The program reads in doubles from a file two at a time, uses those values to create Rectangle objects with a length and width, calculates the area of each rectangle, and outputs the rectangle with the largest area. It creates and initializes a Rectangle for the first input values as the largest so far, then loops to continue reading input and creating rectangles, comparing each new one to the current largest by area and updating the largest if a bigger one is found.

1. In Java;
Input is from a file. The input is all doubles. You are to input these doubles 2 at a time (the
length and width), create a Rectangle and determine if it has the largest area. Output the
Rectangle with the largest area.
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class Lab8Num2 {
public static void main(String[] args) {
File inFile = new File("lab8.in");
Scanner fileInput = null;
try {
fileInput = new Scanner(inFile);
} catch (FileNotFoundException ex) {
}
//get first Rectangle and make it the biggest;
//do NOT put into an arrayList and sort.
while ()
{ //get more data from file
//make Rectangle
//see if it is bigger than biggest so far
//if so, it is the new biggest
}
System.out.println("The biggest rectangle was " + biggest);
}
}
public class Rectangle
{
private double length, width;
public Rectangle()
{
length=0;
width=0;
}
public Rectangle(double len, double wid)
{

2. length=len;
width=wid;
}
public double getLength() {
return length;
}
public void setLength(double length) {
this.length = length;
}
public double getWidth() {
return width;
}
public void setWidth(double width) {
this.width = width;
}
public double area()
{
return length*width;
}
public double perimeter()
{
return 2*(length+width);
}
public String toString()
{
return "Length: " + length + " Width: " + width;
}
public int compareTo(Rectangle r)
{
}
}