2. Sedimentation
• It is physical process
• In this process heavier organic and inorganic particles settle down at
bottom of the sedimentation tank.
• For achieve the removal of suspended settleble particles of desired size
the wastewater is retained in sedimentation tank for a fixed time which
is called detention period.
• The upper clear water is collected from the tank.
• The bottom of the tank formation of sludge because of settled
particles.
• The sludge is drawn out from the bottom through the pipe called
sludge pipe.
3. Type of sedimentation
• Plain Sedimentation
• Sediment with coagulation
The settlement of the particle largely depends upon their specific gravity and
their type.
4. Stoke’s Law
𝑣 =
𝑔
18
(𝑠 − 1)𝑑2
𝜗
Where v = settling velocity mm/sec
d = Diameter of particle, mm
μ = Dynamic viscosity of wastewater centistoke
ν =
𝜇
𝜌
= 𝑘𝑖𝑛𝑒𝑚𝑎𝑡𝑖𝑐 𝑣𝑖𝑠𝑐𝑜𝑠𝑖𝑡𝑦 𝑜𝑓 𝑤𝑎𝑠𝑡𝑒𝑤𝑎𝑡𝑒𝑟, 𝑐𝑒𝑛𝑡𝑖𝑠𝑡𝑜𝑘𝑒
g = acceleration due to gravity 9810 mm/𝑠𝑒𝑐2
If taking g = 981 cm/𝑠𝑒𝑐2
and 𝑣= 1 centistoke at 20 C the Factor
𝑔
18𝑣
= 545
At 20 C V = 545 (s - 1) 𝒅 𝟐
At Other temp V =418 (s - 1) 𝒅 𝟐 𝟑𝒕+𝟕𝟎
𝟏𝟎𝟎
5. Newton’s Law
V = 𝟑. 𝟑𝟑𝒈𝒅(𝒔 − 𝟏)
Where v = settling velocity mm/sec
d = Diameter of particle, mm
g = acceleration due to gravity 9810 mm/𝑠𝑒𝑐2
6. Hazen’s Equation
V =418 (s-1)
𝟑𝒕+𝟕𝟎
𝟏𝟎𝟎
Where v = settling velocity mm/sec
d = Diameter of particle, mm
t = temperature
Stoke’s law is valid for particles < 0.2mm and Newton’s equation is valid for
particles > 1mm.
The grit particles of wastewater are having size between 0.1 to 1 mm.
7. Hazen’s Equation
V =60.6 (s-1)d
𝟑𝒕+𝟕𝟎
𝟏𝟎𝟎
Where v = settling velocity mm/sec
d = Diameter of particle, mm
t = temperature
This equation is applicable for discrete spherical grit particle.
8. Type of settling tanks
Based on nature of working
Fill and Empty type
Continuous flow type
Based on location in treatment plant
Preliminary settling tank
Primary Settling tank
Secondary Settling tank
Based on shape of the tank in plant
Rectangular settling tank
Circular tanks
9. Fill and Empty type
This type of tank first of all wastewater is filled and allowed to
remains in still condition for about one hour.
The supernatant is drawn out and settled sludge is cleared.
The cleaning takes another 4 to 6 hours
There is wastage of time and labour
Generally not provided in wastewater treatment plant.
10. Continuous flow type
This type of tanks wastewater is continuously supplied at one point
called inlet and same after treatment leaves continuously from the
other point called outlet.
The wastewater entering the tank is called influent and leaving the
tank is called effluent.
11. Surface Overflow Rate
It is expressed in
𝑚3
𝑚2 /𝑑𝑎𝑦.
Sr No Type of sedimentation SOR Depth
Average flow Peak Flow
1 Primary settling only 25-30 50-60 3 to 3.5
2 Primary settling followed by
secondary treatment
35-50 80-125 3 to 3.5
3 Primary settling with activated
sludge returns
25 -35 50-60 3.5 to 4.5
4 Secondary settling with trickling
filter
10-25 40-50 3 to 3.5
5 Secondary settling with activated
sludge
15-35 40-50 3.5 to 4.5
6 Secondary settling with extended
aeration
8-15 35 3.5 to 4.5
12. Detention Period
It is theoretical time for which wastewater remains inside the tank.
It is calculated by dividing the volume of tank with the discharge.
It is normally kept as 1 to 1.5 hours for wastewater treatment.
The detention time in PST is not increase because of the
development of septic condition.
13. Velocity of flow
Velocity of flow in case of rectangular primary sedimentation tanks
can be taken between 15 to 30 cm/min.
14. Weir loading rate
Weir loading rates have some effect on removal efficiency of settling
tanks.
PST are generally designed for loading less than 370
𝑚3
𝑚
/𝑑
15. Dimension for PST
Clarifier Classification Range Typical
Rectangular
Length, m 10 to 100 25 to 60
Length to width ratio 1 to 7.5 4
Length to depth ratio 4.0 to 25.0 7 to 18
Width 3 – 24 6 to 10
Side water depth, m 2.5 to 3.0 3.5
Circular
Diameter, m 3 to 60 10 – 40
Side water depth, m 3 to 6 4
16. Example
Design a primarily settling tank of rectangular shape for a town having
population of 40000 with water supply of 135 l/c/d
Assume 80% of water supply to the town is converted in to wastewater
waste water formed daily = 40000 * 135 * 0.8 litre
= 40 * 135 * 0.8 m3
= 4320 m3/d
Assume detention period of 2 hours.
capacity of tank = flow for 2 hour = 4320 * 2 / 24
= 360 m3
Again let us assume SOR of 30 m3/m2 day
surface area = water flow / SOR
= 4320 / 30
= 144 m2
Effective depth = volume / Surface area = 360/144 = 2.5 m
17. Example
Design a primarily settling tank of rectangular shape for a town having
population of 40000 with water supply of 135 l/c/d
Take L/B = 4
L = 4B
L * B = 144
4B * B = 144
B = 6
L = 4B = 4 * 6 = 24 m
Provide 4 m additional for inlet and outlet arrangment
L = 24 + 4 = 28 m
Effective depth = 2.5 m
Provide 1 m for sludge accumulation and 0.5 m for free board
Total depth = 2.5 + 1 + 0.5 = 4.0 m
Hence dimension of tank will be 6 * 28 * 4 m.