Since They are not Divisible by any other number and are divisible 1.pdf

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Since They are not Divisible by any other number and are divisible 1 and themselves. B:Prime numbers Solution Since They are not Divisible by any other number and are divisible 1 and themselves. B:Prime numbers.

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The disclosure requirements for the assignment of specific receivables include reporting them separately as a current asset, but it does not include presenting the equity in assigned accounts parenthetically or in a note. Solution The disclosure requirements for the assignment of specific receivables include reporting them separately as a current asset, but it does not include presenting the equity in assigned accounts parenthetically or in a note..

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HPLC, is a chromatographic technique used to separate a mixture of compounds in analytical chemistry and biochemistry with the purpose of identifying, quantifying and purifying the individual components of the mixture. Some common examples are the separation and quantitation of performance enhancement drugs (e.g. steroids) in urine samples, or of vitamin D levels in serum. HPLC typically utilizes different types of stationary phases (i.e. sorbents) contained in columns, a pump that moves the mobile phase and sample components through the column, and a detector capable of providing characteristic retention times for the sample components and area counts reflecting the amount of each analyte passing through the detector. The detector may also provide additional information related to the analyte, (i.e. UV/Vis spectroscopic data, if so equipped). Analyte retention time varies depending on the strength of its interactions with the stationary phase, the composition and flow rate of mobile phase used, and on the column dimensions. HPLC is a form of liquid chromatography that utilizes small size columns (typically 250 mm or shorter and 4.6 mm i.d. or smaller; packed with smaller particles), and higher mobile phase pressures compared to ordinary liquid chromatography. Solution HPLC, is a chromatographic technique used to separate a mixture of compounds in analytical chemistry and biochemistry with the purpose of identifying, quantifying and purifying the individual components of the mixture. Some common examples are the separation and quantitation of performance enhancement drugs (e.g. steroids) in urine samples, or of vitamin D levels in serum. HPLC typically utilizes different types of stationary phases (i.e. sorbents) contained in columns, a pump that moves the mobile phase and sample components through the column, and a detector capable of providing characteristic retention times for the sample components and area counts reflecting the amount of each analyte passing through the detector. The detector may also provide additional information related to the analyte, (i.e. UV/Vis spectroscopic data, if so equipped). Analyte retention time varies depending on the strength of its interactions with the stationary phase, the composition and flow rate of mobile phase used, and on the column dimensions. HPLC is a form of liquid chromatography that utilizes small size columns (typically 250 mm or shorter and 4.6 mm i.d. or smaller; packed with smaller particles), and higher mobile phase pressures compared to ordinary liquid chromatography..

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evo-devo stands for Evolutionary developmental biology (It compares the developmental processes of different organisms to infer the ancestral relationships between them and how developmental processes evolved.) Solution evo-devo stands for Evolutionary developmental biology (It compares the developmental processes of different organisms to infer the ancestral relationships between them and how developmental processes evolved.).

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B. Cryptanalysis is the act of obtaining plain text from cipher text without a key. Cryptanalysis is the study of breaking encryption systems. Although it can mean obtaining the plain text from the cipher text without a key, it can also mean that the cryptosystem was cracked because someone found a weakness in the cryptosystem’s implementation. Such was the case with wired equivalent privacy (WEP). Solution B. Cryptanalysis is the act of obtaining plain text from cipher text without a key. Cryptanalysis is the study of breaking encryption systems. Although it can mean obtaining the plain text from the cipher text without a key, it can also mean that the cryptosystem was cracked because someone found a weakness in the cryptosystem’s implementation. Such was the case with wired equivalent privacy (WEP)..

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ANS: import java.util.Scanner; class Bina_node { Bina_node l_1, r_1; int dt;//here declare variables public Bina_node()//constructor { l_1 = null; r_1 = null; dt = 0; } public Bina_node(int n)//here parameter constractor { l_1 = null; r_1 = null; dt = n; } public void nin_left(Bina_node n)//copy constractor { l_1 = n; } public void nin_right(Bina_node n) { r_1 = n; } public Bina_node get_lstf() { return l_1; } public Bina_node get_go() { return r_1; } public void set_data(int d) { dt = d; } public int get_data() { return dt; } } class Bina_tree//class banary tree { private Bina_node rf; public Bina_tree() { rf = null; } public boolean isEmpty()//here empty or not { return rf == null; } public void tee_insert(int dt) { rf = tee_insert(rf, dt); } private Bina_node tee_insert(Bina_node node, int dt) { if (node == null) node = new Bina_node(dt); else { if (node.get_go() == null) node.r_1 = tee_insert(node.r_1, dt); else node.l_1 = tee_insert(node.l_1, dt); } return node; } public int cou_Node() { return cou_Node(rf); } private int cou_Node(Bina_node r) { if (r == null) return 0; else { int l = 1; l += cou_Node(r.get_lstf()); l += cou_Node(r.get_go()); return l; } } public boolean bin_serc(int tree_val)//function called { return bin_serc(rf, tree_val); } private boolean bin_serc(Bina_node r, int tree_val) { if (r.get_data() == tree_val) return true; if (r.get_lstf() != null) if (bin_serc(r.get_lstf(), tree_val)) return true; if (r.get_go() != null) if (bin_serc(r.get_go(), tree_val)) return true; return false; } public void in_order() { in_order(rf); } private void in_order(Bina_node r) { if (r != null) { in_order(r.get_lstf()); System.out.print(r.get_data() +\" \"); in_order(r.get_go()); } } public void pre_order() { pre_order(rf); } private void pre_order(Bina_node r) { if (r != null) { System.out.print(r.get_data() +\" \"); pre_order(r.get_lstf()); pre_order(r.get_go()); } } public void post_order() { post_order(rf); } private void post_order(Bina_node r) { if (r != null) { post_order(r.get_lstf()); post_order(r.get_go()); System.out.print(r.get_data() +\" \"); } } } public class Bina_Tree//binary tree class { public static void main(String[] args)//here main methode { Scanner sc = new Scanner(System.in);//here scanner Bina_tree bin_c = new Bina_tree(); System.out.println(\"Binary Tree \ \"); char ch; do { System.out.println(\"\ here Binary Tree Operations\ \"); System.out.println(\"1 for insert 2 for search 3 for count 4 for check\");//here choice numbers int cho = sc.nextInt(); int k; switch (cho) { k++; case 1 :System.out.println(\"please enter insert ele\"); bin_c.tee_insert( sc.nextInt() ); break; case 2 :System.out.println(\"enter bin_search\");//here search option System.out.println(\"result\"+ bin_c.bin_serc( sc.nextInt() ));//result break; case 3 :System.out.println(\"Nodes\"+ bin_c.cou_Node()); break; case 4 :System.out.println(\"Empty\"+ bin_c.isEmpty()); break; default ://here default condition System.out.println(\"enter 1 TO 4 only.

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30.metaphase. It is the second phase of mitosis. Ith the help of spindle fibers chromosomes line up in the middle 31.salts and atp 32.active transport .ebergybin the form of atp is utilised. 33.haploid. Always half the number of chromosomes are produced from gametes 34.diffusion of water across a membrane from low concentration to high concentration 35.diploid 36. CO2 and O2. Gas molecules are extremely small and can pass. Whereas proteins cannot pass. 37.true Solution 30.metaphase. It is the second phase of mitosis. Ith the help of spindle fibers chromosomes line up in the middle 31.salts and atp 32.active transport .ebergybin the form of atp is utilised. 33.haploid. Always half the number of chromosomes are produced from gametes 34.diffusion of water across a membrane from low concentration to high concentration 35.diploid 36. CO2 and O2. Gas molecules are extremely small and can pass. Whereas proteins cannot pass. 37.true.

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