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a. Assuming complete dissociation, we can have [O.pdf

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a. Assuming complete dissociation, we can have [OH-] = 2.20x10-2 M... So, pOH= 1.657 Therefore, pH=12.342 [H30+]=4.54x10^-13M Solution a. Assuming complete dissociation, we can have [OH-] = 2.20x10-2 M... So, pOH= 1.657 Therefore, pH=12.342 [H30+]=4.54x10^-13M.

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a. Assuming complete dissociation, we can have [OH-] = 2.20x10-2 M... So, pOH= 1.657 Therefore, pH=12.342 [H30+]=4.54x10^-13M Solution a. Assuming complete dissociation, we can have [OH-] = 2.20x10-2 M... So, pOH= 1.657 Therefore, pH=12.342 [H30+]=4.54x10^-13M

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a. Assuming complete dissociation, we can have [O.pdf

  • 1. a. Assuming complete dissociation, we can have [OH-] = 2.20x10-2 M... So, pOH= 1.657 Therefore, pH=12.342 [H30+]=4.54x10^-13M Solution a. Assuming complete dissociation, we can have [OH-] = 2.20x10-2 M... So, pOH= 1.657 Therefore, pH=12.342 [H30+]=4.54x10^-13M