Find an equation of the line that has slope m and y-intercept b. (Le.pdf

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Find an equation of the line that has slope m and y-intercept b. (Let x be the independent variable and y be the dependent variable.) Solution y = (-1/2)x + (1/4) If you want the equation in standard form you can multiply by 4: 4y = -2x + 1 and get x and y on the same side: 2x + 4y = 1.

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Find a simplified form of the difference quotient.Then find the value of the difference quotient when x = 2 and h = 1. Type only this numerical value. f(x) = x^2 -1 Solution f(x) = x^2 -1 => f(x+h) = (x+h)^2 -1 = x^2 + 2xh + h^2 -1 Different quotient = lim h->0 [f(x+h) - f(x)]/h = lim h->0 [( x^2+2xh+h^2 -1) - (x^2-1) ]/h = lim h->0 [2xh +h^2]/h = lim h->0 (2x+h) = 2x When h=1 and x=2, difference quotient = 2x+ h = (2*2) +1 = 5.

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