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Structure
lecture2
1-Axial loads only
2-Loads applies at end
points only
3- Elements are joined
by pins only
1-Determine the force in each
member of the truss ?
 
 
 
 
0 1
0 2
0 3
2
tan tan
3
tan 0 4
3
X X X
Y Y Y
A Y
Y
X
X Y
F A B P
F A B
M B L Ph
B h
B L
B B



    
   
   

  
  



2-Determine the force in each member of
the truss and indicate whether the the
members are in tension or compression ?
1 1
2 2
2 2
3
2 3 22 2
0
0
0
0 ( )
0 ( )
0 ( )
X X X
Y Y Y Y Y
A Y Y
F A P A P
Ph
F A B A B
L
Ph
M Ph B L B
L
Ph Ph
F F Tension
L L
F P F P Tension
F L h L
F F F Compression
Lh L
     

      
     
   
   
 
      
   



3-Determine the force in each member of
the truss and indicate whether the the
members are in tension or compression ?
0
600
0
400
400*3 600*4 *6 0
600
200
X
X
Y
Y Y
C Y
Y
Y
F
C N
F
A C
M A
A N
C N
  

  
 
    




At joint A
At joint C
At joint D
1 2
2
2
1
3
0
5
4
600 0
5
600*5
750 ( )
4
3
750 450 ( )
5
X
Y
F F F
F F
F N Compression
F N Tension
 
     
 
 
     
 

  
 
  
 


4
5
0
600 ( )
0
200 ( )
X
Y
F
F N Compression
F
F N Compression
  
 
  
 


3 3
0
3
450 600 250 ( )
5
XF
F F N Tension
  
 
    
 

4-Determine the force in each member of
the truss and indicate whether the the
members are in tension or compression ?
At joint B
At joint C
At joint A
0
500 sin 45 0 707.1 ( )
0
45 0 500 ( )
X
BC BC
Y
BC BA BA
F
N F N F N Compression
F
F Cos N F F N Tension
  
   
  
   


0
707.1 45 0 500 ( )
0
707.1 45 0 500
X
CA CA
Y
Y Y
F
F Cos N F N Tension
F
C Sin N C N
  
    
  
   


0
500 0 500
0
500 0 500
X
X X
Y
Y Y
F
N A A N
F
N A A N
  
   
  
   


*
1 1 3 2
1 1 3 2 2 2
2 22 2
2 2
2 2
1 3
1
3
0
0
0
0
0
( )
0
X
Y
Y
Y
C Y
Y
F
P F F F Cos
L
P F F F
h L
F
h
D P F
h L
h L
F P D
h
M D L P h F h
P h D L
F
h

  
   
 
    
 
  
 
   
 

 
    
 
  
 



6-Determine the force in each member of
the truss and indicate whether the the
members are in tension or compression ?
1
Method of joints : we willbegainbyanalzingthe
equilibrium of joint D , and then proceed to
analyze joints Cand D
1
tan 26.57
2
At joint D
0
600 26.57 0
1341.64 ( )
0
X
DC
DC
Y
F
F Sin
F N Compression
F
   
  
 
  
 

  


/
/
1341.64 26.57 0
1200 ( )
At joint C
0
26.57 0 0
0
1341.64 ( )
At joint E
0
900 45 0
1272.79 ( )
0
1200 1272.79 45 0
DE
DE
X
CE CE
Y
CB
X
EB
EB
Y
EA
EA
Cos F
F N Tension
F
F Cos F
F
F N Compression
F
F Sin
F N Compression
F
Cos F
F
 

  
   
  

  
 

  
  





2100 ( )
Note , the equilibrium analysis of joint Acan be used to
determine the components of supports reaction atA
N Tension
Kites team l2
Kites team l2
Kites team l2
Kites team l2
Kites team l2
Kites team l2

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  • 2. 1-Axial loads only 2-Loads applies at end points only 3- Elements are joined by pins only
  • 3. 1-Determine the force in each member of the truss ?         0 1 0 2 0 3 2 tan tan 3 tan 0 4 3 X X X Y Y Y A Y Y X X Y F A B P F A B M B L Ph B h B L B B                          
  • 4. 2-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? 1 1 2 2 2 2 3 2 3 22 2 0 0 0 0 ( ) 0 ( ) 0 ( ) X X X Y Y Y Y Y A Y Y F A P A P Ph F A B A B L Ph M Ph B L B L Ph Ph F F Tension L L F P F P Tension F L h L F F F Compression Lh L                                            
  • 5. 3-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? 0 600 0 400 400*3 600*4 *6 0 600 200 X X Y Y Y C Y Y Y F C N F A C M A A N C N                  
  • 6. At joint A At joint C At joint D 1 2 2 2 1 3 0 5 4 600 0 5 600*5 750 ( ) 4 3 750 450 ( ) 5 X Y F F F F F F N Compression F N Tension                                  4 5 0 600 ( ) 0 200 ( ) X Y F F N Compression F F N Compression             3 3 0 3 450 600 250 ( ) 5 XF F F N Tension             
  • 7. 4-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? At joint B At joint C At joint A 0 500 sin 45 0 707.1 ( ) 0 45 0 500 ( ) X BC BC Y BC BA BA F N F N F N Compression F F Cos N F F N Tension                 0 707.1 45 0 500 ( ) 0 707.1 45 0 500 X CA CA Y Y Y F F Cos N F N Tension F C Sin N C N                  0 500 0 500 0 500 0 500 X X X Y Y Y F N A A N F N A A N                
  • 8. * 1 1 3 2 1 1 3 2 2 2 2 22 2 2 2 2 2 1 3 1 3 0 0 0 0 0 ( ) 0 X Y Y Y C Y Y F P F F F Cos L P F F F h L F h D P F h L h L F P D h M D L P h F h P h D L F h                                              
  • 9. 6-Determine the force in each member of the truss and indicate whether the the members are in tension or compression ? 1 Method of joints : we willbegainbyanalzingthe equilibrium of joint D , and then proceed to analyze joints Cand D 1 tan 26.57 2 At joint D 0 600 26.57 0 1341.64 ( ) 0 X DC DC Y F F Sin F N Compression F                     / / 1341.64 26.57 0 1200 ( ) At joint C 0 26.57 0 0 0 1341.64 ( ) At joint E 0 900 45 0 1272.79 ( ) 0 1200 1272.79 45 0 DE DE X CE CE Y CB X EB EB Y EA EA Cos F F N Tension F F Cos F F F N Compression F F Sin F N Compression F Cos F F                                2100 ( ) Note , the equilibrium analysis of joint Acan be used to determine the components of supports reaction atA N Tension