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Arithmetic Series- the sum of the
arithmetic sequence
FORMULA
General Formula
an=a1+(n-1)d
Sn = n/2 (a1 + an)
Or
Sn = n/2 [2a1 +(n-1)d
Example 1. 3, 11, 19
Find S6
d=8
an=a1+(n-1)d
a6 = 3+(6-1)8
3+(5)8
3+40
a6 = 43
Sn = n/2 (a1 + an)
S6 = 6/2 (3 + 43)
S6 = 3 (46)
S6 =138
Example #2: a1=7 and d=9
Find S9
an=a1+(n-1)d
a9 = 7+(9-1)9
7+(8)9
a9 = 72
Sn = n/2 (a1 + an)
S9 = 9/2 (7 + 79)
9(43)
S9 = 387
Example #3:
If you were given P50.00 on the first day of
school, P55.00 on the second day and
additional P5.00 daily, how much money
will you be able to save by the end of the
week?
a14= 2weeks
 an=a1+(n-1)d
 a14 = 50+(14-1)5
 50+(13)5
 50+(13)5
 a14 = 115
 Sn = n/2 (a1 + an)
 S14 = 14/2 (50 + 115)
 7(165)
 S14 = 1115
Example #4: find S10 if:
a. a1 = 5 and an= 68
B. a1 = 5, d= -7 an= ?
 c. 3, 5, 7, 11
D. 6, 3, 0, -3
a. a1 = 5 and an= 68
Sn = n/2 (a1 + an)
10/2 (5+68)
5 (73)
S10=365
B. a1 = 5, d= -7 n=10 an= ?
Sn = n/2 [2a1 +(n-1)d]
10/2 [2(5) +(10-1)-7]
5 [10 + 9 (-7)]
5 [ 10 + (-63) ]
5 [-53 ]
S10=-265
c. 3,5,7,11
a1 = 3, d= 2 n=10 an= ?
Sn = n/2 [2a1 +(n-1)d]
10/2 [2(3) +(10-1)2]
5 [6 + 9 (2)]
5 [6 + 18]
5 [24]
Sn =120
d. 6, 3, 0, -3
a1 = 6, d= -3 n=10 an= ?
Sn = n/2 [2a1 +(n-1)d]
10/2 [2(6) +(10-1)-3]
5 [12 + 9 (-3)]
5 [12 + (-27)]
5 [-15]
Sn =-75
Example #5: Find the first term and the last term
and the sum of each finite arithmetic series.
 1. 𝑛=1
31
6𝑛
 2. 𝑛=3
20
(3𝑛 − 1)
 3. 𝑛=2
16
(3𝑛 + 4)
 4
1. 𝑛=1
31
6𝑛
a1 = 6n
 =6(1)
 =6
an=6n
 =6(31)
 =186
n=31
Sn = n/2 (a1 + an)
31/2 (6 + 186)
31/2(192)
31(96)
2976
2. 𝑛=3
20
(3𝑛 − 1)
a1 = 3n-1
 =3(3)-1
 =9-1
 8
an =3n-1
 =3(20)-1
 =60-1
59
n=18 (20-3+1)=18
Sn = n/2 (a1 + an)
18/2 (8 + 59)
18/2(67)
9(67)
603
3. 𝑛=2
16
(3𝑛 + 4)
a1 = 3n+4
 =3(2)+4
 =6+4
 =10
an=3n+4
 =3(16)+4
 =48+4
 52
n=15
Sn = n/2 (a1 + an)
15/2 (10 + 52)
15/2(62)
15/2(62)
15 (31)
465
Example number 6: Evaluate the related
series of each problem.
1. 13, 15, 17, 19, 21, 23
= 108

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Arithmetic series

  • 1. Arithmetic Series- the sum of the arithmetic sequence
  • 2. FORMULA General Formula an=a1+(n-1)d Sn = n/2 (a1 + an) Or Sn = n/2 [2a1 +(n-1)d
  • 3. Example 1. 3, 11, 19 Find S6 d=8
  • 5. Sn = n/2 (a1 + an) S6 = 6/2 (3 + 43) S6 = 3 (46) S6 =138
  • 6. Example #2: a1=7 and d=9 Find S9 an=a1+(n-1)d a9 = 7+(9-1)9 7+(8)9 a9 = 72 Sn = n/2 (a1 + an) S9 = 9/2 (7 + 79) 9(43) S9 = 387
  • 7. Example #3: If you were given P50.00 on the first day of school, P55.00 on the second day and additional P5.00 daily, how much money will you be able to save by the end of the week?
  • 8. a14= 2weeks  an=a1+(n-1)d  a14 = 50+(14-1)5  50+(13)5  50+(13)5  a14 = 115  Sn = n/2 (a1 + an)  S14 = 14/2 (50 + 115)  7(165)  S14 = 1115
  • 9. Example #4: find S10 if: a. a1 = 5 and an= 68 B. a1 = 5, d= -7 an= ?  c. 3, 5, 7, 11 D. 6, 3, 0, -3
  • 10. a. a1 = 5 and an= 68 Sn = n/2 (a1 + an) 10/2 (5+68) 5 (73) S10=365
  • 11. B. a1 = 5, d= -7 n=10 an= ? Sn = n/2 [2a1 +(n-1)d] 10/2 [2(5) +(10-1)-7] 5 [10 + 9 (-7)] 5 [ 10 + (-63) ] 5 [-53 ] S10=-265
  • 12. c. 3,5,7,11 a1 = 3, d= 2 n=10 an= ? Sn = n/2 [2a1 +(n-1)d] 10/2 [2(3) +(10-1)2] 5 [6 + 9 (2)] 5 [6 + 18] 5 [24] Sn =120
  • 13. d. 6, 3, 0, -3 a1 = 6, d= -3 n=10 an= ? Sn = n/2 [2a1 +(n-1)d] 10/2 [2(6) +(10-1)-3] 5 [12 + 9 (-3)] 5 [12 + (-27)] 5 [-15] Sn =-75
  • 14. Example #5: Find the first term and the last term and the sum of each finite arithmetic series.  1. 𝑛=1 31 6𝑛  2. 𝑛=3 20 (3𝑛 − 1)  3. 𝑛=2 16 (3𝑛 + 4)  4
  • 15. 1. 𝑛=1 31 6𝑛 a1 = 6n  =6(1)  =6 an=6n  =6(31)  =186 n=31
  • 16. Sn = n/2 (a1 + an) 31/2 (6 + 186) 31/2(192) 31(96) 2976
  • 17. 2. 𝑛=3 20 (3𝑛 − 1) a1 = 3n-1  =3(3)-1  =9-1  8 an =3n-1  =3(20)-1  =60-1 59 n=18 (20-3+1)=18
  • 18. Sn = n/2 (a1 + an) 18/2 (8 + 59) 18/2(67) 9(67) 603
  • 19. 3. 𝑛=2 16 (3𝑛 + 4) a1 = 3n+4  =3(2)+4  =6+4  =10 an=3n+4  =3(16)+4  =48+4  52 n=15
  • 20. Sn = n/2 (a1 + an) 15/2 (10 + 52) 15/2(62) 15/2(62) 15 (31) 465
  • 21. Example number 6: Evaluate the related series of each problem. 1. 13, 15, 17, 19, 21, 23 = 108