Government and Not for profit accounting 2022 CAFR (City of Anaheim) S.pdf

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Government and Not for profit accounting 2022 CAFR (City of Anaheim) Select one of the more recently established (and larger) capital projects funds (a major fund, if there is one). a) From where did the fund receive most of its resources? b) Did the city acquire or construct new capital assets using resources of this fund? If so, in what amount? c) Does this fund have any longterm debts associated with it? If so, does the government maintain a debt service fund to account for the resources to service the debt? d) Did the government issue additional longterm debt to support governmental activities during the year? Did it repay any longterm debt used to support governmental activities? Did it engage in any insubstance defeasances?.

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Grouper Corporation is authorized to issue both preferred and commonstock. The par value of the preferred is $50 . During the first year of operations, the company had the following events and traruactions pectainung to its preferred stock. Feb. I Isoued 21.500 shares for cashat $60 pershare July: 1 Issued 10,500 shares for cishat $64 pershare Post to the stockholders' equity accounts. (Post entries in the order of joumat entrles prisented in the previous part).

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Guessing or knowing the initial TCP sequence number (ISN) that a server will choose enables an attacker to establish a TCP connection. Please discuss if the following solutions are secure (to prevent hijacking etc.) against off-path attackers and why. [x] denotes truncation of x to the 32 32 least significant bits. K is a (permanent) secret key stored locally and only known to the server. H represents a secure hash function (e.g., SHA256) and its algorithm is publicly known. Also note that || means concatenation and current timestamp is represented as UNIX timestamp. You can assume that 4 tuple information (source / destination IP and port) are known to the attacker. (1) Server selects ISN as ISN = [H(K)] . 32 (2) Server computes ISN as follows: ISN = [H(source IP address XOR destination IP address XOR current timestamp XOR K)] . 32 (3) Server computes ISN as ISN = [H(source IP address || destination IP address || source port number || destination port number || current timestamp)] . 32 (4) Server selects ISN using a standard (i.e., publicly-known) pseudo random generator with K as a seed. (5) Server selects ISN as ISN = [AES ECB(K, counter)] , where the counter is continuous from 32 the previous communication session..

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Greener Pastures Corporation borrowed $1 , 100 , 000 on November 1, 2021. The note carried a 9 percent interest rate with the principal and interest payable on June 1, 2022. (a) The note issued on November 1 . (b) The interest accrual on December 31 110.6 (Algo) Part 1 1. Indicate the effects of the amounts for the abovo transactions. (Enter any decreases to assets, liabilities, or stockholders equity with a minus sign. Do not round intermediate calculations.y.

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Given the following class in Java : public class ThreeTenDynArray<T> { //default initial capacity / minimum capacity private static final int MIN_CAPACITY = 2; //underlying array for storage -- you MUST use this for credit! //Do NOT change the name or type private T[] data; private int size = 0; private int capacity = 0; // ADD MORE PRIVATE MEMBERS HERE IF NEEDED! /** * */ @SuppressWarnings("unchecked") public ThreeTenDynArray() { // Constructor // Initial capacity of the storage should be MIN_CAPACITY // Hint: Can't remember how to make an array of generic Ts? It's in the textbook... data = (T[])(new Object[MIN_CAPACITY]); size = 0; capacity = MIN_CAPACITY; } /** * @param initCapacity */ @SuppressWarnings("unchecked") public ThreeTenDynArray(int initCapacity) { // Constructor // Initial capacity of the storage should be initCapacity. // - Throw IllegalArgumentException if initCapacity is smaller than // MIN_CAPACITY 2 // - Use this _exact_ error message for the exception // (quotes are not part of the message): // "Capacity must be at least 2!" if (initCapacity < MIN_CAPACITY) { throw new IllegalArgumentException("Capacity must be at least 2!"); } } /** * @return */ public int size() { // Report the current number of elements // O(1) return size; //default return, remove/change as needed } /** * @return */ public int capacity() { // Report max number of elements of the current storage // (subject to change since this is a _dynamic_ ) // O(1) return capacity; //default return, remove/change as needed } /** * @param index index you're changing * @param value what you're adding * @return the old item at the index */ public T set(int index, T value) { // Replace the item at the given index to be the given value. // Return the old item at that index. // Note: You cannot add new items (i.e. cannot increase size) with this method. // O(1) //return firstIndexOf(value); // - Throw IndexOutOfBoundsException if index is not valid // - Use this code to produce the correct error message for // the exception (do not use a different message): // "Index: " + index + " out of bounds!" if (index < 0 && index >= size) { throw new IndexOutOfBoundsException("Index: " + index + " out of bounds!"); } // - Throw IllegalArgumentException if value is null. // - Use this _exact_ error message for the exception // (quotes are not part of the message): // "Cannot include null values!" if (value==null) { throw new IllegalArgumentException("Cannot include null values!"); } T oldValue = data[index]; data[index] = value; return oldValue; //default return, remove/change as needed } /** * @param index * @return */ public T get(int index) { // Return the item at the given index if (index < 0 && index >= size) { throw new IndexOutOfBoundsException("Index: " + index + " out of bounds!"); } // O(1) // Use the exception (and error message) described in set() // for invalid indicies. return data[index]; //default return, remove/change as needed } /** * @param value */ @SuppressWarn.

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Given Information #1: Period 1 is when Devah is working and earning money, and Period 2 is when she is retired and not working. In the beginning of her life, she is provided with utility over consumption by During period 1, Devah will have total income of $1000 that she can either devote to c or to 1 savings, s . Any money that she saves can be used for consumption in period 2 (during which time she will not have any other source of income). Assume that interest on savings is zero. GIVEN INFORMATION #2 GIVEN INFORMATION #3 PLEASE SOLVE:.

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Give concise and substantial answers by relating your answers to your own experience. Practice intellectual integrity 1. Discuss the significance of the use of technology in teaching and learning language and literature. give particular technology applications that us use in the classroom to improve learning outcomes - 2. Discuss the use of social networking, research and technology to address global communication trends and issues - 25% 3. Narrate and explain how the various technology tools/ instruments may facilitate effective development of the ff. language skills 2.1 Writing 2.2. Listening and Speaking 3. Reading and 4. Viewing - Give particular examples -.

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Given an IntNode struct and the operating functions for a linked list, complete the following functions to extend the functionality of the linked list: IntNode* IntNode_GetNth(IntNode* firstNode, int n)- Return a pointer to the nth node of the list starting at firstNode. void IntNode_PrintList(IntNode* firstNode) - Call IntNode_PrintNodeData() to output values of the list starting at firstNode. Do not add extra space characters in between values. int IntNode_SumList(IntNode* firstNode) - Return the sum of the values of all nodes starting at firstNode. Note: The code for IntNode_Create() provided here differs from the code shown in the book. The given main() performs various actions to test IntNode_GetNth(), IntNode_PrintList(), and IntNode_SumList(). main() reads 5 integers from a user: The number of nodes to be added to a new list The value of the first node of the list An increment between the values of two consecutive nodes. A value of a new node The position of a node after which the new node will be added, with 1 indicating the first node Ex: If the input is: the output is: Here's the code #include <stdio.h> #include <stdlib.h> typedef struct IntNode_struct { int dataVal; struct IntNode_struct* nextNodePtr; } IntNode; // Allocate a node for initData IntNode* IntNode_Create (int initData) { IntNode* newNode = (IntNode*)malloc(sizeof(IntNode)); newNode->dataVal = initData; newNode->nextNodePtr = NULL; return newNode; } /* Insert newNode after node. Before: thisNode -- next After: thisNode -- newNode -- next */ void IntNode_InsertAfter (IntNode* thisNode, IntNode* newNode) { IntNode* tmpNext = NULL; tmpNext = thisNode->nextNodePtr; // Remember next thisNode->nextNodePtr = newNode; // this -- new -- ? newNode->nextNodePtr = tmpNext; // this -- new -- next } // Print dataVal void IntNode_PrintNodeData(IntNode* thisNode) { printf("%d ", thisNode->dataVal); } // Grab location pointed by nextNodePtr IntNode* IntNode_GetNext(IntNode* thisNode) { return thisNode->nextNodePtr; } /* ******** New functions ********/ // Return the length of the list int IntNode_Length(IntNode* firstNode) { int length = 0; IntNode* currentNode = firstNode; while(currentNode != NULL) { ++length; currentNode = currentNode->nextNodePtr; } return length; } // Return the Nth element of the list. First node is 1. IntNode* IntNode_GetNth(IntNode* firstNode, int pos) { /* Type your code here. */ } // Print the entire list starting at firstNode void IntNode_PrintList(IntNode* firstNode) { /* Type your code here. */ } // Sum the numbers in the list int IntNode_SumList(IntNode* firstNode) { /* Type your code here. */ } int main(void) { IntNode* firstNode = NULL; IntNode* lastNode = NULL; IntNode* newNode = NULL; IntNode* curNode = NULL; int listSize; // how many integers to read int increment; // increment between consecutive node values int firstNum; // first node value // New node for newNum will be inserted after position newPos (first node = 1) int newPos; int newNum; int i; .

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Getting error : (Return type of out-of-line definition of 'Product::GetProductCondition' differs from that in the declaration) Please help to show correct code in product file that will compile and build successfully. all code below and files Main.cpp #include <iostream> #include <time.h> #include "InventorySystem.hpp" #include <iostream> #include "Product.hpp" #include <time.h> #include <stdlib.h> using namespace std; int main() { srand(time( NULL )); Inventory_System *h1 = nullptr ; h1 = new Inventory_System("Radioshack", 117); h1->BuildInventory(); h1->ShowInventory(); h1->ShowDefectInventory(); h1->Terminate(); delete h1; return 0; }; InventorySystem.cpp #include "InventorySystem.hpp" #include "InventoryItem.hpp" #include "Product.hpp" #include <iostream> #include <fstream> #include <sstream> Inventory_System::Inventory_System() { } Inventory_System::Inventory_System(std::string name, int id) : store_name(name), store_id(id) { } Inventory_System::~Inventory_System() { for ( int i = 0; i < item_count; i++) { delete ptr_inv_item[i]; } } int Inventory_System::GetStoreId(){ return store_id; } int Inventory_System::GetItemCount(){ return item_count; } std::string Inventory_System::GetStoreName(){ return store_name; } void Inventory_System::BuildInventory() { std::ifstream file("products_test.txt", std::ios::in); std::string name, quantity, price, condition; Inventory_Item *item; if (!file) { std::cerr << "Error: Failed to open file\n"; exit(-1); } else { while (!file.eof()) { item = new Product(); Product *product = static_cast <Product*> (item); std::getline(file, name, ';'); product->SetItemName(name); std::getline(file, quantity, ';'); product->SetItemQuantity(stoi(quantity)); std::getline(file, price, ';'); product->SetProductPrice(stold(price)); std::getline(file, condition, '\n'); switch (condition[0]) { case 'D': product->SetProductCondition(PC_DEFECTIVE); break ; case 'N': product->SetProductCondition(PC_NEW); break ; case 'R': product->SetProductCondition(PC_REFURBISHED); break ; case 'U': product->SetProductCondition(PC_USED); break ; default : product->SetProductCondition(PC_NEW); break ; } product->SetProductId(rand() % 10000); ptr_inv_item[item_count] = product; item_count++; } } } void Inventory_System::ShowInventory() { for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); temp->Display(); } } void Inventory_System::ShowDefectInventory() { for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); if (temp->GetProductCondition() == PC_DEFECTIVE) { temp->Display(); } } } void Inventory_System::Terminate() { std::ofstream file; std::stringstream ss; file.open("example.txt"); for ( int i = 0; i < item_count; i++) { Product *temp = static_cast <Product*> (ptr_inv_item[i]); file << temp->GetItemName() << ";" << temp->GetItemQuantity() << ";" << temp->GetProductPrice() << ";"; switch (temp->GetProductCondition()) { case PC_DEFECTIVE: file << "D\n"; brea.

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