pH + pOH = 14 pOH = 4.5 [OH-] = 10-4.5 Fe(OH)2 <---> Fe2+ + 2 OH- M M 2M 2M = 10-4.5 M = 0.5*10-4.5 = 1.58*10-5 mol/l Right? Solution pH + pOH = 14 pOH = 4.5 [OH-] = 10-4.5 Fe(OH)2 <---> Fe2+ + 2 OH- M M 2M 2M = 10-4.5 M = 0.5*10-4.5 = 1.58*10-5 mol/l Right?.