The document contains an ecumenical prayer in Tagalog requesting God's guidance in their studies and to develop virtues as good citizens. It ends with "Amen". It then outlines the vision of the Tomas Claudio Colleges Basic Education Department to provide quality basic education to develop responsible citizens and uphold leadership in technology. The mission is then stated as offering quality instruction to prepare learners for the modern world, developing God-loving, creative and dedicated students to safeguard national resources.

2. ECUMENICAL
PRAYER
 Panginoon, maraming Salamat po sa dakilang araw
na ito. Kami po ay nagpupuri at niluluwalhati ang
inyong mga kaloob na biyaya sa amin. Gabayan po
ninyo kami sa aming pag- aaral at sa pagtuklas ng
bagong kaalaman na magtataguyod sa amin upang
maging mahusay mong tagapaglingkod. Ipadala po
ninyo ang inyong banal na espiritu upang
magningas sa puso ng bawat isa sa amin ang
maalab na pagnanais na maging isang mahusay na
mamamayan, na may malasakit sa pamilya, kapwa,
kalikasan at sa mahal na bansang Pilipinas. Ang
lahat ng ito ay hinihiling namin sa matamis at
dakilang pangalan ni Hesus na aming
tagapagligtas.
 Amen.

3. TCC-BED
VISION
The Tomas Claudio Colleges Basic
Education Department envisions to
be the provider of quality basic
instructions vested to educate the
21st century learners to hone
responsible citizens of the
community, to inculcate the
Claudian spirit and to uphold the
leadership in the field of
technology.

4. TCC-BED
MISSION
To realize its aim, the Tomas
Claudio Colleges Basic
Education Department will:
Offer quality basic instructions
that will prepare the learners
thrive in today’s contemporary
world, develop learners who are
God-loving, creative, truthful,
self –reliant, and dedicated to
safeguard the nation resources.

5. ATTENDANCE

6. WORK AND
ENERGY

8. W
O
R
K
Work is done when a task
produces a change in energy
Work is the product of a force
acting on an object and its
resulting displacement.
Work is done when a
task produces a change
in energy
Work is a scalar quantity and
can also be positive or
negative.

9. W
O
R
K
Work is a scalar
quantity and can also be
positive or negative.
It is harder to go up than to
go down. Work done by the
force of gravity is NEGATIVE
when we go up, and
POSITIVE when we go down

10. Factors
affecting
work
done:
The
application of
a force
The movement
of the object by
that force over
a distance

11. W
O
R
K
Therefore:
Work = Force x Distance
W = Fd
 Units: Joule (J)
 1 J = 1 N.m
 Note that for work to be done, the force requires a
distance
Newton-meter

12. HOW TO
COMPUTE
FOR WORK
STANDARD FORMULA:
W=Fd
Where:
W= work
F= force
d= distance
Units used:
W= J (joules)
F= N (newton)
d= m ( meter)
Joules = N●m
SAMPLE PROBLEM #1
Matthew uses 45 N of force to stop the cart 0.5 m from
running his foot over. How much work does he do?
GIVEN: FORMULA: SOLUTION:
W=
F=
d=
45 N
0.5 m
???
W=Fd
W= (45N) (0.5 m)
W= 22.5 N●m Joules = N●m
W= 22.5 J
FINAL ANSWER:

13. HOW TO
COMPUTE
FOR WORK
SAMPLE PROBLEM #2
Melissa uses a force of 25 N to lift her grocery bag while
doing 50 J of work. How far did she lift the grocery bags?
GIVEN: FORMULA: SOLUTION:
W=
F=
d=
25 N
50 J
???
W=Fd d= 50 J
25 N
Joules = N●m
d= 2 m
FINAL ANSWER:
d=W
F
F F

14. HOW TO
COMPUTE
FOR WORK
SAMPLE PROBLEM #3
The baseball player does 1,250 J of work when hitting a baseball
into left field. Assuming the baseball landed 100m away from
home plate, how much force did the player use to hit the ball?
GIVEN: FORMULA: SOLUTION:
W=
F=
d=
1,250 J
100 m
???
W=Fd F= 1,250 J
100 m
Joules = N●m
F= 12.5 N
FINAL ANSWER:
F= W
d
d d

15. LET’S
PRACTICE
WORK FORCE DISTANCE
255 N 10.25 m
2,613.75 J
3,500 J 25.75 m
135.92 N
1,200 J 285 N 4.90m

16. E
N
E
R
G
Y
Energy is the ability or the
capacity to do work.
When you say an object has
energy, it means it can exert
force on another object to do
work on it.
Energy is needed in
performing your every
day.
Energy is the ability or
strength to do active physical
things.

17. E
N
E
R
G
Y
FORMS
CHEMICAL
ELECTRICAL
NUCLEAR
SOUND
LIGHT
MECHANICAL
In this chapter, we will
focus on

18. MECHANICAL
ENERGY
The energy of an
object due to its
motion or position.
The sum of an object’s
Kinetic or Potential
Energy.
POTENTIAL ENERGY
The energy possessed by a body by virtue of
its position relative to others
The energy stored in an object or simply as
the energy at rest.
KINETIC ENERGY
The energy possessed by a body because of
its motion
The energy in motion.

20. LAW OF
CONSERVATION
OF
MECHANICAL
ENERGY
This law states that
“the total mechanical
energy is the sum of
the kinetic energy and
potential energy in a
conservative system is
constant”.
When a ball is thrown upward, with an
initial velocity, it continuously goes up
and it starts to go down when its
energy is already used up.
The kinetic energy becomes zero, it
changes into potential energy.
When the ball is on its way down to
the ground, potential energy. Is
changed back again into kinetic
energy.

21. HOW TO
COMPUTE
FOR
POTENTIAL
ENERGY
STANDARD FORMULA:
PE=mgh
Where:
PE= potential energy
m= mass
g= acceleration due to gravity
h= height
Units used:
PE= J (joules)
m= kg (kilogram)
g= m/s2 ( meter
per second
squared)
h= m (meter)
SAMPLE PROBLEM #1
If a stone has a mass of 5 kg and is elevated to a height of 10 m,
solve the potential energy of the block.
GIVEN: FORMULA: SOLUTION:
PE=
m=
g=
h=
5 kg
10 m
9.8 m/s2
PE=mgh
PE= (5 kg) (10 m)
PE= 490 kg●m/s2 = N
(N)(m) =N●m
N●m = J
PE= 490 J
FINAL ANSWER:
(9.8 m/s2)

22. HOW TO
COMPUTE
FOR
POTENTIAL
ENERGY
STANDARD FORMULA:
PE=mgh
Where:
PE= potential energy
m= mass
g= acceleration due to gravity
h= height
Units used:
PE= J (joules)
m= kg (kilogram)
g= m/s2 ( meter
per second
squared)
h= m (meter)
SAMPLE PROBLEM #2
A woman which has mass of 60 kg climbs a set of stairs that are
3 m high. How much potential energy does she gain as a result
of the climb?
GIVEN: FORMULA: SOLUTION:
PE=
m=
g=
h=
60 kg
3m
9.8 m/s2
PE=mgh
PE= (60 kg) (3 m)
PE= 1,764 kg●m/s2 = N
(N)(m) =N●m
N●m = J
PE= 1,764 J
FINAL ANSWER:
(9.8 m/s2)

23. Practice
Exercise 1
 GIVEN:
PE=?
 m= 80 kg
 g= 9.8 m/s2
 h= 5 m
FORMULA:
PE=mgh SOLUTION:
PE= (80kg) ( 9.8 m/s₂)(5m)
Final answer:
3920 J
A man with a mass of 80 kg climbs a tree with a height of 5
meters. Compute for the potential energy. Show the given,
formula and solution.

24. HOW TO
COMPUTE
FOR KINETIC
ENERGY
STANDARD FORMULA:
KE=1/2 mv2
Where:
KE=kinetic energy
m= mass
v= velocity
Units used:
KE= J (joules)
m= kg (kilogram)
v= m/s (meter per
second)
SAMPLE PROBLEM #1
A ball rolling down the hill has a mass of 1.5 kg moving at 5 m/s.
Find its kinetic energy.
GIVEN: FORMULA: SOLUTION:
KE=
m=
v=
1.5 kg
5 m/s
???
KE=1/2mv2
KE= 1/2 (5 m/s)2
KE= (25)
KE= 18.75 J
FINAL ANSWER:
(1.5 kg)
(1.5 kg)
1/2
KE= 18.75

25. HOW TO
COMPUTE
FOR KINETIC
ENERGY
STANDARD FORMULA:
KE=1/2 mv2
Where:
KE=kinetic energy
m= mass
v= velocity
Units used:
KE= J (joules)
m= kg (kilogram)
v= m/s (meter per
second)
SAMPLE PROBLEM #2
A cart weighs 15 kg is rolling down a hill with a velocity of 4.2 m/s.
What is the kinetic energy of the cart?
GIVEN: FORMULA: SOLUTION:
KE=
m=
v=
15 kg
4.2 m/s
???
KE=1/2mv2
KE= 1/2 (4.2 m/s)2
KE= (17.64)
KE= 132.3 J
FINAL ANSWER:
(15 kg)
(15 kg)
1/2
KE= 132.3

26. SEATWORK
MASS VELOCITY KINETIC ENERGY
2 kg 3 m/s 9 J
4.5 kg 5 m/s 56.25 J
25 g 2.1 m/s 0.06 J

27.  DIRECTIONS: COMPUTETHE FOLLOWING
PROBLEM. SHOWTHE GIVEN, FORMULA,
SOLUTION AND FINAL ANSWER.
 1.Find the KE of an empty van of mass 1000kg
moving at 2m/s.
 2.Find the KE of van when it is loaded with
goods to give a total mass of 2000kg, and
moving at 2m/s.
 3. Find KE of unloaded van that has a mass of
1,500 when it speeds up to 4m/s.

28. HOW TO
COMPUTE
FOR KINETIC
ENERGY
STANDARD FORMULA:
KE=1/2 mv2
Where:
KE=kinetic energy
m= mass
v= velocity
Units used:
KE= J (joules)
m= kg (kilogram)
v= m/s (meter per
second)
SAMPLE PROBLEM #2
1.Find the KE of an empty van of mass 1000kg moving at 2m/s.
GIVEN: FORMULA: SOLUTION:
KE=
m=
v=
1000 kg
2 m/s
???
KE=1/2mv2
KE= 1/2 (2 m/s)2
KE= (4)
KE= 2,000 J
FINAL ANSWER:
(1000 kg)
(1000 kg)
1/2
KE= 2,000

29. HOW TO
COMPUTE
FOR KINETIC
ENERGY
STANDARD FORMULA:
KE=1/2 mv2
Where:
KE=kinetic energy
m= mass
v= velocity
Units used:
KE= J (joules)
m= kg (kilogram)
v= m/s (meter per
second)
SAMPLE PROBLEM #2
2.Find the KE of van when it is loaded with goods to give a total
mass of 2000kg, and moving at 2m/s.
GIVEN: FORMULA: SOLUTION:
KE=
m=
v=
2000 kg
2 m/s
???
KE=1/2mv2
KE= 1/2 (2 m/s)2
KE= (4)
KE= 4,000 J
FINAL ANSWER:
(2000 kg)
(2000 kg)
1/2
KE= 4,000

30. HOW TO
COMPUTE
FOR KINETIC
ENERGY
STANDARD FORMULA:
KE=1/2 mv2
Where:
KE=kinetic energy
m= mass
v= velocity
Units used:
KE= J (joules)
m= kg (kilogram)
v= m/s (meter per
second)
SAMPLE PROBLEM #2
3. Find KE of unloaded van that has a mass of 1,500 kg when it
speeds up to 4m/s.
GIVEN: FORMULA: SOLUTION:
KE=
m=
v=
1,500 kg
4 m/s
???
KE=1/2mv2
KE= 1/2 (4m/s)2
KE= (16)
KE= 12,000 J
FINAL ANSWER:
(1,500 kg)
(1,500 kg)
1/2
KE= 12,000

31. HOW TO
COMPUTE
FOR
POTENTIAL
ENERGY
STANDARD FORMULA:
PE=mgh
Where:
PE= potential energy
m= mass
g= acceleration due to gravity
h= height
Units used:
PE= J (joules)
m= kg (kilogram)
g= m/s2 ( meter
per second
squared)
h= m (meter)
SEATWORK
Compute the potential energy of an apple which has a mass of
0.010 kg with a height of 10m.
GIVEN: FORMULA: SOLUTION:
PE=
m=
g=
h=
60 kg
3m
9.8 m/s2
PE=mgh
PE=(0.010 kg) ( 10m)
PE= 0.98 kg●m/s2 = N
(N)(m) =N●m
N●m = J
PE= 0.98 J
FINAL ANSWER:
(9.8 m/s2)

32. HOW TO
COMPUTE
FOR KINETIC
ENERGY
STANDARD FORMULA:
KE=1/2 mv2
Where:
KE=kinetic energy
m= mass
v= velocity
Units used:
KE= J (joules)
m= kg (kilogram)
v= m/s (meter per
second)
SEATWORK
1. Compute the kinetic energy of a car which has a mass of 85 kg
with a height of 10m/s.
GIVEN: FORMULA: SOLUTION:
KE=
m=
v=
1,500 kg
4 m/s
???
KE=1/2mv2
KE= 1/2 (10m/s)2
KE= (100)
KE= 4,250 J
FINAL ANSWER:
(85kg)
(85kg)
1/2
KE= 4,250