This slide explains about Pointer to string literals, Array of Pointers.

1. Prepared by
Mohammed Sikander
Technical Lead
Cranes Software International Limited

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char *ptr_name = “SIKANDER”;
char str_name[ ] = “SIKANDER”;
• Can we make a pointer point to string literal?

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char *ptr_name = “SIKANDER”;
char str_name[ ] = “SIKANDER”;
printf(“ %s n“ , ptr_name);
printf(“ %s n“ , str_name);
• Can we print the string through pointer.

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char *ptr_name = “SIKANDER”;
char str_name[ ] = “SIKANDER”;
printf(“Length of %s = %dn“ , ptr_name , strlen(ptr_name));
printf(“Length of %s = %dn“ , str_name , strlen(str_name));

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char *ptr_name = “SIKANDER”;
char str_name[ ] = “MUQADDAR”;
printf(“Size of ptr_name = %dn“ , sizeof(ptr_name));
printf(“Size of str_name = %dn“ , sizeof(str_name));

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9. We can have arrays where each element
can be a pointer
int *
char **
int *
int *
int *
int *
int *arr_ptr[5];
int
int
int
int
int
int arr[5];
What is size of arr?
What is size of arr_ptr?

10. char **
Char *arr_ptr[5];
char
*
char *
char *
char *
char *
char
char
char
char
char
Char arr[5];
What is size of arr?
What is size of arr_ptr?

11. int x = 10;
int *ptr = &x;
int arr[5]
int *ptr = arr;
int a = 10;
int b = 23;
int arr[ ] = {12,34,54};
int *ptr[ ] = {&a , &b , arr};

12. char *capitalCities[] = { “Bangalore”, “Chennai”,
“Guwahati”, “Amravathi”};
Bangalore
Chennai
Guwahati
Amravathi
*
*
*
*
char *
char *
char *
char *
char *str = “VxWorks”;

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14.  names++ tries to change the base address of array.
 We cannot change the base address of array.
 Str was a pointer, names is an array.
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17. char **
*
Bangalore
Chennai
Guwahati
Amravathi
NULL
*
*
*
*
char *
char *
char *
char *

18.  Void pointers can hold the address of any
type of object.
 Dereferencing on void pointers are not
allowed.
 Incrementing void pointers are not allowed.

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