2. Evaporation
• Terminology
– Evaporation – process by which liquid
water passes directly to the vapor phase
– Transpiration - process by which liquid
water passes from liquid to vapor through
plant metabolism
– Sublimation - process by which water
passes directly from the solid phase to the
vapor phase
3. Factors Influencing Evaporation
• Energy supply for
vaporization (latent heat)
– Solar radiation
• Transport of vapor away from
evaporative surface
– Wind velocity over surface
– Specific humidity gradient
above surface
• Vegetated surfaces
– Supply of moisture to the
surface
– Evapotranspiration (ET)
• Potential Evapotranspiration
(PET) – moisture supply is not
limited
nR
E
Net radiation
Evaporation
Air Flow
u
4. Evaporation from a Water
Surface
• Simplest form of evaporation
– From free liquid of permanently saturated
surface
5. Evaporation from a Pan
• National Weather Service Class A
type
• Installed on a wooden platform in a
grassy location
• Filled with water to within 2.5 inches
of the top
• Evaporation rate is measured by
manual readings or with an analog
output evaporation gauge
h
Area, A
CS
w
a
AEm wv
dt
dh
E
nRsH
Sensible
heat to air
Net radiation Vapor flow rate
Heat conducted
to ground
G
6. Methods of Estimating Evaporation
• Energy Balance Method
• Aerodynamic method
• Combined method
7. Energy Method
• CV contains liquid and vapor phase water
• Continuity - Liquid phase
CS
w
CV
wv d
dt
d
m dAV
0
dt
dh
Aw No flow of liquid
water through CS
AEm wv
E
dt
dh
hw
a
vm
dt
dh
E
nRsH
G
8. Energy Method
• Continuity - Vapor phase
CS
avw qAE dAV
0
Steady flow of air
over water
AEw
CS
av
CV
avv qdq
dt
d
m dAV
CS
av
w
q
A
E dAV
1
CS
avv qm dAV
hw
a
vm
dt
dh
E
nRsH
G
10. Energy Method
• Energy Eq. for Water in CV
Assume:
1. Constant temp of water in CV
2. Change of heat is change in internal energy of water evaporated
hw
a
vm
dt
dh
E
nRsH
G
vvml
dt
dH
GHR
dt
dH
sn
GHRml snvv AEm w
GHR
Al
E sn
wv
1
Recall:
wv
n
r
l
R
E
Neglecting sensible and ground heat
fluxes
11. Wind as a Factor in Evaporation
• Wind has a major effect on evaporation, E
– Wind removes vapor-laden air by convection
– This Keeps boundary layer thin
– Maintains a high rate of water transfer from
liquid to vapor phase
– Wind is also turbulent
• Convective diffusion is several orders of magnitude
larger than molecular diffusion
12. Aerodynamic Method
• Include transport of vapor
away from water surface
as function of:
– Humidity gradient above
surface
– Wind speed across surface
• Upward vapor flux
• Upward momentum flux
nR
E
Net radiation
Evaporation
Air Flow
12
21
zz
qq
K
dz
dq
Km
vv
wa
v
wa
12
12
zz
uu
K
dz
du
K mama
12
21
uuK
qqK
m
m
vvw
13. Aerodynamic Method
• Log-velocity profile
• Momentum flux
nR
E
Net radiation
Evaporation
Air Flow
12
21
uuK
qqK
m
m
vvw
oZ
Z
ku
u
ln
1
*
2
12
12
ln
ZZ
uuk
a
2
12
12
2
ln
21
ZZK
uuqqkK
m
m
vvaw
Thornthwaite-Holzman Equation
u
Z
14. Aerodynamic Method
• Often only available at 1
elevation
• Simplifying
nR
E
Net radiation
Evaporation
Air Flow
2
12
12
2
ln
21
ZZK
uuqqkK
m
m
vvaw
uqv and
2
2
2
2
ln
622.0
o
aasa
ZZP
ueek
m
AEm w
aasa eeBE
2
2
2
2
ln
622.0
ow
a
ZZP
uk
B
2@pressurevapor Zea
15. Combined Method
• Evaporation is calculated by
– Aerodynamic method
• Energy supply is not limiting
– Energy method
• Vapor transport is not limiting
• Normally, both are limiting, so use a combination
method
ar EEE
wv
n
r
l
R
EE
aasa eeBEE
wv
hp
Kl
pKC
622.0
2
)3.237(
4098
T
e
dT
de ss
rEE
3.1
Priestly & Taylor
16. Example
– Elev = 2 m,
– Press = 101.3 kPa,
– Wind speed = 3 m/s,
– Net Radiation = 200 W/m2,
– Air Temp = 25 degC,
– Rel. Humidity = 40%,
• Use Combo Method to find Evaporation
kJ/kg244110)25*36.22500(
237010501.2
3
6
x
Txlv
mm/day10.7
997*102441
200
3
xl
R
E
wv
n
r
17. Example (Cont.)
– Elev = 2 m,
– Press = 101.3 kPa,
– Wind speed = 3 m/s,
– Net Radiation = 200 W/m2,
– Air Temp = 25 degC,
– Rel. Humidity = 40%,
• Use Combo Method to find Evaporation
mm/day45.7
)day1/s86400(*)m1/mm1000(*126731671054.4 11
xEa
sm/Pa1054.4
1032ln997*3.101
3*19.1*4.0*622.0
ln
622.0 11
24
2
2
2
2
2
x
xZZP
uk
B
ow
a
Pa3167ase
Pa12673167*4.0* asha eRe
18. Example (Cont.)
– Elev = 2 m,
– Press = 101.3 kPa,
– Wind speed = 3 m/s,
– Net Radiation = 200 W/m2,
– Air Temp = 25 degC,
– Rel. Humidity = 40%,
Pa/degC1.67
102441*622.0
103.101*1005
622.0 3
3
x
x
Kl
pKC
wv
hp
• Use Combo Method to find Evaporation
Pa/degC7.188
)253.237(
3167*4098
2
738.0
mm/day2.745.7*262.010.7*738.0
ar EEE
262.0
19. Example
– Net Radiation = 200 W/m2,
– Air Temp = 25 degC,
• Use Priestly-Taylor Method to find
Evaporation rate for a water body
rEE
3.1 Priestly & Taylor
mm/day10.7rE 738.0
mm/day80.610.7*738.0*3.1 E
20. Evapotranspiration
• Evapotranspiration
– Combination of evaporation from soil surface and
transpiration from vegetation
– Governing factors
• Energy supply and vapor transport
• Supply of moisture at evaporative surfaces
– Reference crop
• 8-15 cm of healthy growing green grass with abundant water
– Combo Method works well if B is calibrated to local
conditions
21. Potential Evapotranspiration
• Multiply reference crop ET by a Crop Coefficient and a
Soil Coefficient rcs ETkkET
3.10.2
t;CoefficienCrop
c
c
k
k
10
t;CoefficienSoil
s
s
k
k
ETActualET
ETCropReferencerET
http://www.ext.colostate.edu/pubs/crops/04707.html
CORN
0
0.1
0.2
0.3
0.4
0.5
0.6
0.7
0.8
0.9
1
0 20 40 60 80 100 120 140 160
Time Since Planting (Days)
CropCoefficient,kc