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pH + pOH = 14
pOH = 4.5
[OH-] = 10-4.5
Fe(OH)2 <---> Fe2+ + 2 OH-
M M 2M
2M = 10-4.5
M = 0.5*10-4.5 = 1.58*10-5 mol/l
Right?
Solution
pH + pOH = 14
pOH = 4.5
[OH-] = 10-4.5
Fe(OH)2 <---> Fe2+ + 2 OH-
M M 2M
2M = 10-4.5
M = 0.5*10-4.5 = 1.58*10-5 mol/l
Right?

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pH + pOH = 14 pOH = 4.5 [OH-] = 10-4.5Fe(OH)2 --- Fe2+ + 2 O.pdf

  • 1. pH + pOH = 14 pOH = 4.5 [OH-] = 10-4.5 Fe(OH)2 <---> Fe2+ + 2 OH- M M 2M 2M = 10-4.5 M = 0.5*10-4.5 = 1.58*10-5 mol/l Right? Solution pH + pOH = 14 pOH = 4.5 [OH-] = 10-4.5 Fe(OH)2 <---> Fe2+ + 2 OH- M M 2M 2M = 10-4.5 M = 0.5*10-4.5 = 1.58*10-5 mol/l Right?