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MULTI-STEP
EQUATIONS
Section 2.3 pages 91-96
Previously
11π‘₯ = 77
11π‘₯
11
=
77
11
Divide by 11 on both sides
π‘₯ = 7
Multi-Step Equations
β–  More than one operation to solve
β–  Work backwards in order of operations
β–  Undo all operations to isolate the variable
Solve the equation
2π‘Ž βˆ’ 6 = 4
+6 + 6
2π‘Ž = 10
Γ· 2 Γ· 2
π‘Ž = 5
Solve the equation
𝑛 + 1
βˆ’2
= 15βˆ’2 βˆ™ βˆ™ βˆ’2
𝑛 + 1 = βˆ’30
βˆ’1 βˆ’ 1
𝑛 = βˆ’31
Translate and then solve
Twelve decreased by twice a number is -34.
12 βˆ’ 2π‘₯ = βˆ’34
βˆ’12 βˆ’ 12
βˆ’2π‘₯ = βˆ’46
Γ· βˆ’2 Γ· βˆ’2
π‘₯ = 23
A Multi Part Problem
If 3π‘š + 4 = βˆ’11, what is the value of 2π‘š + 14?
Part 1: Find the value of π‘š by solving the given equation.
Part 2: Substitute in what you found to evaluate the value of the given expression.
3π‘š + 4 = βˆ’11
3π‘š = βˆ’15
π‘š = βˆ’5
2π‘š + 14
2(βˆ’5) + 14
βˆ’10 + 14
4
The answer to the question is 4.
Algebra 1i Homework
Page 94-95 #11-22, 24, 25, 48-50
Consecutive Integers
β–  Integers that come in counting order
β–  For example 4, 5, 6 can be written as 𝑛, 𝑛 + 1, 𝑛 + 2
β–  n is the first of the consecutive integers
Consecutive Odd or Even Integers
β–  Odd or Even numbers in counting order
β–  Skips every other number
β–  Must add 2 each term
β–  Consecutive Odd example: 5, 7, 9 can be written as 𝑛, 𝑛 + 2, 𝑛 + 4
β–  Consecutive Even example: 12, 14, 16 can be written as 𝑛, 𝑛 + 2, 𝑛 + 4
Write an equation and solve
Find three consecutive integers with a sum of 21.
Add 𝑛, 𝑛 + 1, π‘Žπ‘›π‘‘ , 𝑛 + 2 to equal 21
𝑛 + 𝑛 + 1 + 𝑛 + 2 = 21
3𝑛 + 3 = 21
3𝑛 = 18
𝑛 = 6
𝑛 + 1 = 7
𝑛 = 6
𝑛 + 2 = 8
The three integers are 6, 7, and 8.
Algebra 1 Homework
Page 94-95 #24-39, 42-50

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2 3 multi step equations

  • 3. Multi-Step Equations β–  More than one operation to solve β–  Work backwards in order of operations β–  Undo all operations to isolate the variable
  • 4. Solve the equation 2π‘Ž βˆ’ 6 = 4 +6 + 6 2π‘Ž = 10 Γ· 2 Γ· 2 π‘Ž = 5
  • 5. Solve the equation 𝑛 + 1 βˆ’2 = 15βˆ’2 βˆ™ βˆ™ βˆ’2 𝑛 + 1 = βˆ’30 βˆ’1 βˆ’ 1 𝑛 = βˆ’31
  • 6. Translate and then solve Twelve decreased by twice a number is -34. 12 βˆ’ 2π‘₯ = βˆ’34 βˆ’12 βˆ’ 12 βˆ’2π‘₯ = βˆ’46 Γ· βˆ’2 Γ· βˆ’2 π‘₯ = 23
  • 7. A Multi Part Problem If 3π‘š + 4 = βˆ’11, what is the value of 2π‘š + 14? Part 1: Find the value of π‘š by solving the given equation. Part 2: Substitute in what you found to evaluate the value of the given expression. 3π‘š + 4 = βˆ’11 3π‘š = βˆ’15 π‘š = βˆ’5 2π‘š + 14 2(βˆ’5) + 14 βˆ’10 + 14 4 The answer to the question is 4.
  • 8. Algebra 1i Homework Page 94-95 #11-22, 24, 25, 48-50
  • 9. Consecutive Integers β–  Integers that come in counting order β–  For example 4, 5, 6 can be written as 𝑛, 𝑛 + 1, 𝑛 + 2 β–  n is the first of the consecutive integers
  • 10. Consecutive Odd or Even Integers β–  Odd or Even numbers in counting order β–  Skips every other number β–  Must add 2 each term β–  Consecutive Odd example: 5, 7, 9 can be written as 𝑛, 𝑛 + 2, 𝑛 + 4 β–  Consecutive Even example: 12, 14, 16 can be written as 𝑛, 𝑛 + 2, 𝑛 + 4
  • 11. Write an equation and solve Find three consecutive integers with a sum of 21. Add 𝑛, 𝑛 + 1, π‘Žπ‘›π‘‘ , 𝑛 + 2 to equal 21 𝑛 + 𝑛 + 1 + 𝑛 + 2 = 21 3𝑛 + 3 = 21 3𝑛 = 18 𝑛 = 6 𝑛 + 1 = 7 𝑛 = 6 𝑛 + 2 = 8 The three integers are 6, 7, and 8.
  • 12. Algebra 1 Homework Page 94-95 #24-39, 42-50