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NOVEL LESSON TEMPLATE
I LESSON TEMPLATE I 
Name of the Teacher: Divya P.R 
N arne of the School : Model School 
Name of the Subject: Mathematics 
Name of the Unit mJ~mnuo6lJJc£Mro 
Name of the Topic mJ~mnuo6lJJ(D)16)(~.1 6)nJJcmacmcmJ6OBcro 
Curricular Statement: 
CONTENT ANALYSIS 
Term 
Concept 
Equation 
-x+( -y) = -x-y = -(x+y) 
x-(-y) = x+y 
-x-( -y) = -x+y 
Standard 
Strength 
Date 
Time 
VIII 
·· 15 
·· 25.09.2014 
45 Min.
LEARNING OUTCOME 
The student will be able to, 
~ recall the information about negative numbers 
~ interpret the concept of negative number 
~ explain the peculiarities of negative numbers 
~ use the above concept in another familiar situation 
~ judge the appropriateness of above concept in another familiar situation. 
~ perfonn computation skill. 
~ accept the beauty of mathematics 
PRE-REQUISITES 
TEACHING-LEARNING RESOURCES 
Charts
CLASSROOM INTERACTION PROCEDURE 
Introduction 
cmaWjJoJ18 8SlaLO cmaru(O)(()1&1l.g,J36)8J6Tl5u ~Jm) <m0(()olSlOO3CTD3. 
1. 6JU)Jml ffi)o61.lj8~36)S CD6TD9J6TDu 
oJ~gjj<UTIDlm3 @S(O)3ru<fO<UTIDJ6TDu 
n{J)CTD36)S ml.OJmo 
ffi) 0 61.Ij 8 (f{) 8 ~ S 3!8 (TO) JO 3 0 
n{J)CTD36)S ruleJ 830CQ)3!89 
6JU)JmJ6)(()CTD 
u 
oJOCQ)J!8ldJ ? 
2. n{J)CTD36)S ruleJ -10 
mlCTD36)S ruleJ - 20 
mm(f{) 63CTD3!8.Q..(OCTDJaJO 
mm36)S ruleJ6)CQ)(TO)u ? 
3. 63!8CTD CD36TDmo 63CTDu 63CTDJ6TTl!8~ 
(()!8 6Tl5 CD 3 6TTl mo (() 6Tl5U m J eJ J6TTl!8 ~ 
- 2 CD36TTlmo - 2 n{J)l(O) ? 
Presentation 
EXPECTED PUPIL RESPONSE 
-30 
4
CLASSROOM INTERACTION PROCEDURE 
Activity 1 
anawj)nJlca.2.l)ro§' lnJr3rouol&ll.gJ' nJ§lca nJ~roool(Q))cOO3ruJ('r6 «3lQ)ruUOj6)&lS3(ffi3. 
81. 
No 
x y 
1. n$(ffi36)S rul~ n$(ffi36)S rul~(8(Q)) 
2 
3 y-I 
-1 (x-I) 
n$(ffi36)S rul~ 
x+4 
6TO))m) 4 
-x -y -x+(-y) -x-y -(x+y) 
-x+( -y) = -x-y = (X+y) «3lQ)6)6Tn(ffiu anawj)nJlca(Q)36)S m.ln.O)(Q)(800)6)S ca3§lcacrO ca6)6mOO3(ffi3. 
Activity 11 
anawj)nJlca .2.l)ro§, lnJr3rouol&ll.gJ' nJ§lca nJ~roool(Q))cOO)m) «3lQ)ruUOj6)&lS3(ffi3. 
x y -x -y x-(-y) x+y -x-(-y) -(x+y) 
4 2 
6 2 
-4 -2 
-6 -2 
EXPECTED PUPIL RESPONSE 
ca3§lcacrO nJ§lca nJ~roool(Q))cOO3(ffi3
CLASSROOM INTERACTION PROCEDURE 
CO'l3smcm3~ .!llm.g:l(Q)leJ~61S(Q)3o rulU081&Ml6mamJ)leJ~61S(Q)3o x, Y n(pcmlru n@co) CTUo6l.lj8® 
®0(Q))eJ3o x -( -y) = x+y ~o -x -( -y) = -x+y ~o ®0616mcmu «rrOwj)nJ18(Q)361S CTUnD)(Q)(8amJ))61S 
83§18® 8616mamJ)3cm3. 
CO'l3smcmu «rrOwj)nJ18 .!ll)m§u LnJ8muol&l1oo3cm3. 
mJ~mamJ)l6)eJ 6)nJJ<Ula <UlCOU6UT3uO 
X,Y n(pcml CTUo6l.lj8®OO 
1. -x+-y = -x-y = -(x+y) 
2. x-( -y) = x+y 
3. -x-( -y) = -x+y 
APPLICATION/REVIEW (LUl~n~r f2mruCOoj 
1. x = 28, y = -8 ®0(Q))raO 
-x+(-y) = -x-y = -(x+y) 
®0616mcma 6lCO'l§1(Q)loo38 
2. x = 28, y = 5 ®0(Q))raO 
x-(-y) = x+y 
®0616mcm3 6lCO'l§1(Q)looa8 
EXPECTED PUPIL RESPONSE 
1. -x+( -y) = -28+8 = -20 
-x-y = -28+8 = -20 
-(x+y) = -(28-8) = -20 
-x+(-y) = -x-y = -(x+y) 
2.
FOLLOWUP ACTIVITY 
1. X = -36, y = 48 «fl0CW)roO -x- (-y) = -x + y «fl06)6Tnonu 6)(O)~lcwloo68 
2. X = -536, Y = 288 «fl06)6TnEalam -x + (-y) = -x -y = - (x + y) «fl06)6Tnonu 6)(O)gJlcwloo68 
.~.

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Novel lesson template

  • 2. I LESSON TEMPLATE I Name of the Teacher: Divya P.R N arne of the School : Model School Name of the Subject: Mathematics Name of the Unit mJ~mnuo6lJJc£Mro Name of the Topic mJ~mnuo6lJJ(D)16)(~.1 6)nJJcmacmcmJ6OBcro Curricular Statement: CONTENT ANALYSIS Term Concept Equation -x+( -y) = -x-y = -(x+y) x-(-y) = x+y -x-( -y) = -x+y Standard Strength Date Time VIII ·· 15 ·· 25.09.2014 45 Min.
  • 3. LEARNING OUTCOME The student will be able to, ~ recall the information about negative numbers ~ interpret the concept of negative number ~ explain the peculiarities of negative numbers ~ use the above concept in another familiar situation ~ judge the appropriateness of above concept in another familiar situation. ~ perfonn computation skill. ~ accept the beauty of mathematics PRE-REQUISITES TEACHING-LEARNING RESOURCES Charts
  • 4. CLASSROOM INTERACTION PROCEDURE Introduction cmaWjJoJ18 8SlaLO cmaru(O)(()1&1l.g,J36)8J6Tl5u ~Jm) <m0(()olSlOO3CTD3. 1. 6JU)Jml ffi)o61.lj8~36)S CD6TD9J6TDu oJ~gjj<UTIDlm3 @S(O)3ru<fO<UTIDJ6TDu n{J)CTD36)S ml.OJmo ffi) 0 61.Ij 8 (f{) 8 ~ S 3!8 (TO) JO 3 0 n{J)CTD36)S ruleJ 830CQ)3!89 6JU)JmJ6)(()CTD u oJOCQ)J!8ldJ ? 2. n{J)CTD36)S ruleJ -10 mlCTD36)S ruleJ - 20 mm(f{) 63CTD3!8.Q..(OCTDJaJO mm36)S ruleJ6)CQ)(TO)u ? 3. 63!8CTD CD36TDmo 63CTDu 63CTDJ6TTl!8~ (()!8 6Tl5 CD 3 6TTl mo (() 6Tl5U m J eJ J6TTl!8 ~ - 2 CD36TTlmo - 2 n{J)l(O) ? Presentation EXPECTED PUPIL RESPONSE -30 4
  • 5. CLASSROOM INTERACTION PROCEDURE Activity 1 anawj)nJlca.2.l)ro§' lnJr3rouol&ll.gJ' nJ§lca nJ~roool(Q))cOO3ruJ('r6 «3lQ)ruUOj6)&lS3(ffi3. 81. No x y 1. n$(ffi36)S rul~ n$(ffi36)S rul~(8(Q)) 2 3 y-I -1 (x-I) n$(ffi36)S rul~ x+4 6TO))m) 4 -x -y -x+(-y) -x-y -(x+y) -x+( -y) = -x-y = (X+y) «3lQ)6)6Tn(ffiu anawj)nJlca(Q)36)S m.ln.O)(Q)(800)6)S ca3§lcacrO ca6)6mOO3(ffi3. Activity 11 anawj)nJlca .2.l)ro§, lnJr3rouol&ll.gJ' nJ§lca nJ~roool(Q))cOO)m) «3lQ)ruUOj6)&lS3(ffi3. x y -x -y x-(-y) x+y -x-(-y) -(x+y) 4 2 6 2 -4 -2 -6 -2 EXPECTED PUPIL RESPONSE ca3§lcacrO nJ§lca nJ~roool(Q))cOO3(ffi3
  • 6. CLASSROOM INTERACTION PROCEDURE CO'l3smcm3~ .!llm.g:l(Q)leJ~61S(Q)3o rulU081&Ml6mamJ)leJ~61S(Q)3o x, Y n(pcmlru n@co) CTUo6l.lj8® ®0(Q))eJ3o x -( -y) = x+y ~o -x -( -y) = -x+y ~o ®0616mcmu «rrOwj)nJ18(Q)361S CTUnD)(Q)(8amJ))61S 83§18® 8616mamJ)3cm3. CO'l3smcmu «rrOwj)nJ18 .!ll)m§u LnJ8muol&l1oo3cm3. mJ~mamJ)l6)eJ 6)nJJ<Ula <UlCOU6UT3uO X,Y n(pcml CTUo6l.lj8®OO 1. -x+-y = -x-y = -(x+y) 2. x-( -y) = x+y 3. -x-( -y) = -x+y APPLICATION/REVIEW (LUl~n~r f2mruCOoj 1. x = 28, y = -8 ®0(Q))raO -x+(-y) = -x-y = -(x+y) ®0616mcma 6lCO'l§1(Q)loo38 2. x = 28, y = 5 ®0(Q))raO x-(-y) = x+y ®0616mcm3 6lCO'l§1(Q)looa8 EXPECTED PUPIL RESPONSE 1. -x+( -y) = -28+8 = -20 -x-y = -28+8 = -20 -(x+y) = -(28-8) = -20 -x+(-y) = -x-y = -(x+y) 2.
  • 7. FOLLOWUP ACTIVITY 1. X = -36, y = 48 «fl0CW)roO -x- (-y) = -x + y «fl06)6Tnonu 6)(O)~lcwloo68 2. X = -536, Y = 288 «fl06)6TnEalam -x + (-y) = -x -y = - (x + y) «fl06)6Tnonu 6)(O)gJlcwloo68 .~.