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SOLVING THE
BOLTZMANN
TRANSPORT
EQUATION:
DISPLACED-
MAXWELL
APPROXIMATION
Done by :
C.Alagu muthu akhila
• As you all know Boltzmann'sTransport equation has close
correspondence to the whole continuity
equation.Therefore, it can be regarded as a balance
conservation or continuity equation for the distribution
function.
• Let us discuss the ways of solving the distribution function
or ways of solving the Boltzmann'sTransport Equation or
working with the Boltzmann'sTransport Equation to get the
device current carrier concentration and so on .The first
approach, you can solve for n and Jn as follows;
• You solve for the function f from the Boltzmann'sTransport Equation
and derive n and Jn from this formula . In general even numerical
solution of Boltzmann'sTransport Equation is rather difficult because f
is a function of 7 variables. x, y, z, Px, Py, Pz and t.
• So when you look at a picture in 3 dimensions then you see the
distribution function really becomes complicated you are having 7
variables. If you look at in 1-dimension then you have only x and the Px
apart from t. But in 3 dimensions it is complicated. However, in
equilibrium the Boltzmann'sTransport Equation gets simplified because
the term S and time varying terms vanish and so f can be solved for
analytically.
Here the no change is present with respect to time so they
disappear and there is no excess generation.
Therefore under equilibrium, the equation simplifies.
• There 0 indicates the equilibrium and timeT is removed . Now, the total energy E is
nothing but the sum of potential energy which we represent as Ec. Now here please
note that this is capital version of the Greek Letter Epsilon .
• This term will be 0 because things will not change with time.This term will be 0 for the
same reason things do not change with time and this term is also 0 because there is no
excess generation or recombination. So, you see they are left with only these 2 terms =
0.
One can attempt modifications of the equilibrium function f to treat a general case. So,
we get a distribution function for equilibrium.
• And for non-equilibrium cases what we do is we disturb this function or we pert up this
function or modify this function by introducing some additional terms to represent the
effect of non-equilibrium and we try to see whether this form satisfies the Boltzmann's
Transport Equation.
This is our Boltzmann's Transport Equation, okay. Now, we will
substitute this function f0 and evaluate the derivatives which are there.
Or rather derive the derivatives of this function.
F != 1/1+exponential EEf / KTl where this E is the total energy. substitute
this in this equation the sum of the 2 terms should become zero.
this Ec is appearing in this exponential which is in the denominator. Now
since this is a little bit involved what we can do is, we will make a
substitution we will assume that this quantity is y then our f0 turns out to
be = 1/1+e power y.
Now I differentiate with respect to P, the EC is not a function of P, it is a
potential energy.
I will get 2 times P/2Mn which is P/Mn and P/Mn is nothing but the velocity,
V which were using here.Tl is again not a function ofT, you can treat as a
constant. In this case then thisV also gets cancelled out of the equation.
K is a constant,after solving the numerator ,we get that force is negative
gradient of potential energy.
• dEc/dx is nothing but - of f. we are getting - of f/K timesTl and here you
have f/K timesTl. I am not removing K timesTl because it is multiplying
this term dEf/dx. Okay, then let me put this terms here the K when I am
can cancelling this K, I can cancel this K also
this dy/dx is nothing but 1/Tl into dEf/dx with a negative sign + this quantity
multiplied by dy/dx of 1/Tl and this is = 0 . Since this relation should hold for all
values of P, all values of momentum.
Tl is non 0 the only way this will work is that dEf/dx = 0 and dy/dx of 1/Tl = 0, which
is nothing but d ofTl/dx = 0.
this function is a solution of the Boltzmann'sTransport Equation under equilibrium
if df/dx = 0, dTl/dx = 0.
• WKT the first level course you know that this particular function is nothing but the Fermi–Dirac
function FD
• Here , suffix MB stands for Maxwell-Boltzmann distribution .
• separate out the exponential of -P square/2Mn kTl term which is contributed by this kinetic
energy term and the other quantity.
• One approach to solving the Boltzmann'sTransport Equation is to take the equilibrium distribution
function and perturb it to accommodate the happenings of nonequilibrium case. Under equilibrium the
entire carrier population has no net motion in any direction or no drift velocity.
• the equilibrium distribution function is like this.The effect on non-equilibrium will be to introduce a
directed velocity. shifting the momentum or there is a non 0 momentum, average momentum.
• the distribution function is shifting to the right, to display the average
momentum, non 0 momentum.This average momentum nothing but effective
mass multiplied by the directed velocity. Under Quasi-equilibrium you find that the
shape of the distribution function about the mean value is remaining the same, if
the disturbance from equilibrium is small .
• The quantity is which vary with x and t are all indicated in the equation in previous
slide. Quasi-equilibrium is characterized by the condition the electron temperature
Tn = the lattice temperature.
• Under non-equilibrium condition the Fermi level is replaced by the Quasi Fermi
level concept.
• In terms of the curve the large deviation from equilibrium is reflected in spreading
of the curve, right. So, here the peak is sharp but under non-equilibrium the peak is
broad.
• more and more carriers are taking up momenta on either side of
the average value. Now this effect is captured by changing the
quantityTn. So, in non-equilibriumTn becomes more thanTl.
• If this denominator is large, then this width of the peak region will
increase, this clear from the nature of the Gaussian function.
• The current density is given by this formula and operation
according to this formula leads you to this equation. Q times, -Q
times carrier concentration N into directed velocityVd.
• 3D version this x is replaced by r.
• kinetic energy density = half MnVd square this the so called directed kinetic energy
or drift energy and 3/2 times kTn which is the random kinetic energy or so called
thermal energy.This multiplied by n ,it is called a Displaced-Maxwellian
Approximation
• here you have the Maxwell’s equations with Quasi-static approximation and
magnetic field = 0.There are 2 equations E = - grad psi equation and then you have
Lorentz force equation which gives you the force because of electric field or
potential gradient. this force and the electric field that is given here is used in the
Boltzmann transport equation to solve for the distribution function f.
• We have 2 Boltzmann transport equations, one for electron other for whole. (in the
next slide)
• The lattice temperature is to be solved from the equation for heat flux.
Heat flux may be applied or it may be generated within the device they
have explained how heat flux can be generated
• On left hand side you have the time derivative of lattice temperature multiplied by 2
quantities rho, which is the mass density of the material, semi connector material and see
which is the specific heat capacity. On the right hand side, you have divergence of the so
called heat flux Q which is written as proportional to the temperature gradientTl.The
constant of proportionality is thermal conductivity which is a function of temperature. one
source of heat is the so called joule heating.This is so calledVI loss.
• there is a microscopic description of the heat generation because of
ohmic losses.Then you can have energy generated because of excess
recombination. So R – G is excess recombination. So if carriers
recombine and if the mechanism of carrier recombination involves
furanones then heat will be generated.
• Ec Ev and this the recombination, right, process in which the electron
jumps into a hole and this energy gap.
• the equation for heat flux, so here time derivative ofTl because the quantity
analog is to PsTl, right hand side is special derivative of the flux because of
temperature that is a heat flux Q and this Q we write as proportional to the
temperature gradient. So in 1-dimension we are writing, so and you have a
negative sign because the heat flows from higher temperature to lower
temperature.
• the diffusion current of holes goes from higher concentration to lower
concentration.
• mass density which means mass
• per unit volume that is kg per meter cube or gram per centimeter cube and
this is specific heat capacity.This is thermal conductivity.
• The equations of carrier transport consist of 2 Boltzmann's
Transport Equations 1 for electron and 1 for hole and the equation
for heat flux. So, the connection between the 2 sets of equations
we shown here from the electromagnetic filed equations you get
the solution for the electric field or potential and from there you
can get the force on an electron.
• This information is fed into the transport equations which give us
output the current density of electrons the carrier concentration of
electrons the current density of holes and carrier concentration of
holes.
THE
SECOND
APPROAC
H
• The goal of modeling n and Jn are functions of 4 variables only x, y, z and t
and filter out detail distributions of f over Px, Py and Pz.
• In the process of finding out n and Jn from f we are filtering out the
effects of Px, Py and Pz.
• The BTE can be converted into balance equations for carrier
concentration n and current density Jn ,both as a function of position and
time by multiplying the BTE with appropriate functions, which are
denoted as phi of P divided by the local volume deltaV.This is your
Boltzmann’sTransport Equation.
• n is given by 1/deltaV into sigma f of x, P, i t where you are summing up over all
the available states or allowed states. Jn on the other hand is 1/deltaV into now
here you multiply by –qPi/Mn, multiply the distribution function.Sum f over the
available states and divide by deltaV.
• For n, summing up I =1 to M dou f/dou t is same as taking the derivative of the
sum I = 1 to M of f.
• This is the so called function of, this is the so called phi of P that we are
talking about. In this case, the phi of P was simply = unity 1. Here phi of P
is -Q into P/Mn.Then multiply all the terms by the appropriate function.
• For example, if I want to write an equation for dou n/dou t I multiplying
everything by 1. So, this turns remain as it is and then I have to sum all of
them all these terms over the states. In this case I have to multiply each
of the terms here with this function phi of P and then do the summation.
Division of by deltaV is not a big matter because deltaV will get even
cancelled out in all the terms.
summary
• Under equilibrium the BoltzmannTransport Equation becomes simple
and it is possible to guess a solution for this simple equation.
• Then the Fermi-Dirac function or its approximation namely distribution
actually works very well under equilibrium was found.
• Then we said that you can use this equilibrium function and modify it by
making it a Displaced-Maxwellian function by introducing the directed
velocity term in the equation which is the sign of non-equilibrium. In
equilibrium there is no directed velocity no momentum. In non-
equilibrium you have a net momentum or a directed velocity.
• So, we introduced this term the resulting function was called Displaced-
Maxwellian.
• Modifying the carrier temperature and using this directed velocity we
can modify this distribution function at equilibrium sufficiently to
manage the non-equilibrium conditions.Then formula of how to use
this function to derive n and Jn was given.
• Therefore, we need to use alternate approaches and another approach
we outlined was using the fact that n and Jn required for our device
modeling actually does not need the detail distribution of momentum
and therefore we can convert the BoltzmannTransport Equation into
equations of n and Jn.

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Solving the Boltzmann Transport Equation: Displaced-Maxwell Approximation

  • 2. • As you all know Boltzmann'sTransport equation has close correspondence to the whole continuity equation.Therefore, it can be regarded as a balance conservation or continuity equation for the distribution function. • Let us discuss the ways of solving the distribution function or ways of solving the Boltzmann'sTransport Equation or working with the Boltzmann'sTransport Equation to get the device current carrier concentration and so on .The first approach, you can solve for n and Jn as follows;
  • 3.
  • 4. • You solve for the function f from the Boltzmann'sTransport Equation and derive n and Jn from this formula . In general even numerical solution of Boltzmann'sTransport Equation is rather difficult because f is a function of 7 variables. x, y, z, Px, Py, Pz and t. • So when you look at a picture in 3 dimensions then you see the distribution function really becomes complicated you are having 7 variables. If you look at in 1-dimension then you have only x and the Px apart from t. But in 3 dimensions it is complicated. However, in equilibrium the Boltzmann'sTransport Equation gets simplified because the term S and time varying terms vanish and so f can be solved for analytically.
  • 5. Here the no change is present with respect to time so they disappear and there is no excess generation. Therefore under equilibrium, the equation simplifies.
  • 6.
  • 7. • There 0 indicates the equilibrium and timeT is removed . Now, the total energy E is nothing but the sum of potential energy which we represent as Ec. Now here please note that this is capital version of the Greek Letter Epsilon . • This term will be 0 because things will not change with time.This term will be 0 for the same reason things do not change with time and this term is also 0 because there is no excess generation or recombination. So, you see they are left with only these 2 terms = 0. One can attempt modifications of the equilibrium function f to treat a general case. So, we get a distribution function for equilibrium. • And for non-equilibrium cases what we do is we disturb this function or we pert up this function or modify this function by introducing some additional terms to represent the effect of non-equilibrium and we try to see whether this form satisfies the Boltzmann's Transport Equation.
  • 8. This is our Boltzmann's Transport Equation, okay. Now, we will substitute this function f0 and evaluate the derivatives which are there. Or rather derive the derivatives of this function. F != 1/1+exponential EEf / KTl where this E is the total energy. substitute this in this equation the sum of the 2 terms should become zero.
  • 9.
  • 10. this Ec is appearing in this exponential which is in the denominator. Now since this is a little bit involved what we can do is, we will make a substitution we will assume that this quantity is y then our f0 turns out to be = 1/1+e power y. Now I differentiate with respect to P, the EC is not a function of P, it is a potential energy. I will get 2 times P/2Mn which is P/Mn and P/Mn is nothing but the velocity, V which were using here.Tl is again not a function ofT, you can treat as a constant. In this case then thisV also gets cancelled out of the equation. K is a constant,after solving the numerator ,we get that force is negative gradient of potential energy.
  • 11. • dEc/dx is nothing but - of f. we are getting - of f/K timesTl and here you have f/K timesTl. I am not removing K timesTl because it is multiplying this term dEf/dx. Okay, then let me put this terms here the K when I am can cancelling this K, I can cancel this K also
  • 12. this dy/dx is nothing but 1/Tl into dEf/dx with a negative sign + this quantity multiplied by dy/dx of 1/Tl and this is = 0 . Since this relation should hold for all values of P, all values of momentum. Tl is non 0 the only way this will work is that dEf/dx = 0 and dy/dx of 1/Tl = 0, which is nothing but d ofTl/dx = 0. this function is a solution of the Boltzmann'sTransport Equation under equilibrium if df/dx = 0, dTl/dx = 0.
  • 13. • WKT the first level course you know that this particular function is nothing but the Fermi–Dirac function FD • Here , suffix MB stands for Maxwell-Boltzmann distribution . • separate out the exponential of -P square/2Mn kTl term which is contributed by this kinetic energy term and the other quantity.
  • 14.
  • 15. • One approach to solving the Boltzmann'sTransport Equation is to take the equilibrium distribution function and perturb it to accommodate the happenings of nonequilibrium case. Under equilibrium the entire carrier population has no net motion in any direction or no drift velocity. • the equilibrium distribution function is like this.The effect on non-equilibrium will be to introduce a directed velocity. shifting the momentum or there is a non 0 momentum, average momentum.
  • 16. • the distribution function is shifting to the right, to display the average momentum, non 0 momentum.This average momentum nothing but effective mass multiplied by the directed velocity. Under Quasi-equilibrium you find that the shape of the distribution function about the mean value is remaining the same, if the disturbance from equilibrium is small . • The quantity is which vary with x and t are all indicated in the equation in previous slide. Quasi-equilibrium is characterized by the condition the electron temperature Tn = the lattice temperature. • Under non-equilibrium condition the Fermi level is replaced by the Quasi Fermi level concept. • In terms of the curve the large deviation from equilibrium is reflected in spreading of the curve, right. So, here the peak is sharp but under non-equilibrium the peak is broad.
  • 17. • more and more carriers are taking up momenta on either side of the average value. Now this effect is captured by changing the quantityTn. So, in non-equilibriumTn becomes more thanTl. • If this denominator is large, then this width of the peak region will increase, this clear from the nature of the Gaussian function. • The current density is given by this formula and operation according to this formula leads you to this equation. Q times, -Q times carrier concentration N into directed velocityVd. • 3D version this x is replaced by r.
  • 18. • kinetic energy density = half MnVd square this the so called directed kinetic energy or drift energy and 3/2 times kTn which is the random kinetic energy or so called thermal energy.This multiplied by n ,it is called a Displaced-Maxwellian Approximation • here you have the Maxwell’s equations with Quasi-static approximation and magnetic field = 0.There are 2 equations E = - grad psi equation and then you have Lorentz force equation which gives you the force because of electric field or potential gradient. this force and the electric field that is given here is used in the Boltzmann transport equation to solve for the distribution function f. • We have 2 Boltzmann transport equations, one for electron other for whole. (in the next slide) • The lattice temperature is to be solved from the equation for heat flux.
  • 19. Heat flux may be applied or it may be generated within the device they have explained how heat flux can be generated
  • 20. • On left hand side you have the time derivative of lattice temperature multiplied by 2 quantities rho, which is the mass density of the material, semi connector material and see which is the specific heat capacity. On the right hand side, you have divergence of the so called heat flux Q which is written as proportional to the temperature gradientTl.The constant of proportionality is thermal conductivity which is a function of temperature. one source of heat is the so called joule heating.This is so calledVI loss.
  • 21. • there is a microscopic description of the heat generation because of ohmic losses.Then you can have energy generated because of excess recombination. So R – G is excess recombination. So if carriers recombine and if the mechanism of carrier recombination involves furanones then heat will be generated. • Ec Ev and this the recombination, right, process in which the electron jumps into a hole and this energy gap.
  • 22. • the equation for heat flux, so here time derivative ofTl because the quantity analog is to PsTl, right hand side is special derivative of the flux because of temperature that is a heat flux Q and this Q we write as proportional to the temperature gradient. So in 1-dimension we are writing, so and you have a negative sign because the heat flows from higher temperature to lower temperature. • the diffusion current of holes goes from higher concentration to lower concentration. • mass density which means mass • per unit volume that is kg per meter cube or gram per centimeter cube and this is specific heat capacity.This is thermal conductivity.
  • 23. • The equations of carrier transport consist of 2 Boltzmann's Transport Equations 1 for electron and 1 for hole and the equation for heat flux. So, the connection between the 2 sets of equations we shown here from the electromagnetic filed equations you get the solution for the electric field or potential and from there you can get the force on an electron. • This information is fed into the transport equations which give us output the current density of electrons the carrier concentration of electrons the current density of holes and carrier concentration of holes.
  • 25. • The goal of modeling n and Jn are functions of 4 variables only x, y, z and t and filter out detail distributions of f over Px, Py and Pz. • In the process of finding out n and Jn from f we are filtering out the effects of Px, Py and Pz. • The BTE can be converted into balance equations for carrier concentration n and current density Jn ,both as a function of position and time by multiplying the BTE with appropriate functions, which are denoted as phi of P divided by the local volume deltaV.This is your Boltzmann’sTransport Equation.
  • 26. • n is given by 1/deltaV into sigma f of x, P, i t where you are summing up over all the available states or allowed states. Jn on the other hand is 1/deltaV into now here you multiply by –qPi/Mn, multiply the distribution function.Sum f over the available states and divide by deltaV. • For n, summing up I =1 to M dou f/dou t is same as taking the derivative of the sum I = 1 to M of f.
  • 27. • This is the so called function of, this is the so called phi of P that we are talking about. In this case, the phi of P was simply = unity 1. Here phi of P is -Q into P/Mn.Then multiply all the terms by the appropriate function. • For example, if I want to write an equation for dou n/dou t I multiplying everything by 1. So, this turns remain as it is and then I have to sum all of them all these terms over the states. In this case I have to multiply each of the terms here with this function phi of P and then do the summation. Division of by deltaV is not a big matter because deltaV will get even cancelled out in all the terms.
  • 29. • Under equilibrium the BoltzmannTransport Equation becomes simple and it is possible to guess a solution for this simple equation. • Then the Fermi-Dirac function or its approximation namely distribution actually works very well under equilibrium was found. • Then we said that you can use this equilibrium function and modify it by making it a Displaced-Maxwellian function by introducing the directed velocity term in the equation which is the sign of non-equilibrium. In equilibrium there is no directed velocity no momentum. In non- equilibrium you have a net momentum or a directed velocity. • So, we introduced this term the resulting function was called Displaced- Maxwellian.
  • 30. • Modifying the carrier temperature and using this directed velocity we can modify this distribution function at equilibrium sufficiently to manage the non-equilibrium conditions.Then formula of how to use this function to derive n and Jn was given. • Therefore, we need to use alternate approaches and another approach we outlined was using the fact that n and Jn required for our device modeling actually does not need the detail distribution of momentum and therefore we can convert the BoltzmannTransport Equation into equations of n and Jn.