SlideShare a Scribd company logo
1 of 16
Download to read offline
指導教授:吳金典 專題學生:馬宜訢
Solving ODE's problem using
the Galerkin's method
INTRODUCTION:
Consider the ODE:
𝑎
𝑑 𝑦
𝑑𝑥
+ 𝑏
𝑑𝑦
𝑑𝑥
+ 𝑐𝑦 = 𝑓(𝑥)
With boundary condition:
y(L0) = B0
y(L1) = B1
Since we are going to use the Galerkin’s method, splitting the whole domain into n elements evenly
before the computation is necessary.
In this report, I am going to find out the relations of (a, 𝜀 ), (b, 𝜀 ), (n, 𝜀 ), where 𝜀 is the
maximum difference of the approximation 𝑦(𝑥) and the exact solution 𝑦(𝑥) along all 𝑥 ∈ [𝐿0, 𝐿1].
Hence, define 𝜀 as:
𝜀 ≡ 𝑚𝑎𝑥 ∈[ , ]{|𝑦(𝑥) − 𝑦(𝑥)|}
In order to make more efforts in the variables a, b, n, which we are interested about, fix c=1 and f(x)=x,
L0=0, L1=1, B0=B1=0. So the ODE’s problem becomes:
𝑎
𝑑 𝑦
𝑑𝑥
+ 𝑏
𝑑𝑦
𝑑𝑥
+ 𝑦 = 𝑥
y(0) = 0
y(1) = 0
A demonstration of Galerkin’s method.
the following contains data of:
1. a= (0.01,0.1,1,10,100), b=1, c=1, and changing n.
2. a=(1,2 , 2 ,2 , 2 , 2 ), b=1, c=1, and changing n.
3. a=1, b= (0.01,0.1,1,10,100), c=1, and changing n.
4. a=1, b= (1,2 , 2 ,2 , 2 , 2 ), c=1, and changing n.
DATAS:
for a=1, b=1, c=1
compute for n=2 , 2 .. 2 , 3 , 3 . . 3 ,4 , 4 . . 4
n 𝜀 ratio
2 2.2091e-02 -
2 5.5664e-03 2.5197e-01
2 1.4101e-03 2.5332e-01
2 3.5376e-04 2.5087e-01
2 8.8517e-05 2.5022e-01
2 2.2134e-05 2.5005e-01
2 5.5338e-06 2.5001e-01
2 1.3835e-06 2.5000e-01
2 3.4587e-07 2.5000e-01
2 8.6468e-08 2.5000e-01
3 9.9214e-03 -
3 1.1170e-03 1.1259e-01
3 1.2435e-04 1.1132e-01
3 1.3819e-05 1.1113e-01
3 1.5355e-06 1.1111e-01
3 1.7061e-07 1.1111e-01
4 5.5664e-03 -
4 3.5376e-04 6.3553e-02
4 2.2134e-05 6.2567e-02
4 1.3835e-06 6.2506e-02
4 8.6468e-08 6.2499e-02
Observation:
2.5000e-01=0.25=
1.1111e-01=0.1111=
6.2499e-02=0.062499≅ 0.0625=
Claim1: 𝜀 (n*r)/ 𝜀 (n)~ for n is sufficient large.
Changing ‘a’
for a=100, b=1, c=1
compute for n=2 , 2 .. 2 , 3 , 3 . . 3 ,4 , 4 . . 4
n 𝜀 ratio
2 2.3435e-04 -
2 6.8254e-05 2.9124e-01
2 1.8267e-05 2.6763e-01
2 4.7167e-06 2.5822e-01
2 1.1979e-06 2.5397e-01
2 3.0182e-07 2.5195e-01
2 7.5747e-08 2.5097e-01
2 1.8973e-08 2.5048e-01
2 4.7479e-09 2.5024e-01
2 1.1876e-09 2.5012e-01
3 1.1562e-04 -
3 1.4538e-05 1.2574e-01
3 1.6778e-06 1.1540e-01
3 1.8873e-07 1.1249e-01
3 2.1056e-08 1.1156e-01
3 2.3427e-09 1.1126e-01
4 6.8254e-05 -
4 4.7167e-06 6.9105e-02
4 3.0182e-07 6.3990e-02
4 1.8973e-08 6.2862e-02
4 1.1876e-09 6.2594e-02
Claim1 is satisfied.
Changing ‘a’
for a=10, b=1, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3 , 4 , 4 . . 4
n 𝜀 ratio
2 2.3407e-03 -
2 6.7283e-04 2.8745e-01
2 1.7869e-04 2.6558e-01
2 4.5952e-05 2.5716e-01
2 1.1646e-05 2.5344e-01
2 2.9311e-06 2.5168e-01
2 7.3522e-07 2.5083e-01
2 1.8411e-07 2.5041e-01
2 4.6066e-08 2.5021e-01
2 1.1521e-08 2.5010e-01
3 1.1452e-03 -
3 1.4209e-04 1.2408e-01
3 1.6318e-05 1.1484e-01
3 1.8324e-06 1.1230e-01
3 2.0432e-07 1.1150e-01
3 2.2728e-08 1.1124e-01
4 6.7283e-04 -
4 4.5952e-05 6.8296e-02
4 2.9311e-06 6.3786e-02
4 1.8411e-07 6.2813e-02
4 1.1521e-08 6.2577e-02
Claim1 is satisfied.
Changing ‘a’
for a=0.1, b=1, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3 ,4 , 4 . . 4
n 𝜀 ratio
2 3.2616e+00 -
2 1.9072e-01 5.8476e-02
2 7.0270e-02 3.6844e-01
2 2.4792e-02 3.5282e-01
2 7.6057e-03 3.0678e-01
2 2.1329e-03 2.8043e-01
2 5.6570e-04 2.6523e-01
2 1.4574e-04 2.5762e-01
2 3.6990e-05 2.5381e-01
2 9.3181e-06 2.5191e-01
3 2.5658e-01 -
3 5.9726e-02 2.3278e-01
3 1.0249e-02 1.7161e-01
3 1.3648e-03 1.3316e-01
3 1.6149e-04 1.1832e-01
3 1.8329e-05 1.1350e-01
4 1.9072e-01 -
4 2.4792e-02 1.2999e-01
4 2.1329e-03 8.6032e-02
4 1.4574e-04 6.8330e-02
4 9.3181e-06 6.3936e-02
Claim1 is satisfied.
Changing ‘a’
for a=0.01, b=1, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3 ,4 , 4 . . 4
n 𝜀 ratio
2 1.3523e+00 -
2 2.4501e+00 1.8119e+00
2 1.4093e+00 5.7521e-01
2 5.2583e-01 3.7311e-01
2 2.6395e-01 5.0197e-01
2 1.1207e-01 4.2456e-01
2 4.2906e-02 3.8287e-01
2 1.3765e-02 3.2081e-01
2 3.9932e-03 2.9010e-01
2 1.0787e-03 2.7012e-01
2 2.8054e-04 2.6007e-01
3 8.8810e-01 -
3 5.8544e-01 6.5920e-01
3 3.2494e-01 5.5503e-01
3 8.2991e-02 2.5541e-01
3 1.5043e-02 1.8126e-01
3 2.0621e-03 1.3708e-01
4 2.4501e+00 -
4 5.2583e-01 2.1461e-01
4 1.1207e-01 2.1313e-01
4 1.3765e-02 1.2283e-01
4 1.0787e-03 7.8365e-02
Claim1 is satisfied.
Note that in this case the ratios marked in yellow are not very close to the numbers in the claim compare to
previous cases. It is because of the shrinking of ‘a’ makes the stiffness matrix less symmetric. To continue the
process, these ratios would converge to .
for a= (0.01,0.1,1,10,100), b=1, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3
n 𝜀
(a=0.01)
𝜀
(a=0.1)
𝜀
(a=1)
𝜀
(a=10)
𝜀
(a=100)
2 1.3523e+00 3.2616e+00 2.2091e-02 2.3407e-03 2.3435e-04
2 2.4501e+00 1.9072e-01 5.5664e-03 6.7283e-04 6.8254e-05
2 1.4093e+00 7.0270e-02 1.4101e-03 1.7869e-04 1.8267e-05
2 5.2583e-01 2.4792e-02 3.5376e-04 4.5952e-05 4.7167e-06
2 2.6395e-01 7.6057e-03 8.8517e-05 1.1646e-05 1.1979e-06
2 1.1207e-01 2.1329e-03 2.2134e-05 2.9311e-06 3.0182e-07
2 4.2906e-02 5.6570e-04 5.5338e-06 7.3522e-07 7.5747e-08
2 1.3765e-02 1.4574e-04 1.3835e-06 1.8411e-07 1.8973e-08
2 3.9932e-03 3.6990e-05 3.4587e-07 4.6066e-08 4.7479e-09
2 1.0787e-03 9.3181e-06 8.6468e-08 1.1521e-08 1.1876e-09
n 𝜀 (a=0.1)/
𝜀 (a=0.01)
𝜀 (a=1)/
𝜀 (a=0.1)
𝜀 (a=10)/
𝜀 (a=1)
𝜀 (a=100)/
𝜀 (a=10)
2 2.41189 0.00677 0.10596 0.10012
2 0.07784 0.02919 0.12087 0.10144
2 0.04986 0.02007 0.12672 0.10223
2 0.04715 0.01427 0.12990 0.10264
2 0.02881 0.01164 0.13157 0.10286
2 0.01903 0.01038 0.13243 0.10297
2 0.01318 0.00978 0.13286 0.10303
2 0.01059 0.00949 0.13308 0.10305
2 0.00926 0.00935 0.13319 0.10307
2 0.00864 0.00928 0.13324 0.10308
10*ratio 0.08638 0.09280 1.33240 1.03081
Observation:
For each fixed n, compare 𝜀 .
The second table shows the ratio of 𝜀 (10*a) and 𝜀 (a), it seems that when ‘a’ becomes larger,
ratio*10 would become nearer to 1.
Claim2: ℎ ∗ 𝜀 (a*h)/ 𝜀 (a)~1 when n and a is sufficient large, where h is a real number.
for a= (2 , 2 , 2 , 2 , 2 , 2 , 2 ), b=1, c=1
compute for n=2 , 2 .. 2
n 𝜀
(a=2)
𝜀
(a=4)
𝜀
(a=8)
𝜀
(a=16)
𝜀
(a=32)
𝜀
(a=64)
𝜀
(a=128)
2 1.1533e-02 5.8303e-03 2.9245e-03 1.4638e-03 7.3219e-04 3.6616e-04 1.8309e-04
2 3.1268e-03 1.6396e-03 8.3759e-04 4.2307e-04 2.1259e-04 1.0655e-04 5.3341e-05
2 8.0313e-04 4.2996e-04 2.2197e-04 1.1272e-04 5.6791e-05 2.8503e-05 1.4278e-05
2 2.0293e-04 1.0983e-04 5.7018e-05 2.9036e-05 1.4650e-05 7.3580e-06 3.6872e-06
2 5.0970e-05 2.7739e-05 1.4442e-05 7.3653e-06 3.7188e-06 1.8685e-06 9.3651e-07
2 1.2770e-05 6.9692e-06 3.6338e-06 1.8546e-06 9.3674e-07 4.7074e-07 2.3596e-07
2 3.1959e-06 1.7466e-06 9.1135e-07 4.6529e-07 2.3506e-07 1.1814e-07 5.9220e-08
2 7.9937e-07 4.3718e-07 2.2820e-07 1.1653e-07 5.8875e-08 2.9591e-08 1.4834e-08
2 1.9989e-07 1.0936e-07 5.7095e-08 2.9158e-08 1.4733e-08 7.4047e-09 3.7120e-09
2 4.9980e-08 2.7348e-08 1.4279e-08 7.2927e-09 3.6848e-09 1.8521e-09 9.2845e-10
n 𝜀
(a=2)/
𝜀
(a=1)
𝜀
(a=4)/
𝜀
(a=2)
𝜀
(a=8)/
𝜀
(a=4)
𝜀
(a=16)/
𝜀
(a=8)
𝜀
(a=32)/
𝜀
(a=16)
𝜀
(a=64)/
𝜀
(a=32)
𝜀
(a=128)/
𝜀
(a=64)
2 0.52207 0.50553 0.50160 0.50053 0.50020 0.50009 0.50003
2 0.56173 0.52437 0.51085 0.50510 0.50249 0.50120 0.50062
2 0.56956 0.53536 0.51626 0.50782 0.50382 0.50189 0.50093
2 0.57364 0.54122 0.51915 0.50924 0.50455 0.50225 0.50111
2 0.57582 0.54422 0.52064 0.50999 0.50491 0.50245 0.50121
2 0.57694 0.54575 0.52141 0.51037 0.50509 0.50253 0.50125
2 0.57752 0.54651 0.52179 0.51055 0.50519 0.50260 0.50127
2 0.57779 0.54691 0.52198 0.51065 0.50523 0.50261 0.50130
2 0.57793 0.54710 0.52208 0.51069 0.50528 0.50259 0.50130
2 0.57802 0.54718 0.52212 0.51073 0.50527 0.50263 0.50130
2*ratio
1.15603 1.09436 1.04424 1.02146 1.01054 1.00526 1.00259
Claim2 is satisfied.
Changing ‘b’
for a=1, b=100, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3
n 𝜀 ratio
2 6.4471e-02 -
2 1.4649e-02 2.2722e-01
2 4.2792e-03 2.9212e-01
2 2.5516e-03 5.9627e-01
2 1.2997e-03 5.0938e-01
2 5.6193e-04 4.3234e-01
2 2.1546e-04 3.8342e-01
2 6.9192e-05 3.2114e-01
2 2.0087e-05 2.9031e-01
2 5.4282e-06 2.7024e-01
3 4.3075e-03 -
3 3.1214e-03 7.2465e-01
3 1.5952e-03 5.1106e-01
3 4.1635e-04 2.6100e-01
3 7.5608e-05 1.8160e-01
3 1.0375e-05 1.3723e-01
Changing ‘b’
for a=1, b=10, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3
n 𝜀 ratio
2 3.4755e-02 -
2 8.9486e-03 2.5747e-01
2 3.8442e-03 4.2959e-01
2 1.3545e-03 3.5234e-01
2 4.1696e-04 3.0783e-01
2 1.1723e-04 2.8117e-01
2 3.1147e-05 2.6569e-01
2 8.0320e-06 2.5787e-01
2 2.0397e-06 2.5394e-01
2 5.1394e-07 2.5197e-01
3 1.2415e-02 -
3 3.2637e-03 2.6289e-01
3 5.6149e-04 1.7204e-01
3 7.5069e-05 1.3370e-01
3 8.8995e-06 1.1855e-01
3 1.0108e-06 1.1358e-01
Changing ‘b’
for a=1, b=0.1, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3
n 𝜀 ratio
2 2.5672e-02 -
2 7.1212e-03 2.7739e-01
2 1.8417e-03 2.5861e-01
2 4.6632e-04 2.5321e-01
2 1.1721e-04 2.5134e-01
2 2.9373e-05 2.5061e-01
2 7.3517e-06 2.5029e-01
2 1.8390e-06 2.5014e-01
2 4.5987e-07 2.5007e-01
2 1.1498e-07 2.5003e-01
3 1.2297e-02 -
3 1.4596e-03 1.1870e-01
3 1.6448e-04 1.1269e-01
3 1.8346e-05 1.1154e-01
3 2.0409e-06 1.1124e-01
3 2.2686e-07 1.1115e-01
Changing ‘b’
for a=1, b=0.01, c=1
compute for n=2 , 2 .. 2 ,3 , 3 . . 3
n 𝜀 ratio
2 2.5937e-02 -
2 7.2708e-03 2.8032e-01
2 1.8911e-03 2.6010e-01
2 4.8025e-04 2.5395e-01
2 1.2088e-04 2.5171e-01
2 3.0317e-05 2.5079e-01
2 7.5909e-06 2.5038e-01
2 1.8991e-06 2.5019e-01
2 4.7496e-07 2.5009e-01
2 1.1876e-07 2.5005e-01
3 1.2509e-02 -
3 1.4998e-03 1.1989e-01
3 1.6960e-04 1.1308e-01
3 1.8939e-05 1.1167e-01
3 2.1077e-06 1.1129e-01
3 2.3431e-07 1.1117e-01
for a=1, b= (0.01,0.1,1,10,100), c=1
compute for n=2 , 2 .. 2
n 𝜀
(b=0.01)
𝜀
(b=0.1)
𝜀
(b=1)
𝜀
(b=10)
𝜀
(b=100)
2 2.5937e-02 2.5672e-02 2.2091e-02 3.4755e-02 6.4471e-02
2 7.2708e-03 7.1212e-03 5.5664e-03 8.9486e-03 1.4649e-02
2 1.8911e-03 1.8417e-03 1.4101e-03 3.8442e-03 4.2792e-03
2 4.8025e-04 4.6632e-04 3.5376e-04 1.3545e-03 2.5516e-03
2 1.2088e-04 1.1721e-04 8.8517e-05 4.1696e-04 1.2997e-03
2 3.0317e-05 2.9373e-05 2.2134e-05 1.1723e-04 5.6193e-04
2 7.5909e-06 7.3517e-06 5.5338e-06 3.1147e-05 2.1546e-04
2 1.8991e-06 1.8390e-06 1.3835e-06 8.0320e-06 6.9192e-05
2 4.7496e-07 4.5987e-07 3.4587e-07 2.0397e-06 2.0087e-05
2 1.1876e-07 1.1498e-07 8.6468e-08 5.1394e-07 5.4282e-06
n 𝜀 (b=0.1)/
𝜀 (b=0.01)
𝜀 (b=1)/
𝜀 (b=0.1)
𝜀 (b=10)/
𝜀 (b=1)
𝜀 (b=100)/
𝜀 (b=10)
2 0.98978 0.86051 1.57327 1.85501
2 0.97942 0.78167 1.60761 1.63702
2 0.97388 0.76565 2.72619 1.11316
2 0.97099 0.75862 3.82887 1.88379
2 0.96964 0.75520 4.71051 3.11709
2 0.96886 0.75355 5.29638 4.79340
2 0.96849 0.75272 5.62850 6.91752
2 0.96835 0.75231 5.80557 8.61454
2 0.96823 0.75210 5.89730 9.84802
2 0.96817 0.75203 5.94370 10.56193
Claim3:
𝜀 (b*k)/ 𝜀 (b)~1 when n is sufficient large and b is sufficient small, where k is a real number.
n 𝜀
(b=2 )
𝜀
(b=2 )
𝜀
(b=2 )
𝜀
(b=2 )
𝜀
(b=2 )
𝜀
(b=2 )
𝜀
(b=1)
2 2.5921e-02 2.5876e-02 2.5785e-02 2.5595e-02 2.5190e-02 2.4278e-02 2.2091e-02
2 7.2615e-03 7.2356e-03 7.1838e-03 7.0794e-03 6.8680e-03 6.4376e-03 5.5664e-03
2 1.8880e-03 1.8794e-03 1.8622e-03 1.8280e-03 1.7600e-03 1.6268e-03 1.4101e-03
2 4.7937e-04 4.7694e-04 4.7210e-04 4.6249e-04 4.4360e-04 4.0720e-04 3.5376e-04
2 1.2065e-04 1.2001e-04 1.1873e-04 1.1620e-04 1.1124e-04 1.0185e-04 8.8517e-05
2 3.0258e-05 3.0092e-05 2.9764e-05 2.9114e-05 2.7845e-05 2.5464e-05 2.2134e-05
2 7.5757e-06 7.5339e-06 7.4507e-06 7.2862e-06 6.9653e-06 6.3663e-06 5.5338e-06
2 1.8953e-06 1.8848e-06 1.8639e-06 1.8225e-06 1.7418e-06 1.5916e-06 1.3835e-06
2 4.7400e-07 4.7136e-07 4.6611e-07 4.5574e-07 4.3551e-07 3.9790e-07 3.4587e-07
2 1.1852e-07 1.1786e-07 1.1655e-07 1.1395e-07 1.0888e-07 9.9475e-08 8.6468e-08
n 𝜀 (b=1)/
𝜀 (b=1/2)
𝜀 (b=1/2)/
𝜀 (b=1/4)
𝜀 (b=1/4)/
𝜀 (b=1/8)
𝜀 (b=1/8)/
𝜀 (b=1/16)
𝜀 (b=1/16)/
𝜀 (b=1/32)
𝜀 (b=1/32)/
𝜀 (b=1/64)
2 0.90992 0.96380 0.98418 0.99263 0.99648 0.99826
2 0.86467 0.93733 0.97014 0.98547 0.99284 0.99643
2 0.86679 0.92432 0.96280 0.98163 0.99085 0.99544
2 0.86876 0.91794 0.95916 0.97964 0.98985 0.99493
2 0.86909 0.91559 0.95731 0.97869 0.98933 0.99470
2 0.86923 0.91449 0.95641 0.97816 0.98910 0.99451
2 0.86923 0.91400 0.95596 0.97792 0.98896 0.99448
2 0.86925 0.91377 0.95572 0.97779 0.98891 0.99446
2 0.86924 0.91364 0.95561 0.97775 0.98886 0.99443
2 0.86924 0.91362 0.95551 0.97769 0.98889 0.99443
Claim3 is satisfied.
Conclusion:
1. Suppose r is a natural number, then
𝑟 ∗ 𝜀 (n*r)/ 𝜀 (n)~ 1 for n is sufficient large.
2. Assume n is sufficient large. Fixed n. Suppose h is a real number, then
ℎ ∗ 𝜀 (a*h)/ 𝜀 (a)~1
For a is sufficient large.
3. Assume n is sufficient large. Fixed n. Suppose k is a real number, then
𝜀 (b*k)/ 𝜀 (b)~1
For b is sufficient small

More Related Content

What's hot

What's hot (9)

Econ ch 9
Econ ch 9Econ ch 9
Econ ch 9
 
Shi20396 ch18
Shi20396 ch18Shi20396 ch18
Shi20396 ch18
 
Mechanics engineering statics forces analysis 3D
Mechanics engineering statics forces analysis 3DMechanics engineering statics forces analysis 3D
Mechanics engineering statics forces analysis 3D
 
Sub1567
Sub1567Sub1567
Sub1567
 
EDGE-NEIGHBOR RUPTURE DEGREE ON GRAPH OPERATIONS
EDGE-NEIGHBOR RUPTURE DEGREE ON GRAPH OPERATIONSEDGE-NEIGHBOR RUPTURE DEGREE ON GRAPH OPERATIONS
EDGE-NEIGHBOR RUPTURE DEGREE ON GRAPH OPERATIONS
 
เลขยกกำลัง
เลขยกกำลังเลขยกกำลัง
เลขยกกำลัง
 
Application of ibearugbulem’s model for optimizing granite concrete mix
Application of ibearugbulem’s model for optimizing granite concrete mixApplication of ibearugbulem’s model for optimizing granite concrete mix
Application of ibearugbulem’s model for optimizing granite concrete mix
 
Chapter 6 indices
Chapter 6 indicesChapter 6 indices
Chapter 6 indices
 
CIVE702 Midterm Report Combined
CIVE702 Midterm Report CombinedCIVE702 Midterm Report Combined
CIVE702 Midterm Report Combined
 

Similar to Solving ODEs using Galerkin's method

Kunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdf
Kunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdfKunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdf
Kunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdfMutiaraPutri41
 
Exponent & Logarithm
Exponent &  LogarithmExponent &  Logarithm
Exponent & Logarithmguest0ffcb4
 
Multi Objective Optimization of PMEDM Process Parameter by Topsis Method
Multi Objective Optimization of PMEDM Process Parameter by Topsis MethodMulti Objective Optimization of PMEDM Process Parameter by Topsis Method
Multi Objective Optimization of PMEDM Process Parameter by Topsis Methodijtsrd
 
Physics Notes: Solved numerical of Physics first year
Physics Notes: Solved numerical of Physics first yearPhysics Notes: Solved numerical of Physics first year
Physics Notes: Solved numerical of Physics first yearRam Chand
 
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์krookay2012
 
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์krookay2012
 
EJERCICIOS RESUELTOS DE LOGARITMOS
EJERCICIOS RESUELTOS DE LOGARITMOSEJERCICIOS RESUELTOS DE LOGARITMOS
EJERCICIOS RESUELTOS DE LOGARITMOSADRIANULLOAP
 
Tarea 2 hidraulica iii-cabrera arias roberto alejandro
Tarea 2 hidraulica iii-cabrera arias roberto alejandroTarea 2 hidraulica iii-cabrera arias roberto alejandro
Tarea 2 hidraulica iii-cabrera arias roberto alejandroAlejandro Cabrera
 
Ejercicios asignados a yonathan david diaz granados
Ejercicios asignados a yonathan david diaz granadosEjercicios asignados a yonathan david diaz granados
Ejercicios asignados a yonathan david diaz granadosYonathanDavidDiazGra
 
Electronic spectra problems
Electronic spectra problemsElectronic spectra problems
Electronic spectra problemsSANTHANAM V
 
EENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docx
EENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docxEENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docx
EENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docxjack60216
 
[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx
[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx
[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docxdanielfoster65629
 
3. market projections
3. market projections3. market projections
3. market projectionsRudy Flores
 
Solutions completo elementos de maquinas de shigley 8th edition
Solutions completo elementos de maquinas de shigley 8th editionSolutions completo elementos de maquinas de shigley 8th edition
Solutions completo elementos de maquinas de shigley 8th editionfercrotti
 
Mq9 nsw 5 3 answers
Mq9 nsw 5 3 answersMq9 nsw 5 3 answers
Mq9 nsw 5 3 answersShubham Saha
 

Similar to Solving ODEs using Galerkin's method (20)

Kunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdf
Kunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdfKunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdf
Kunci Jawaban kalkulus edisi 9[yunusFairVry.blogspot.com].pdf
 
Exponent & Logarithm
Exponent &  LogarithmExponent &  Logarithm
Exponent & Logarithm
 
Chapter002math
Chapter002mathChapter002math
Chapter002math
 
Multi Objective Optimization of PMEDM Process Parameter by Topsis Method
Multi Objective Optimization of PMEDM Process Parameter by Topsis MethodMulti Objective Optimization of PMEDM Process Parameter by Topsis Method
Multi Objective Optimization of PMEDM Process Parameter by Topsis Method
 
Physics Notes: Solved numerical of Physics first year
Physics Notes: Solved numerical of Physics first yearPhysics Notes: Solved numerical of Physics first year
Physics Notes: Solved numerical of Physics first year
 
Chapter001
Chapter001Chapter001
Chapter001
 
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
 
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
คณิตศาสตร์ 60 เฟรม กาญจนรัตน์
 
0. preliminares
0. preliminares0. preliminares
0. preliminares
 
EJERCICIOS RESUELTOS DE LOGARITMOS
EJERCICIOS RESUELTOS DE LOGARITMOSEJERCICIOS RESUELTOS DE LOGARITMOS
EJERCICIOS RESUELTOS DE LOGARITMOS
 
Tarea 2 hidraulica iii-cabrera arias roberto alejandro
Tarea 2 hidraulica iii-cabrera arias roberto alejandroTarea 2 hidraulica iii-cabrera arias roberto alejandro
Tarea 2 hidraulica iii-cabrera arias roberto alejandro
 
Maths book2 Text book answer
Maths book2 Text book answerMaths book2 Text book answer
Maths book2 Text book answer
 
Ejercicios asignados a yonathan david diaz granados
Ejercicios asignados a yonathan david diaz granadosEjercicios asignados a yonathan david diaz granados
Ejercicios asignados a yonathan david diaz granados
 
Electronic spectra problems
Electronic spectra problemsElectronic spectra problems
Electronic spectra problems
 
EENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docx
EENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docxEENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docx
EENG 3305Linear Circuit Analysis IIFinal ExamDecembe.docx
 
Ch02
Ch02Ch02
Ch02
 
[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx
[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx
[Q1~12]Aclothingstoreisconsideringtwomethodstoreducetheselosses1).docx
 
3. market projections
3. market projections3. market projections
3. market projections
 
Solutions completo elementos de maquinas de shigley 8th edition
Solutions completo elementos de maquinas de shigley 8th editionSolutions completo elementos de maquinas de shigley 8th edition
Solutions completo elementos de maquinas de shigley 8th edition
 
Mq9 nsw 5 3 answers
Mq9 nsw 5 3 answersMq9 nsw 5 3 answers
Mq9 nsw 5 3 answers
 

More from JamesMa54

Foodie 餐廳推薦系統
Foodie 餐廳推薦系統Foodie 餐廳推薦系統
Foodie 餐廳推薦系統JamesMa54
 
The shannon channel coding theorem
The shannon channel coding theoremThe shannon channel coding theorem
The shannon channel coding theoremJamesMa54
 
Classical communication over quantum channel
Classical communication over quantum channelClassical communication over quantum channel
Classical communication over quantum channelJamesMa54
 
Solving the energy problem of helium final report
Solving the energy problem of helium final reportSolving the energy problem of helium final report
Solving the energy problem of helium final reportJamesMa54
 
Exact synthesis of unitaries generated by Clifford and T gates
Exact synthesis of unitaries generated by Clifford and T gatesExact synthesis of unitaries generated by Clifford and T gates
Exact synthesis of unitaries generated by Clifford and T gatesJamesMa54
 
Fast and efficient exact synthesis of single qubit unitaries generated by cli...
Fast and efficient exact synthesis of single qubit unitaries generated by cli...Fast and efficient exact synthesis of single qubit unitaries generated by cli...
Fast and efficient exact synthesis of single qubit unitaries generated by cli...JamesMa54
 
Solovay Kitaev theorem
Solovay Kitaev theoremSolovay Kitaev theorem
Solovay Kitaev theoremJamesMa54
 
Visual cryptography using pixels partition
Visual cryptography using pixels partition Visual cryptography using pixels partition
Visual cryptography using pixels partition JamesMa54
 

More from JamesMa54 (8)

Foodie 餐廳推薦系統
Foodie 餐廳推薦系統Foodie 餐廳推薦系統
Foodie 餐廳推薦系統
 
The shannon channel coding theorem
The shannon channel coding theoremThe shannon channel coding theorem
The shannon channel coding theorem
 
Classical communication over quantum channel
Classical communication over quantum channelClassical communication over quantum channel
Classical communication over quantum channel
 
Solving the energy problem of helium final report
Solving the energy problem of helium final reportSolving the energy problem of helium final report
Solving the energy problem of helium final report
 
Exact synthesis of unitaries generated by Clifford and T gates
Exact synthesis of unitaries generated by Clifford and T gatesExact synthesis of unitaries generated by Clifford and T gates
Exact synthesis of unitaries generated by Clifford and T gates
 
Fast and efficient exact synthesis of single qubit unitaries generated by cli...
Fast and efficient exact synthesis of single qubit unitaries generated by cli...Fast and efficient exact synthesis of single qubit unitaries generated by cli...
Fast and efficient exact synthesis of single qubit unitaries generated by cli...
 
Solovay Kitaev theorem
Solovay Kitaev theoremSolovay Kitaev theorem
Solovay Kitaev theorem
 
Visual cryptography using pixels partition
Visual cryptography using pixels partition Visual cryptography using pixels partition
Visual cryptography using pixels partition
 

Recently uploaded

Disentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOSTDisentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOSTSérgio Sacani
 
STERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCE
STERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCESTERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCE
STERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCEPRINCE C P
 
Physiochemical properties of nanomaterials and its nanotoxicity.pptx
Physiochemical properties of nanomaterials and its nanotoxicity.pptxPhysiochemical properties of nanomaterials and its nanotoxicity.pptx
Physiochemical properties of nanomaterials and its nanotoxicity.pptxAArockiyaNisha
 
Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...
Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...
Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...anilsa9823
 
Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝
Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝
Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝soniya singh
 
BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.
BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.
BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.PraveenaKalaiselvan1
 
Nanoparticles synthesis and characterization​ ​
Nanoparticles synthesis and characterization​  ​Nanoparticles synthesis and characterization​  ​
Nanoparticles synthesis and characterization​ ​kaibalyasahoo82800
 
Unlocking the Potential: Deep dive into ocean of Ceramic Magnets.pptx
Unlocking  the Potential: Deep dive into ocean of Ceramic Magnets.pptxUnlocking  the Potential: Deep dive into ocean of Ceramic Magnets.pptx
Unlocking the Potential: Deep dive into ocean of Ceramic Magnets.pptxanandsmhk
 
Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |
Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |
Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |aasikanpl
 
zoogeography of pakistan.pptx fauna of Pakistan
zoogeography of pakistan.pptx fauna of Pakistanzoogeography of pakistan.pptx fauna of Pakistan
zoogeography of pakistan.pptx fauna of Pakistanzohaibmir069
 
Natural Polymer Based Nanomaterials
Natural Polymer Based NanomaterialsNatural Polymer Based Nanomaterials
Natural Polymer Based NanomaterialsAArockiyaNisha
 
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...Sérgio Sacani
 
Genomic DNA And Complementary DNA Libraries construction.
Genomic DNA And Complementary DNA Libraries construction.Genomic DNA And Complementary DNA Libraries construction.
Genomic DNA And Complementary DNA Libraries construction.k64182334
 
CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service 🪡
CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service  🪡CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service  🪡
CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service 🪡anilsa9823
 
Luciferase in rDNA technology (biotechnology).pptx
Luciferase in rDNA technology (biotechnology).pptxLuciferase in rDNA technology (biotechnology).pptx
Luciferase in rDNA technology (biotechnology).pptxAleenaTreesaSaji
 
Dashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tanta
Dashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tantaDashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tanta
Dashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tantaPraksha3
 
Is RISC-V ready for HPC workload? Maybe?
Is RISC-V ready for HPC workload? Maybe?Is RISC-V ready for HPC workload? Maybe?
Is RISC-V ready for HPC workload? Maybe?Patrick Diehl
 
The Black hole shadow in Modified Gravity
The Black hole shadow in Modified GravityThe Black hole shadow in Modified Gravity
The Black hole shadow in Modified GravitySubhadipsau21168
 
Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...
Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...
Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...jana861314
 

Recently uploaded (20)

Disentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOSTDisentangling the origin of chemical differences using GHOST
Disentangling the origin of chemical differences using GHOST
 
STERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCE
STERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCESTERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCE
STERILITY TESTING OF PHARMACEUTICALS ppt by DR.C.P.PRINCE
 
Physiochemical properties of nanomaterials and its nanotoxicity.pptx
Physiochemical properties of nanomaterials and its nanotoxicity.pptxPhysiochemical properties of nanomaterials and its nanotoxicity.pptx
Physiochemical properties of nanomaterials and its nanotoxicity.pptx
 
Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...
Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...
Lucknow 💋 Russian Call Girls Lucknow Finest Escorts Service 8923113531 Availa...
 
Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝
Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝
Call Girls in Munirka Delhi 💯Call Us 🔝8264348440🔝
 
BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.
BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.
BIOETHICS IN RECOMBINANT DNA TECHNOLOGY.
 
Nanoparticles synthesis and characterization​ ​
Nanoparticles synthesis and characterization​  ​Nanoparticles synthesis and characterization​  ​
Nanoparticles synthesis and characterization​ ​
 
Unlocking the Potential: Deep dive into ocean of Ceramic Magnets.pptx
Unlocking  the Potential: Deep dive into ocean of Ceramic Magnets.pptxUnlocking  the Potential: Deep dive into ocean of Ceramic Magnets.pptx
Unlocking the Potential: Deep dive into ocean of Ceramic Magnets.pptx
 
Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |
Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |
Call Us ≽ 9953322196 ≼ Call Girls In Mukherjee Nagar(Delhi) |
 
zoogeography of pakistan.pptx fauna of Pakistan
zoogeography of pakistan.pptx fauna of Pakistanzoogeography of pakistan.pptx fauna of Pakistan
zoogeography of pakistan.pptx fauna of Pakistan
 
Natural Polymer Based Nanomaterials
Natural Polymer Based NanomaterialsNatural Polymer Based Nanomaterials
Natural Polymer Based Nanomaterials
 
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
All-domain Anomaly Resolution Office U.S. Department of Defense (U) Case: “Eg...
 
Genomic DNA And Complementary DNA Libraries construction.
Genomic DNA And Complementary DNA Libraries construction.Genomic DNA And Complementary DNA Libraries construction.
Genomic DNA And Complementary DNA Libraries construction.
 
CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service 🪡
CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service  🪡CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service  🪡
CALL ON ➥8923113531 🔝Call Girls Kesar Bagh Lucknow best Night Fun service 🪡
 
Luciferase in rDNA technology (biotechnology).pptx
Luciferase in rDNA technology (biotechnology).pptxLuciferase in rDNA technology (biotechnology).pptx
Luciferase in rDNA technology (biotechnology).pptx
 
Dashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tanta
Dashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tantaDashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tanta
Dashanga agada a formulation of Agada tantra dealt in 3 Rd year bams agada tanta
 
Is RISC-V ready for HPC workload? Maybe?
Is RISC-V ready for HPC workload? Maybe?Is RISC-V ready for HPC workload? Maybe?
Is RISC-V ready for HPC workload? Maybe?
 
9953056974 Young Call Girls In Mahavir enclave Indian Quality Escort service
9953056974 Young Call Girls In Mahavir enclave Indian Quality Escort service9953056974 Young Call Girls In Mahavir enclave Indian Quality Escort service
9953056974 Young Call Girls In Mahavir enclave Indian Quality Escort service
 
The Black hole shadow in Modified Gravity
The Black hole shadow in Modified GravityThe Black hole shadow in Modified Gravity
The Black hole shadow in Modified Gravity
 
Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...
Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...
Traditional Agroforestry System in India- Shifting Cultivation, Taungya, Home...
 

Solving ODEs using Galerkin's method

  • 2. INTRODUCTION: Consider the ODE: 𝑎 𝑑 𝑦 𝑑𝑥 + 𝑏 𝑑𝑦 𝑑𝑥 + 𝑐𝑦 = 𝑓(𝑥) With boundary condition: y(L0) = B0 y(L1) = B1 Since we are going to use the Galerkin’s method, splitting the whole domain into n elements evenly before the computation is necessary. In this report, I am going to find out the relations of (a, 𝜀 ), (b, 𝜀 ), (n, 𝜀 ), where 𝜀 is the maximum difference of the approximation 𝑦(𝑥) and the exact solution 𝑦(𝑥) along all 𝑥 ∈ [𝐿0, 𝐿1]. Hence, define 𝜀 as: 𝜀 ≡ 𝑚𝑎𝑥 ∈[ , ]{|𝑦(𝑥) − 𝑦(𝑥)|} In order to make more efforts in the variables a, b, n, which we are interested about, fix c=1 and f(x)=x, L0=0, L1=1, B0=B1=0. So the ODE’s problem becomes: 𝑎 𝑑 𝑦 𝑑𝑥 + 𝑏 𝑑𝑦 𝑑𝑥 + 𝑦 = 𝑥 y(0) = 0 y(1) = 0 A demonstration of Galerkin’s method.
  • 3. the following contains data of: 1. a= (0.01,0.1,1,10,100), b=1, c=1, and changing n. 2. a=(1,2 , 2 ,2 , 2 , 2 ), b=1, c=1, and changing n. 3. a=1, b= (0.01,0.1,1,10,100), c=1, and changing n. 4. a=1, b= (1,2 , 2 ,2 , 2 , 2 ), c=1, and changing n. DATAS: for a=1, b=1, c=1 compute for n=2 , 2 .. 2 , 3 , 3 . . 3 ,4 , 4 . . 4 n 𝜀 ratio 2 2.2091e-02 - 2 5.5664e-03 2.5197e-01 2 1.4101e-03 2.5332e-01 2 3.5376e-04 2.5087e-01 2 8.8517e-05 2.5022e-01 2 2.2134e-05 2.5005e-01 2 5.5338e-06 2.5001e-01 2 1.3835e-06 2.5000e-01 2 3.4587e-07 2.5000e-01 2 8.6468e-08 2.5000e-01 3 9.9214e-03 - 3 1.1170e-03 1.1259e-01 3 1.2435e-04 1.1132e-01 3 1.3819e-05 1.1113e-01 3 1.5355e-06 1.1111e-01 3 1.7061e-07 1.1111e-01 4 5.5664e-03 - 4 3.5376e-04 6.3553e-02 4 2.2134e-05 6.2567e-02 4 1.3835e-06 6.2506e-02 4 8.6468e-08 6.2499e-02 Observation: 2.5000e-01=0.25= 1.1111e-01=0.1111= 6.2499e-02=0.062499≅ 0.0625= Claim1: 𝜀 (n*r)/ 𝜀 (n)~ for n is sufficient large.
  • 4. Changing ‘a’ for a=100, b=1, c=1 compute for n=2 , 2 .. 2 , 3 , 3 . . 3 ,4 , 4 . . 4 n 𝜀 ratio 2 2.3435e-04 - 2 6.8254e-05 2.9124e-01 2 1.8267e-05 2.6763e-01 2 4.7167e-06 2.5822e-01 2 1.1979e-06 2.5397e-01 2 3.0182e-07 2.5195e-01 2 7.5747e-08 2.5097e-01 2 1.8973e-08 2.5048e-01 2 4.7479e-09 2.5024e-01 2 1.1876e-09 2.5012e-01 3 1.1562e-04 - 3 1.4538e-05 1.2574e-01 3 1.6778e-06 1.1540e-01 3 1.8873e-07 1.1249e-01 3 2.1056e-08 1.1156e-01 3 2.3427e-09 1.1126e-01 4 6.8254e-05 - 4 4.7167e-06 6.9105e-02 4 3.0182e-07 6.3990e-02 4 1.8973e-08 6.2862e-02 4 1.1876e-09 6.2594e-02 Claim1 is satisfied.
  • 5. Changing ‘a’ for a=10, b=1, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 , 4 , 4 . . 4 n 𝜀 ratio 2 2.3407e-03 - 2 6.7283e-04 2.8745e-01 2 1.7869e-04 2.6558e-01 2 4.5952e-05 2.5716e-01 2 1.1646e-05 2.5344e-01 2 2.9311e-06 2.5168e-01 2 7.3522e-07 2.5083e-01 2 1.8411e-07 2.5041e-01 2 4.6066e-08 2.5021e-01 2 1.1521e-08 2.5010e-01 3 1.1452e-03 - 3 1.4209e-04 1.2408e-01 3 1.6318e-05 1.1484e-01 3 1.8324e-06 1.1230e-01 3 2.0432e-07 1.1150e-01 3 2.2728e-08 1.1124e-01 4 6.7283e-04 - 4 4.5952e-05 6.8296e-02 4 2.9311e-06 6.3786e-02 4 1.8411e-07 6.2813e-02 4 1.1521e-08 6.2577e-02 Claim1 is satisfied.
  • 6. Changing ‘a’ for a=0.1, b=1, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 ,4 , 4 . . 4 n 𝜀 ratio 2 3.2616e+00 - 2 1.9072e-01 5.8476e-02 2 7.0270e-02 3.6844e-01 2 2.4792e-02 3.5282e-01 2 7.6057e-03 3.0678e-01 2 2.1329e-03 2.8043e-01 2 5.6570e-04 2.6523e-01 2 1.4574e-04 2.5762e-01 2 3.6990e-05 2.5381e-01 2 9.3181e-06 2.5191e-01 3 2.5658e-01 - 3 5.9726e-02 2.3278e-01 3 1.0249e-02 1.7161e-01 3 1.3648e-03 1.3316e-01 3 1.6149e-04 1.1832e-01 3 1.8329e-05 1.1350e-01 4 1.9072e-01 - 4 2.4792e-02 1.2999e-01 4 2.1329e-03 8.6032e-02 4 1.4574e-04 6.8330e-02 4 9.3181e-06 6.3936e-02 Claim1 is satisfied.
  • 7. Changing ‘a’ for a=0.01, b=1, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 ,4 , 4 . . 4 n 𝜀 ratio 2 1.3523e+00 - 2 2.4501e+00 1.8119e+00 2 1.4093e+00 5.7521e-01 2 5.2583e-01 3.7311e-01 2 2.6395e-01 5.0197e-01 2 1.1207e-01 4.2456e-01 2 4.2906e-02 3.8287e-01 2 1.3765e-02 3.2081e-01 2 3.9932e-03 2.9010e-01 2 1.0787e-03 2.7012e-01 2 2.8054e-04 2.6007e-01 3 8.8810e-01 - 3 5.8544e-01 6.5920e-01 3 3.2494e-01 5.5503e-01 3 8.2991e-02 2.5541e-01 3 1.5043e-02 1.8126e-01 3 2.0621e-03 1.3708e-01 4 2.4501e+00 - 4 5.2583e-01 2.1461e-01 4 1.1207e-01 2.1313e-01 4 1.3765e-02 1.2283e-01 4 1.0787e-03 7.8365e-02 Claim1 is satisfied. Note that in this case the ratios marked in yellow are not very close to the numbers in the claim compare to previous cases. It is because of the shrinking of ‘a’ makes the stiffness matrix less symmetric. To continue the process, these ratios would converge to .
  • 8. for a= (0.01,0.1,1,10,100), b=1, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 n 𝜀 (a=0.01) 𝜀 (a=0.1) 𝜀 (a=1) 𝜀 (a=10) 𝜀 (a=100) 2 1.3523e+00 3.2616e+00 2.2091e-02 2.3407e-03 2.3435e-04 2 2.4501e+00 1.9072e-01 5.5664e-03 6.7283e-04 6.8254e-05 2 1.4093e+00 7.0270e-02 1.4101e-03 1.7869e-04 1.8267e-05 2 5.2583e-01 2.4792e-02 3.5376e-04 4.5952e-05 4.7167e-06 2 2.6395e-01 7.6057e-03 8.8517e-05 1.1646e-05 1.1979e-06 2 1.1207e-01 2.1329e-03 2.2134e-05 2.9311e-06 3.0182e-07 2 4.2906e-02 5.6570e-04 5.5338e-06 7.3522e-07 7.5747e-08 2 1.3765e-02 1.4574e-04 1.3835e-06 1.8411e-07 1.8973e-08 2 3.9932e-03 3.6990e-05 3.4587e-07 4.6066e-08 4.7479e-09 2 1.0787e-03 9.3181e-06 8.6468e-08 1.1521e-08 1.1876e-09 n 𝜀 (a=0.1)/ 𝜀 (a=0.01) 𝜀 (a=1)/ 𝜀 (a=0.1) 𝜀 (a=10)/ 𝜀 (a=1) 𝜀 (a=100)/ 𝜀 (a=10) 2 2.41189 0.00677 0.10596 0.10012 2 0.07784 0.02919 0.12087 0.10144 2 0.04986 0.02007 0.12672 0.10223 2 0.04715 0.01427 0.12990 0.10264 2 0.02881 0.01164 0.13157 0.10286 2 0.01903 0.01038 0.13243 0.10297 2 0.01318 0.00978 0.13286 0.10303 2 0.01059 0.00949 0.13308 0.10305 2 0.00926 0.00935 0.13319 0.10307 2 0.00864 0.00928 0.13324 0.10308 10*ratio 0.08638 0.09280 1.33240 1.03081 Observation: For each fixed n, compare 𝜀 . The second table shows the ratio of 𝜀 (10*a) and 𝜀 (a), it seems that when ‘a’ becomes larger, ratio*10 would become nearer to 1. Claim2: ℎ ∗ 𝜀 (a*h)/ 𝜀 (a)~1 when n and a is sufficient large, where h is a real number.
  • 9. for a= (2 , 2 , 2 , 2 , 2 , 2 , 2 ), b=1, c=1 compute for n=2 , 2 .. 2 n 𝜀 (a=2) 𝜀 (a=4) 𝜀 (a=8) 𝜀 (a=16) 𝜀 (a=32) 𝜀 (a=64) 𝜀 (a=128) 2 1.1533e-02 5.8303e-03 2.9245e-03 1.4638e-03 7.3219e-04 3.6616e-04 1.8309e-04 2 3.1268e-03 1.6396e-03 8.3759e-04 4.2307e-04 2.1259e-04 1.0655e-04 5.3341e-05 2 8.0313e-04 4.2996e-04 2.2197e-04 1.1272e-04 5.6791e-05 2.8503e-05 1.4278e-05 2 2.0293e-04 1.0983e-04 5.7018e-05 2.9036e-05 1.4650e-05 7.3580e-06 3.6872e-06 2 5.0970e-05 2.7739e-05 1.4442e-05 7.3653e-06 3.7188e-06 1.8685e-06 9.3651e-07 2 1.2770e-05 6.9692e-06 3.6338e-06 1.8546e-06 9.3674e-07 4.7074e-07 2.3596e-07 2 3.1959e-06 1.7466e-06 9.1135e-07 4.6529e-07 2.3506e-07 1.1814e-07 5.9220e-08 2 7.9937e-07 4.3718e-07 2.2820e-07 1.1653e-07 5.8875e-08 2.9591e-08 1.4834e-08 2 1.9989e-07 1.0936e-07 5.7095e-08 2.9158e-08 1.4733e-08 7.4047e-09 3.7120e-09 2 4.9980e-08 2.7348e-08 1.4279e-08 7.2927e-09 3.6848e-09 1.8521e-09 9.2845e-10 n 𝜀 (a=2)/ 𝜀 (a=1) 𝜀 (a=4)/ 𝜀 (a=2) 𝜀 (a=8)/ 𝜀 (a=4) 𝜀 (a=16)/ 𝜀 (a=8) 𝜀 (a=32)/ 𝜀 (a=16) 𝜀 (a=64)/ 𝜀 (a=32) 𝜀 (a=128)/ 𝜀 (a=64) 2 0.52207 0.50553 0.50160 0.50053 0.50020 0.50009 0.50003 2 0.56173 0.52437 0.51085 0.50510 0.50249 0.50120 0.50062 2 0.56956 0.53536 0.51626 0.50782 0.50382 0.50189 0.50093 2 0.57364 0.54122 0.51915 0.50924 0.50455 0.50225 0.50111 2 0.57582 0.54422 0.52064 0.50999 0.50491 0.50245 0.50121 2 0.57694 0.54575 0.52141 0.51037 0.50509 0.50253 0.50125 2 0.57752 0.54651 0.52179 0.51055 0.50519 0.50260 0.50127 2 0.57779 0.54691 0.52198 0.51065 0.50523 0.50261 0.50130 2 0.57793 0.54710 0.52208 0.51069 0.50528 0.50259 0.50130 2 0.57802 0.54718 0.52212 0.51073 0.50527 0.50263 0.50130 2*ratio 1.15603 1.09436 1.04424 1.02146 1.01054 1.00526 1.00259 Claim2 is satisfied.
  • 10. Changing ‘b’ for a=1, b=100, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 n 𝜀 ratio 2 6.4471e-02 - 2 1.4649e-02 2.2722e-01 2 4.2792e-03 2.9212e-01 2 2.5516e-03 5.9627e-01 2 1.2997e-03 5.0938e-01 2 5.6193e-04 4.3234e-01 2 2.1546e-04 3.8342e-01 2 6.9192e-05 3.2114e-01 2 2.0087e-05 2.9031e-01 2 5.4282e-06 2.7024e-01 3 4.3075e-03 - 3 3.1214e-03 7.2465e-01 3 1.5952e-03 5.1106e-01 3 4.1635e-04 2.6100e-01 3 7.5608e-05 1.8160e-01 3 1.0375e-05 1.3723e-01
  • 11. Changing ‘b’ for a=1, b=10, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 n 𝜀 ratio 2 3.4755e-02 - 2 8.9486e-03 2.5747e-01 2 3.8442e-03 4.2959e-01 2 1.3545e-03 3.5234e-01 2 4.1696e-04 3.0783e-01 2 1.1723e-04 2.8117e-01 2 3.1147e-05 2.6569e-01 2 8.0320e-06 2.5787e-01 2 2.0397e-06 2.5394e-01 2 5.1394e-07 2.5197e-01 3 1.2415e-02 - 3 3.2637e-03 2.6289e-01 3 5.6149e-04 1.7204e-01 3 7.5069e-05 1.3370e-01 3 8.8995e-06 1.1855e-01 3 1.0108e-06 1.1358e-01
  • 12. Changing ‘b’ for a=1, b=0.1, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 n 𝜀 ratio 2 2.5672e-02 - 2 7.1212e-03 2.7739e-01 2 1.8417e-03 2.5861e-01 2 4.6632e-04 2.5321e-01 2 1.1721e-04 2.5134e-01 2 2.9373e-05 2.5061e-01 2 7.3517e-06 2.5029e-01 2 1.8390e-06 2.5014e-01 2 4.5987e-07 2.5007e-01 2 1.1498e-07 2.5003e-01 3 1.2297e-02 - 3 1.4596e-03 1.1870e-01 3 1.6448e-04 1.1269e-01 3 1.8346e-05 1.1154e-01 3 2.0409e-06 1.1124e-01 3 2.2686e-07 1.1115e-01
  • 13. Changing ‘b’ for a=1, b=0.01, c=1 compute for n=2 , 2 .. 2 ,3 , 3 . . 3 n 𝜀 ratio 2 2.5937e-02 - 2 7.2708e-03 2.8032e-01 2 1.8911e-03 2.6010e-01 2 4.8025e-04 2.5395e-01 2 1.2088e-04 2.5171e-01 2 3.0317e-05 2.5079e-01 2 7.5909e-06 2.5038e-01 2 1.8991e-06 2.5019e-01 2 4.7496e-07 2.5009e-01 2 1.1876e-07 2.5005e-01 3 1.2509e-02 - 3 1.4998e-03 1.1989e-01 3 1.6960e-04 1.1308e-01 3 1.8939e-05 1.1167e-01 3 2.1077e-06 1.1129e-01 3 2.3431e-07 1.1117e-01
  • 14. for a=1, b= (0.01,0.1,1,10,100), c=1 compute for n=2 , 2 .. 2 n 𝜀 (b=0.01) 𝜀 (b=0.1) 𝜀 (b=1) 𝜀 (b=10) 𝜀 (b=100) 2 2.5937e-02 2.5672e-02 2.2091e-02 3.4755e-02 6.4471e-02 2 7.2708e-03 7.1212e-03 5.5664e-03 8.9486e-03 1.4649e-02 2 1.8911e-03 1.8417e-03 1.4101e-03 3.8442e-03 4.2792e-03 2 4.8025e-04 4.6632e-04 3.5376e-04 1.3545e-03 2.5516e-03 2 1.2088e-04 1.1721e-04 8.8517e-05 4.1696e-04 1.2997e-03 2 3.0317e-05 2.9373e-05 2.2134e-05 1.1723e-04 5.6193e-04 2 7.5909e-06 7.3517e-06 5.5338e-06 3.1147e-05 2.1546e-04 2 1.8991e-06 1.8390e-06 1.3835e-06 8.0320e-06 6.9192e-05 2 4.7496e-07 4.5987e-07 3.4587e-07 2.0397e-06 2.0087e-05 2 1.1876e-07 1.1498e-07 8.6468e-08 5.1394e-07 5.4282e-06 n 𝜀 (b=0.1)/ 𝜀 (b=0.01) 𝜀 (b=1)/ 𝜀 (b=0.1) 𝜀 (b=10)/ 𝜀 (b=1) 𝜀 (b=100)/ 𝜀 (b=10) 2 0.98978 0.86051 1.57327 1.85501 2 0.97942 0.78167 1.60761 1.63702 2 0.97388 0.76565 2.72619 1.11316 2 0.97099 0.75862 3.82887 1.88379 2 0.96964 0.75520 4.71051 3.11709 2 0.96886 0.75355 5.29638 4.79340 2 0.96849 0.75272 5.62850 6.91752 2 0.96835 0.75231 5.80557 8.61454 2 0.96823 0.75210 5.89730 9.84802 2 0.96817 0.75203 5.94370 10.56193 Claim3: 𝜀 (b*k)/ 𝜀 (b)~1 when n is sufficient large and b is sufficient small, where k is a real number.
  • 15. n 𝜀 (b=2 ) 𝜀 (b=2 ) 𝜀 (b=2 ) 𝜀 (b=2 ) 𝜀 (b=2 ) 𝜀 (b=2 ) 𝜀 (b=1) 2 2.5921e-02 2.5876e-02 2.5785e-02 2.5595e-02 2.5190e-02 2.4278e-02 2.2091e-02 2 7.2615e-03 7.2356e-03 7.1838e-03 7.0794e-03 6.8680e-03 6.4376e-03 5.5664e-03 2 1.8880e-03 1.8794e-03 1.8622e-03 1.8280e-03 1.7600e-03 1.6268e-03 1.4101e-03 2 4.7937e-04 4.7694e-04 4.7210e-04 4.6249e-04 4.4360e-04 4.0720e-04 3.5376e-04 2 1.2065e-04 1.2001e-04 1.1873e-04 1.1620e-04 1.1124e-04 1.0185e-04 8.8517e-05 2 3.0258e-05 3.0092e-05 2.9764e-05 2.9114e-05 2.7845e-05 2.5464e-05 2.2134e-05 2 7.5757e-06 7.5339e-06 7.4507e-06 7.2862e-06 6.9653e-06 6.3663e-06 5.5338e-06 2 1.8953e-06 1.8848e-06 1.8639e-06 1.8225e-06 1.7418e-06 1.5916e-06 1.3835e-06 2 4.7400e-07 4.7136e-07 4.6611e-07 4.5574e-07 4.3551e-07 3.9790e-07 3.4587e-07 2 1.1852e-07 1.1786e-07 1.1655e-07 1.1395e-07 1.0888e-07 9.9475e-08 8.6468e-08 n 𝜀 (b=1)/ 𝜀 (b=1/2) 𝜀 (b=1/2)/ 𝜀 (b=1/4) 𝜀 (b=1/4)/ 𝜀 (b=1/8) 𝜀 (b=1/8)/ 𝜀 (b=1/16) 𝜀 (b=1/16)/ 𝜀 (b=1/32) 𝜀 (b=1/32)/ 𝜀 (b=1/64) 2 0.90992 0.96380 0.98418 0.99263 0.99648 0.99826 2 0.86467 0.93733 0.97014 0.98547 0.99284 0.99643 2 0.86679 0.92432 0.96280 0.98163 0.99085 0.99544 2 0.86876 0.91794 0.95916 0.97964 0.98985 0.99493 2 0.86909 0.91559 0.95731 0.97869 0.98933 0.99470 2 0.86923 0.91449 0.95641 0.97816 0.98910 0.99451 2 0.86923 0.91400 0.95596 0.97792 0.98896 0.99448 2 0.86925 0.91377 0.95572 0.97779 0.98891 0.99446 2 0.86924 0.91364 0.95561 0.97775 0.98886 0.99443 2 0.86924 0.91362 0.95551 0.97769 0.98889 0.99443 Claim3 is satisfied.
  • 16. Conclusion: 1. Suppose r is a natural number, then 𝑟 ∗ 𝜀 (n*r)/ 𝜀 (n)~ 1 for n is sufficient large. 2. Assume n is sufficient large. Fixed n. Suppose h is a real number, then ℎ ∗ 𝜀 (a*h)/ 𝜀 (a)~1 For a is sufficient large. 3. Assume n is sufficient large. Fixed n. Suppose k is a real number, then 𝜀 (b*k)/ 𝜀 (b)~1 For b is sufficient small