Find an equation of the tangent line at the given point. So far, I have I know that the next step is to get the dy/dx on one side, then plug it into the tangent line equation, but I can\'t figure out how to do that since dy/dx is on both sides and seem to cancel each other out. Solution no need to get dy/dx on one side just substitute (0,pi) cos(-pi)(2-dy/dx) = 0 dy/dx = 2 hence m=2 y-pi = m(x-0) y-pi = 2x 2x-y+pi = 0.

1. Find an equation of the tangent line at the given point.
So far, I have
I know that the next step is to get the dy/dx on one side, then plug it into the tangent line
equation, but I can't figure out how to do that since dy/dx is on both sides and seem to cancel
each other out.
Solution
no need to get dy/dx on one side just substitute (0,pi) cos(-pi)(2-dy/dx) = 0 dy/dx =
2 hence m=2 y-pi = m(x-0) y-pi = 2x 2x-y+pi = 0