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NAMA  : YOSAFAT E.L. HOELY 

NIM      : 12110056 

PRODI  : SISTIM INFORMASI 


                                 TUGAS KALKULUS II 
 


    1.   ∫(X + 3X ‐ 8X + 15)dx 
               7       6
                                           =       x8 +  x7 ‐  x2 + 5x + c 

                                          =     x8 +  x7 ‐ 4x2 + 5x + c 


    2.   ∫(    x4 ‐ 12X2+  X + 6)dx        =       x4 ‐  x3 +  x2 + 6x + c 

                                          =     x4 ‐ 4x3 +  x2 + 6x + c 


    3.   ∫(x    1/3
                    + 4x 2/5 )dx          =     x 4/3 +   x 20/7 + c 
          

    4.   ∫(x – 1)4  dx 
          
         Misalnya,         U = x ‐1 maka du/dx = x 
                                                dx = du/x 
          

                   ∫       4  
         jadi,  (x – 1) dx  =         ∫U4  du/x 
                                  =  ½ . ⅕ . U5 + c 
                                  = 1/10 (x‐1)5 + c 
          
          
          
          
          
          



                       big.yozhy@gmail.com
NAMA  : YOSAFAT E.L. HOELY 

NIM      : 12110056 

PRODI  : SISTIM INFORMASI 

          

    5.   ∫         dx                         =   x ∫ 2/4 dx 
          
                                              =               x 2/4 + 1 + c 

                                               
                                              =         x6/4 + c 


                                              =    x6/4 + c 
                                               
                                              =    x6/4 + c 

    6.   ∫x (6x2 – 5)4 dx 
         Penyelesaian : 
         Misalnya,      U = 6x2 – 5 maka  du/dx = 12x 
                                                  du = 12x dx 
                                                        du = x dx 

              ∫ x (6x2 – 5)4 dx = ∫u4 . 
         Jadi,                                         du 

                                     =    ∫u4 du 
                                           

                                      
                                     =   .   u5 + c 
                                      
                                     =   (6x2 – 5)5 + c 

 




                   big.yozhy@gmail.com
NAMA  : YOSAFAT E.L. HOELY 

NIM      : 12110056 

PRODI  : SISTIM INFORMASI 

 

    7.   ∫ x5 (5x6 – 2)7 dx 
         Penyelesaian : 
                                                           5
         Misalnya,     U = 5x6 – 2 maka  du/dx = 30x  
                                               5
                                                X  dx =     du 

              ∫ x5 (5x6 – 2)7 dx = ∫
         Jadi,                                 u7du 
          

                                  =    ∫u7 du 
          
                                  =     .   u8 + c 
          
                                   =   (5x6 – 2)8 + c 




                      big.yozhy@gmail.com

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Tugas 1 kalkulus

  • 1. NAMA  : YOSAFAT E.L. HOELY  NIM      : 12110056  PRODI  : SISTIM INFORMASI  TUGAS KALKULUS II    1. ∫(X + 3X ‐ 8X + 15)dx  7 6  =     x8 +  x7 ‐  x2 + 5x + c  =     x8 +  x7 ‐ 4x2 + 5x + c  2. ∫( x4 ‐ 12X2+  X + 6)dx   =     x4 ‐  x3 +  x2 + 6x + c  =     x4 ‐ 4x3 +  x2 + 6x + c  3. ∫(x  1/3  + 4x 2/5 )dx    =     x 4/3 +   x 20/7 + c    4. ∫(x – 1)4  dx    Misalnya,  U = x ‐1 maka du/dx = x                   dx = du/x    ∫ 4   jadi,  (x – 1) dx  =  ∫U4  du/x  =  ½ . ⅕ . U5 + c  = 1/10 (x‐1)5 + c              big.yozhy@gmail.com
  • 2. NAMA  : YOSAFAT E.L. HOELY  NIM      : 12110056  PRODI  : SISTIM INFORMASI    5. ∫  dx      =   x ∫ 2/4 dx    =    x 2/4 + 1 + c    =   x6/4 + c  =    x6/4 + c    =    x6/4 + c  6. ∫x (6x2 – 5)4 dx  Penyelesaian :  Misalnya,  U = 6x2 – 5 maka  du/dx = 12x                      du = 12x dx     du = x dx  ∫ x (6x2 – 5)4 dx = ∫u4 .  Jadi,   du  =  ∫u4 du      =   .   u5 + c    =   (6x2 – 5)5 + c    big.yozhy@gmail.com
  • 3. NAMA  : YOSAFAT E.L. HOELY  NIM      : 12110056  PRODI  : SISTIM INFORMASI    7. ∫ x5 (5x6 – 2)7 dx  Penyelesaian :  5 Misalnya,  U = 5x6 – 2 maka  du/dx = 30x   5                X  dx =   du  ∫ x5 (5x6 – 2)7 dx = ∫ Jadi,    u7du       =    ∫u7 du       =   .   u8 + c                =   (5x6 – 2)8 + c  big.yozhy@gmail.com