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ENERGY BAND
DIAGRAM
By KS SUDHAN DHARSHAN-17D093
Energy Band Diagrams
• In the previous lecture, we discussed the ex-diagrams of heterojunction under
equilibrium. A p-n
• junction under high forward bias and 2 dimensional band diagrams then we also
showed how the
• band diagram can be used as a tool for analysis of PN Junction or deriving
information about full
• concentration, electron concentration, electron current density, hole current
density, potential and
• electric field apart from representing a known distribution of electrons holes, JN,
JP, psi and p.
• In this lecture, we shall discuss the correspondence between e-k and e-x
diagrams.
E-K Relationship
• Let us begin with the utility of the E-K relation, this relation
helps us determine the velocity, momentum and mass of a
carrier in a crystal having a given energy E, now you might
wonder that is not this determination is very simple that is the
determination of the mass, energy and momentum of a
carrier of a given energy. Now so far we are used to a free
electron right calculating various quantities for a free electron,
now for a free electron the mass does not change with energy,
the mass is constant.
For a free electron the energy momentum relation is simply energy
= p square/2m0 and therefore if I want to know the momentum for
a given energy I can simply use the formula p = square root of 2m0
E, if I want to know the velocity of the electron for a given energy E
assuming the energy to be kinetic energy because that is when we
can write E as p square/2m0 you can get the velocity as follows E
equal to half of m0v square.
And therefore the velocity V is nothing but 2E/m0 under square
root, now all this is fine for a free electron but for electrons in the
crystal things are not so simple we will find that the effective mass
or the mass of the electron depends on energy, similarly the energy
versus momentum relation is more complex right, so let us look at
these features.
Electron velocity is equal to the group velocity of the wave packet which is
given by the formula vg = 1/h cross into the gradient of the energy E where
the gradient is obtained with respect to the wave vector K okay, that is what
this formula means so this is where you have to use the E-K relation, so the
slope of E-K relation actually gives you the group velocity.
Carrier Momentum:
The momentum of a carrier is given the name crystal momentum, now
let us see what is the origin of this name how the particular
momentum of a carrier that we employ in a crystal is different from
the true instantaneous momentum the carrier does have a true
instantaneous momentum in a crystal. However, as we will see it is not
possible to determine the true instantaneous momentum easily.
And instead we use a momentum like term that we call as crystal
momentum, so in electron subjected to a force F for a time dt
experiences an increase in electron energy of dE = the force multiplied
by the velocity this is a dot product because force and the velocity
which is a group velocity are both vectors and so you have to take a
dot product multiplied by dt. So force into velocity is power and then
you multiplied power by time you get the energy.
Carrier Mass
These ideas using one-dimensional situation, so for a one-dimensional case let us say
this is the E-K relation as shown here in the first below in zone these are the points
where the slope of this E-K relation is maximum, now the group velocity is the slope
of this E-K relation and that works out to something like this, now this is interesting
now what does it mean? So you find that the group velocity increases linearly with K
and K represents in some form the crystal momentum because the h cross k is crystal
momentum.
So, k is proportional to crystal momentum, so the velocity is increasing linearly with
momentum this somewhat like and the picture of an electron in vacuum. However, as
energy goes on increasing you find that at this point the velocity has reached a peak
and there after even though the momentum is increasing the velocity is decreasing,
now this appears counter intuitive right it
is not something that you would expect, now this is something that we have to
accept from the analysis of the electron in a crystal based on quantum mechanics
It is the effect of crystal potential and the wave nature of electron and at some
point here the electron changes its direction again and it is moving to the right, so
in response to a constant force with time and electron in crystal will exhibit
oscillatory motion
Probability distributions of the electrons throughout the lattice and
relationship of this distribution with energy bands, so here we are plotting
the wave function psi magnitude square okay, now this wave function is
solved for from the Schrodinger equation, in the previous lecture we have
shown some example of psi x that has been solved from somewhat realistic
crystal potential right.
Now for this energy level the associated wave function give rise to this kind of
probability distribution, where what you find is the distribution is reaching a
peak at the location of atom and it rapidly decays to 0, so what is the
meaning of this, this means the electron can be found either over here or
over here or over here and so on, this means that electron is really bound to
the atom localized.
Energy Band And Probability Distribution
THANK YOU

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Energy band diagram lec3.ppt

  • 1. ENERGY BAND DIAGRAM By KS SUDHAN DHARSHAN-17D093
  • 2. Energy Band Diagrams • In the previous lecture, we discussed the ex-diagrams of heterojunction under equilibrium. A p-n • junction under high forward bias and 2 dimensional band diagrams then we also showed how the • band diagram can be used as a tool for analysis of PN Junction or deriving information about full • concentration, electron concentration, electron current density, hole current density, potential and • electric field apart from representing a known distribution of electrons holes, JN, JP, psi and p. • In this lecture, we shall discuss the correspondence between e-k and e-x diagrams.
  • 3.
  • 4. E-K Relationship • Let us begin with the utility of the E-K relation, this relation helps us determine the velocity, momentum and mass of a carrier in a crystal having a given energy E, now you might wonder that is not this determination is very simple that is the determination of the mass, energy and momentum of a carrier of a given energy. Now so far we are used to a free electron right calculating various quantities for a free electron, now for a free electron the mass does not change with energy, the mass is constant.
  • 5.
  • 6. For a free electron the energy momentum relation is simply energy = p square/2m0 and therefore if I want to know the momentum for a given energy I can simply use the formula p = square root of 2m0 E, if I want to know the velocity of the electron for a given energy E assuming the energy to be kinetic energy because that is when we can write E as p square/2m0 you can get the velocity as follows E equal to half of m0v square. And therefore the velocity V is nothing but 2E/m0 under square root, now all this is fine for a free electron but for electrons in the crystal things are not so simple we will find that the effective mass or the mass of the electron depends on energy, similarly the energy versus momentum relation is more complex right, so let us look at these features.
  • 7. Electron velocity is equal to the group velocity of the wave packet which is given by the formula vg = 1/h cross into the gradient of the energy E where the gradient is obtained with respect to the wave vector K okay, that is what this formula means so this is where you have to use the E-K relation, so the slope of E-K relation actually gives you the group velocity.
  • 8.
  • 9. Carrier Momentum: The momentum of a carrier is given the name crystal momentum, now let us see what is the origin of this name how the particular momentum of a carrier that we employ in a crystal is different from the true instantaneous momentum the carrier does have a true instantaneous momentum in a crystal. However, as we will see it is not possible to determine the true instantaneous momentum easily. And instead we use a momentum like term that we call as crystal momentum, so in electron subjected to a force F for a time dt experiences an increase in electron energy of dE = the force multiplied by the velocity this is a dot product because force and the velocity which is a group velocity are both vectors and so you have to take a dot product multiplied by dt. So force into velocity is power and then you multiplied power by time you get the energy.
  • 10.
  • 11. Carrier Mass These ideas using one-dimensional situation, so for a one-dimensional case let us say this is the E-K relation as shown here in the first below in zone these are the points where the slope of this E-K relation is maximum, now the group velocity is the slope of this E-K relation and that works out to something like this, now this is interesting now what does it mean? So you find that the group velocity increases linearly with K and K represents in some form the crystal momentum because the h cross k is crystal momentum. So, k is proportional to crystal momentum, so the velocity is increasing linearly with momentum this somewhat like and the picture of an electron in vacuum. However, as energy goes on increasing you find that at this point the velocity has reached a peak and there after even though the momentum is increasing the velocity is decreasing, now this appears counter intuitive right it is not something that you would expect, now this is something that we have to accept from the analysis of the electron in a crystal based on quantum mechanics
  • 12. It is the effect of crystal potential and the wave nature of electron and at some point here the electron changes its direction again and it is moving to the right, so in response to a constant force with time and electron in crystal will exhibit oscillatory motion
  • 13. Probability distributions of the electrons throughout the lattice and relationship of this distribution with energy bands, so here we are plotting the wave function psi magnitude square okay, now this wave function is solved for from the Schrodinger equation, in the previous lecture we have shown some example of psi x that has been solved from somewhat realistic crystal potential right. Now for this energy level the associated wave function give rise to this kind of probability distribution, where what you find is the distribution is reaching a peak at the location of atom and it rapidly decays to 0, so what is the meaning of this, this means the electron can be found either over here or over here or over here and so on, this means that electron is really bound to the atom localized. Energy Band And Probability Distribution
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Editor's Notes

  1. Carrier Mass
  2. Energy Band And Probability Distribution