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initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L Solution initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L.

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initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L Solution initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L

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  • 1. initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L Solution initially 2 moles of HCl per L of water suppose x L of water is added more final Molarity =2/(x+1)=.1 =>x=20-1=19L