Input is from a file- The input is all doubles- You are to input these.pdf

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Input is from a file. The input is all doubles. You are to input these doubles 2 at a time (the length and width), create a Rectangle and determine if it has the largest area. Output the Rectangle with the largest area. import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; public class Lab8Num2 { public static void main(String[] args) { File inFile = new File("lab8.in"); Scanner fileInput = null; try { fileInput = new Scanner(inFile); } catch (FileNotFoundException ex) { } //get first Rectangle and make it the biggest; //do NOT put into an arrayList and sort. while () { //get more data from file //make Rectangle //see if it is bigger than biggest so far //if so, it is the new biggest } System.out.println("The biggest rectangle was " + biggest); } } public class Rectangle { private double length, width; public Rectangle() { length=0; width=0; } public Rectangle(double len, double wid) { length=len; width=wid; } public double getLength() { return length; } public void setLength(double length) { this.length = length; } public double getWidth() { return width; } public void setWidth(double width) { this.width = width; } public double area() { return length*width; } public double perimeter() { return 2*(length+width); } public String toString() { return "Length: " + length + " Width: " + width; } public int compareTo(Rectangle r) { } } .

Education

}
public double getLength() {
return length;
}
public void setLength(double length) {
this.length = length;
}
public double getWidth() {
return width;
}
public void setWidth(double width) {
this.width = width;
}
public double area()
{
return length*width;
}
public double perimeter()
{
return 2*(length+width);
}
public String toString()
{
return "Length: " + length + " Width: " + width;
}
public int compareTo(Rectangle r)
{
}
}

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Given 8 distinct integers from the set {1, 2, . . . , 16}, prove that there exists k such that ai aj = k has at least 3 distinct solutions (ai , aj ) ? Solution For any k (unless the K is zero), at least 3 distinct solutions need not be existing. Let\'s look at the next most favourable case If k= 2; We have to consider the case where the number of solutions of ai-aj=2 are minimum since we have to show that at least 3 distinct solutions exist (which means even in the most unfavourable case for a chosen k there will be 3 distinct solutions satisfying the equation ai-aj=2) If k = 2; we start by taking numbers that are not at all 2 units apart from each other; So we start with 1 and move 3 units successively ahead 1, 4, 7, 10,13, 16; Now we notice that these 6 numbers are of 3k+1 form; remaining numbers can be any 2 ranomdly selected say 2 and 11; we get 4-2 = 2 and 13-11=2; Hence only 2 distinct solutions are possible..

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