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Chapter 2 MacromechanicalAnalysis of a Lamina
Hygrothermal Stresses and Strains
Dr.Autar Kaw
Department of Mechanical Engineering
University of South Florida,Tampa, FL 33620
Courtesy of the Textbook
Mechanics of Composite Materials by Kaw
 For a unidirectional lamina
 Thermally induced strains:
 Moisture induced strains:




























































0
+
0
+
S
0
0
0
S
S
0
S
S
= C
2
C
1
T
2
T
1
12
2
1
66
22
12
12
11
12
2
1



































0
T
=
0
2
1
T
2
T
1





























0
C
=
0
2
1
C
2
C
1




(2.174)
(2.175)
(2.176)
 For a unidirectional lamina




























































0
0
0
0
0
0
2
1
2
1
12
2
1
66
22
12
12
11
12
2
1
ε
ε
+
ε
ε
+
τ
σ
σ
S
S
S
S
S
=
γ
ε
ε
C
C
T
T




































γ
ε
-
ε
-
ε
ε
-
ε
-
ε
Q
Q
Q
Q
Q
=
τ
σ
σ
C
T
C
T
12
2
2
2
1
1
1
66
22
12
12
11
12
2
1
0
0
0
0
(2.174)
(2.177)
 For an angular lamina
 Thermally induced strains:
 Moisture induced strains:
































































γ
ε
ε
+
γ
ε
ε
+
τ
σ
σ
S
S
S
S
S
S
S
S
S
=
γ
ε
ε
C
xy
C
y
C
x
T
xy
T
y
T
x
xy
y
x
xy
y
x
66
26
16
26
22
12
16
12
11

































xy
y
x
T
xy
T
y
T
x
T
=

































xy
y
x
C
xy
C
y
C
x
C
=
(2.178)
(2.179)
(2.180)
 For an angular lamina
























0
2
2
1
1
α
α
]
= [T
/
α
α
α
-
xy
y
x
















s
c
sc
sc
sc
c
s
sc
s
c
=
T
2
2
2
2
2
2
1
2
2
]
[












s
-
c
sc
sc
-
2sc
-
c
s
2sc
s
c
=
[T]
2
2
2
2
2
2
)
(
=
c 
Cos
)
(
=
s 
Sin
(2.181)
(2.95) (2.96)
(2.97a,b)
 For an angular lamina
























0
]
[T
=
/2
2
1
1
-
xy
y
x





















s
c
sc
sc
2sc
c
s
2sc
s
c
=
]
[T
2
2
2
2
2
2
1












s
-
c
sc
sc
-
2sc
-
c
s
2sc
s
c
=
[T]
2
2
2
2
2
2
)
(
=
c 
Cos
)
(
=
s 
Sin
(2.95) (2.96)
(2.97a,b)
(2.182)
Find the following for a 600
angle lamina of Glass/Epoxy
a) coefficients of thermal expansion,
b) coefficients of moisture expansion,
c) strains under a temperature change of -1000
C and a moisture absorption of 0.02 kg/kg.
Use properties of unidirectional Glass/Epoxy lamina from Table 2.1.
a) From Table 2.1,
C,
/
m/m
10
8.6
= 0
-6
1 

C.
/
m/m
10
22.1
= 0
-6
2 

Using Equation (2.181), gives
,
0
10
22.1
10
8.6
0.5000
-
0.4330
-
0.4330
0.8660
0.2500
0.7500
0.8660
-
0.7500
0.2500
=
/2
6
-
-6
xy
y
x







































C.
/
m/m
10
11.69
-
10
11.98
10
18.73
= 0
6
-
6
-
-6
xy
y
x






























.
0
]
[T
=
/2
2
1
1
-
xy
y
x





























(2.181)
b) From Table 2.1
m/m/kg/kg,
0
=
1

m/m/kg/kg.
0.6
=
2

Using Equation (2.182) gives
































0
0.6
0.0
0.5000
-
0.4330
-
0.4330
0.8660
0.2500
0.7500
0.8660
-
0.7500
0.2500
=
/2
xy
y
x



m/m/kg/kg
0.5196
-
0.1500
0.4500
=
xy
y
x

















































0
]
[T
=
/2
2
1
1
-
xy
y
x





(2.182)
c) Now using Equations (2.179) and (2.180) to calculate the strains as.
(0.02)
0.5196
-
0.1500
0.4500
+
(-100)
10
11.69
-
10
11.98
10
18.73
=
6
-
6
-
-6
xy
y
x








































m/m
10
0.9223
-
10
0.1802
10
0.7127
=
2
2
2



























































































C
xy
C
y
C
x
T
xy
T
y
T
x
xy
y
x
66
26
16
26
22
12
16
12
11
xy
y
x
+
+
S
S
S
S
S
S
S
S
S
= (2.178)
Chapter2_9_hygrothermal stresses and strains.pptx

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Chapter2_9_hygrothermal stresses and strains.pptx

  • 1. Chapter 2 MacromechanicalAnalysis of a Lamina Hygrothermal Stresses and Strains Dr.Autar Kaw Department of Mechanical Engineering University of South Florida,Tampa, FL 33620 Courtesy of the Textbook Mechanics of Composite Materials by Kaw
  • 2.  For a unidirectional lamina  Thermally induced strains:  Moisture induced strains:                                                             0 + 0 + S 0 0 0 S S 0 S S = C 2 C 1 T 2 T 1 12 2 1 66 22 12 12 11 12 2 1                                    0 T = 0 2 1 T 2 T 1                              0 C = 0 2 1 C 2 C 1     (2.174) (2.175) (2.176)
  • 3.  For a unidirectional lamina                                                             0 0 0 0 0 0 2 1 2 1 12 2 1 66 22 12 12 11 12 2 1 ε ε + ε ε + τ σ σ S S S S S = γ ε ε C C T T                                     γ ε - ε - ε ε - ε - ε Q Q Q Q Q = τ σ σ C T C T 12 2 2 2 1 1 1 66 22 12 12 11 12 2 1 0 0 0 0 (2.174) (2.177)
  • 4.  For an angular lamina  Thermally induced strains:  Moisture induced strains:                                                                 γ ε ε + γ ε ε + τ σ σ S S S S S S S S S = γ ε ε C xy C y C x T xy T y T x xy y x xy y x 66 26 16 26 22 12 16 12 11                                  xy y x T xy T y T x T =                                  xy y x C xy C y C x C = (2.178) (2.179) (2.180)
  • 5.  For an angular lamina                         0 2 2 1 1 α α ] = [T / α α α - xy y x                 s c sc sc sc c s sc s c = T 2 2 2 2 2 2 1 2 2 ] [             s - c sc sc - 2sc - c s 2sc s c = [T] 2 2 2 2 2 2 ) ( = c  Cos ) ( = s  Sin (2.181) (2.95) (2.96) (2.97a,b)
  • 6.  For an angular lamina                         0 ] [T = /2 2 1 1 - xy y x                      s c sc sc 2sc c s 2sc s c = ] [T 2 2 2 2 2 2 1             s - c sc sc - 2sc - c s 2sc s c = [T] 2 2 2 2 2 2 ) ( = c  Cos ) ( = s  Sin (2.95) (2.96) (2.97a,b) (2.182)
  • 7. Find the following for a 600 angle lamina of Glass/Epoxy a) coefficients of thermal expansion, b) coefficients of moisture expansion, c) strains under a temperature change of -1000 C and a moisture absorption of 0.02 kg/kg. Use properties of unidirectional Glass/Epoxy lamina from Table 2.1.
  • 8. a) From Table 2.1, C, / m/m 10 8.6 = 0 -6 1   C. / m/m 10 22.1 = 0 -6 2   Using Equation (2.181), gives , 0 10 22.1 10 8.6 0.5000 - 0.4330 - 0.4330 0.8660 0.2500 0.7500 0.8660 - 0.7500 0.2500 = /2 6 - -6 xy y x                                        C. / m/m 10 11.69 - 10 11.98 10 18.73 = 0 6 - 6 - -6 xy y x                               . 0 ] [T = /2 2 1 1 - xy y x                              (2.181)
  • 9. b) From Table 2.1 m/m/kg/kg, 0 = 1  m/m/kg/kg. 0.6 = 2  Using Equation (2.182) gives                                 0 0.6 0.0 0.5000 - 0.4330 - 0.4330 0.8660 0.2500 0.7500 0.8660 - 0.7500 0.2500 = /2 xy y x    m/m/kg/kg 0.5196 - 0.1500 0.4500 = xy y x                                                  0 ] [T = /2 2 1 1 - xy y x      (2.182)
  • 10. c) Now using Equations (2.179) and (2.180) to calculate the strains as. (0.02) 0.5196 - 0.1500 0.4500 + (-100) 10 11.69 - 10 11.98 10 18.73 = 6 - 6 - -6 xy y x                                         m/m 10 0.9223 - 10 0.1802 10 0.7127 = 2 2 2                                                                                            C xy C y C x T xy T y T x xy y x 66 26 16 26 22 12 16 12 11 xy y x + + S S S S S S S S S = (2.178)