iii) bind to JAK and inhibit their kinase (iv) target JAK for degradation via proteosome pathway.
AnswerSOCS are the supressor of cytokine signaling proteins and a.pdf
AnswerSOCS are the supressor of cytokine signaling proteins and a.pdf
anupamele
The pre-mRNA is converted into mature mRNA by modifications known as post-transcriptional modifications. The three main modifications involved are Solution The pre-mRNA is converted into mature mRNA by modifications known as post-transcriptional modifications. The three main modifications involved are.
The pre-mRNA is converted into mature mRNA by modifications known as.pdf
The pre-mRNA is converted into mature mRNA by modifications known as.pdf
anupamele
CH3CH2OH will have high boiling point becauseof the presence of hydrogen bonding in it (O-H) Solution CH3CH2OH will have high boiling point becauseof the presence of hydrogen bonding in it (O-H).
CH3CH2OH will have high boiling point becauseof t.pdf
CH3CH2OH will have high boiling point becauseof t.pdf
anupamele
SO4 would have isolated (unlinked) tetrahedra that are all oxygen anions that are have some sort of metal bound to them. for example Mg2SiO4, Fe2SiO4 I believe it would be called a nesosilicates or orthosilicate. Solution SO4 would have isolated (unlinked) tetrahedra that are all oxygen anions that are have some sort of metal bound to them. for example Mg2SiO4, Fe2SiO4 I believe it would be called a nesosilicates or orthosilicate..
SO4 would have isolated (unlinked) tetrahedra that are all oxygen an.pdf
SO4 would have isolated (unlinked) tetrahedra that are all oxygen an.pdf
anupamele
//Tested on Eclipse /****************Equivalence.java*************/ package chegg; import java.util.Scanner; public class Equivalence { /*Income tax calculation method*/ public void calculateTax(double income){ double tax=0; /*Based on provided data in question*/ if(income<10){ tax=tax+0; }else if(income>=10 && income<20){ tax=tax+(income*10)/100; }else if(income>=20 && income<40){ /*add 10 % of 10k means 1k needs to be added in tax*/ tax=tax+1+((income-20)*12)/100; }else if(income>=40 && income<80){ /*add 10 % of 10k means 1k and 12% of 20k needs to be added in tax*/ tax=tax+1+2.4+((income-40)*15)/100; }else if(income>=80){ /*add 10 % of 10k means 1k and 12% of 20k and 15 % of 40k needs to be added in tax*/ tax=tax+1+2.4+6+((income-80)*20)/100; } System.out.println(\"Total Tax is: $\"+tax+\"K\"); } /*Main method start*/ public static void main(String args[]){ /*Variable declaration*/ double income; Scanner input=new Scanner(System.in); /*Class object creation*/ Equivalence equivalence=new Equivalence(); /*Prompt for income*/ System.out.println(\"Please Enter the income\"); income=input.nextDouble(); /*calling calculateTax method*/ equivalence.calculateTax(income); } } /************output***********/ Please Enter the income 25 Total Tax is: $1.6K Solution //Tested on Eclipse /****************Equivalence.java*************/ package chegg; import java.util.Scanner; public class Equivalence { /*Income tax calculation method*/ public void calculateTax(double income){ double tax=0; /*Based on provided data in question*/ if(income<10){ tax=tax+0; }else if(income>=10 && income<20){ tax=tax+(income*10)/100; }else if(income>=20 && income<40){ /*add 10 % of 10k means 1k needs to be added in tax*/ tax=tax+1+((income-20)*12)/100; }else if(income>=40 && income<80){ /*add 10 % of 10k means 1k and 12% of 20k needs to be added in tax*/ tax=tax+1+2.4+((income-40)*15)/100; }else if(income>=80){ /*add 10 % of 10k means 1k and 12% of 20k and 15 % of 40k needs to be added in tax*/ tax=tax+1+2.4+6+((income-80)*20)/100; } System.out.println(\"Total Tax is: $\"+tax+\"K\"); } /*Main method start*/ public static void main(String args[]){ /*Variable declaration*/ double income; Scanner input=new Scanner(System.in); /*Class object creation*/ Equivalence equivalence=new Equivalence(); /*Prompt for income*/ System.out.println(\"Please Enter the income\"); income=input.nextDouble(); /*calling calculateTax method*/ equivalence.calculateTax(income); } } /************output***********/ Please Enter the income 25 Total Tax is: $1.6K.
Tested on EclipseEquivalence.java.pdf
Tested on EclipseEquivalence.java.pdf
anupamele
Psychotherapy is the utilization of mental techniques, especially when in light of general individual collaboration, to help a man change and conquer issues in coveted ways. Psychotherapy intends to enhance an individual\'s prosperity and psychological well-being, to determine or relieve troublesome practices, convictions, impulses, considerations, or feelings, and to enhance connections and social abilities. Certain psychotherapies are considered proof based for treating some analyzed mental issue. 1. Concentrate on influence and articulation of feeling. Psychodynamic treatment empowers investigation also, discourse of the full scope of a patient\'s feelings. The specialist helps the patient depict and put words to emotions, counting conflicting emotions, sentiments that are upsetting or undermining, and emotions that the patient may not at first have the capacity to perceive or recognize (this remains rather than an intellectual concentration, where the more prominent accentuation is on musings and convictions; Blagys and Hilsenroth, 2002) There is likewise an acknowledgment that scholarly understanding is not the same as passionate understanding, which resounds at a profound level and prompts to change (this is one motivation behind why numerous clever and mentally disapproved of individuals can clarify the explanations behind their dif- ficulties, yet their comprehension does not help them overcome those challenges). 2. Investigation of endeavors to abstain from upsetting considerations and emotions. Individuals do an awesome numerous things, intentionally and unconsciously, to maintain a strategic distance from perspectives of experience that are disturbing. This evasion (in hypothetical terms, protection and resistance) may take coarse structures, for example, missing sessions, arriving late, or being shifty. It might take unobtrusive structures that are hard to perceive in normal social talk, for example, inconspicuous movements of theme when certain thoughts emerge, concentrating on accidental parts of an affair instead of on what is mentally significant, taking care of truths and occasions to the rejection of effect, concentrating on outer conditions as opposed to one\'s own part in forming occasions, thus on.Psychodynamic specialists effectively concentrate on and investigate shirkings. 3. Distinguishing proof of repeating topics and designs. Psychodynamic advisors work to distinguish what\'s more, investigate repeating topics and examples in patients\' contemplations, sentiments, self-idea, connections, and beneficial encounters. Now and again, a patient might be intensely mindful of repeating designs that are agonizing or self-vanquishing yet feel not able to escape them (e.g., a man who over and over finds himself attracted to sentimental accomplices who are sincerely inaccessible; a lady who consistently attacks herself at the point when achievement is close by). In different cases, the patient might be unconscious of the exampl.
Psychotherapy is the utilization of mental techniques, especially wh.pdf
Psychotherapy is the utilization of mental techniques, especially wh.pdf
anupamele
let E>0 be given there exists d1,d2 >0 such that |f(x)-L| lim f(x) = L as x tends to a thus proved Solution let E>0 be given there exists d1,d2 >0 such that |f(x)-L| lim f(x) = L as x tends to a thus proved.
let E0 be giventhere exists d1,d2 0 such thatf(x)-L E for 0.pdf
let E0 be giventhere exists d1,d2 0 such thatf(x)-L E for 0.pdf
anupamele
import java.util.ArrayList; import java.util.List; public class SearchList { /** * param args */ public static void main(String[] args) { List list = new ArrayList(); list.add(3); list.add(3); list.add(1); System.out.println(\"Search element 3 in list [3,3,1] :\" + search(list, 3)); System.out.println(\"Search element 5 in list [3,3,1] :\" + search(list, 5)); } /** * method to find the index of element in the list * param list * param element * return */ public static int search(List list, Object element) { int index = -1; if (list == null || element == null) throw new NullPointerException(); else { int searchElement = (int) element; for (int i = 0; i < list.size(); i++) { int number = (int) list.get(i); if (number == searchElement) { index = i; } } } return index; } } OUTPUT: Search element 3 in list [3,3,1] :1 Search element 5 in list [3,3,1] :-1 Solution import java.util.ArrayList; import java.util.List; public class SearchList { /** * param args */ public static void main(String[] args) { List list = new ArrayList(); list.add(3); list.add(3); list.add(1); System.out.println(\"Search element 3 in list [3,3,1] :\" + search(list, 3)); System.out.println(\"Search element 5 in list [3,3,1] :\" + search(list, 5)); } /** * method to find the index of element in the list * param list * param element * return */ public static int search(List list, Object element) { int index = -1; if (list == null || element == null) throw new NullPointerException(); else { int searchElement = (int) element; for (int i = 0; i < list.size(); i++) { int number = (int) list.get(i); if (number == searchElement) { index = i; } } } return index; } } OUTPUT: Search element 3 in list [3,3,1] :1 Search element 5 in list [3,3,1] :-1.
import java.util.ArrayList; import java.util.List;public class S.pdf
import java.util.ArrayList; import java.util.List;public class S.pdf
anupamele
Heterotrophic bacteria is not able to lead the planktonic way of life as heterotrophic bacteria are unable to produce their own food where as planktons are able to produce their own food with the help of sunlight by a process called photosynthesis. Heterotrophic bacteria depends on source of organic carbon and derives its energy by the break down of the organic carbon. Solution Heterotrophic bacteria is not able to lead the planktonic way of life as heterotrophic bacteria are unable to produce their own food where as planktons are able to produce their own food with the help of sunlight by a process called photosynthesis. Heterotrophic bacteria depends on source of organic carbon and derives its energy by the break down of the organic carbon..
Heterotrophic bacteria is not able to lead the planktonic way of lif.pdf
Heterotrophic bacteria is not able to lead the planktonic way of lif.pdf
anupamele
Program code examples (known also as worked examples) play a crucial role in learning how to program. Instructors use examples extensively to demonstrate the semantics of the programming language being taught and to highlight the fundamental coding patterns. Programming textbooks allocate considerable space to present and explain code examples. To make the process of studying code examples more interactive, CS education researchers developed a range of tools to engage students in the study of code examples. These tools include codecasts (codemotion,codecast,elicasts), interactive example explorers (WebEx, PCEX), and tutoring systems (DeepTutor). An important component in all types of worked examples is code explanations associated with specific code lines or code chunks of an example. The explanations connect examples with general programming knowledge explaining the role and function of code fragments or their behavior. In textbooks, these explanations are usually presented as comments in the code or as explanations on the margins. The example explorer tools allow students to examine these explanations interactively. Tutoring systems, which engage students in explaining the code, use these model explanations to check student responses and provide scaffolding. In all these cases, to make a worked example re-usable beyond its presentation in a lecture, the explanations have to be authored by instructors or domain experts i.e., produced and integrated into a specific system. As the experience of the last 10 years demonstrated, these explanations are hard to obtain. Those already collected are usually “locked” in a specific example-focused system and can’t be reused. The purpose of this working group is to support broader re-used of worked examples augmented with explanations. Our current plan is to develop а standard approach to represent explained examples. This approach will enable an example created for any of the existing systems to be explored in a standard format and imported into any other example-focused system. We plan to follow a successful experience of the PEML working group focused on re-using programming exercises.
SPLICE Working Group:Reusable Code Examples
SPLICE Working Group:Reusable Code Examples
Peter Brusilovsky
In this webinar, Tapp Network experts shared how to boost your nonprofit's digital presence, donor engagement, and ideas for nonprofits seeking to enhance their online marketing and fundraising efforts.
Introduction to TechSoup’s Digital Marketing Services and Use Cases
Introduction to TechSoup’s Digital Marketing Services and Use Cases
TechSoup
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mole of NaOH= 12/40 =0.3 so molarity = 0.3/1.8 = 0.167 so ans B) 0.167 Solution mole of NaOH= 12/40 =0.3 so molarity = 0.3/1.8 = 0.167 so ans B) 0.167.
mole of NaOH= 1240 =0.3 so molarity = 0.31.8 = .pdf
mole of NaOH= 1240 =0.3 so molarity = 0.31.8 = .pdf
anupamele
millimoles of HBr=50*0.04=2 millimoles of KOH=25*.107=2.675 millimoles of acid remaining=0 millimoles of base remaining=0.675 Kb=[OH-][K+]/[KOH] 1=[OH-]*2/0.675 [oh-]=0.675/2 =0.3375 pH=14+log(0.3375) =13.53 Solution millimoles of HBr=50*0.04=2 millimoles of KOH=25*.107=2.675 millimoles of acid remaining=0 millimoles of base remaining=0.675 Kb=[OH-][K+]/[KOH] 1=[OH-]*2/0.675 [oh-]=0.675/2 =0.3375 pH=14+log(0.3375) =13.53.
millimoles of HBr=500.04=2 millimoles of KOH=25.pdf
millimoles of HBr=500.04=2 millimoles of KOH=25.pdf
anupamele
initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L Solution initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L.
initially 2 moles of HCl per L of water suppose x.pdf
initially 2 moles of HCl per L of water suppose x.pdf
anupamele
i cant see the question.. please post the complete question so dat i can provide uthe best possible answer..... Solution i cant see the question.. please post the complete question so dat i can provide uthe best possible answer......
i cant see the question.. please post the complet.pdf
i cant see the question.. please post the complet.pdf
anupamele
hey pls give the reactions.... Solution hey pls give the reactions.....
hey pls give the reactions.... .pdf
hey pls give the reactions.... .pdf
anupamele
FT-Raman spectra of some calcium phosphates, calcium carbonate and calcium hydroxide are reported. Comparing with dispersive Raman spectra, it is shown that some strong bands in the FT-Raman spectra of these compounds which have been erroneously assigned to Ramanbands, are in fact fluorescence emission bands. The origin of these fluorescencebands have been discussed in terms of rare earth impurities in a particular structure. It is further concluded that in using FT-Raman spectroscopy of minerals, care should be taken in not confusing the fluorescencebands with Raman scattering bands. Among instrumental techniques, fluorescence spectroscopy is recognized as one of the more sensitive. In fluorescence, the intensity of the emission of the sample is measured. The reason for the high sensitivity of fluorescence techniques is that the emission signal is measured above a low background level. This is inherently more sensitive than comparing two relatively large signals as in absorption spectroscopy. The sensitivity of fluorescence techniques is as much as 1000 times more sensitive than absorption spectroscopy. A spectrofluorometer with high sensitivity is an asset for the researcher. It is obvious that an instrument with high sensitivity will be able to perform experiments with the fluorescing species at a low concentration. For analytical measurements, sensitivity determines the detection limit of a material. For research in life science, it may be important to work at concentration levels that are very low. This is almost always the case in biomedical research. A more subtle requirement is the need to measure changes in fluorescence during the course of an experiment. Even though the gross signal levels may be high, the changes in the signal may be quite small. The ability to reliably measure these small changes is directly dependent upon the sensitivity of the fluorometer. The measurement of sensitivity has been discussed in the literature [1]. Unfortunately, there is little consensus on a standard procedure for determining this important capability. This paper discusses the measurement of sensitivity and details two methods that are applicable to any instrument. The Spectrofluorometer The sensitivity of fluorescence is dependent on both the fluorophore and the instrument. The response of a fluorophore will depend on the molar absorptivity and the quantum yield. These factors are, in general, beyond the control of the analyst. The sensitivity of a spectrofluorometer depends on a number of factors. Instrumental contributions to sensitivity are described below. 1. Source intensity. In general, a brighter excitation source will result in brighter emission. The source for most fluorometers is a xenon arc, which has a high intensity between 200-900 nm, the spectral region where most fluorescence experiments are performed. While a high power arc lamp is good for highest intensity, a more important criteria is the brightness of the lamp. The brightness.
FT-Raman spectra of some calcium phosphates, calc.pdf
FT-Raman spectra of some calcium phosphates, calc.pdf
anupamele
H is oxidised here no O2 is not oxidised as it gains electrons yes Cu is reduced here Solution H is oxidised here no O2 is not oxidised as it gains electrons yes Cu is reduced here.
H is oxidised here no O2 is not oxidised as it g.pdf
H is oxidised here no O2 is not oxidised as it g.pdf
anupamele
Current Stock price = Expected dividend / (Required rate of return - Growth rate) = $2.54 / (11% - 3.50%) = $2.54 / 7.50% = $33.87 Current Stock price is $33.87. Solution Current Stock price = Expected dividend / (Required rate of return - Growth rate) = $2.54 / (11% - 3.50%) = $2.54 / 7.50% = $33.87 Current Stock price is $33.87..
Current Stock price = Expected dividend (Required rate of return -.pdf
Current Stock price = Expected dividend (Required rate of return -.pdf
anupamele
YES the news stories in the Illustrated American sympathetic or non-sympathetic to the cause of the strikers. The Homestead Strike - this was at the Homestead Steel Works, owned by Andrew Carnegie but run by Henry Clay Frick. Labor went on strike because of pay rates that were continually adjusted down as well as poor working conditions. Carnegie was in Scotland at this time and Frick was the man on the spot and in charge. A miscommunication between these two resulted in Frick using too much force to suppress the strikers. Labor was responsible for the strike, but Frick (and maybe Carnegie) were resposible for subsequent events and deaths. The Homestead strike was organized and purposeful, a harbinger of the type of strike which would mark the modern age of labor relations in the United States. The AA strike at the Homestead steel mill in 1892 was different from previous large-scale strikes in American history such as the Great railroad strike of 1877 or the Great Southwest Railroad Strike of 1886. Earlier strikes had been largely leaderless and disorganized mass uprisings of workers. The AFL refused to call for a boycott of Carnegie products in September 1892. Wholesale crossing of the picket line occurred, first among Eastern European immigrants and then among all workers. The strike had collapsed so much that the state militia pulled out on October 13, ending the 95-day occupation. The AA was nearly bankrupted by the job action. Weekly Union relief for a member averaged $6.25 but totalled a staggering $10,000 per week when including 1,600 strikers. With only 192 out of more than 3,800 strikers in attendance, the Homestead chapter of the AA voted, 101 to 91, to return to work on November 20, 1892. Solution YES the news stories in the Illustrated American sympathetic or non-sympathetic to the cause of the strikers. The Homestead Strike - this was at the Homestead Steel Works, owned by Andrew Carnegie but run by Henry Clay Frick. Labor went on strike because of pay rates that were continually adjusted down as well as poor working conditions. Carnegie was in Scotland at this time and Frick was the man on the spot and in charge. A miscommunication between these two resulted in Frick using too much force to suppress the strikers. Labor was responsible for the strike, but Frick (and maybe Carnegie) were resposible for subsequent events and deaths. The Homestead strike was organized and purposeful, a harbinger of the type of strike which would mark the modern age of labor relations in the United States. The AA strike at the Homestead steel mill in 1892 was different from previous large-scale strikes in American history such as the Great railroad strike of 1877 or the Great Southwest Railroad Strike of 1886. Earlier strikes had been largely leaderless and disorganized mass uprisings of workers. The AFL refused to call for a boycott of Carnegie products in September 1892. Wholesale crossing of the picket line occurred, first among Eastern European i.
YES the news stories in the Illustrated American sympathetic or non-.pdf
YES the news stories in the Illustrated American sympathetic or non-.pdf
anupamele
Well its quite an easy one. The given curve is a cardioid. The limits of theta, unless otherwise mentioned is always from 0 to . The secret to finding it is that, cos=(r-4)/3 . So for any value of r in polar coordinate, (r-4)/3 will give some value. But we know cos=cos(2-), so the same value wil be given by and 2- . So if we put =2-, we get = which is maximum range for non repeatation of r values. A simpler way to find the range is: You get the minimum value of r at cos=-1, so minimum r=1. So range of r must be from 1 to 4 + 3cos. r is minimm at = and maximum of r is when cos=1 that is =0. So your can range from 0 to . However, integrating from 0 to will only give you half the area ( upper part of curve). So multiply the answer with 2 to get the full area. Solution Well its quite an easy one. The given curve is a cardioid. The limits of theta, unless otherwise mentioned is always from 0 to . The secret to finding it is that, cos=(r-4)/3 . So for any value of r in polar coordinate, (r-4)/3 will give some value. But we know cos=cos(2-), so the same value wil be given by and 2- . So if we put =2-, we get = which is maximum range for non repeatation of r values. A simpler way to find the range is: You get the minimum value of r at cos=-1, so minimum r=1. So range of r must be from 1 to 4 + 3cos. r is minimm at = and maximum of r is when cos=1 that is =0. So your can range from 0 to . However, integrating from 0 to will only give you half the area ( upper part of curve). So multiply the answer with 2 to get the full area..
Well its quite an easy one. The given curve is a cardioid. The limit.pdf
Well its quite an easy one. The given curve is a cardioid. The limit.pdf
anupamele
Total ionic Equation is : 2Cu2+ +4 Cl - + 4H+ +SO42- ---> Cu2SiO4+ 4H+ + 4Cl- Spectator ions are : H+ & Cl - Spectator ions are : H+ & Cl - Net ionic Equation is : 2Cu2+ + SO42- --->Cu2SiO4 Solution Total ionic Equation is : 2Cu2+ +4 Cl - + 4H+ +SO42- ---> Cu2SiO4+ 4H+ + 4Cl- Spectator ions are : H+ & Cl - Spectator ions are : H+ & Cl - Net ionic Equation is : 2Cu2+ + SO42- --->Cu2SiO4.
Total ionic Equation is 2Cu2+ +4 Cl - + 4H+ +SO42- --- Cu2SiO4+ 4.pdf
Total ionic Equation is 2Cu2+ +4 Cl - + 4H+ +SO42- --- Cu2SiO4+ 4.pdf
anupamele
Answer: SOCS are the supressor of cytokine signaling proteins and are negative feedback regulators of JAK-STAT signaling pathway. It means the SOCS are inhibitors of activation of JAK-STAT pathway proteins. As JAK-STAT pathway plays essential roles in initiation and development of cancers, mutation in SOCS family proteins could be one of the mechanism of abnormal activation of STAT . The expression of SOCS are inversly related to the STAT-3 activation. Hence overexpression of SOCS may not be lead to cancer risk. Overexpression of SOCS may supress the cytokine signaling or inhibit cytokine signaling by (i) Blocking STAT recruitment to the cytokine receptor (ii) may target protein for degradation (iii) bind to JAK and inhibit their kinase (iv) target JAK for degradation via proteosome pathway Solution Answer: SOCS are the supressor of cytokine signaling proteins and are negative feedback regulators of JAK-STAT signaling pathway. It means the SOCS are inhibitors of activation of JAK-STAT pathway proteins. As JAK-STAT pathway plays essential roles in initiation and development of cancers, mutation in SOCS family proteins could be one of the mechanism of abnormal activation of STAT . The expression of SOCS are inversly related to the STAT-3 activation. Hence overexpression of SOCS may not be lead to cancer risk. Overexpression of SOCS may supress the cytokine signaling or inhibit cytokine signaling by (i) Blocking STAT recruitment to the cytokine receptor (ii) may target protein for degradation (iii) bind to JAK and inhibit their kinase (iv) target JAK for degradation via proteosome pathway.
AnswerSOCS are the supressor of cytokine signaling proteins and a.pdf
AnswerSOCS are the supressor of cytokine signaling proteins and a.pdf
anupamele
The pre-mRNA is converted into mature mRNA by modifications known as post-transcriptional modifications. The three main modifications involved are Solution The pre-mRNA is converted into mature mRNA by modifications known as post-transcriptional modifications. The three main modifications involved are.
The pre-mRNA is converted into mature mRNA by modifications known as.pdf
The pre-mRNA is converted into mature mRNA by modifications known as.pdf
anupamele
CH3CH2OH will have high boiling point becauseof the presence of hydrogen bonding in it (O-H) Solution CH3CH2OH will have high boiling point becauseof the presence of hydrogen bonding in it (O-H).
CH3CH2OH will have high boiling point becauseof t.pdf
CH3CH2OH will have high boiling point becauseof t.pdf
anupamele
SO4 would have isolated (unlinked) tetrahedra that are all oxygen anions that are have some sort of metal bound to them. for example Mg2SiO4, Fe2SiO4 I believe it would be called a nesosilicates or orthosilicate. Solution SO4 would have isolated (unlinked) tetrahedra that are all oxygen anions that are have some sort of metal bound to them. for example Mg2SiO4, Fe2SiO4 I believe it would be called a nesosilicates or orthosilicate..
SO4 would have isolated (unlinked) tetrahedra that are all oxygen an.pdf
SO4 would have isolated (unlinked) tetrahedra that are all oxygen an.pdf
anupamele
//Tested on Eclipse /****************Equivalence.java*************/ package chegg; import java.util.Scanner; public class Equivalence { /*Income tax calculation method*/ public void calculateTax(double income){ double tax=0; /*Based on provided data in question*/ if(income<10){ tax=tax+0; }else if(income>=10 && income<20){ tax=tax+(income*10)/100; }else if(income>=20 && income<40){ /*add 10 % of 10k means 1k needs to be added in tax*/ tax=tax+1+((income-20)*12)/100; }else if(income>=40 && income<80){ /*add 10 % of 10k means 1k and 12% of 20k needs to be added in tax*/ tax=tax+1+2.4+((income-40)*15)/100; }else if(income>=80){ /*add 10 % of 10k means 1k and 12% of 20k and 15 % of 40k needs to be added in tax*/ tax=tax+1+2.4+6+((income-80)*20)/100; } System.out.println(\"Total Tax is: $\"+tax+\"K\"); } /*Main method start*/ public static void main(String args[]){ /*Variable declaration*/ double income; Scanner input=new Scanner(System.in); /*Class object creation*/ Equivalence equivalence=new Equivalence(); /*Prompt for income*/ System.out.println(\"Please Enter the income\"); income=input.nextDouble(); /*calling calculateTax method*/ equivalence.calculateTax(income); } } /************output***********/ Please Enter the income 25 Total Tax is: $1.6K Solution //Tested on Eclipse /****************Equivalence.java*************/ package chegg; import java.util.Scanner; public class Equivalence { /*Income tax calculation method*/ public void calculateTax(double income){ double tax=0; /*Based on provided data in question*/ if(income<10){ tax=tax+0; }else if(income>=10 && income<20){ tax=tax+(income*10)/100; }else if(income>=20 && income<40){ /*add 10 % of 10k means 1k needs to be added in tax*/ tax=tax+1+((income-20)*12)/100; }else if(income>=40 && income<80){ /*add 10 % of 10k means 1k and 12% of 20k needs to be added in tax*/ tax=tax+1+2.4+((income-40)*15)/100; }else if(income>=80){ /*add 10 % of 10k means 1k and 12% of 20k and 15 % of 40k needs to be added in tax*/ tax=tax+1+2.4+6+((income-80)*20)/100; } System.out.println(\"Total Tax is: $\"+tax+\"K\"); } /*Main method start*/ public static void main(String args[]){ /*Variable declaration*/ double income; Scanner input=new Scanner(System.in); /*Class object creation*/ Equivalence equivalence=new Equivalence(); /*Prompt for income*/ System.out.println(\"Please Enter the income\"); income=input.nextDouble(); /*calling calculateTax method*/ equivalence.calculateTax(income); } } /************output***********/ Please Enter the income 25 Total Tax is: $1.6K.
Tested on EclipseEquivalence.java.pdf
Tested on EclipseEquivalence.java.pdf
anupamele
Psychotherapy is the utilization of mental techniques, especially when in light of general individual collaboration, to help a man change and conquer issues in coveted ways. Psychotherapy intends to enhance an individual\'s prosperity and psychological well-being, to determine or relieve troublesome practices, convictions, impulses, considerations, or feelings, and to enhance connections and social abilities. Certain psychotherapies are considered proof based for treating some analyzed mental issue. 1. Concentrate on influence and articulation of feeling. Psychodynamic treatment empowers investigation also, discourse of the full scope of a patient\'s feelings. The specialist helps the patient depict and put words to emotions, counting conflicting emotions, sentiments that are upsetting or undermining, and emotions that the patient may not at first have the capacity to perceive or recognize (this remains rather than an intellectual concentration, where the more prominent accentuation is on musings and convictions; Blagys and Hilsenroth, 2002) There is likewise an acknowledgment that scholarly understanding is not the same as passionate understanding, which resounds at a profound level and prompts to change (this is one motivation behind why numerous clever and mentally disapproved of individuals can clarify the explanations behind their dif- ficulties, yet their comprehension does not help them overcome those challenges). 2. Investigation of endeavors to abstain from upsetting considerations and emotions. Individuals do an awesome numerous things, intentionally and unconsciously, to maintain a strategic distance from perspectives of experience that are disturbing. This evasion (in hypothetical terms, protection and resistance) may take coarse structures, for example, missing sessions, arriving late, or being shifty. It might take unobtrusive structures that are hard to perceive in normal social talk, for example, inconspicuous movements of theme when certain thoughts emerge, concentrating on accidental parts of an affair instead of on what is mentally significant, taking care of truths and occasions to the rejection of effect, concentrating on outer conditions as opposed to one\'s own part in forming occasions, thus on.Psychodynamic specialists effectively concentrate on and investigate shirkings. 3. Distinguishing proof of repeating topics and designs. Psychodynamic advisors work to distinguish what\'s more, investigate repeating topics and examples in patients\' contemplations, sentiments, self-idea, connections, and beneficial encounters. Now and again, a patient might be intensely mindful of repeating designs that are agonizing or self-vanquishing yet feel not able to escape them (e.g., a man who over and over finds himself attracted to sentimental accomplices who are sincerely inaccessible; a lady who consistently attacks herself at the point when achievement is close by). In different cases, the patient might be unconscious of the exampl.
Psychotherapy is the utilization of mental techniques, especially wh.pdf
Psychotherapy is the utilization of mental techniques, especially wh.pdf
anupamele
let E>0 be given there exists d1,d2 >0 such that |f(x)-L| lim f(x) = L as x tends to a thus proved Solution let E>0 be given there exists d1,d2 >0 such that |f(x)-L| lim f(x) = L as x tends to a thus proved.
let E0 be giventhere exists d1,d2 0 such thatf(x)-L E for 0.pdf
let E0 be giventhere exists d1,d2 0 such thatf(x)-L E for 0.pdf
anupamele
import java.util.ArrayList; import java.util.List; public class SearchList { /** * param args */ public static void main(String[] args) { List list = new ArrayList(); list.add(3); list.add(3); list.add(1); System.out.println(\"Search element 3 in list [3,3,1] :\" + search(list, 3)); System.out.println(\"Search element 5 in list [3,3,1] :\" + search(list, 5)); } /** * method to find the index of element in the list * param list * param element * return */ public static int search(List list, Object element) { int index = -1; if (list == null || element == null) throw new NullPointerException(); else { int searchElement = (int) element; for (int i = 0; i < list.size(); i++) { int number = (int) list.get(i); if (number == searchElement) { index = i; } } } return index; } } OUTPUT: Search element 3 in list [3,3,1] :1 Search element 5 in list [3,3,1] :-1 Solution import java.util.ArrayList; import java.util.List; public class SearchList { /** * param args */ public static void main(String[] args) { List list = new ArrayList(); list.add(3); list.add(3); list.add(1); System.out.println(\"Search element 3 in list [3,3,1] :\" + search(list, 3)); System.out.println(\"Search element 5 in list [3,3,1] :\" + search(list, 5)); } /** * method to find the index of element in the list * param list * param element * return */ public static int search(List list, Object element) { int index = -1; if (list == null || element == null) throw new NullPointerException(); else { int searchElement = (int) element; for (int i = 0; i < list.size(); i++) { int number = (int) list.get(i); if (number == searchElement) { index = i; } } } return index; } } OUTPUT: Search element 3 in list [3,3,1] :1 Search element 5 in list [3,3,1] :-1.
import java.util.ArrayList; import java.util.List;public class S.pdf
import java.util.ArrayList; import java.util.List;public class S.pdf
anupamele
Heterotrophic bacteria is not able to lead the planktonic way of life as heterotrophic bacteria are unable to produce their own food where as planktons are able to produce their own food with the help of sunlight by a process called photosynthesis. Heterotrophic bacteria depends on source of organic carbon and derives its energy by the break down of the organic carbon. Solution Heterotrophic bacteria is not able to lead the planktonic way of life as heterotrophic bacteria are unable to produce their own food where as planktons are able to produce their own food with the help of sunlight by a process called photosynthesis. Heterotrophic bacteria depends on source of organic carbon and derives its energy by the break down of the organic carbon..
Heterotrophic bacteria is not able to lead the planktonic way of lif.pdf
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add more chloride ions .pdf
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