Abstract The Equation Fifth Test We test the Equation Gerges Equation For The Moon Orbital Motion θ Per Solar Day = θ Of The Previous Day + 0.985 degrees - The angle θ is the smallest one in a Pythagoras triangle - 0.985 degrees = (360 degrees /365.25 days) The Equation Concept - The Equation Concept Is Discussed In The First Paper Of This Series (References) - This Paper Provides The 5th Test For The Equation - The Test Uses The Moon Distance Data During The Period (From 6th June 2020 To 30th June 2020) - This test is different from the previous tests because we'll test the moon 2 motions, The ascending and descending together (Test For 25 Sequenced Days) - The 5th Test Results Will Be Discussed And Analyzed Gerges Francis Tawdrous +201022532292

1. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
1
The Moon Motion Basic Equation (VI) (Test No.5)
The Author Authorized To Be Used By
Mr. Gerges Francis Tawdrous
A Student–Physics Department- Physics
& Mathematics Faculty –
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Dr. Budochkina, Svetlana Aleksandrovna
Associate Professor (Mathematical Analysis
and Theory of Functions Department)
Peoples' Friendship University of Russia
(RUDN University) – Moscow – Russia
Phone +201022532292
E-Mail: mrwaheid@gmail.com
Curriculum Vitae http://vixra.org/abs/1902.0044
Phone +7 (495) 952-35-83
E-Mail: budochkina-sa@rudn.ru, sbudotchkina@yandex.ru
Website
http://web-local.rudn.ru/web-local/prep/rj/index.php?id=2944&p=19024
The Assumption Of S. Virgin Mary -Written in Cairo – Egypt – 31st
October 2020
Abstract
The Equation Fifth Test
We test the Equation
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
The Equation Concept
- The Equation Concept Is Discussed In The First Paper Of This Series (References)
- This Paper Provides The 5th
Test For The Equation
- The Test Uses The Moon Distance Data During The Period (From 6th
June 2020
To 30th
June 2020)
- This test is different from the previous tests because we'll test the moon 2 motions,
The ascending and descending together (Test For 25 Sequenced Days)
- The 5th
Test Results Will Be Discussed And Analyzed
References
The Moon Motion Basic Equation
https://www.academia.edu/s/46a3441e4a
or
https://www.academia.edu/44396469/The_Moon_Motion_Basic_Equation
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation

2. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
2
1- The Equation 5th
Test
1-1 The Equation 5th
Test (6-30 June 2020)
1-2 The Test Results Discussion And Analysis
1-1 The Equation 5th
Test (6-30 June 2020)
We use the moon distance real data during 6th
June 2020 to 30th
June 2020
The moon distance data as following
I-Data
Date The Earth Moon Distance
6 – 6-2020 369418
7 – 6-2020 373729
8 – 6-2020 378917
9 – 6-2020 384534
10-6-2020 390096
11-6-2020 395156
12-6-2020 399345
13-6-2020 402395
14-6-2020 404153
15-6-2020 404574
16-6-2020 403718
17-6-2020 401733
18-6-2020 398840
19-6-2020 395303
20-6-2020 391409
21-6-2020 387432
22-6-2020 383607
23-6-2020 380110
24-6-2020 377044
25-6-2020 374451
26-6-2020 372338
27-6-2020 370703
28-6-2020 369571
29-6-2020 369005
30-6-2020 369106
Data Reference is
https://www.timeanddate.com/moon/egypt/cairo?month=1
Note Please
- We use the moon ascending motion from perigee to apogee (far from Earth)
because of that we minus the angle (0.985 degrees) from the previous day (θ)
- Let's begin our test

3. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
3
II- The Equation Test
Gerges Equation For The Moon Orbital Motion
θ Per Solar Day = θ Of The Previous Day + 0.985 degrees
- The angle θ is the smallest one in a Pythagoras triangle
- 0.985 degrees = (360 degrees /365.25 days)
Because we test the both motions, we have to distinguish between them
1st
The Ascending Motion
(1) 6 –June -2020
Jun 6 369418 km Jun 7 373729km (The Next Day)
On 6/6/2020 the moon Earth distance was 369418 km
So we need to know where the moon will be on the next day (7/6/2020)?
Let's try to do that….
- The radius =369418 km so C (orbital circumference) = 369418 x 2π=2.321 mkm
- The moon moves it during 29.53 days ( L0= 2.321 mkm/29.53) = 78602.1 km
- L0= 78602.1 km but L0 = 88000 km Cos θ0
- θ0= 26.721 degrees
- θ1= θ0- 0.9856262 = 26.721 - 0.9856262 = 25.7354 degrees
- L1 = 88000 km (Cos 25.7354 degrees) = 79271.1 km
- During 29.53 days = L1 x29.53 = 79271.1 km x 29.53 = 2.34 mkm
- 2.34 mkm = 2π x 372562 km
- i.e. The moon on next day (7/6/2020) should be on 372562 km
The registered value on 7/6/2020 (373729 km)
The difference = 373729 km – 372562 km = 1167 km

4. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
4
(2) 7 –June -2020
Jun 7 373729 km Jun 8 378917km (The Next Day)
On 7/6/2020 the moon Earth distance was 373729 km
So we need to know where the moon will be on the next day (8/6/2020)?
Let's try to do that….
- The radius =373729 km so C (orbital circumference) = 373729 x 2π=2.348 mkm
- The moon moves it during 29.53 days ( L0= 2.348 mkm/29.53) = 79519.4 km
- L0= 79519.4 km but L0 = 88000 km Cos θ0
- θ0= 25.36 degrees
- θ1= θ0- 0.9856262 = 25.36 - 0.9856262 = 24.375 degrees
- L1 = 88000 km (Cos 24.375 degrees) = 80156 km
- During 29.53 days = L1 x29.53 = 80156 km x 29.53 = 2.367 mkm
- 2.367 mkm = 2π x 376720.8 km
- i.e. The moon on next day (8/6/2020) should be on 376720.8 km
The registered value on 8/6/2020 (378917 km)
The difference = 378917 km – 376720.8 km = 2197 km

5. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
5
(3) 8 – June -2020
Jun 8 378917 km Jun 9 384534km (The Next Day)
On 8/6/2020 the moon Earth distance was 378917 km
So we need to know where the moon will be on the next day (9/6/2020)?
Let's try to do that….
- The radius =378917 km so C (orbital circumference) = 378917 x 2π=2.3808 mkm
- The moon moves it during 29.53 days ( L0= 2.3808 mkm/29.53) = 80623.3 km
- L0= 80623.3 km but L0 = 88000 km Cos θ0
- θ0= 23.627 degrees
- θ1= θ0- 0.9856262 = 23. 627 - 0.9856262 = 22.6414 degrees
- L1 = 88000 km (Cos 22.6414 degrees) = 81218 km
- During 29.53 days = L1 x29.53 = 81218 km x 29.53 = 2.3983 mkm
- 2.3983 mkm = 2π x 381712.2 km
- i.e. The moon on next day (9/6/2020) should be on 381712.2 km
The registered value on 9/6/2020 (384534 km)
The difference = 384534 km – 381712.2 km = 2822 km

6. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
6
(4) 9 – June -2020
Jun 9 384534 km Jun 10 390096km (The Next Day)
On 9/6/2020 the moon Earth distance was 384534 km
So we need to know where the moon will be on the next day (10/6/2020)?
Let's try to do that….
- The radius =384534 km so C (orbital circumference) = 384534 x 2π=2.416 mkm
- The moon moves it during 29.53 days ( L0= 2.416 mkm/29.53) = 81818.4 km
- L0= 81818.4 km but L0 = 88000 km Cos θ0
- θ0= 21.60 degrees
- θ1= θ0- 0.9856262 = 21. 60 - 0.9856262 = 20.6177 degrees
- L1 = 88000 km (Cos 20.6177 degrees) = 82363.6 km
- During 29.53 days = L1 x29.53 = 82363.6 km x 29.53 = 2.4321 mkm
- 2.4321 mkm = 2π x 387096.5 km
- i.e. The moon on next day (10/6/2020) should be on 387096.5 km
The registered value on 10/6/2020 (390096 km)
The difference = 390096 km – 387096.5 km = 3000 km

7. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
7
(5) 10 – June -2020
Jun 10 390096 km Jun 11 395156km (The Next Day)
On 10/6/2020 the moon Earth distance was 390096 km
So we need to know where the moon will be on the next day (11/6/2020)?
Let's try to do that….
- The radius =390096 km so C (orbital circumference) = 390096 x 2π=2.451 mkm
- The moon moves it during 29.53 days ( L0= 2.451 mkm/29.53) = 83002 km
- L0= 83002 km but L0 = 88000 km Cos θ0
- θ0= 19.4033 degrees
- θ1= θ0- 0.9856262 = 19.4033 - 0.9856262 = 18.4177 degrees
- L1 = 88000 km (Cos 18.4177 degrees) = 83492.5 km
- During 29.53 days = L1 x29.53 = 83492.5 km x 29.53 = 2.4655 mkm
- 2.4655 mkm = 2π x 392401.7 km
- i.e. The moon on next day (11/6/2020) should be on 392401.7 km
The registered value on 11/6/2020 (395156 km)
The difference = 395156 km – 392401.7 km = 2755 km

8. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
8
(5) 11 – June -2020
Jun 11 395156 km Jun 12 399345 km (The Next Day)
On 11/6/2020 the moon Earth distance was 395156 km
So we need to know where the moon will be on the next day (12/6/2020)?
Let's try to do that….
- The radius =395156 km so C (orbital circumference) = 395156 x 2π=2.482 mkm
- The moon moves it during 29.53 days ( L0= 2.482 mkm/29.53) = 84078.5 km
- L0= 84078.5 km but L0 = 88000 km Cos θ0
- θ0= 17.169 degrees
- θ1= θ0- 0.9856262 = 17.169 - 0.9856262 = 16.1834 degrees
- L1 = 88000 km (Cos 16.1834 degrees) = 84512.9 km
- During 29.53 days = L1 x29.53 = 84512.9 km x 29.53 = 2.4956 mkm
- 2.4956 mkm = 2π x 397197.6 km
- i.e. The moon on next day (12/6/2020) should be on 397197.6 km
The registered value on 12/6/2020 (399345 km)
The difference = 399345 km – 397197.6 km = 2148 km

9. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
9
(6) 12 – June -2020
Jun 12 399345 km Jun 13 402395 km (The Next Day)
On 12/6/2020 the moon Earth distance was 399345 km
So we need to know where the moon will be on the next day (13/6/2020)?
Let's try to do that….
- The radius =399345 km so C (orbital circumference) = 399345 x 2π=2.509 mkm
- The moon moves it during 29.53 days ( L0= 2.509 mkm/29.53) = 84970 km
- L0= 84970 km but L0 = 88000 km Cos θ0
- θ0= 15.0794 degrees
- θ1= θ0- 0.9856262 = 15.0794 - 0.9856262 = 14.0938 degrees
- L1 = 88000 km (Cos 14.0938 degrees) = 85351 km
- During 29.53 days = L1 x29.53 = 85351 km x 29.53 = 2.5204 mkm
- 2.5204 mkm = 2π x 401136.7 km
- i.e. The moon on next day (13/6/2020) should be on 401136.7 km
The registered value on 13/6/2020 (402395 km)
The difference = 402395 km – 401136.7 km = 1259 km

10. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
10
(7) 13 – June -2020
Jun 13 402395 km Jun 14 404153 km (The Next Day)
On 13/6/2020 the moon Earth distance was 402395 km
So we need to know where the moon will be on the next day (14/6/2020)?
Let's try to do that….
- The radius =402395 km so C (orbital circumference) = 402395 x 2π=2.528 mkm
- The moon moves it during 29.53 days ( L0= 2.528 mkm/29.53) = 85618.8 km
- L0= 85618.8 km but L0 = 88000 km Cos θ0
- θ0= 13.3592 degrees
- θ1= θ0- 0.9856262 = 13.3592 - 0.9856262 = 12.373 degrees
- L1 = 88000 km (Cos 12.373 degrees) = 85955.8 km
- During 29.53 days = L1 x29.53 = 85955.8 km x 29.53 = 2.5382 mkm
- 2.5382 mkm = 2π x 403979.2 km
- i.e. The moon on next day (14/6/2020) should be on 403979.2 km
The registered value on 14/6/2020 (404153 km)
The difference = 404153 km – 403979.2 km = 174 km
Note Please
- This day is the last day in the moon ascending motion from Perigee to apogee, on
the next day the moon will stay on apogee for one more day (404574 km) on (15th
- 6-2020), and then on (16th
-6-2020) will start its descending motion (403718
km). So we will start the descending motion analysis in next page, and because it's
a descending motion we will add the value 0.985 degrees to the angle (θ)

11. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
11
1st
The Descending Motion
(8) 15 – June -2020
Jun 15 404574 km Jun 16 403718 km (The Next Day)
On 15/6/2020 the moon Earth distance was 404574 km
So we need to know where the moon will be on the next day (16/6/2020)?
Let's try to do that….
- The radius =404574 km so C (orbital circumference) = 404574 x 2π=2.542 mkm
- The moon moves it during 29.53 days ( L0= 2.542 mkm/29.53) = 86082.4 km
- L0= 86082.4 km but L0 = 88000 km Cos θ0
- θ0= 11.983 degrees
- θ1= θ0+ 0.9856262 = 11.983 +0.9856262 = 12.968669 degrees
- L1 = 88000 km (Cos 12.968669 degrees) = 85755.3 km
- During 29.53 days = L1 x29.53 = 85755.3 km x 29.53 = 2.532 mkm
- 2.532 mkm = 2π x 403037 km
- i.e. The moon on next day (16/6/2020) should be on 403037 km
The registered value on 16/6/2020 (403718 km)
The difference = 403718 km – 403037 km = 681 km

12. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
12
(9) 16 – June -2020
Jun 16 403718 km Jun 17 401733 km (The Next Day)
On 16/6/2020 the moon Earth distance was 403718 km
So we need to know where the moon will be on the next day (17/6/2020)?
Let's try to do that….
- The radius =403718 km so C (orbital circumference) = 403718 x 2π=2.536 mkm
- The moon moves it during 29.53 days ( L0= 2.536 mkm/29.53) = 85900 km
- L0= 85900 km but L0 = 88000 km Cos θ0
- θ0= 12.5413 degrees
- θ1= θ0+ 0.9856262 = 12.5413 +0.9856262 = 13.527 degrees
- L1 = 88000 km (Cos 13.527 degrees) = 85558.8 km
- During 29.53 days = L1 x29.53 = 85558.8 km x 29.53 = 2.5265 mkm
- 2.5265 mkm = 2π x 402113.4 km
- i.e. The moon on next day (17/6/2020) should be on 402113.4 km
The registered value on 17/6/2020 (401733 km)
The difference = 401733 km – 402113.4 km = 381 km

13. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
13
(10) 17 – June -2020
Jun 17 401733 km Jun 18 398840 km (The Next Day)
On 17/6/2020 the moon Earth distance was 401733 km
So we need to know where the moon will be on the next day (18/6/2020)?
Let's try to do that….
- The radius =401733 km so C (orbital circumference) = 401733 x 2π=2.524 mkm
- The moon moves it during 29.53 days ( L0= 2.524 mkm/29.53) = 85478 km
- L0= 85478 km but L0 = 88000 km Cos θ0
- θ0= 13.75 degrees
- θ1= θ0+ 0.9856262 = 13.75 +0.9856262 = 14.7361 degrees
- L1 = 88000 km (Cos 14.7361 degrees) = 85105.4 km
- During 29.53 days = L1 x29.53 = 85105.4 km x 29.53 = 2.51316 mkm
- 2.51316 mkm = 2π x 399982.5 km
- i.e. The moon on next day (18/6/2020) should be on 399982.5 km
The registered value on 18/6/2020 (398840 km)
The difference = 398840 km – 399982.5 km = 1143 km

14. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
14
(11) 18 – June -2020
Jun 18 398840 km Jun 19 395303 km (The Next Day)
On 18/6/2020 the moon Earth distance was 398840 km
So we need to know where the moon will be on the next day (19/6/2020)?
Let's try to do that….
- The radius =398840 km so C (orbital circumference) = 398840 x 2π=2.505 mkm
- The moon moves it during 29.53 days ( L0= 2.505 mkm/29.53) = 84862.36 km
- L0= 84862.36 km but L0 = 88000 km Cos θ0
- θ0= 15.346 degrees
- θ1= θ0+ 0.9856262 = 15.346 +0.9856262 = 16.331 degrees
- L1 = 88000 km (Cos 16.331 degrees) = 84449.2 km
- During 29.53 days = L1 x29.53 = 84449.2 km x 29.53 = 2.4937 mkm
- 2.4937 mkm = 2π x 396898.2 km
- i.e. The moon on next day (19/6/2020) should be on 396898.2 km
The registered value on 19/6/2020 (395303 km)
The difference = 395303 km – 396898.2 km = 1596 km

15. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
15
(12) 19 – June -2020
Jun 19 395303 km Jun 20 391409 km (The Next Day)
On 19/6/2020 the moon Earth distance was 395303 km
So we need to know where the moon will be on the next day (20/6/2020)?
Let's try to do that….
- The radius =395303 km so C (orbital circumference) = 395303 x 2π=2.483 mkm
- The moon moves it during 29.53 days ( L0= 2.483 mkm/29.53) = 84109.8 km
- L0= 84109.8 km but L0 = 88000 km Cos θ0
- θ0= 17.1 degrees
- θ1= θ0+0.9856262 = 17.1 +0.9856262 = 18.0856 degrees
- L1 = 88000 km (Cos 18.0856 degrees) = 83652.2 km
- During 29.53 days = L1 x29.53 = 83652.2 km x 29.53 = 2.47 mkm
- 2.47 mkm = 2π x 393152.6 km
- i.e. The moon on next day (20/6/2020) should be on 393152.6 km
The registered value on 20/6/2020 (391409 km)
The difference = 391409 km – 393152.6 km = 1744 km

16. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
16
(13) 20 – June -2020
Jun 20 391409 km Jun 21 387432 km (The Next Day)
On 20/6/2020 the moon Earth distance was 391409 km
So we need to know where the moon will be on the next day (21/6/2020)?
Let's try to do that….
- The radius =391409 km so C (orbital circumference) = 391409 x 2π=2.459 mkm
- The moon moves it during 29.53 days ( L0= 2.459 mkm/29.53) = 83281.3 km
- L0= 83281.3 km but L0 = 88000 km Cos θ0
- θ0= 18.848 degrees
- θ1= θ0+ 0.9856262 = 18.848 +0.9856262 = 19.8338 degrees
- L1 = 88000 km (Cos 19.8338 degrees) = 82780 km
- During 29.53 days = L1 x29.53 = 82780 km x 29.53 = 2.444 mkm
- 2.444 mkm = 2π x 389052.7 km
- i.e. The moon on next day (21/6/2020) should be on 389052.7 km
The registered value on 21/6/2020 (387432 km)
The difference = 387432 km – 389052.7 km =1621 km

17. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
17
(14) 21 – June -2020
Jun 21 387432 km Jun 22 383607 km (The Next Day)
On 21/6/2020 the moon Earth distance was 387432 km
So we need to know where the moon will be on the next day (22/6/2020)?
Let's try to do that….
- The radius =387432 km so C (orbital circumference) = 387432 x 2π=2.434 mkm
- The moon moves it during 29.53 days ( L0= 2.434 mkm/29.53) = 82435 km
- L0= 82435 km but L0 = 88000 km Cos θ0
- θ0= 20.485 degrees
- θ1= θ0+ 0.9856262 = 20.485 +0.9856262 = 21.47 degrees
- L1 = 88000 km (Cos 21.47 degrees) = 81893.1 km
- During 29.53 days = L1 x29.53 = 81893.1 km x 29.53 = 2.4183 mkm
- 2.4183 mkm = 2π x 384884.9 km
- i.e. The moon on next day (22/6/2020) should be on 384884.9 km
The registered value on 22/6/2020 (383607 km)
The difference = 383607 km – 384884.9 km =1278 km

18. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
18
(15) 22 – June -2020
Jun 22 383607 km Jun 23 380110 km (The Next Day)
On 22/6/2020 the moon Earth distance was 383607 km
So we need to know where the moon will be on the next day (23/6/2020)?
Let's try to do that….
- The radius =383607 km so C (orbital circumference) = 383607 x 2π=2.41 mkm
- The moon moves it during 29.53 days ( L0= 2.41 mkm/29.53) = 81621.2 km
- L0= 81621.2 km but L0 = 88000 km Cos θ0
- θ0= 21.9495 degrees
- θ1= θ0+ 0.9856262 = 21.9495 +0.9856262 = 22.935 degrees
- L1 = 88000 km (Cos 22.935 degrees) = 81043.2 km
- During 29.53 days = L1 x29.53 = 81043.2 km x 29.53 = 2.3932 mkm
- 2.3932 mkm = 2π x 380890 km
- i.e. The moon on next day (23/6/2020) should be on 380890 km
The registered value on 23/6/2020 (380110 km)
The difference = 380110 km – 380890 km =780 km

19. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
19
(16) 23 – June -2020
Jun 23 380110 km Jun 24 377044 km (The Next Day)
On 23/6/2020 the moon Earth distance was 380110 km
So we need to know where the moon will be on the next day (24/6/2020)?
Let's try to do that….
- The radius =380110 km so C (orbital circumference) = 380110 x 2π=2.388 mkm
- The moon moves it during 29.53 days ( L0= 2.388 mkm/29.53) = 80877 km
- L0= 80877 km but L0 = 88000 km Cos θ0
- θ0= 23.2112 degrees
- θ1= θ0+ 0.9856262 = 23.2112 +0.9856262 = 24.1968 degrees
- L1 = 88000 km (Cos 24.1968 degrees) = 80268.5 km
- During 29.53 days = L1 x29.53 = 80268.5 km x 29.53 = 2.37 mkm
- 2.37 mkm = 2π x 377249.8 km
- i.e. The moon on next day (24/6/2020) should be on 377250 km
The registered value on 24/6/2020 (377044 km)
The difference = 377044 km – 377250 km =206 km

20. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
20
(17) 24 – June -2020
Jun 24 377044 km Jun 25 374451 km (The Next Day)
On 24/6/2020 the moon Earth distance was 377044 km
So we need to know where the moon will be on the next day (25/6/2020)?
Let's try to do that….
- The radius =377044 km so C (orbital circumference) = 377044 x 2π=2.369 mkm
- The moon moves it during 29.53 days ( L0= 2.369 mkm/29.53) = 80224.8 km
- L0= 80224.8 km but L0 = 88000 km Cos θ0
- θ0= 24.266 degrees
- θ1= θ0+ 0.9856262 = 24.266 +0.9856262 = 25.2519 degrees
- L1 = 88000 km (Cos 25.2519 degrees) = 79590.7 km
- During 29.53 days = L1 x29.53 = 79590.7 km x 29.53 = 2.35 mkm
- 2.35 mkm = 2π x 374046.3 km
- i.e. The moon on next day (25/6/2020) should be on 374046 km
The registered value on 25/6/2020 (374451 km)
The difference = 374451 km – 374046 km =405 km

21. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
21
(18) 25 – June -2020
Jun 25 374451 km Jun 26 372338 km (The Next Day)
On 25/6/2020 the moon Earth distance was 374451 km
So we need to know where the moon will be on the next day (26/6/2020)?
Let's try to do that….
- The radius =374451 km so C (orbital circumference) = 374451 x 2π=2.352 mkm
- The moon moves it during 29.53 days ( L0= 2.352 mkm/29.53) = 79673 km
- L0= 79673 km but L0 = 88000 km Cos θ0
- θ0= 25.126 degrees
- θ1= θ0+ 0.9856262 = 25.126 +0.9856262 = 26.111 degrees
- L1 = 88000 km (Cos 26.111 degrees) = 79018.5 km
- During 29.53 days = L1 x29.53 = 79018.5 km x 29.53 = 2.3334 mkm
- 2.3334 mkm = 2π x 371374.7 km
- i.e. The moon on next day (26/6/2020) should be on 371374.7 km
The registered value on 26/6/2020 (372338 km)
The difference = 372338 km – 371374.7 =964 km

22. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
22
(19) 26 – June -2020
Jun 26 372338 km Jun 27 370703 km (The Next Day)
On 26/6/2020 the moon Earth distance was 372338 km
So we need to know where the moon will be on the next day (27/6/2020)?
Let's try to do that….
- The radius =372338 km so C (orbital circumference) = 372338 x 2π=2.339 mkm
- The moon moves it during 29.53 days ( L0= 2.339 mkm/29.53) = 79223.4 km
- L0= 79223.4 km but L0 = 88000 km Cos θ0
- θ0= 25.8 degrees
- θ1= θ0+ 0.9856262 = 25.8 +0.9856262 = 26.792 degrees
- L1 = 88000 km (Cos 26.792 degrees) = 78552.7 km
- During 29.53 days = L1 x29.53 = 78552.7 km x 29.53 = 2.3196 mkm
- 2.3196 mkm = 2π x 369185.7 km
- i.e. The moon on next day (27/6/2020) should be on 369185.7 km
The registered value on 27/6/2020 (370703 km)
The difference = 370703 km – 369185.7 =1518 km
Note Please
- This day is the last day in the moon descending motion, after it the moon stay in
perigee 3 days!! (28-6-2020 369571 km), (29-6-2020 369005 km), (30-6-2020
369106 km) –
- That tells, when the moon changes its motion from ascending to descending and
vice versa, the moon consumes long time in this process which causes great error
for the calculations…
- i.e. there's specific reason at perigee and apogee point causes the moon to stay
longer time there than expected…
- based on that, we have to analyze the equation test results for 20 days only

23. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
23
1-2 The Test Results Discussion And Analysis
Let's take a look on the different distances between the equation results and the
registered data in following
Day Registered Data Equation Results Difference
6-6-2020 369418 km ----------------------- -----------------------
7-6-2020 373729 km 372562 km 1167 km
8-6-2020 378917 km 376721 km 2197 km
9-6-2020 384534 km 381712 km 2822 km
10-6-2020 390096 km 387097 km 3000 km
11-6-2020 395156 km 392401 km 2755 km
12-6-2020 399345 km 397197 km 2148 km
13-6-2020 402395 km 401136 km 1259 km
14-6-2020 404153 km 403979 km 174 km
15-6-2020 404574 km ----------------------- ----------------
16-6-2020 403718 km 403037 km 681 km
17-6-2020 401733 km 402113 km 381 km
18-6-2020 398840 km 399982 km 1143 km
19-6-2020 395303 km 396898 km 1596 km
20-6-2020 391409 km 393152 km 1744 km
21-6-2020 387432 km 389052 km 1621 km
22-6-2020 383607 km 384885 km 1278 km
23-6-2020 380110 km 380890 km 780 km
24-6-2020 377044 km 377250 km 206 km
25-6-2020 374451 km 374046 km 405 km
36-6-2020 372338 km 371374 km 964 km
27-6-2020 370703 km 369186 km 1517 km
369571 km ----------------------
369005 km ----------------------
369106 km ----------------------
[
The Test Results Analysis:
- The Total Results Are 20 Values
o 11 values less than 1280 km (Error 3%)
o 4 values around 1300-2000 km (Error 4.6 %)
o 5 values around 2000- 3000 km (Error 7%)
- The Distance Between Perigee And Apogee =43000 Km
- 1280 km (as error) = 3%
- 2000 km (as error) = 4.6%
- 3000 km )as error)= 7%

24. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
24
The Conclusion
The Equation Is correct and trustee
The Conclusion Explanation
- This test contains the moon both motions, the ascending and descending from
perigee to apogee and vice versa
- The Equation works sufficiently in the moon steadily motion. each degree causes
the moon distance to Earth to be changed with different values but its max value
may be around (3000 km)
- The ascending motion is a similar to the descending motion both use the equation
sufficiently
- It's noticeable and noteworthy, to refer to that, when the moon changes its motion
from ascending to descending or vice versa that consumes a period of time and the
moon distance to The Earth can't be defined clearly based on the day degree that
because of that..
The Equation Concept is discussed in the previous paper, please review
The Moon Motion Basic Equation
Session
https://www.academia.edu/s/46a3441e4a
or
https://www.academia.edu/44396469/The_Moon_Motion_Basic_Equation
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation

25. IN THE ALMIGHTY GOD NAME
Through the Mother of God mediation
I do this research
Gerges Francis Tawadrous/
2nd
Course student – physics Faculty – People's Friendship University – Moscow –Russia..
mrwaheid1@yahoo.com mrwaheid@gmail.com +201022532292
25
References
The Moon Motion Trajectory Analysis (II)
https://www.academia.edu/44368860/The_Moon_Motion_Trajectory_Analysis_II_
The Moon Motion Basic Equation (III) (Test No.2)
https://www.academia.edu/s/e493aec33a
or
https://www.slideshare.net/Gergesfrancis/the-moon-motion-basic-equation-iii-test-no2
Light Motion Features Are Discovered in Planet Motion
https://www.slideshare.net/Gergesfrancis/light-motion-features-are-discovered-in-planet-motion
or
https://www.academia.edu/44286772/Light_Motion_Features_Are_Discovered_in_Planet_Motion
Can Different Rates Of Time Be Found In The Solar System Motion?(II)
https://www.academia.edu/44334645/Can_Different_Rates_Of_Time_Be_Found_In_The_Solar_System_Motion_II_
Dr. Budochkina, Svetlana Aleksandrovna
Associate professor - Candidate of physico-mathematical sciences (2005)
http://www.mathnet.ru/eng/person22119
List of publications on Google Scholar
List of publications on ZentralBlatt
https://mathscinet.ams.org/mathscinet/MRAuthorID/757317
http://elibrary.ru/author_items.asp?spin=6087-3245
http://orcid.org/0000-0003-3447-0425
http://www.researcherid.com/rid/G-7453-2014
http://www.scopus.com/authid/detail.url?authorId=6507007003
https://www.researchgate.net/profile/Svetlana_Budochkina
Full list of
publications:
http://web-local.rudn.ru/web-
local/prep/rj/index.php?id=2944&p=15209
Mr.Gerges Francis Tawdrous +201022532292
Physics Department- Physics & Mathematics Faculty
Gerges Francis Tawdrous +201022532292
Curriculum Vitae http://vixra.org/abs/1902.0044
E-mail mrwaheid@gmail.com
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