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UNIT - 3
PROBLEM SOLVING
AND
OFFICE AUTOMATION
Program
• Program is a collection of instructions that
will perform some task.
Problem Solving Steps
• Analyse the problem.
• Identify the solution for the problem and
divide it into small task.
• Algorithm has to be prepared.
• Based on the algorithm the program will
be created.
• Then it has to be executed.
Program Development Cycle
Methodologies
• Program planning method
• Waterfall method etc,.
Program planning method
Specification
Review
Informal Design
Test & Debug
Coding
Formal Design
Maintaining
• Specification review
– collect the requirements
– understand the requirements
• Informal Design
– Identifies the major tasks
– Identifies the subtasks
• Formal Design
– It converts the informal design to some format
that can be understand by others.
• Coding
– It converts the Design into Programs.
– It translate these programs to machine
language.
• Test & Debug
– It use sample data to test whether it works
properly.
– It also eliminate the errors.
• Maintaining
– It Modifies the programs if necessary.
Waterfall method
Feasibility
Analysis
Maintenance
Testing
Impl
Design
• Feasibility
–It determines whether it is possible to
create the project or not.
–It also produce the plans and the
estimates.
• Analysis
–It get the requirements from the
customer.
–It analysis the requirements.
• Design
–It is the process of designing how the
requirements to be implemented.
• Implementation
–It converts the designs into code.
–After coding it use language translators
to compile the code.
• Testing
–Here the modules are integrated
together.
–Then the project is tested and find
whether it meets the customer/user
requirements.
• Maintenance
–It make modifications based on the
customer feedbacks.
Algorithm
• Algorithm is a finite sequence of
instructions required for producing the
desired result.
Characteristics
• The steps in the algorithm must be
unambiguous .
• It should be written in sequence.
• Ensure that the algorithm will terminate.
• It should conclude after a finite number of
steps.
Factors used to judge the algorithm
• Time
• Memory
• Accuracy
• Sequence etc,.
Representations
• Flowcharts
• Normal English
• Pseudo code etc,.
Example
• Addition of two numbers
Step1: Start
Step2: Read a, b
Step3: Add the value of a with b and
store the result in c.
Step4: Display the value of c
Step5: Stop
Flowcharts
• It is the pictorial representation of the
algorithm.
Flowchart Symbols
• Terminal symbol
– It is used to represent the start, end of the
program logic.
• Input/Output
– It is used for input or output.
• Process Symbol
– It is used to represent the calculations, data
movements, initialization operations etc,.
• Decision Symbol
– It is used to denote a decision to be made at
that point
• Flow lines
– It is used to connect the symbols
• Connectors
– It is used to connect the flow lines.
Guidelines for preparing flowcharts
• It should be simple.
• Standard symbols should be used.
• The flow lines should not intersect each
others.
• In case of complex flowcharts use the
connectors symbols.
• Only one flow line should enter the
process symbol and only one flow line
should come out from a process symbol.
• Only one flow line used with the terminal
symbol.
START
STOP
• Only one flow line should enter the
decision symbol and two or three flowlines
may leave from the decision symbol.
Benefits of Flowcharts
• Makes Logic Clear
• Communication
• Effective Analysis
• Useful in coding
• Useful in Testing etc,.
Limits of Flowcharts
• It is difficult to use flowcharts for large
program
• Difficult to modify
• Cost etc,.
Pseudocode
• Pseudo means imitates and code means
instruction.
• It is formal design tool.
• It is also called Program Design Language.
Keywords
• READ,GET
• PRINT,DISPLAY
• COMPUTE,CALCULATE
Guideline for writing Pseudocode
• Steps should be understandable
• Capitalize the keyword.
• Indent to show hierarchy.
• End multiple line structure etc,.
Example
READ a,b
C=a+b
WRITE C
stop
Example
READ a,b
IF a>b
PRINT a is greater
ELSE
PRINT b is greater
ENDIF
stop
Advantage & Disadvantage
• It can be easily modified
• It can be understood easily
• Compare to flowchart it is difficult to
understand the program logic.
Sequence control structure
Flow chart Pseudocode
Process 1
Process 2
Process n
Process 2
Process n
Process 1
Design Structures
Sequence control structure
• The instructions are computed in
sequence i.e. it performs instruction
one after another.
• It uses top-down approach.
Design Structures
Example
START
C=a+b
Print c
Read a,b
STOP
SELECTION CONTROL STRUCTURE
• It is used for making decisions.
• It allows the program to make a choice
from alternative paths.
• IF …THEN
• IF …THEN… ELSE
• CASE etc.,
IF…THEN
Pseudocode Flow chart
IF condition THEN
process 1
.
.
END IF
.
.
If
condition
NO
YES
Process 1
Example
Start
Read a
If a>0
Print a is Positive
Stop
no
yes
IF…THEN…ELSE
Pseudocode Flowchart
IF condition THEN
process 1
.
.
ELSE
process 2
.
.
END IF
.
.
If
condition
YES NO
Process 1 Process 2
Example
Start
Read a,b
If a>b
Print a is Greater
Print b is Greater
Stop
no
yes
CASE structure
Pseudocode Flow chart
.
.
CASE Type
Case Type-1:
Process 1
Case Type-2:
Process 2
.
.
Case Type-n:
Process n
.
.
END CASE
Type 1
Type 2
Type 3
Process 1
Process 2
Process 3
no
no
no
yes
yes
yes
start
stop
Read m1,m2,m3
Avg=(m1+m2+m3)/3
If
Avg>=60
If
Avg>=50
If
Avg>=35
Fail
Print
First Class
Print
Second Class
Print
Third Class
Example: Finding the Grade
Looping control structure
• It is used to execute some instructions
several time based on some condition.
• WHILE loop
• Do…WHILE loop etc.,
WHILE Loop
Pseudocode Flow chart
.
.
WHILE condition
.
.
Body of the loop
.
.
END WHILE
Body of The loop
condition
no
yes
Example
Start
Num=0
Num=Num+1
Print Num
while
Num<5
stop
no
yes
DO…WHILE Loop
Pseudocode Flow chart
DO
.
.
Body of the loop
.
.
WHILE condition
.
.
END WHILE
Body of The loop
condition
no
yes
Example
Start
Num=0
Num=Num+1
Print Num
while
Num<5
stop
no
yes
Example: Finding the area of a circle
Algorithm
Step1: Start
Step2: Read the value of r
Step3: Calculate area = 3.14*r*r
Step4: Print area
Step5: Stop
Pseudocode
Set area
READ the r
COMPUTE area=3.14*r*r
PRINT area
stop
Flowchart
START
area=3.14*r*r
Print area
Read r
STOP
Find the largest among three Numbers
Algorithm
Step1: Start
Step2: Read the value of a, b, c
Step3: IF (a>b) and (a>c) THEN
print a is largest
ELSE IF (b>c) THEN
print b is largest
ELSE
print c is largest
Step4: Stop
Pseudocode
READ a, b, c
IF (a>b) and (a>c) THEN
WRITE a is largest
ELSE IF (b>c) THEN
WRITE b is largest
ELSE
WRITE c is largest
ENDIF
stop
Flowchart
START
Print b
Is largest
Read a,b,c
stop
If
(a>b) and
(a>c)
If
b>c
Print a
Is largest
Print c
Is largest
no
yes
yes
no
Finding roots of the Quadratic equation
Step:1 Start
Step:2 Enter the values of a,b,c
Step:3 Find the value of D Using the Formula,
D = b*b-4*a*c
Step:4 If D is greater than or equal to zero find 2
roots
root1(-b+sqrt(D))/(2*a)
root2(-b-sqrt(D))/(2*a)
Step:5 Print root1 & root2
Step:6 If D is less than zero, then print the roots
are imaginary
Step:7 Stop
Pseudocode
Set root1,root2
READ the value of a, b, c
Find D b*b-4*a*c
IF D>=0 THEN
calculate root1=(-b+sqrt(D))/(2*a)
root2=(-b-sqrt(D))/(2*a)
ELSE
Roots are imaginary
END IF
WRITE root1,root2
Stop
Flow chart
Start
Stop
D=b*b-4*a*c
Root1=[-b+sqrt(D)]/(2*a)
Root2=[-b+sqrt(D)]/(2*a)
Read a,b,c
Print root1,root2
If D>=0
no
yes
Print
roots are imaginary
Swapping two variables
Algorithm
Step1: Start
Step2: Read the value of a, b
Step3: c = a
a = b
b = c
Step4: Print the value of a and b
Step5: Stop
Pseudocode
READ the value of a, b
To swap use
c = a
a = b
b = c
WRITE a, b
stop
Flowchart
START
c = a
a = b
b = c
Print a, b
Read a, b
STOP
Swapping two variables without using
another variable
Algorithm
Step1: Start
Step2: Read the value of a, b
Step3: a = a + b
b = a - b
a = a - b
Step4: Print the value of a and b
Step5: Stop
Pseudocode
READ the value of a, b
To swap use
a = a + b
b = a - b
a = a - b
WRITE a, b
stop
Flowchart
START
a = a + b
b = a - b
a = a - b
Print a, b
Read a, b
STOP
Finding the year is leap year or not
Algorithm
Step1: Start
Step2: Read the value of year
Step3: IF year % 4 ==0 THEN
print It is a Leap year
ELSE
print It is not a Leap year
Step4: Stop
Pseudocode
READ year
IF year % 4 ==0 THEN
WRITE It is a Leap year
ELSE
WRITE It is not a Leap year
ENDIF
stop
Flowchart
Start
Read year
year % 4 ==0
Print It is
a Leap year Print It is not a
Leap year
Stop
no
yes
Finding the Factorial
Algorithm
Step1: Start
Step2: Read the value of n and set i =1
Step3: While i <= n do
fact =fact * i
i = i + 1
else Goto step5
Step4: Goto step 3
Step5: print the value of fact
Step6: Stop
Pseudocode
READ the value of n and set i =1
WHILE (i <= n) do
fact =fact * i
i = i + 1
ENDWHILE
Repeat the loop until condition fails
WRITE fact
stop
Flowchart
Start
Read n
i = 1
fact=fact * i
i=i+1
Print fact
while
i<=n
stop
no
yes
Finding the Sum of the digits
Algorithm
Step1: Start
Step2: Read the value of n and set i = 0, sum = 0
Step3: While n>0 do
r=n%10
sum=sum + r
n=n/10
else Goto step5
Step4: Goto step 3
Step5: print the value of sum
Step6: Stop
Pseudocode
READ the value of n and set i =0, sum=0
WHILE (n>0) do
r=n%10
sum=sum + r
n=n/10
ENDWHILE
Repeat the loop until condition fails
WRITE sum
stop
Flowchart Start
r = 0,sum=0
r=n%10
sum=sum + r
n=n/10
Print sum
while
n>0
stop
no
yes
Read n
Finding the Reverse of a Number
Algorithm
Step1: Start
Step2: Read the value of n and set i = 0, sum = 0
Step3: While n>0 do
r=n%10
sum=sum *10 + r
n=n/10
else Goto step5
Step4: Goto step 3
Step5: print the value of sum
Step6: Stop
Pseudocode
READ the value of n and set i =0, sum=0
WHILE (n>0) do
r=n%10
sum=sum *10 + r
n=n/10
ENDWHILE
Repeat the loop until condition fails
WRITE sum
stop
Flowchart Start
r = 0,sum=0
r=n%10
sum=sum *10 + r
n=n/10
Print sum
while
n>0
stop
no
yes
Read n
Armstrong Number
Example: 153
13 +53 + 33 =153
Finding an Armstrong Number
Algorithm
Step1: Start
Step2: Read the value of n and set a = n, sum = 0
Step3: While n>0 do
r=n%10
sum=sum + r*r*r
n=n/10
else Goto step5
Step4: Goto step 3
Step5: If a = sum then
Print Armstrong Number
Else
Print It is Not an Armstrong Number
Endif
Step6: Stop
Pseudocode
READ the value of n and set a =n, sum=0
WHILE (n>0) do
r=n%10
sum=sum + r*r*r
n=n/10
ENDWHILE
Repeat the loop until condition fails
IF a=sum THEN
WRITE Armstrong Number
ELSE
WRITE It is not an Armstrong Number
ENDIF
stop
Flowchart Start
a = n,sum=0
r=n%10
sum=sum + r*r*r
n=n/10
Print Armstrong No
while
n>0
stop
no
yes
Read n
if
a=sum
Print It is Not an
Armstrong No
Fibonacci series
Example:
0 1 1 2 3 5 8 11….
Finding the Fibonacci series
Algorithm
Step1: Start
Step2: Read the value of n and set f=0,f1=-1, f2=1
Step3: While (f<n) do
f=f1+f2
f1=f2
f2=f
Print f
else Goto step5
Step4: Goto step 3
Step5: Stop
Pseudocode
READ the value of n and set f=0 ,f1=-1, f2=1
WHILE (f<n) do
f=f1+f2
f1=f2
f2=f
WRITE f
ENDWHILE
Repeat the loop until condition fails
stop
Flowchart Start
f=0,f1= -1,f2=1
f=f1+f2
f1=f2
f2=f
Print f
while
f<n
stop
no
yes
Read n
Conversion of Celsius to Fahrenheit
Algorithm
Step1: Start
Step2: Read the value of Celsius
Step3: Fahrenheit = (1.8* Celsius) + 32
Step4: Print Fahrenheit
Step5: Stop
Pseudocode
Set Fahrenheit
READ the Celsius
COMPUTE Fahrenheit = (1.8* Celsius) + 32
PRINT Fahrenheit
stop
Flowchart
START
Fahrenheit = (1.8* Celsius) + 32
Print Fahrenheit
Read Celsius
STOP
Conversion of Fahrenheit to Celsius
Algorithm
Step1: Start
Step2: Read the value of Fahrenheit
Step3:Calculate Celsius =(Fahrenheit – 32)/1.8
Step4: Print Celsius
Step5: Stop
Pseudocode
Set Celsius
READ the Fahrenheit
COMPUTE Celsius =(Fahrenheit – 32)/1.8
PRINT Celsius
stop
Flowchart
START
Celsius =(Fahrenheit – 32)/1.8
Print Celsius
Read Fahrenheit
STOP
Finding the sum of odd number between 1 to n
Algorithm
Step1: Start
Step2: Read the value of n and set sum=0,i=1
Step3: While (i<=n) do
sum=sum+i
i=i+2
else Goto step5
Step4: Goto step 3
Step5: Print sum
Step6: Stop
Pseudocode
READ the value of n and set sum=0,i=1
WHILE (i<=n) do
sum=sum+i
i=i+2
ENDWHILE
Repeat the loop until condition fails
WRITE sum
stop
Flowchart Start
sum=0,i=1
sum=sum+i
i=i+2
Print sum
stop
Read n
While i<=n
Finding the sum of even number between 1 to n
Algorithm
Step1: Start
Step2: Read the value of n and set sum=0,i=0
Step3: While (i<=n) do
sum=sum+i
i=i+2
else Goto step 5
Step4: Goto step 3
Step5: Print sum
Step6: Stop
Pseudocode
READ the value of n and set sum=0,i=0
WHILE (i<=n) do
sum=sum+i
i=i+2
ENDWHILE
Repeat the loop until condition fails
WRITE sum
stop
Flowchart Start
sum=0,i=0
sum=sum+i
i=i+2
Print sum
stop
Read n
While i<=n
Conversion of Binary number to Decimal
Algorithm
Step1: Start
Step2: Read the value of n and set i = 0, sum = 0
Step3: While n>0 do
r=n%10
sum=sum + r*pow(2,i)
n=n/10
i=i+1
else Goto step5
Step4: Goto step 3
Step5: print the value of sum
Step6: Stop
Pseudocode
READ the value of n and set i =0, sum=0
WHILE (n>0) do
r=n%10
sum=sum + r*pow(2,i)
n=n/10
i=i+1
ENDWHILE
Repeat the loop until condition fails
WRITE sum
stop
Flowchart Start
sum=0,i=0
Print sum
stop
Read n
While n>0
r=n%10
sum=sum + r*Pow(2,i)
n=n/10
i=i+1
Application software
Packages
Application software
• Set of programs, which is used to perform
some specific task.
• Example:
• Word processor
• Spreadsheet program
• Database program etc,.
MS-Word
• Starting MS-Word
Start  All Programs  Microsoft
Office  Microsoft Office Word
• Creating a New Document
File  New (or) ctrl+N
(or) clicking the new button
• Opening a Document
File  Open (or) ctrl+O
(or) clicking the open button
• Saving a New Document
File  Save (or) ctrl+S
(or) clicking the save button
• Printing a Document
File  Print (or) ctrl+P
(or) clicking the open button
• Moving the Text
Ctrl+X
(or) clicking the cut button
• Copying the Text
Ctrl+P
(or) clicking the copy button
Find and Replace
• Find & Replace
Edit Find and Replace (or) Ctrl+F
Formatting the Document
• Format Menu (Format  Font)
–Font size, type, colour, Subscript,
Superscript, Spacing,Text Effects etc,.
–Bullets and Numberings
–Changing case
–Borders and Shadings etc,.
UNIT 3 PROBLEM SOLVING AND OFFICE AUTOMATION

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