Define and explain chemical equilibrium Include the defenition o.pdf

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Define and explain chemical equilibrium? Include the defenition of reactants and products Define and explain chemical equilibrium? Include the defenition of reactants and products Solution In a chemical reaction, chemical equilibrium is the state in which both reactants and products are available at concentrations which have no further inclination to change with time. Usually, this state comes about when the forward reaction continues at an indistinguishable rate from the reverse reaction. The reaction rates of the forward and backward reactions are, for the most part, not zero, but rather equal. In this way, there are no net changes in the concentrations of the reactant(s) and product(s). Reactant: The substances that outcome from the recombination of molecules is known as the products of the reaction. At the point when chemical reactions are written down, the reactants are written on the left side, in a similar way to a math equation; one reactant in addition to another. Product: Products are the species formed from chemical reactions. Amid a chemical reaction, reactants are transformed into products in the wake of going through a high vitality transition state. Simply the substances that are formed after the reactions of reactant, due to making of new bonds in between the atoms/ions/molecules/compounds..

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most extra cellular environments contain a high concentration of sodium ions (Na+). consider a cell membrane that is permeable to potassium (K+) and is in equilibrium. the diffusion of K+ has left the inside of the ell slightly negatively charged and the outside slightly positively charged. suppose that the cell membrane now opens some sodium channels what happens? A) there is no flow across the membrane. the outside of the cell is positeely charged drivingthe sodium ions father away from the cell. B) there is no flow across the membrane. the cell is in equilibrim and so the electric repulsionof the Na+ exactly counters the effects of diffusion. C) the cell becomes positvely charged. both diffusion and the electric attraction to the cell drive into the cell D) the cell becomes positvely charged; diffusion is reversed and K+ are drived back into the cell Solution The cell becomes positively charged, diffusion is reversed and K+ are drived back into the cell..

most extra cellular environments contain a high concentration of sod.pdf

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Let X be the prive of a meal at a local diner( X = $8,$10,and $12) and let Y be the amount of tip left per meal (Y = $1.50,$2 or $2.50). the joint probability function of X and Y is given by a. Find f(X = 10, Y=2) and interpret what this value represents. c. Find the marginal distributions of X and Y. d. Determine if X and Y are independent Random Variables or not. Explain why or why not.f(x,y)Y=1.50Y=2.00Y=2.50X=8.3.120X=10.15.135.025X=12.03.15.09 Solution.

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LinearPerson.java Please help me the JAVA program Please provide the output. LinearPerson A LinearPerson lives on a number line. At any time, he or she has a position, such as 0 or 3 or -5. He or she can move one position at a time. He or she has a direction of movement. So if a LinearPerson is moving right and is at position -3, the new position will be -2. If a LinearPerson is moving left and is at position -3, the new position will be -4. The following describes the LinearPerson class: You should decide the instance variables needed for LinearPerson. Overloaded constructors: a no-argument constructor that sets the current position at 0 and the current direction as \"to the right.\" a constructor that takes one int as a parameter; the parameter represents the initial position of the LinearPerson methods: public void turn() // changes the direction of the LinearPerson (right to left, or left to right) public void move() // moves the LinearPerson one position in his or her current direction public int getPosition() // returns the current position of the LinearPerson As an example LinearPerson sophie = new LinearPerson(); // sophie is at position 0, moving right sophie.turn(); // sophie is at position 0, moving left sophie.move(); // sophie is at position -1, moving left sophie.move(); // sophie is at position -2, moving left sophie.turn(); // sophie is at position -2, moving right sophie.move(); // sophie is at position -1, moving right Create a class LinearPersonPairthat creates two LinearPerson objects, one using the no-argument constructor, the other object should be created at a given location. The program moves the objects in various directions and prints their final locations. Solution class LinearPerson { private String direction; // current direction private int position; // current position public static final String RIGHT = \"right\"; public static final String LEFT = \"left\"; // no arg constructor public LinearPerson() { this.position = 0; this.direction = LinearPerson.RIGHT; } //arg constructor LinearPerson(int position) { this.position = position; // setting the initial position if (position >= 0) { this.direction = LinearPerson.RIGHT; // setting the direction to right if position is >=0 } else { this.direction = LinearPerson.LEFT; // setting the direction to left if position is < 0 } } //get the curent direction public String getDirection() { return direction; } // get the current position public int getPosition() { return position; } // method to turn the direction public void turn(){ if(this.direction==LinearPerson.RIGHT){ this.direction=LinearPerson.LEFT; // set the direction to left if current direction is right }else{ this.direction=LinearPerson.RIGHT; // set the direction to left if current direction is right } } //method to move the position in current direction public void move(){ if(this.direction==LinearPerson.RIGHT){ this.position=this.position+1; // move the position to right }else{ this.position=this.position-1; //.

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C Language Problem Please Explain If int n1 = 5, and int d1 = 2, what are the results of the following operations? (assume double frac) frac = (double)n1/(double)d1;frac = (double)n1/d1 + 3.5; frac = (double)(n1/d1) + 2.5; Solution Here the heart of functionality is typecasting. What is typecasting? Type casting is a way to convert a variable from one data type to another data type. frac = (double)n1/(double)d1; n1 = 5 and d1 = 2 what this (double)n1/(double)d1 does.. here typecasting is preforming so (double)n1 = 5.000000 (double)d1 = 2.000000 frac = 5.000000/2.000000 frac = 2.500000 frac = (double)n1/d1 + 3.5; Here only n1 is typecasted into double so n1 is 5.000000 and d1 is 2 (double)n1/d1 + 3.5 => (5.000000 / 2) + 3.5 => 2.500000 + 3.5 => 6.000000 frac is 6.000000 frac = (double)(n1/d1) + 3.5; here there is no typecasting between n1 and d1 ... after division is perform then typecasting is going to applied so (double)(n1/d1) + 3.5 (double)(5/2) + 3.5 (double)(2) + 3.5 2.000000 + 3.5 5.500000 Answer is 5.500000.

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A saturated sample has a mass 0.69 kilograms when wet and 0.5 kg when dry. Assuming that the specific gravity is 2.7, compute the void ratio, porosity and dry density of this material. Solution water content (w) = (wet weight -dry weigt)/dry weight =(0.69-0.5)/0.5 =0.38 void ratio(e) = (wG)/s =0.38*2.7/1 =1.026 porosity=(e/(1+e)) =1.026/(1+1.026) =0.51 dry density=G*unit weight of water(1+e) =2.7*62.43/(1+1.026) =83.2 lb/ft3.

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