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A Riemann sum is a certain kind of approximation of an integral by a finite sum. It is named after
nineteenth century German mathematician Bernhard Riemann. One very common application is
approximating the area of functions or lines on a graph, but also the length of curves and other
approximations.
EXAMPLE 1: Find the area of the region bounded by 𝑓(π‘₯) = π‘₯2
+ 1 on an interval [0,4] using L4
SOLUTION: Note: In getting the area of the rectangle the formula you used π‘Žπ‘Ÿπ‘’π‘Ž = 𝐿 π‘₯ π‘Š.
Length With Area
1st
1 1 1
2nd
2 1 2
3rd
5 1 5
4th
10 1 10
Final Answer πŸπŸ– π’–π’π’Šπ’•πŸ
Under Estimated
Finding the length:
𝑓(0) = (0)2
+ 1 = 1 (1st
rectangle)
𝑓(1) = (1)2
+ 1 = 2 (2nd
rectangle)
𝑓(2) = (2)2
+ 1 = 5 (3rd
rectangle)
𝑓(3) = (3)2
+ 1 = 10 (4th
rectangle)

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Approximating Area and Length Using Riemann Sums

  • 1. A Riemann sum is a certain kind of approximation of an integral by a finite sum. It is named after nineteenth century German mathematician Bernhard Riemann. One very common application is approximating the area of functions or lines on a graph, but also the length of curves and other approximations. EXAMPLE 1: Find the area of the region bounded by 𝑓(π‘₯) = π‘₯2 + 1 on an interval [0,4] using L4 SOLUTION: Note: In getting the area of the rectangle the formula you used π‘Žπ‘Ÿπ‘’π‘Ž = 𝐿 π‘₯ π‘Š. Length With Area 1st 1 1 1 2nd 2 1 2 3rd 5 1 5 4th 10 1 10 Final Answer πŸπŸ– π’–π’π’Šπ’•πŸ Under Estimated
  • 2. Finding the length: 𝑓(0) = (0)2 + 1 = 1 (1st rectangle) 𝑓(1) = (1)2 + 1 = 2 (2nd rectangle) 𝑓(2) = (2)2 + 1 = 5 (3rd rectangle) 𝑓(3) = (3)2 + 1 = 10 (4th rectangle)